Query suggestions needed

Question

Please help with this complex query, I have been working on a solution for hours now. Here is a simplified version:
I have 3 fields in tableA:field1, field2, field3
I want to return all those records that have both field2 and field3 the same but field1 different.
For example:
Field1 Field2 Field3
======================
Cars Blue 6 liter
Cars Blue 6 liter
Van Blue 6 liter
Cars Green 5 liter
Cars Green 5 liter
I need the first 3 records returned because field2 and field3 are the same but field1 is different.
Anyone have any ideas?

Answer 1

I think the second SELECT is unnessary. In other words, the following should be equivalent:
SELECT
    TABLEA.*
FROM
    TABLEA
WHERE
    (FIELD2, FIELD3)
    IN
        SELECT
            FIELD2,
            FIELD3
        FROM
                SELECT DISTINCT
                    FIELD1,
                    FIELD2,
                    FIELD3
                FROM
                    TABLEA
        GROUP BY
            FIELD2,
            FIELD3
        HAVING
            COUNT(*) > 1
    )Assuming FIELD1 is NOT NULL, it is also possible to eliminate the SELECT DISTINCT by using COUNT(DISTINCT...), as in something like:
SELECT
    TABLEA.*
FROM
    TABLEA
WHERE
    (FIELD2, FIELD3)
    IN
        SELECT
            FIELD2,
            FIELD3
        FROM
            TABLEA
        GROUP BY
            FIELD2,
            FIELD3
        HAVING
            COUNT(DISTINCT FIELD1) > 1
    )No doubt there are yet other solutions using analytics.