Query to generate a report

Question

Hi All,
I am trying to query the following table to generate a report
SQL> select * from sample_tab;
ID ITEM_CODE STATUS
smtabid01 book placed
smtabid01 book billed
smtabid01 book shipped
smtabid02 Magazine placed
smtabid02 Magazine billed
smtabid03 stationary placed
smtabid04 Folders placed
smtabid04 Folders shipped
8 rows selected.
Report should be as follows
ID ITEM_CODE PLACED BILLED SHIPPED
smtabid01 book Success Success Success
smtabid02 Magazine Success Success Pending
smtabid03 stationary Success Pending Pending
smtabid04 Folders Success Pending Success
Basically I am trying to group the status of all the id's into single row
I have tried the following query, but this gives the output for each row. I know this is not the correct query but I couldnt figure out how to accomplish this
select id,item_code,decode(status,'PLACED','Success','Pending'),decode(status,'BILLED','Success','Pending'),decode(status,'SHIPPED','Success','Pending')
from sample_tab;
Can anybody please help!!
Thank you!!

Answer 1

Hi,
You're on the right track!
The query you posted is producing multiple rows for each id: you want one row per id. That sounds like a job for "GROUP BY id".
This does what you want:
SELECT     id,     item_code
,     NVL (MAX (DECODE (status, 'placed',  'Success')), 'Pending')     AS placed
,     NVL (MAX (DECODE (status, 'billed',  'Success')), 'Pending')     AS billed
,     NVL (MAX (DECODE (status, 'shipped', 'Success')), 'Pending')     AS shipped
FROM     sample_tab
GROUP BY     id,     item_code
ORDER BY     id,     item_code;