Query to get the Quantities on Reservations window in Inventory
Hi All,
how can I get the Onhand Quantity and Available quantity on Item Reservations Details window( Inventory-->On hand Qunatity-->Reservations) in Oracle Apps 11i.I need to build a query wih all the reservation details.I need help in calculating the Quantities diplayed on the reservations form.
Could any one pls help me on this.
Thanks,
PV
Hi
Use the following query
SELECT SUM(transaction_quantity) A
FROM
MTL_ONHAND_QUANTITIES_DETAIL
WHERE
inventory_item_id = :INVENTORY_ITEM_ID
AND organization_id =:WH_ID;
QTY Reserved :---
SELECT SUM(RESERVATION_QUANTITY) B
FROM MTL_RESERVATIONS
WHERE inventory_item_id = :INVENTORY_ITEM_ID
AND organization_id = :WH_ID;
SELECT SUM(transaction_quantity) C
FROM
MTL_ONHAND_QUANTITIES_DETAIL
WHERE inventory_item_id = :INVENTORY_ITEM_ID
AND organization_id = :WH_ID
AND subinventory_code IN (SELECT SECONDARY_INVENTORY_NAME
FROM
MTL_SECONDARY_INVENTORIES
WHERE organization_id =:WH_ID
AND reservable_type = '2');
Qty Available :---
QTY_AV_BR:=nvl(A,0)- (nvl(B,0)+ nvl(C,0));
Hope this helps you
Thanks,
Vijay
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3020 2012 2 0.00 31075.53 0.00 0.00 0.00
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3020 2012 2 -112477.00 31075.53 24185.79 -158288.94 5625.44
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course-----groupname---TotalMembers---NotStarted---INProgress---Completed
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Course1-----state11-------12---------------6----------3-------------3
Course1------District111--10---------------5----------0-------------0
Course1--------City1111----0---------------0----------0-------------0
Course1--------City1112----1---------------0----------0-------------1
Course1--------City1113----6---------------3----------2-------------1
Course1---country2--------12---------------6----------3-------------3
Course1----state21--------12---------------6----------3-------------3
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Course2----state11--------12---------------6----------2-------------3
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Course2------District211--10---------------5----------0-------------0
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Course2--------City2113----6---------------3----------2-------------1
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(I have just given some examle data in tables, to get the idea)
"Groups" Table (This table gives the information of the group)
GROUPID-----NAME-------PARENTID
1---------Universe--------1
2---------country1--------1
3---------state11---------2
4---------District111-----3
5---------City1111--------4
6---------City1112--------4
7---------City1113--------4
8---------country2--------1
9---------state21---------8
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12--------City2112--------10
13--------City2113--------10
"Users" Table (This table provides the user information)
userID----FIRSTNAME---LASTNAME
user1-----------Jim-------Carry
user2-----------Tom-------lee
user3-----------sunny-----boo
user4-----------mary------mall
"User-Group" Tables (This table provides the relation between the groups
and the members)
GROUPID---userID
3-------------user1
3-------------user2
3-------------user4
4-------------user5
5-------------user6
5-------------user7
user_score (This table provides the user scores of different courses)
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user1------course2-----NotStarted
user2------course1-----NotStarted
user2------course2-----complete
user3------course1-----complete
user3------course2-----InProgress
user4------course2-----complete
user4------course1-----NotStarted
I will explain the first four lines of the above result.
Course1---country1--------12---------------6----------4-------------2
Course1-----state11-------12---------------6----------4-------------2
Course1------District111--10---------------5----------3-------------2
Course1--------City1111----0---------------0----------0-------------0
Course1--------City1112----1---------------0----------0-------------1
Course1--------City1113----6---------------3----------2-------------1
# "city1111" group has 0 members
# "city1112" group has 1 member (1 member completed the course1)
# "city1113" group has 6 members(3 members notStarted,2 members
InProgress,1 member completed the course1)
# "District111" is the parent group of above three groups, and has 3
members.(2 members NotStarted,1 member InProgress the course1). But this
group has child groups, so the scores of this group has to rollup the
child groups scores also. Thats why it has 2+3+0+0=6 members Not
Started,1+2+0+0=3 members InProgress,0+0+1+1=2 members completed.
# "state11" group also same as the above group.
I am able to get the group hierarchy by using "Connect By" like follows
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But i want to get the result as i have mentioned in the begining of this discussion.
I am using oracle 8i (oracle8.1.7).
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Srinivas MThis may not be exactly what you want,
but it should be fairly close:
SET LINESIZE 100
SET PAGESIZE 24
COLUMN groupname FORMAT A20
SELECT INITCAP (user_score.course) "course",
groupnames.name "groupname",
COUNT (*) "TotalMembers",
SUM (NVL (DECODE (UPPER (user_score.status), 'NOTSTARTED', 1), 0)) "NotStarted",
SUM (NVL (DECODE (UPPER (user_score.status), 'INPROGRESS', 1), 0)) "InProgress",
SUM (NVL (DECODE (UPPER (user_score.status), 'COMPLETE', 1), 0)) "Completed"
FROM user_score,
user_group,
(SELECT ROWNUM rn,
name,
groupid
FROM (SELECT LPAD (' ', 2 * LEVEL - 2) || name AS name,
groupid
FROM groups
START WITH groupid = 1
CONNECT BY PRIOR groupid = parentid)) groupnames
WHERE user_score.userid = user_group.userid
AND user_group.groupid IN
(SELECT groupid
FROM groups
START WITH groupid = groupnames.groupid
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I entered the minimal test data that you
provided and a bit more and got this result
(It was formatted as you requested,
but I don't know if it will display properly
on this post, or wrap around):
course groupname TotalMembers NotStarted InProgress Completed
Course1 Universe 6 2 0 4
Course1 country1 5 2 0 3
Course1 state11 5 2 0 3
Course1 District111 2 0 0 2
Course1 City1112 1 0 0 1
Course1 City1113 1 0 0 1
Course1 country2 1 0 0 1
Course1 state21 1 0 0 1
Course1 District211 1 0 0 1
Course1 City2113 1 0 0 1
Course2 Universe 5 1 1 3
Course2 country1 4 1 1 2
Course2 state11 4 1 1 2
Course2 District111 1 0 1 0
Course2 City1113 1 0 1 0
Course2 country2 1 0 0 1
Course2 state21 1 0 0 1
Course2 District211 1 0 0 1
Course2 City2113 1 0 0 1
Here is the test data that I used, in case
anyone else wants to play with it:
create table groups
(groupid number,
name varchar2(15),
parentid number)
insert into groups
values (1,'Universe',null)
insert into groups
values (2,'country1',1)
insert into groups
values (3,'state11',2)
insert into groups
values (4,'District111',3)
insert into groups
values (5,'City1111',4)
insert into groups
values (6,'City1112',4)
insert into groups
values (7,'City1113',4)
insert into groups
values (8,'country2',1)
insert into groups
values (9,'state21',8)
insert into groups
values (10,'District211',9)
insert into groups
values (11,'City2111',10)
insert into groups
values (12,'City2112',10)
insert into groups
values (13,'City2113',10)
create table user_group
(groupid number,
userid varchar2(5))
insert into user_group
values (3,'user1')
insert into user_group
values (3,'user2')
insert into user_group
values (3,'user4')
insert into user_group
values (4,'user5')
insert into user_group
values (5,'user6')
insert into user_group
values (5,'user7')
insert into user_group
values (7,'user8')
insert into user_group
values (13,'user9')
insert into user_group
values (11,'use11')
insert into user_group
values (6,'use6')
create table user_score
(userid varchar2(5),
course varchar2(7),
status varchar2(10))
insert into user_score
values ('use6','course1','complete')
insert into user_score
values ('user9','course1','complete')
insert into user_score
values ('user9','course2','complete')
insert into user_score
values ('user8','course1','complete')
insert into user_score
values ('user8','course2','InProgress')
insert into user_score
values ('user1','course1','complete')
insert into user_score
values ('user1','course2','NotStarted')
insert into user_score
values ('user2','course1','NotStarted')
insert into user_score
values ('user2','course2','complete')
insert into user_score
values ('user3','course1','complete')
insert into user_score
values ('user3','course2','InProgress')
insert into user_score
values ('user4','course2','complete')
insert into user_score
values ('user4','course1','NotStarted')
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