Question about static (+multithreading)

Sample program for multithreading:
cvidir\samples\utility\Threading\ThreadSafeVar\IncrementValue.prj
Why all of global variables and functions are static ?
regards
Frog

This is a CVI question and should be posted to the LabWindows/CVI forum instead. Static flags are used to tell the compiler that these global declarations are not used outside this code module (C file). It's good programming practice to declare global variables only used in one module as static.
Best Regards,
Chris Matthews
National Instruments

Similar Messages

Administration Panel Error and a Question about Static IPs

Since there appears to be no other place to report errors within the latest generation of Linksys router firmwares, I thought the forums may be the best place.
If you use remote access to your router's Administration management console, upon saving any changes you are sent to the
"Your settings have been successfully saved." page. Upon clicking cancel it successfully attempts to route to the appropriate hostname but does not consider the port being used; therefore, unless you have your management console hosted on port 80 it does not bring you back to the right place.
This is mostly an annoyance.
My question is I'm wondering if it's possible to assign static IP addresses from the router.
On my older (much older) Linksys routers (before Cisco bought them out) you could easily assign static IPs.
I cannot seem to find a way to do with newer generations. All suggestions recommend assigning static IPs from the
network devices themselves, however that poses problems on modern mobile devices which don't let you do that,
and for laptops that are brought into a lot of different networks it becomes an annoyance to change those settings manually.
I have a EA4500 router.
Solved!
Go to Solution.

You want to assign a specific ip address to your computers/network devices thru the router? You can use the DHCP reservation feature of this router.
"A DHCP Reservation is a permanent IP address assignment. It is a specific IP address within a DHCP scope that is permanently reserved for leased use to a specific DHCP client."
Please check this link:
http://www6.nohold.net/Cisco2/ukp.aspx?vw=1&docid=71dac52653fa4944ae5e4f94ebdf9586_17362.xml&pid=80&...

Question about static properties in implementation (.m) file

I've been using some static properties in my implementation files so they can be accessed by class methods like so for example:
#import etc
static Class foo; // <-- Here is where I've been defining static properties
@implementation Bar
- init {
foo = [Class new]; // initialize property
+ getObject { // now any where else in my code I can use [Foo getObject]
return foo;
- dealloc {
[foo release];
I've been doing this so that in other classes, I can simply go like:
[Foo getObject]
Can someone give me some more details about what's going on here though? It's been working but I'm nervous because I don't know much about it.
ie. What kind of property is it? (nonatomic, retain)? Is this bad practice?
Thanks to anyone who can shed some light on this.

First off, it's not a property. It's a static variable. And the code you have isn't a good idea. Static variables should NOT be set via instance methods.
Think about the following code:
// In some other class
Bar x = [[Bar alloc] init];
Bar y = [[Bar alloc] init];
Think about what just happened. In the 'foo' class you have now created two 'foo' objects and the first one is now leaked.
The proper way to initialize static variables is with the 'initialize' class method. This is only ever called once, the first time the class is referenced.
static Class foo;
@implementation Bar
+ (void)initialize {
foo = [[Bar alloc] init];
- init {
// Do nothing with 'foo'
+ (Bar)getObject {
return foo;
- (void)dealloc {
// Do nothing with 'foo'
The only downside, sort of, is that 'foo' is never dealloc'ed except when the app exits. But this isn't typically a problem.

Question about static ip

Here's the situation:
I live in a house of about 30 tenants. The place uses a cisco WRVS4400N router. It seems that my computer gets assigned a temporary ip automatically and then there will be times when I get "kicked out" and my computer doesn't get connected to the internet. Sometimes for few minutes and sometimes for hours.
No idea what happens there but could be that there are no ips left to assign to my computer and someone else gets the ip address.
Anyway I'm trying to find out if I can configure my computer with a static ip.
The maximum number of dhcp users was changed from 50 to 100 by me. IDK if that means that I can assign a static ip from 1 to 100 but say I pick a number 160 so the ip would be xxx.xxx.x.160.
1. What are the steps I have to undertake to configure my computer on the router page? What info. do I have to modify?
2. After I modify settings on the router page, do I have to change settings on my computer?

Al,
You do not need to change anything in the router. You can simply assign your PC a static IP address. If your DHCP pool is xxx.xxx.x.100-200, use something like xxx.xxx.x.99 on your PC to avoid IP conflict. (assign an address that is not used by the DHCP server) If your router is xxx.xxx.x.1, set that as the Default Gateway and Primary DNS Server on the PC. You can also use 8.8.8.8 as the DNS Server if you wish. The Subnet Mask should be 255.255.255.0
See the following link for excellent instructions about giving a PC a static IP:
http://www.howtogeek.com/howto/19249/how-to-assign-a-static-ip-address-in-xp-vista-or-windows-7/

Question about static method hiding

I undestand that a static method may only be hidden in a subclass not overridden. But, I don't understand why an exception type thrown by the subclass method must be a subtype of the exception type thrown by the superclass method. For example,
public class A {
public static void foo() throws ExceptionA { }
public class B extends A {
public static void foo() throws ExceptionB { }
gives a compile-time error if ExceptionB is not a subclass of ExceptionA. This makes perfect sense in the non-static case but what does it matter here?
Thanks,
Tim

I don't understand your point. In either case, static
or non-static, ExceptionB must be the same or a
subclass of ExceptionA. My question is why this
matters in the static case.I think it's for binary compatibility, that is, so that you can make changes to Java source files and recompile only the changed files. If you originally did not have the static method in class B, and called B.foo() in another class, the A.foo() method would actually be called at run time. If you then change the B class and add a foo() method, it must be compatible so that the other class's method call is still valid.
If you're unfamiliar with the concept of binary compatibility, read the chapter in the Java Language Specification. It's a critical but often overlooked aspect of the Java language.

See this question about static object

1)static A a =new A();
2) A a1=new A();
what is the difference between them?

static A a =new A();
When this line is written in another class say : class b;
a is accessible without the need for declaring an object of b.
i.e., b.a
Not in the other case.
Many factory classes and methods are accessed this way coz, the classes are private and abstract, so u cannot make an object of that class.
For example:
System.out.println() - here println() is a method, out is an object of some class that is declared static in the class System. if it were'nt static, then we had to make an object of the System class and then access the out object,
hope this helps
let me know

Question about static context when using classes

hey there.
i'm pretty new to java an here's my problem:
public class kreise {
     public static void main (String[] args) {
         //creating the circles
         create a = new create(1,4,3);
         create b = new create(7,2,5);
         System.out.println(a);
         System.out.println(b);
         //diameters...unimportant right now
         getDiameter a_ = new getDiameter(a.radius);
         getDiameter b_ = new getDiameter(b.radius);
         System.out.println(a_);
         System.out.println(b_);
         //moving the circles
         double x = 2;
         double y = 9;
         double z = 3;
         a = create.move();
         System.out.println(a);
}creating a circle makes use of the class create which looks like this:
public class create {
    public double k1;
    public double k2;
    public double radius;
    public create(double x,double y,double r) {
        k1 = x;
        k2 = y;
        radius = r;
    public create move() {
        k1 = 1;
        k2 = 1;
        radius = 3;
        return new create (k1,k2,radius);
    public String toString() {
    return "Koordinaten: "+k1+" / "+k2+". Radius: "+radius;
}now that's all totally fine, but when i try to usw create.move to change the circles coordinates the compiler says that the non-static method move() can't be referenced from a static context. so far i've seen that my main() funktion MUST be static. when declaring the doubles k1, k2, and radius in create() static it works, but then of course when having created the second circle it overwrites the first one.
i pretty much have the feeling this is very much a standard beginner problem, but searching for the topic never really brought up my problem exactly. thanks in advance!

You can't access a non-static method from within a static context. So, you have to call move() from outside of the main method. main has to be static because, in short, at least one method has to be static because there haven't been any objects initialized when the program is started. There are more fundamental problems than with just the static context issue.
I'm confused by your code though. You call create.move(), but this would only be possible if move() was static, and from what I see, it's not. Now that's just one part of it. My second issue is that the logic behind the move() method is very messy. You shouldn't return a newly instantiated object, instead it should just change the fields of the current object. Also as a general rule, instance fields should be private; you have them as public, and this would be problematic because anything can access it.
Have you heard of getters and setters? That would be what I recommend.
Now, also, when you are "moving" it, you are basically creating a new circle with completely differently properties; in light of this, I've renamed it change(). Here would be my version of your code:
public class CircleTester {
    public static void main (String[] args)
         //Bad way to do it, but here's one way around it:
         new CircleTester().moveCircle();
    private void moveCircle()     //really a bad method, but for now, it'll do
        Circle a = new Circle(1,4,3);
        Circle b = new Circle(7,2,5);
        System.out.println(a);
        System.out.println(b);
        //diameters. Don't need to have a new getDiameter class
        double a_ = a.getRadius() * 2;     //Instead of doing * 2 each time, you could have a method that just returns the radius * 2
        double b_ = b.getRadius() * 2;
        System.out.println(a_);
        System.out.println(b_);
        //move the circle
        a.change(2,9,3);
        System.out.println(a);
public class Circle {
    private double k1;
    private double k2;
    private double radius;
    public Circle(double x,double y,double r)
        k1 = x;
        k2 = y;
        radius = r;
    public void change(int x, int y, int r)
        k1 = x;
        k2 = y;
        radius = r;
    public String toString()
         return "Koordinaten: "+k1+" / "+k2+". Radius: "+radius;
    public double getRadius()
         return radius;
}On another note, there is already a ellipse class: http://java.sun.com/j2se/1.5.0/docs/api/java/awt/geom/Ellipse2D.html

A basic question about static variables and methods

What would be the effects if I declare lots of static variables and static methods in my class?
Would my program run faster?
Would the class take more memory spaces? (If so, how do I estimate an appropriate number of variabls and methods to be declared static?)
Thank you @_@

when you declare a static var the var isn't created for every instance of the class, it just "live" in the class
when you declare a static method is the same, so if you have:
class MyClass
static int myMethod()
//Method work
you dont need to have a instance of the class to call myMethod, you can do such things like this.
int value = Myclass.myMethod();
if myMethod isn't static you can't do this.. so, if
class MyClass
int myMethod()
//Method work
you CAN'T call
int value = MyClass.myMethod();
instead, you have to write
MyClass m;
m = new MyClass();
value = m.myMethod();

Question about static

A class variable is any field declared with the static modifier; this tells the
compiler that there is exactly one copy of this variable in existence,
regardless of how many times the class has been instantiated.
So I thought , I could have an builtin-counter with this code-snippet
public class SpieleInfo {
    // ....public int creator = 0;
    private static int spielNummer = 0;     // aktuelle Nummer
    public SpieleInfo(int clientId) {
        super();
        spielNummer ++;
    public static int getSpielNummer() {
        return spielNummer;
    }But for each SpielInfo spielInfo = new SpielInfo (anInt ) ;
System.out.println(spielInfo.getSpielNummer() )I always get a zero for output.
I dont see my mistake
TIA
Hanns

public class SpieleInfo {
     //      ....public int creator = 0;
    private static int spielNummer = 0;     // aktuelle Nummer
    public SpieleInfo(int clientId) {
        super();
        spielNummer ++;
    public static int getSpielNummer() {
        return spielNummer;
      * @param args
     public static void main(String[] args) {
          // TODO Auto-generated method stub
          SpieleInfo spielInfo = new SpieleInfo (4 ) ;
          SpieleInfo spielInfo2 = new SpieleInfo (4 ) ;
            System.out.println(spielInfo.getSpielNummer() );
}Tried your code it works for me sorry, the only change i had to make was to add the e into SpieleInfo variable declaration you dont have another class called SpielInfo do you?
Message was edited by:
mmi1

Questions about Static Initialiser Syntax

Here is a simple script:
public class Radio
private int station;
public Radio(int x)
System.out.println("Constructing a Radio");
station = x;
static {
System.out.println("Inside static initialiser");
I was wondering how when you instantiate a radio object the Static initialiser method runs first before creating the radio. It is clear that it comes after Radio() in the script so how does the JVM know to jump to static and then back to Radio()?
thanks
Richard.

A compiled java class contains two hidden methods, one called "<clinit>" which does the static intialisation and one called "<init>" which does the instance initialization. All the static initialisation which means any explicitly initialized static fields and static blocks are gatherered into the <clinit> method, in the order they are encountered. All the instance field initialisation (and any instance initializer blocks) are gathered into the <init> method (you'll sometimes see these names on stack traces).
The first time you "actively use" a class <clinit> will be called first. When you instanciate a class the <init> method is called prior to any constructor code.

A question about non-static inner class...

hello everybody. i have a question about the non-static inner class. following is a block of codes:
i can declare and have a handle of a non-static inner class, like this : Inner0.HaveValue hv = inn.getHandle( 100 );
but why cannot i create an object of that non-static inner class by calling its constructor? like this : Inner0.HaveValue hv = Inner0.HaveValue( 100 );
is it true that "you can never CREATE an object of a non-static inner class( an object of Inner0.HaveValue ) without an object of the outer class( an object of Inner0 )"??
does the object "hv" in this program belong to the object of its outer class( that is : "inn" )? if "inn" is destroyed by the gc, can "hv" continue to exist?
thanks a lot. I am a foreigner and my english is not very pure. I hope that i have expressed my idea clearly.
// -------------- the codes -------------------
import java.util.*;
public class Inner0 {
// definition of an inner class HaveValue...
private class HaveValue {
private int itsVal;
public int getValue() {
return itsVal;
public HaveValue( int i ) {
itsVal = i;
// create an object of the inner class by calling this function ...
public HaveValue getHandle( int i ) {
return new HaveValue( i );
public static void main( String[] args ) {
Inner0 inn = new Inner0();
Inner0.HaveValue hv = inn.getHandle( 100 );
System.out.println( "i can create an inner class object." );
System.out.println( "i can also get its value : " + hv.getValue() );
return;
// -------------- end of the codes --------------

when you want to create an object of a non-static inner class, you have to have a reference of the enclosing class.
You can create an instance of the inner class as:
outer.inner oi = new outer().new inner();

Two questions about SG300 DHCP server

Hi,
I have two questions about the DHCP server on the SG300:
On the Address Binding page, what does the "Declined" state mean? I have a NAS device that won't pull an address, and I think that the entry with a state of "Declined" corresponds to this device. It was previously pulling an address from a RV180, so the only difference is that it is now connected to the SG300. I worked around this by manually setting the address on the NAS device, but this won't scale if I run into a lot of other devices that can't pull an address.
I configured a static address binding for a WAP321 and found that instead of pulling the configured address that it pulled a dynamic address. I checked the Address Binding page and see that the dynamic entry that corresponds with the WAP321 has a Client Identifier rather than a MAC address. I changed the static entry for the WAP321 to use the client identifier displayed in the dynamic entry, and now the WAP321 pulls the configured static address. Is this expected behavior?
Thanks,
Bob

With the SX300/500 it is required the client identifier, it doesn't automatically insert it. If static DHCP is made on the switch and you didn't need client identifier, that is more or less fortunate behavior for you
So to answer this question, the expected behavior is to configure client identifier for static DHCP entry.
-Tom
Please mark answered for helpful posts
http://blogs.cisco.com/smallbusiness/

Question about VPN on RV082

Question about VPN on RV082
i connect like diagram
when i use shrewsoft for vpn ipsec i can not connect across rv082 to next hop on wan 1
but when i use PPTP on windows 7 for vpn PPTP i can connect across rv082 but high latency on this connection
please advice me for this issue
many thank i hope someone help me on this

ChicagoGuy72 wrote:
Hello,
I am working with vpn setups for the first time, so I have some questions I would really appriciate some help with. I would like to be able to connect to a computer on a home network through a linksys E2500 router. I have found alot of documentation on connecting to an external vpn from a computer on the lan side of the router, but nothing on connecting from the outside in. The router does have a static ip address with my internet provider, so I can contact the router from the outside. But makeing the connection to the computer on the other side of the router is where I am missing something or I dont realize that it is not possible. On the lan side I am using DHCP to assign the address to the computer I want to connect to. Perhaps I need to make it have a static address also? I realize that when I configure the connection from the outside that I need to direct the connection to the remote computer in some way, unless vpn connections are fully passed through the router and the connection issue I am haveing is with the "inside" computer.
Other info:
I am using windows 7 for the vpn access
Thank you in advance for your help.
Kindly check these links:
http://www.cisco.com/en/US/tech/tk827/tk369/technologies_configuration_example09186a00801e51e2.shtml
http://www.cisco.com/en/US/products/sw/secursw/ps2086/products_configuration_example09186a008009436a...

Basic questions about programing for J9 VM

I need to create a java application to run on a Pocket PC 2003 OS and I'm limited to using IBM's Websphere J9 Virtual Machine. I'm new to using java in this capacity and therefore have lots of questions which I'm guessing are pretty basic. Despite my best efforts, I've found very little to help me online. Below are a couple questions I have that I'm hoping someone can help me with. Even better, if you know of any resources that could help me with these and other questions, I'd love to have them. Thanks in advance.
1. I'm using standard AWT for the GUI but I'm having problems getting frames, dialogs, etc., to come up in anything less then full screen. setSize() and resize() have no effect, even if I extend the frame and override the setMinimumSize, setPreferredSize, setMaximumSize methods. What do I need to do to get a child window to appear in something less than full screen?
2. I'd like to be able to add menu's to the buttom toolbar (with the keyboard) but have no idea how I would add something to it. Can someone point me in the right direction?
3. When my application gets an iconified event I go ahead and call a System.exit() to exit the application. This doesn't kill the java VM though, which continues to run in the background (taking up plenty of memory). If I run my application using the J9w.exe so that it runs without the console, then not only does the VM continue to run, but I have no way to stop it (the running program list can't see it). Since each time I run my application it starts a new VM, it only takes a couple of times before I'm out of memory and have to do a soft reset of the PDA to make things right. Can I kill the VM when I kill my application?
4. I learn best by looking at example code, but have been unable to find any code people are running on J9. I have the GolfScoreTracker installed and running on my PDA, but the jar file contains only the classes. Since it's supposed to be a demo, I had hoped that the source code would be included, is that hoping too much or is the source code available somewhere? In addition, if you know of any applications out there with available source code that are known to run well on a PocketPC J9 environment I'd appreciate the link.

Hi there, I saw your questions, im currently developing a java pocket pc application as well and here's what i go so far:
AWT seem to be hard to use on pocket pc, instead i recommend that you use SWT, which is a technology developed by eclipse. It's already installed on the eclipse plugins, you just need to download the jar and dll files for the pocket pc. They are available at: http://www.eclipse.org/downloads/index.php
I assume that you already have the J9 working on your device. So you only need to copy the SWT.jar file and the swt-win32-3064.dll to the folder containing the .class files on your device.
Now, on your java IDE(im using eclipse) Add the SWT.jar library to your project which should be on C:/eclipse/plugins/org.eclipse.swt.win32_3.0.2/ws/win32/swt.jar or something like taht depending on your eclipse root.
Now you are ready to code some SWT, here is a sample program from Carolyn MacLeod, i modified a few things so it could run on the pocket pc but it's almost the same. Once you coded in eclipse run it, then copy the class file from your desktop to your device(There should be like 4 or 5 classes like sample.class, sample$1.class etc. copy all of them) where you put the jar and dll files(If program does not run you may try to rename the dll file for swt-win32-3050.dll instead of 3064.dll). Now after you have everything set up you need to create the lnk file in order to run the program. On your desktop create a new textfile and write the following on it:
255#"\Archivos de Programa\J9\PPRO10\bin\j9w.exe" "-jcl:PPRO10" "-cp" "\My
Documents\Java\swt.jar" ;\My Documents\Java" sample
Paths depend on your install, and the place where you put your classes and jar file. path for j9w is usually "\Program Files\J9\PPRO10\bin\j9w.exe", and the last word should be the classname.
Currently this form only displays an image on a canvas, click on the browse button and choose a pic and it will display on the canvas. Im trying to connect the form to an oracle database but no success yet on the device.
Hope it helps, if you have any questions about the code or something, and I know the answer, please feel free to ask.
See ya
import org.eclipse.swt.*;
import org.eclipse.swt.widgets.*;
import org.eclipse.swt.layout.*;
import org.eclipse.swt.events.*;
import org.eclipse.swt.graphics.*;
public class sample {
static Shell shell;
static Display display;
static Text dogName;
static Text textdb;
static Combo dogBreed;
static Canvas dogPhoto;
static Image dogImage;
static List categories;
static Text ownerName;
static Text ownerPhone;
static String[] FILTER_EXTS = {"*.jpg"};
public static void main(String[] args) {
display = new Display();
shell = new Shell(display, SWT.RESIZE | SWT.CLOSE);
Menu menu = new Menu(shell, SWT.BAR);
shell.setText("Dog ShowS Entry");
shell.setMenuBar(menu);
GridLayout gridLayout = new GridLayout();
gridLayout.numColumns = 3;
shell.setLayout(gridLayout);
new Label(shell, SWT.NONE).setText("Dog's NameS:");
dogName = new Text(shell, SWT.SINGLE | SWT.BORDER);
GridData gridData = new GridData(GridData.HORIZONTAL_ALIGN_FILL);
gridData.horizontalSpan = 2;
gridData.widthHint = 60;
dogName.setLayoutData(gridData);
new Label(shell, SWT.NONE).setText("Breed:");
dogBreed = new Combo(shell, SWT.NONE);
dogBreed.setItems(new String [] {"Collie", "Pitbull", "Poodle", "Scottie"});
dogBreed.setLayoutData(new GridData(GridData.HORIZONTAL_ALIGN_FILL));
Label label = new Label(shell, SWT.NONE);
label.setText("Categories");
label.setLayoutData(new GridData(GridData.HORIZONTAL_ALIGN_FILL));
new Label(shell, SWT.NONE).setText("Photo:");
dogPhoto = new Canvas(shell, SWT.BORDER);
gridData = new GridData(GridData.FILL_BOTH);
gridData.widthHint = 60;
gridData.verticalSpan = 3;
dogPhoto.setLayoutData(gridData);
dogPhoto.addPaintListener(new PaintListener() {
public void paintControl(final PaintEvent event) {
if (dogImage != null) {
event.gc.drawImage(dogImage, 0, 0);
categories = new List(shell, SWT.MULTI | SWT.BORDER | SWT.V_SCROLL);
categories.setItems(new String [] {
"Best of Breed", "Prettiest Female", "Handsomest Male",
"Best Dressed", "Fluffiest Ears", "Most Colors",
"Best Performer", "Loudest Bark", "Best Behaved",
"Prettiest Eyes", "Most Hair", "Longest Tail",
"Cutest Trick"});
gridData = new GridData(GridData.HORIZONTAL_ALIGN_FILL | GridData.VERTICAL_ALIGN_FILL);
gridData.widthHint = 60;
gridData.verticalSpan = 4;
int listHeight = categories.getItemHeight() * 12;
Rectangle trim = categories.computeTrim(0, 0, 0, listHeight);
gridData.heightHint = trim.height;
categories.setLayoutData(gridData);
Button browse = new Button(shell, SWT.PUSH);
browse.setText("BrowsePic");
gridData = new GridData(GridData.HORIZONTAL_ALIGN_FILL);
gridData.widthHint = 60;
browse.setLayoutData(gridData);
browse.addSelectionListener(new SelectionAdapter() {
     public void widgetSelected(SelectionEvent event) {
          FileDialog dialog = new FileDialog(shell, SWT.OPEN);
          dialog.setFilterExtensions(new String[] {"*.*"});
          String fileName = dialog.open();
if (fileName != null) {
dogImage = new Image(display, fileName);
shell.redraw();
Button delete = new Button(shell, SWT.PUSH);
delete.setText("No action");
gridData = new GridData(GridData.HORIZONTAL_ALIGN_FILL | GridData.VERTICAL_ALIGN_BEGINNING);
gridData.widthHint = 60;
delete.setLayoutData(gridData);
delete.addSelectionListener(new SelectionAdapter() {
public void widgetSelected(SelectionEvent event) {
Button enter = new Button(shell, SWT.PUSH);
enter.setText("No action");
gridData = new GridData(GridData.HORIZONTAL_ALIGN_END);
gridData.horizontalSpan = 3;
enter.setLayoutData(gridData);
enter.addSelectionListener(new SelectionAdapter() {
public void widgetSelected(SelectionEvent event) {
     shell.open();
     while (!shell.isDisposed()) {
          if (!display.readAndDispatch())
               display.sleep();
     display.dispose();
if (dogImage != null) {
dogImage.dispose();
}

Basic questions about CISCO IOS

Hi everybody, Jack here,
I have some basic questions about the Cisco IOS, could someone help me addressing some of them please? Any feedback would be greatly appreciated.
Basically, I have two IP addresses assigned by our Cable ISP. From what I understood you can configure a Cisco router for multiple IP addresses using the IOS, thereby allowing someone like myself to take advantage of having multiple IP addresses. This may seem unnecessary to some, but I've always wanted to put the 2nd IP address to use, since after all, I've been paying for it.
I was just wondering if someone could confirm that what I'm hoping to accomplish is indeed within the capability of the Cisco IOS (i.e. Fully utilize my 2 IP addresses). As well, if someone could kindly suggest a decent CISCO router for online gaming home use that would be super awesome!
Thank you all so much for reading through the wall of text:)
Jack

Jack
Certainly using multiple IP addresses is in the capability of Cisco IOS routers. How they can be used depends on the relationship of the IP addresses. I am assuming that we are talking about IP addresses assigned for the user to use and that the IP address for the ISP connection is not one of these that we are talking about.
If both of the IP addresses that you have been assigned are within the same subnet then you would assign one of the addresses to the router interface to establish IP communication between the router and the ISP and to enable Internet connectivity for the devices inside your network that will use the router as their gateway to the Internet. The other address that is assigned can be used for address translation and in particular for static address translation which would make one of your devices inside to be reachable for connections initiated from the Internet (if that is something that you might want to do).
If the addresses that are assigned to you are in different subnets then you could assign one address to the outside router interface and assign the other address to the router inside interface. Or you could use the second address for address translation.
I do not have much expertise with online gaming, but I would think that either the Cisco 881 router or the 890 router might be appropriate for you. If 100 Mb connection is sufficient then probably the 881 would be the one to look at. If you need Gig connection then look at the 890.
HTH
Rick

Question about static (+multithreading)

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