Rank function in Answers

Hi,
I have to produce a bar-chart with Number of Projects(Y axis), Project Phase(X axis). For example, x axis should have labels like Phase-1, Phase-2 etc., and in each phase teh number of projects should be the bar. The catch is , the number of projects should be counted only in the phase where the "Recorded_date" is max.
In the data base, I can use something similar to this
select * from (
SELECT project_id, phase_id, recorded_date,
ROW_NUMBER() OVER (PARTITION BY project_id ORDER BY recorded_date desc) as rnk
from MAIN.project_detail) a
where rnk=1;
How to implement this? Please let me know if there is an alternate way. I do not want to make changes to the RPD, if I can accomplish this in Answers.
Thank you for your time and help.

So in your case,
select * from (
SELECT project_id, phase_id, recorded_date,
ROW_NUMBER() OVER (PARTITION BY project_id ORDER BY recorded_date desc) as rnk
from MAIN.project_detail) a
where rnk=1;
would be implemented by the statement 'ROW_NUMBER() OVER (PARTITION BY project_id ORDER BY recorded_date desc) as rnk'
getting transformed to,
rank(recorded_date by project_id)
in the column function(fx).

Similar Messages

Error using Rank function in Answers

Hi All,
Am trying to generate a report in Answers which lists Top Accounts with Revenue.
I Ranked the Revenue field and it is returning me correct values. ( Rank(account.revenue) )
But, when I try to filter on this field and restrict the rows which shows only top 10 Accounts, it is returning the following error:
State: HY000. Code: 10058. [NQODBC] [SQL_STATE: HY000] [nQSError: 10058] A general error has occurred. [nQSError: 17001] Oracle Error code: 1792, message: ORA-01792: maximum number of columns in a table or view is 1000 at OCI call OCIStmtExecute. [nQSError: 17010] SQL statement preparation failed. (HY000)
Can any one help me on this.
Thanks in Advance,
Imtiaz.

Hi Joe,
This is the Physical query generated when I use Rank function and the report is fine.
select distinct D1.c1 as c1,
D1.c2 as c2,
D1.c3 as c3,
D1.c4 as c4,
D1.c5 as c5,
D1.c6 as c6,
D1.c7 as c7,
D1.c8 as c8,
D1.c9 as c9,
D1.c10 as c10,
D1.c11 as c11,
D1.c12 as c12,
D1.c13 as c13,
D1.c14 as c14,
D1.c15 as c15
from
(select D1.c1 as c1,
D1.c2 as c2,
D1.c3 as c3,
D1.c4 as c4,
D1.c5 as c5,
D1.c6 as c6,
D1.c7 as c7,
D1.c8 as c8,
D1.c9 as c9,
D1.c10 as c10,
D1.c11 as c11,
D1.c12 as c12,
D1.c13 as c13,
D1.c14 as c14,
D1.c15 as c15
from
(select Case when D1.c1 is not null then Rank() OVER ( ORDER BY D1.c1 DESC NULLS LAST ) end as c1,
D1.c2 as c2,
D1.c3 as c3,
D1.c1 as c4,
D1.c4 as c5,
D1.c5 as c6,
D1.c6 as c7,
D1.c7 as c8,
D1.c8 as c9,
D1.c9 as c10,
D1.c10 as c11,
D1.c11 as c12,
D1.c12 as c13,
D1.c13 as c14,
D1.c14 as c15,
ROW_NUMBER() OVER (PARTITION BY D1.c1, D1.c2, D1.c3, D1.c4, D1.c5, D1.c6, D1.c7, D1.c8, D1.c9, D1.c10, D1.c11, D1.c12, D1.c13, D1.c14 ORDER BY D1.c1 ASC, D1.c2 ASC, D1.c3 ASC, D1.c4 ASC, D1.c5 ASC, D1.c6 ASC, D1.c7 ASC, D1.c8 ASC, D1.c9 ASC, D1.c10 ASC, D1.c11 ASC, D1.c12 ASC, D1.c13 ASC, D1.c14 ASC) as c16
from
(select distinct T690.SUM_REVN_AMT as c1,
T690.NAME as c2,
T2216.NAME as c3,
T690.X_PETROFAC_REVN as c4,
T690.SUM_WIN_PROB as c5,
T690.X_PERCENT_GET as c6,
T690.SUM_WIN_PROB * T690.X_PERCENT_GET / nullif( 100, 0) as c7,
T690.X_EC_PRIORITY as c8,
T19028.LOGIN as c9,
T690.X_COUNTRY as c10,
T690.X_REGION as c11,
T18311.NAME as c12,
T18641.NAME as c13,
T18238.NAME as c14
from
SIEBEL.S_BU T18238 left outer join (
SIEBEL.S_USER T19028 left outer join (
SIEBEL.S_OPTY T690 left outer join SIEBEL.S_STG T2216 On T690.CURR_STG_ID = T2216.ROW_ID) left outer join SIEBEL.S_ORG_EXT T1189 On T690.PR_DEPT_OU_ID = T1189.ROW_ID) left outer join SIEBEL.S_ORG_EXT T18311 /* Competitor */ On T690.PR_CMPT_OU_ID = T18311.ROW_ID) left outer join SIEBEL.S_ORG_EXT T18641 /* Partner */ On T690.PR_PRTNR_ID = T18641.ROW_ID) left outer join SIEBEL.S_POSTN T19114 On T690.PR_POSTN_ID = T19114.PAR_ROW_ID) left outer join SIEBEL.S_OPTY_BU T18280 On T690.ROW_ID = T18280.OPTY_ID) left outer join SIEBEL.S_OPTY_X T19415 On T690.ROW_ID = T19415.PAR_ROW_ID) On T19028.PAR_ROW_ID = T19114.PR_EMP_ID) On T18238.ROW_ID = T18280.BU_ID
) D1
) D1
where ( D1.c16 = 1 )
) D1
order by c1 desc
But When I apply Filter on this Rank column then it gives me the error. THis is the Physical query for that
select distinct Case when D1.c1 is not null then Rank() OVER ( ORDER BY D1.c1 DESC NULLS LAST ) end as c1,
D1.c2 as c2,
D1.c3 as c3,
D1.c1 as c4,
D1.c4 as c5,
D1.c5 as c6,
D1.c6 as c7,
D1.c7 as c8,
D1.c8 as c9,
D1.c9 as c10,
D1.c10 as c11,
D1.c11 as c12,
D1.c12 as c13,
D1.c13 as c14,
D1.c14 as c15
from
(select D1.c1 as c1,
D1.c2 as c2,
D1.c3 as c3,
D1.c4 as c4,
D1.c5 as c5,
D1.c6 as c6,
D1.c7 as c7,
D1.c8 as c8,
D1.c9 as c9,
D1.c10 as c10,
D1.c11 as c11,
D1.c12 as c12,
D1.c13 as c13,
D1.c14 as c14
from
(select T690.SUM_REVN_AMT as c1,
T690.NAME as c2,
T2216.NAME as c3,
T690.X_PETROFAC_REVN as c4,
T690.SUM_WIN_PROB as c5,
T690.X_PERCENT_GET as c6,
T690.SUM_WIN_PROB * T690.X_PERCENT_GET / nullif( 100, 0) as c7,
T690.X_EC_PRIORITY as c8,
T19028.LOGIN as c9,
T690.X_COUNTRY as c10,
T690.X_REGION as c11,
T18311.NAME as c12,
T18641.NAME as c13,
T18238.NAME as c14,
Case when T690.SUM_REVN_AMT is not null then Rank() OVER ( ORDER BY T690.SUM_REVN_AMT DESC NULLS LAST ) end as c15
from
SIEBEL.S_BU T18238 left outer join (
SIEBEL.S_USER T19028 left outer join (
SIEBEL.S_OPTY T690 left outer join SIEBEL.S_STG T2216 On T690.CURR_STG_ID = T2216.ROW_ID) left outer join SIEBEL.S_ORG_EXT T1189 On T690.PR_DEPT_OU_ID = T1189.ROW_ID) left outer join SIEBEL.S_ORG_EXT T18311 /* Competitor */ On T690.PR_CMPT_OU_ID = T18311.ROW_ID) left outer join SIEBEL.S_ORG_EXT T18641 /* Partner */ On T690.PR_PRTNR_ID = T18641.ROW_ID) left outer join SIEBEL.S_POSTN T19114 On T690.PR_POSTN_ID = T19114.PAR_ROW_ID) left outer join SIEBEL.S_OPTY_BU T18280 On T690.ROW_ID = T18280.OPTY_ID) left outer join SIEBEL.S_OPTY_X T19415 On T690.ROW_ID = T19415.PAR_ROW_ID) On T19028.PAR_ROW_ID = T19114.PR_EMP_ID) On T18238.ROW_ID = T18280.BU_ID
) D1
where ( D1.c15 <= 10 )
) D1
order by c2, c3, c4, c5, c6, c7, c8, c9, c10, c11, c12, c13, c14, c15
Thanks,
Imtiaz

RANK Function in AIX vs Windows

I am facing an issue where when I run my report using my windows machine I am able to get the right results with the RANK function. However, when I ran the same report in my AIX machine, I got the following error:
Odbc driver returned an error (SQLExecDirectW).
Error Details
Error Codes: OPR4ONWY:U9IM8TAC:OI2DL65P
State: HY000. Code: 378077472. [NQODBC] [SQL_STATE: HY000] [nQSError: 10058] A general error has occurred. [nQSError: 46008] Internal error: File server/Query/Optimizer/ServiceInterfaceMgr/Src/SQOIGeneratorBuiltIn.cpp, line 3403. (HY000)
If anyone has run into this, please let me know.
Thanks.

One point to make is the Rank function works if you create 1 column with the RANK function in Answers(i.e. Rank(Fact.Sales) ). The issue comes up when you try to create a BIN column to bucket the RANKs in a seperate column.
Here's the SQL:
SELECT Location.Location saw_0, case WHEN RANK(Metrics.Sales) BETWEEN 1 AND 5 then '1-5' WHEN RANK(Metrics.Sales) BETWEEN 5 AND 10 then '5-10' else 'other' end saw_1, Metrics.Sales saw_2, RANK(Metrics.Sales) saw_3 FROM "Rank Prototype" ORDER BY saw_0
So Basically, the issue is when you have a Bucketed Rank Sales Column and a simple Rank Column in the same request. (In AIX the issue exists, in Windows there is no issue.)

How to use "Rank" function in Oracle?

I need to display Top 15 records by using rank function.
Here is my query...I need to pull top 15 FAQ's using the below query.. How can I use RANK function to display the Top 15 FAQ"s in the list.
Select distinct SUb1.FAQ,Sub1.FAQ_Hits,GU.display_Name_FMLS as displayname,ev.ParentLinkrecordid,ev.userid from User GU
Join Event ev
ON LOWER (ev.userid) IN (LOWER (GU.lanid), LOWER (Gu.racfid))
Join (Select distinct sm.stem as FAQ,Sum(ev.Eventresults) as FAQ_Hits,ev.ParentLinkrecordid as Topic_ID from Event ev
Join SubjectMatter sm
ON (TO_CHAR (sm.smrecordid) = ev.eventdetail1) AND ev.eventdetail1 IS NOT NULL AND sm.smtype = 1
Where (Upper(ev.eventsubtype) in (Upper('FAQ'),Upper('OPENFAQ')))
AND TO_DATE (eventdatetime, 'yyyy-mm-dd hh24:mi:ss') >= TO_DATE ('20100601', 'yyyymmdd')
and TO_DATE (eventdatetime, 'yyyy-mm-dd hh24:mi:ss') <= TO_DATE ('20100831', 'yyyymmdd')
Group by sm.stem,ev.Parentlinkrecordid
order by FAQ )sub1
ON Sub1.Topic_ID = ev.ParentLinkrecordid)

A few bits that I noticed in the query ...
in (Upper('FAQ'),Upper('OPENFAQ'))1) Do you really a upper for a string which is already in upper case.
Select distinct sm.stem as FAQ,Sum(ev.Eventresults) as FAQ_Hits,ev.ParentLinkrecordid as Topic_ID2) Do you need a distinct when you are using a GROUP function viz. SUM ?
You rank query is as follows, I am not very good at the ANSI style JOIN so changed it slightly ... :-)
Also notice the usage rank function in the "sub1" query.
select distinct sub1.faq,
 sub1.faq_hits,
 gu.display_name_fmls as displayname,
 ev.parentlinkrecordid,
 ev.userid
from user gu, event ev,
(select rank() over (order by sum(ev.eventresults) desc) rnk,
 sum(ev.eventresults) as faq_hits,
 sm.stem as faq,
 ev.parentlinkrecordid as topic_id
 from event ev, subjectmatter sm
 where (to_char(sm.smrecordid) = ev.eventdetail1)
 and ev.eventdetail1 is not null
 and sm.smtype = 1
 AND upper(ev.eventsubtype) in ('FAQ', 'OPENFAQ')
 and to_date(eventdatetime, 'yyyy-mm-dd hh24:mi:ss') >= to_date('20100601', 'yyyymmdd')
 and to_date(eventdatetime, 'yyyy-mm-dd hh24:mi:ss') <= to_date('20100831', 'yyyymmdd')
 group by sm.stem, ev.parentlinkrecordid
 order by faq) sub1
where lower(ev.userid) in (lower(gu.lanid), lower(gu.racfid))
and sub1.topic_id = ev.parentlinkrecordid)
and sub1.rnk <= 15;Like mentioned above, some sample data would have helped.

RANK FUNCTION IN ORACLE 8I

제품 : PL/SQL
작성날짜 : 2001-09-11
RANK FUNCTION IN ORACLE 8I
==========================
EXPLANATION
oracle 8i(8.1.6) 부터 가능한 rank function 입니다.
8.1.5 에서는 ora-923 error 가 납니다.
plsql 내에서는 oracle 9i 부터 가능합니다.
8.1.6에서는 ora-900 error가 납니다.
EXAMPLE
<RANK() OVER ( query_partition_clause ORDER_BY clause) >
- 중복 rank 값만큼 다음 순위는 생략
SQL>SELECT deptno, ename, sal, comm,
RANK() OVER (PARTITION BY deptno ORDER BY sal DESC, comm) as rk
FROM emp;
DEPTNO ENAME SAL RK
10 KING 5000 1
10 CLARK 2450 2
10 MILLER 1300 3
20 3500 1
20 SCOTT 3000 2
20 FORD 3000 2
20 JONES 2975 4
20 ADAMS 1100 5
20 SMITH 800 6
30 BLAKE 2850 1
30 ALLEN 1600 2
30 TURNER 1500 3
30 WARD 1250 4
30 MARTIN 1250 5
40 JAMES 777 1
9 1
<DENSE_RANK( ) OVER ( query_partition_clause ORDER_BY clause ) >
- 중복 rank 의 수와 무관하게 numbering
SQL>SELECT dname, ename, sal, DENSE_RANK()
OVER (PARTITION BY dname ORDER BY sal) as drank
FROM emp, dept
WHERE emp.deptno = dept.deptno
AND dname IN ('SALES', 'RESEARCH');
DNAME ENAME SAL DRANK
RESEARCH SMITH 800 1
RESEARCH ADAMS 1100 2
RESEARCH JONES 2975 3
RESEARCH SCOTT 3000 4
RESEARCH FORD 3000 4
RESEARCH 3500 5
SALES WARD 1250 1
SALES MARTIN 1250 1
SALES TURNER 1500 2
SALES ALLEN 1600 3
SALES BLAKE 2850 4
plsql 내에서 사용 가능 :oracle 9i 부터
SQL> create table
rank_emp(deptno number(2), ename varchar2(20), sal number(5), rk number(2));
테이블이 생성되었습니다.
SQL> create or replace procedure window_plsql AS
query_str VArchar2(1000);
begin
query_str := 'insert into rank_emp
SELECT deptno, ename, sal,
RANK() OVER (PARTITION BY deptno ORDER BY sal DESC, comm) as rk
FROM emp' ;
Execute Immediate query_str;
end;
2 /
프로시저가 생성되었습니다.
SQL> exec window_plsql
PL/SQL 처리가 정상적으로 완료되었습니다.
SQL> select * from rank_emp;
DEPTNO ENAME SAL RK
10 KING 5000 1
10 CLARK 2450 2
10 MILLER 1300 3
20 SCOTT 3000 1
20 FORD 3000 1
20 JONES 2975 3
20 ADAMS 1100 4
20 SMITH 800 5
30 BLAKE 2850 1
30 ALLEN 1600 2
30 TURNER 1500 3
DEPTNO ENAME SAL RK
30 WARD 1250 4
30 MARTIN 1250 5
30 JAMES 950 6
14 개의 행이 선택되었습니다.

That's correct
The differences between Standard and Enterprise Edition are listed here:
http://www.oracle.com/technology/products/oracle8i/pdf/8i_fam.pdf

Prob in using rank in pl/sql ,need logic same of rank function in any way

I have a query as of the following 
 
SELECT sr_no,cod_acct_no,dat_arrears_due,amt_arrear_due 
FROM ( select cod_acct_no,dat_arrears_due,sum(amt_arrears_due) amt_arrear_due,rank() over (partition by cod_acct_no order by dat_arrears_due asc) sr_no 
 from arrears_table 
 where amt_arrears_due > 0 
and dat_arrears_due <= to_date('31/10/2006','dd/mm/yyyy') 
and COD_ARREAR_TYPE = 'C' 
 group by cod_acct_no,dat_arrears_due 
 ) Z 
WHERE z.sr_no <=5 
 
I have to use this in a cursor in pl/sql but because i have rank analytic function 
I am facing a compilation error ORA-06550: error 
 
Can you give me a logic which gives same output as of above 
 
Regards 
vamsi krishna 
 
 

[1]: (Error): ORA-06550: line 5, column 28: PLS-00103: Encountered the symbol "(" when expecting one of the following: , from 
 
My oracle version is 
Oracle8i Enterprise Edition Release 8.1.6.0.0 - Production 
PL/SQL Release 8.1.6.0.0 - Production 
CORE 8.1.6.0.0 Production 
TNS for 32-bit Windows: Version 8.1.6.0.0 - Production 
NLSRTL Version 3.4.1.0.0 - Production 
 I think it is comming for rank function it self 
 will this version support analytic (rank) function's in pl/sql cursors 
Regards 
vamsi krishna

Rank function without filter in the report

Hi,
I have a problem with Rank() function. The problem is the next one.
I have a table with this rows:
User | DATE | Cost
user1 | 12/02/2011 | 10,4
user1 | 13/02/2011 | 11,1
user1 | 13/02/2011 | 10,1
user1 | 13/02/2011 | 8,1
user2 | 12/02/2011 | 1,4
user2 | 13/02/2011 | 12,1
user2 | 13/02/2011 | 22,1
user2 | 13/02/2011 | 8,1
In the rpd I have a agregate row as SUM(COST), and I need extract te ranking of this SUM(COST) per user, The sum of user1 is 39,7 and the sum of the user 2 is 43,7. If I show in the report all users, the ranking is correct Rank=1 per user2 and Rank=2 per user1, but the problem is that I only want show the user1, when I add a filter to the report user='user1' the ranking value changes from 2 to 1. I need that the ranking value doesn´t change when I introduce a filter.
Any idea about how to solve this problem?
Thanks

Hi Antonio,
On the Rank column in the answers edit the formula as given below.
Case when username = 'user2' then Rank(sum(cost)) else 0 end
Then apply a filter on the Rank column as Rank > 0.
I hope this one helps you.
Regards
AP

How to use RANK function ?

Hello everyone,
here is the query I run in sql developer using RANKFunction.
SELECT Empno, Ename, Job, Mgr, Hiredate, Sal
FROM
(SELECT Empno, Ename, Job, Mgr, Hiredate, Sal,
*RANK*() OVER
(ORDER BY SAL Desc NULLS LAST) AS Emp_Rank
FROM Emp
ORDER BY SAL Desc NULLS LAST)
WHERE Emp_Rank < 6;How I can use this query in my report in obiee or is there any replacement of RANK() function in obiee so that I can use that to get my same above result.
Thanks

Kuldip wrote:
Thanks, you are absolutely correct. However, By doing this I am getting my output as whic I was not expecting.
Students Marks Rank
student1 95 1
student2 95 1
student3 93 3
student4 93 3
student5 91 5
The output should be as instead
Students Marks Rank
student1 95 1
student2 95 1
student3 93 2
student4 93 2
student5 91 3
Can It be done like this ?
Thanks.
Edited by: Kuldip on Mar 15, 2012 11:51 PMHi Boss,
I think you copied the above scenario from this site..
http://oracle-bi.siebelunleashed.com/articles/rank-and-dense-rank-functionsobiee/
Then why asking how to do this? Are you testing us? Doesn't that site say how to achieve this?

Rank function

how to use the RANK function in oracle data integrator??

Hi,
a little google could help you..
https://forums.oracle.com/thread/2158588
Let us know

Rank Function taking a long time to execute in SAP HANA

Hi All,
I have a couple of reports with rank function which is timing out/ or taking a really long time to execute, Is there any way to get the result in less time when rank functions are involved?
the following is a sample of how the Query looks,
SQL 1:
select      a.column1,
                b.column1,
                rank () over(partition by a.column1 order by sum(b.column2) asc)
from         "_SYS_BIC"."Analyticview1"         b
                join          "Table1"            a
                  on          (a.column2 = b.column3)
group by a.column1,
b.column1;
SQL 2:
select    a.column1,
                b.column1,
                rank () over( order by min(b.column1) asc) WJXBFS1
from         "_SYS_BIC"."Analytic view2"         b
                cross join                "Table 2"               a
where      (a.column2 like '%a%'
and b.column1 between 100 and 200)
group by a.column1,
                b.column1
when I visualize the execution plan,the rank function is the one taking up a longer time frame. so I executed the same SQL without the rank() or partition or order by(only with Sum() in SQL1 and Min() in SQL 2) even that took a around an hour to get the result.
1.Does anyone have an any idea to make these queries to execute faster?
2. Does the latency have anything to do with the rank function or could it be size of the result set?
3. is there any workaround to implement these rank function/partition inside the Analytic view itself? if yes, will this make it give the result faster?
Thank you for your help!!
-Gayathri

Krishna,
I tried both of them, Graphical and CE function,
It is also taking a long time to execute
Graphical view giving me the following error after 2 hr and 36 minutes
Could not execute 'SELECT ORDER_ID,ITEM_ID,RANK from "_SYS_BIC"."EMMAPERF/ORDER_FACT_HANA_CV" group by ...' in 2:36:23.411 hours .
SAP DBTech JDBC: [2048]: column store error: search table error: [2620] executor: plan operation failed
CE function - I aborted after 40 mins
Do you know the syntax to declare local variable to use in CE function?

Rank function in a crosstab

I'm trying to rank products based on the order in which they have been bought (by purchase date).
I figured out I could use the Rank function. First problem was that Rank doesn't seem to work on Dates. I have come across this issue by using the DaysBetween function to calculate the days inbetween the first purchase date and today. This gives me a measure that I can use within the Rank function.
Works fine for single Dimention values. However, when I create a cross-tab with multiple values on top, this doesn't work anylonger.
See the example that shows where it goes wrong: [http://www.littlesister.com/example.xls]
Does anyone have any idea how to solve this?
Thanks,
Paul

Paul,
In the crosstab with the multiple values remove the sort on the rank (if it is still on) and put a break on the object which shows the data for Americas, AP, EMEA and WW.
That should show the correct ranking (at least it does in an example I build myself).
Regards,
Harry

Sql tuning using rank function

Hi,
Can someone help me in writing the below qry using rank() function?
DELETE FROM stc_calllog_ext a
WHERE a.stc_save_status = 'CT'
AND ROWID IN (SELECT a.ROWID
FROM stc_calllog_ext a, calllog_ext b
WHERE a.prod_line_code= b.prod_line_code
AND a.brand_code = b.brand_code
AND a.model_number = b.model_number
AND a.stc_save_status != b.stc_save_status
AND trunc(a.stc_start_time) = trunc(b.stc_start_time)
AND a.stc_start_time BETWEEN TRUNC(SYSDATE-8) AND TRUNC(SYSDATE)
AND a.call_taker_userid = b.call_taker_userid
AND a.cons_telephone_no =b.cons_telephone_no
)

With the information you have provided, I've come up with the following.
SELECT A.ACCOUNT_NO, A.PAYMENT_TYPE, A.INSTALLMENT_TYPE, A.DATE_CHANGE
FROM
 (SELECT account_no, payment_type, installment_type, date_change,
 LEAD( (payment_type), 1)
 over (partition by account_no order by account_no, DATE_CHANGE) LEAD_PAY,
 LEAD( (installment_type), 1)
 over (partition by account_no order by account_no, DATE_CHANGE) LEAD_INST
 from T_ACCNTS ) A
WHERE A.PAYMENT_TYPE <> NVL(A.LEAD_PAY,99)
 OR A.INSTALLMENT_TYPE <> NVL(A.LEAD_INST,99)
ORDER BY 1, 4;

Filter on Rank function 10g

Hi Friends,
Need your help. Please!!!
I have used the RANK function to know the different Start, end date period for a Enrollment.NO.
What I want next is to show only the Enroll No, start, end date for a Enrollment No. with the earliest start date, end date. i.e Max(Rank) for that enrollment No.
for RANK column I have used the function RANK("Start Date" by "EnRoll No")
EnRoll No.      Start Date,      End Date,                  Rank
BAD-002     01-Oct-12     31-Dec-12     1
          01-Jul-12     30-Sep-12     2
          01-Apr-12     30-Jun-12     3
RIS-401     01-Dec-06     28-Feb-07     1
          01-Sep-06     30-Nov-06     2
          01-Jun-06     31-Aug-06     3
          01-Mar-06     31-May-06     4
          01-Dec-05     28-Feb-06     5
          01-Sep-05     30-Nov-05     6
          01-Jun-05     31-Aug-05     7
          01-Mar-05     31-May-05     8
          01-Dec-04     28-Feb-05     9
RCB-235     01-Dec-08     28-Feb-09     1
          01-Sep-08     30-Nov-08     2
          01-Jun-08     31-Aug-08     3
          01-Mar-08     31-May-08     4
          01-Dec-07     29-Feb-08     5
          01-Sep-07     30-Nov-07     6
          01-Jun-07     31-Aug-07     7
          01-Mar-07     31-May-07     8
          01-Dec-06     28-Feb-07     9
          01-Sep-06     30-Nov-06     10
          01-Jun-06     31-Aug-06     11
          01-Mar-06     31-May-06     12
          01-Dec-05     28-Feb-06     13
          01-Sep-05     30-Nov-05     14
My desired output is:
EnRoll No.     Start Date     End Date     Rank
BAD-002     01-Apr-12     30-Jun-12     3
RIS-401     01-Dec-04     28-Feb-05     9
RCB-235     01-Sep-05     30-Nov-05     14
Please help me. Its urgent. I am struck at this point.
Many Thanks in advance.
Aachala

Hi Aachala,
Add the following to your filter and you should be all set...
MAX(RANK("Start Date" by "EnRoll No") by "EnRoll No") = RANK("Start Date" by "EnRoll No") by "EnRoll No")
JB

TopN and Rank in OBIEE-Answer

Hi All,
I'm an "OBIEE newbie" and not sure how to use the Topn or Rank function to achieve the desired resullt below.
I have a report that will display the top 10 or 20 (or whaterver # entered by users) of hospitals that have highest # of patients and then a sum of patients from the rest of other hospitals. ex:
Hospitals #patients rank
ABC 1500 1
KLM 1200 2
DEF 1200 2
XYZ 200 10
Other hospistals: 5000
The top 10 or 20 # will be used as a prompt.
Your help is much appreciated !!!
Thanks,
Ty

Hi David,
I did follow John's posting (it's very helpful for a beginner) but I just could not figure out what he did in Pivot table to get the SUM of the one that did not make the top 10 list. If you could show me how to do that :)
Thank you for help!
Ty

Rank function breaks drill down 11g

I have a simple drill down report standard hierarchy and am having a weird issue with the rank function.
This report works on 10g but the upgraded 11g version does not.
When I drill down past the 2nd level it adds an is null filter to the revenue column. This is also the column we are using to base our rank function.
If I move the rank column to the first or last position in the table the drills work perfectly. If I move it to the second column it breaks on the first drill instead of the 2nd.
It works perfectly if drilling on the headings instead of the values. That seems to point to some sort of null coming through when being passed. I've tried using an ifnull and a case statement and neither method works, it just applies the is null filter to the entire column formula.
The client doesn't want to change the position of the rank column so that work around will not do. Any ideas?

A similar thread was recently talked about here:
In OBIEE charts, how do you make drill downs work on custom formulas?
With a calculated column, you need to make sure the source query and destination query have the EXACT same formula and the same name for the field. If it is not 100% identical, it may not work correctly. (I typically use the NAVIGATE function to get to the second query rather than the Drill function.)
Now in some cases, if you try to create a second drill down query with more details in it, the original formula doesn't work the way you want it to. The calculated formulas have to make sense in both source query and destination query in order to work properly. If you have a ranking of the Top 5 Products in the source query, the destination query also has to have the same ranking of Top 5 products in order to work. If you add more fields into the destination query (e.g., adding on product attributes, or # of records associated with that product name etc.), then sometimes the ranking / aggregation in the destination doesn't add up the same way. This causes the system to think that the formulas are different and prevents the drill down.
I managed to get around this by having a 3rd query in between the original summary view and the detailed data view. So the sequence would be (for example):
- Dashboard based summary query (including the calculated ranked product names formula)
- drill down into virtually identical query (add on one slight bit of difference here, for example adding on a second Product Name field ... not a calculated version, but the actual name). Create a drill down this time by clicking on the regular Product Name field (don't drill down on the custom formula)
- final detailed drill-down query
You can format this intermediary drill down query to explain to users that they need to click a second time.
It's not ideal, but it should work. Hope this helps.
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