Read Command from Command Line

Hi.
I am starting my application using the following command at the command line: "java -jar convert.jar config.txt". Is there any way for me to read the "convert.jar" portion of the command.
I am building a server side application that needs to restarted periodically. I get the invocation directory using System.getProperty("user.dir"). I need to know the name of the command so that I can execute something line
"java -jar" + strCommand + System.getProperty("user.dir"), where strCommand is the command "convert.jar" or "/path/to/convert.jar"
Thanks,
Siddharth.

am building a server side application that needs to restarted periodically.The OS has certainly a utility to periodically schedule an application (cron, at, scheduled tasks...)

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SQL Developer BRIDGE command from command line on Windows environment

Is it possible to call SQL Developer BRIDGE command from command line on Windows environment?

Hi <please supply your name>,
SQL Developer Worksheet is not available from the command line.
The BRIDGE command is only supported in the Worksheet.
Its an interesting idea though. Are you trying to script data move from a non Oracle database to an Oracle database using the BRIDGE command?
The BRIDGE command was initially done to allow a simple data move from a non Oracle database to Oracle. We then build the "Copy to Oracle" feature out of it.
http://dermotoneill.blogspot.com/2010/11/cross-database-bridge-statement.html
http://dermotoneill.blogspot.com/2010/11/copy-to-oracle.html
Since the BRIDGE command references connection names, which have to be defined in UI of SQL Developer any solution to run this on the command line would have to work this out.
There are number of ways you can do this without using the BRIDGE command.
1) Perform a capture/convert of your non Oracle database and then generate the "offline" data move scripts.
Theses scripts use SQL*Loader and your non Oracle database tool (Ex: Sybase BCP).
These are run from the command line and can be modified ....
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I would interested to hear your thoughts.
Regards,
Dermot
SQL Developer Team.

Dock commands from command line

Hi,
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Kannan

Sure. Which commands are you interested in?

Running command from command prompt

hai all,
iam using Javamail to send emails. for that iam using the command prompt.the code for executing the commands from the command prompt is as given below.
public static String runCommand(String s)
String result=new String();
     try
     //the command is executed and stored in 'p'
     Process p=Runtime.getRuntime().exe("cmd /c "+s);
     result=(loadStream(p.getInputStream()));
     if(p.waitFor()!=0)
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System.out.println("Result is "+result);
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the contents of the 'javamail' directory are
activation.jar, mail.jar, Msgmultisendsample.java and Msgmultisendsample.class
in the first call to this method i pass the string "set classpath=%classpath%;e:\javamail\mail.jar;e:\javamail\activation.jar;e:\javamail; " here i set the classpath since i will be executing the command from the command prompt.the command works fine and the exitValue() is 0.
in the second call to this method i pass the string "java Msgmultisendsample [email protected] abc 123.456.789.012 true" for running the Msgmultisendsample.class file. but i get the exitValue() as 1 and the command is not getting executed. i dont know how handle this change in the exitValue().
both the above commands works fine if i run directly from C:\ but not when called to this method.
Please help me out people, i will be glad to receieve the replies as early as possible since i have to submit this tomorrow.
Thanks in advance,
Jayanth.

well, the problem is not with the command line arguments. it doesnt matter if we get the input from the user through command prompt or GUI. The problem is only in the handling of the change in exitValue during running.

Trace commands from command prompt

How can I run trace commands from the SQL prompt since I dont have OEM on linux.
How can I perform other diagnostic commands on linux?

minitraktor wrote:
The problem is that it seems very inefficient to open a new command prompt for each command.Maybe so, but efficiency is rarely a reason to change correct code. The question you should be asking yourself is: is it efficient enough?
Is it possible to execute all commands in the same command prompt?It rather depends on whether you need to get a result from each command. If so, I suspect not; if not, you might be able to combine several commands within the same invocation. I'm no expert on this stuff though, so there may be other options (a BAT file?).
Winston
BTW: You do know that your implementation is by no means assured of running the commands in sequence?

Reading Angles From a Line Driver Quadrature Encoder

I currently have a Quadrature Encoder (Line Drive) and am trying to interface it with a PCI-6602 Counter/Timer Card. I have currently had no luck in correctly hooking it up and reading the angle. Past experience with Quadrature Encoder have all been open collector; I have been able to to successfully hook up an open collector encoder with the 6602.
Any help in hooking up the Line Driver encoder with the PCI6602 would be appreciated.
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Justin,
Normally, the mfgr. would include a recommended "Line Receiver" interface circuit for the encoder. I've found that some line-driver encoders actually can be successfully connected directly to the 6602 for quick-and-dirty testing, though you wouldn't want to wire that up arbirtrarily or rely on it for the long term. In any event, it sounds like you'll need to add a line receiver interface.
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SignTool.exe verify /pa returns exit code 1 from the code but works fine while running from command prompt

Hi,
I am using SignTool.exe from a new Process() to verify a codesigned assembly and it returns the exit code 1 whereas it returns exit code 0 while i run the same from Visual Studio Command prompt. Please let me know your thoughts...
Here is my code snippet from VS2012 ultimate on Win7 PC.
p = new Process();
p.StartInfo.FileName = "C:\\Program Files (x86)\\Microsoft SDKs\\Windows\\v7.0A\\Bin\\SignTool.exe";
string args = @"verify";
p.StartInfo.Arguments = args + " "+ "/pa " + "/v "+ name;
p.Start();
p.WaitForExit();
pexitcode = p.ExitCode;
//name = "C:\\Users\\v-maparn\\Documents\\Visual Studio 2012\\Projects\\CodesignVerification\\CodesignVerification\\bin\\Release\\Microsoft.IT.Core.dll"
Thanks,
Mani

Hi Amy,
Thanks for your reply. I am receiving the exit code 1 by the Process even though the SignTool is able to successfully verify the assembly. I ran the below command from command prompt and received no errors or warnings. I assume the exit code should be 0.
I have also verified that this assembly has digital signature embedded as you can see from the output.
output:
C:\Windows\system32>signtool.exe verify /pa /v "C:\Users\v-maparn\Documents\Visu
al Studio 2012\Projects\CodesignVerification\CodesignVerification\bin\Release\Mi
crosoft.IT.Security.UI.SystemSecurityManagement.SSMUIWebHost.dll"
Verifying: C:\Users\v-maparn\Documents\Visual Studio 2012\Projects\CodesignVerif
ication\CodesignVerification\bin\Release\Microsoft.IT.Security.UI.SystemSecurity
Management.SSMUIWebHost.dll
Signature Index: 0 (Primary Signature)
Hash of file (sha1): 1B58113B218260837A6B850561538A804B034F2A
Signing Certificate Chain:
    Issued to: Microsoft Root Certificate Authority
    Issued by: Microsoft Root Certificate Authority
    Expires:   Sun May 09 15:28:13 2021
    SHA1 hash: CDD4EEAE6000AC7F40C3802C171E30148030C072
        Issued to: Microsoft Code Signing PCA
        Issued by: Microsoft Root Certificate Authority
        Expires:   Mon Aug 31 14:29:32 2020
        SHA1 hash: 3CAF9BA2DB5570CAF76942FF99101B993888E257
            Issued to: Microsoft Corporation
            Issued by: Microsoft Code Signing PCA
            Expires:   Thu Apr 24 14:33:39 2014
            SHA1 hash: 108E2BA23632620C427C570B6D9DB51AC31387FE
The signature is timestamped: Mon Dec 30 02:58:12 2013
Timestamp Verified by:
    Issued to: Microsoft Root Certificate Authority
    Issued by: Microsoft Root Certificate Authority
    Expires:   Sun May 09 15:28:13 2021
    SHA1 hash: CDD4EEAE6000AC7F40C3802C171E30148030C072
        Issued to: Microsoft Time-Stamp PCA
        Issued by: Microsoft Root Certificate Authority
        Expires:   Sat Apr 03 05:03:09 2021
        SHA1 hash: 375FCB825C3DC3752A02E34EB70993B4997191EF
            Issued to: Microsoft Time-Stamp Service
            Issued by: Microsoft Time-Stamp PCA
            Expires:   Wed Feb 11 14:11:31 2015
            SHA1 hash: D967AB4CF991F11DA6E318C880F1AF1A9C8D2C7C
Successfully verified: C:\Users\v-maparn\Documents\Visual Studio 2012\Projects\C
odesignVerification\CodesignVerification\bin\Release\Microsoft.IT.Security.UI.Sy
stemSecurityManagement.SSMUIWebHost.dll
Number of files successfully Verified: 1
Number of warnings: 0
Number of errors: 0
C:\Windows\system32>
Thanks,
Mani

VPN Client disconnection from command line

Hi,
I want to connect to IPsec VPN on ISA500 by VPN Client (v 5.0.07.0440, the last version, I think), using command line parameters.
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If I do
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I obtain the list of parameters
vpngui [-c | -sc [sd] [-user <username>] [-pwd <password> ! -eraseuserpwd]] <connection entry>
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Can anyone help me?
Thanks

Prasath,
This appears to be a data flow issue. You need to look in the dataflow log file. Your information indicates the project name is SAMPLES.xml, and the data flow ID is D20091213_014350765. Look at the data flow log file in
C:\dqxi\11_7\repository\configuration_rules\runtme_metadata\project_SAMPLES\D20091213_014350765
Alternatively, you can temporarily replace the transactional reader and writter transforms with their corresonding batch transforms, and run the job from the Project Architect. Any errors will be displayed in the Running window.
Paul

How to delete more than one workbook from command line

Hi, I'd like to delete more than one workbook from command line:
The following syntax, it doesn't work....but I followed the manual instructions:
dis51adm.exe /connect eul/eul@uatdb /delete /workbook "ALE_TEST_1, ALE_TEST_2" /eul eul /log D:\Ale\delete.log
where:
eul/eul@uatdb: is the db’s schema/user where the EUL is installed;
/delete "ALE_TEST_1, ALE_TEST_2": is the command to delete the workbooks, specified inside the “” (with the relative path)
/log D:\Ale\delete.log: is the command to write a log’s file named “delete.log” to track the action
The log file says:
22/4/2008 4:00:26 μμ
dis51adm.exe /connect /delete /workbook ALE_TEST_1, ALE_TEST_2 /eul eul /log D:\Ale\delete.log
Document ALE_TEST_1, ALE_TEST_2 not found in EUL.
Internal EUL Error: ObjectNotFound - Can't find EUL element
There are 0 eul elements to be deleted.
Completed deleting eul elements.
22/4/2008 4:00:29 μμ
Anyone can tell me how is the right syntax ?
Thanks in advance
Alex

Hi Rod
I was coming to that conclusion myself but wanted to wait until the other avenues had been exhausted first - aka making sure of the workbook names.
I checked through all of the command line documentation and read nothing which clearly indicated that only one workbook could be processed at a time, other than the fact that the syntax says workbook and not workbooks, which could be a big clue.
I think you are right though in that it has to be one at a time, which would be a pain.
Best wishes
Michael

How to run a 10g report from command line ?

Good Afternoon,
Please advise if there is a way to run a 10g report from command line.
We use 6i right now and our job scheduler runs reports using "D:\ORADEV6I\BIN\RWRUN60.EXE ..." executable in batch mode on a separate server. We plan to migrate to 10g Database, Forms, Reports. Is there a way to keep this functionality and create a "command" to address an report server and run a report?
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Dmitri

Steps to take.
(1.) In command prompt type RWSERVER SERVER=repserver1 to star the rep server.
(2.) If you get "Javaw.exe The procedure entry point psoasyn could not be located in the dynamic link library orapls10.dll." error do one of the following
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        (b.) Add D:\OracleDevR2\bin to the system env. variable PATH
(3.) Start OC4j
(4.) Now you can access the jobs using URL like:
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Running FlexUnit tests from command line

Sorry if that has been posted before: I searched best I could and nothing came up.
I am interested in building and running my unit tests from the command line so we can add it to a nightly build process.
I am *very* new to all this: basically I picked up Adobe Flash Builder 4 a month ago and I have done *everything* inside that IDE: writing code, building, testing, running.
I looked into at least how to build something from the command line, I found this:
http://help.adobe.com/en_US/flashbuilder/using/WSbde04e3d3e6474c4-59108b2e1215eb9d5e4-8000 .html
Can't get past this error:
Buildfile: /Users/dbanks/build_test.xml
BUILD FAILED
Target "FlexUnitApplication" does not exist in the project "null".
Total time: 0 seconds
Adobe Flash Builder 4:
An error has occurred. See the log file
/Users/dbanks/Documents/Adobe Flash Builder 4/.metadata/.log.
Plus, even if I got this going, I am just building the swf. I also want to run it and capture the output in some meaningful way that can be read/evaluated/acted on.
FWIW, the script/xml I am using to try to build:
build_test.xml:
<?xml version="1.0"?>
<project default="main">
    <target name="main">
        <fb.exportReleaseBuild project="NightclubMogul" />
    </target>
</project>
execute_build_test.sh:
WORKSPACE="$HOME/Documents/AdobeFlashBuilder4"
# works with either FlashBuilder.app or Eclipse.app
"/Applications/AdobeFlashBuilder4" \
    --launcher.suppressErrors   \
    -noSplash   \
    -application org.eclipse.ant.core.antRunner   \
    -data "$WORKSPACE"    \
    -file "/Users/dbanks/build_test.xml" FlexUnitApplication
I am not clear what in here is actually supposed to point to where my project lives: it's off in some directory somewhere. I see that I am pointing to a workspace (Documents/AdobeFlashBuilder4) but when I poke around in there I don't see anything connecting back to the directories where the code lives.
Any help would be great: getting the tests to build from command line, then getting them to run.

C:\>sqlplus @myscript
That would be the easiest variation
C:\>sqlplus user/passwd@tns_alias @myscript
would be an often used variation
And then there is of course the version with parameter passing:
C:\>sqlplus user/passwd@tns_alias @myscript param1 ... paramx
Dunno about MSBuild

Why not all jars picked up by ojdeloy and how to generate build.xml from command line and not JDEV GUI - quick question

Hi All
We have 11.1.1.7 ojdeploy to compile our app.
We notice in the log that not all jars are used in classpath arguments when we explicitly set them up for compilation.
eg:
<path id="classpath">
    <pathelement location="../../Oracle/Middleware/oracle_common/modules/oracle.adf.share_11.1.1/commons-el.jar"/>
    <pathelement location="../../Oracle/Middleware/oracle_common/modules/oracle.adf.share_11.1.1/jsp-el-api.jar"/>
    <pathelement location="../../Oracle/Middleware/oracle_common/modules/oracle.adf.share_11.1.1/oracle-el.jar"/>
    <pathelement location="interface/public_html/WEB-INF/lib/a.jar"/>
    <pathelement location="interface/public_html/WEB-INF/lib/b.jar"/>
    <pathelement location="interface/public_html/WEB-INF/lib/c.jar"/>
    <pathelement location="interface/public_html/WEB-INF/lib/d.jar"/>
</path>
Log Output -
[ora:ojdeploy] /path/to/Oracle/Middleware/jdk160_24/bin/javac
[ora:ojdeploy] -g
[ora:ojdeploy] -Xlint:all
[ora:ojdeploy] -Xlint:-cast
[ora:ojdeploy] -Xlint:-empty
[ora:ojdeploy] -Xlint:-fallthrough
[ora:ojdeploy] -Xlint:-path
[ora:ojdeploy] -Xlint:-serial
[ora:ojdeploy] -Xlint:-unchecked
[ora:ojdeploy] -source 1.6
[ora:ojdeploy] -target 1.6
[ora:ojdeploy] -verbose
[ora:ojdeploy] -encoding Cp1252
[ora:ojdeploy] -classpath
[ora:ojdeploy] /path/to/Oracle/Middleware/jdk160_24/jre/lib/resources.jar:
[ora:ojdeploy] /path/to/Oracle/Middleware/jdk160_24/jre/lib/rt.jar:
[ora:ojdeploy] /path/to/Oracle/Middleware/jdk160_24/jre/lib/jsse.jar:
    [ora:ojdeploy] /path/to/interface/public_html/WEB-INF/lib/a.jar"/>
    [ora:ojdeploy] /path/to/interface/public_html/WEB-INF/lib/c.jar"/>
1- Is it because it depends on how jpr or jws are configured ?
2- How can we automatically generate a build file of the application from command-line (as opposed to using Jdev IDE to click to generate a build.xml) ?

The first warning is happening because you're stating drivers for input devices without need. You haven't disabled hotplug so evdev gets used instead of kbd. This is normal, and you should change the driver line from kbd to evdev so that whatever options (if any) you've specified for the keyboard get parsed.
The second warning is about you not installing acpid.
The third I have no idea about, but look at the synaptics wiki. None of the (WW) are related to your video card.
And every card that has 2 or more output ports show up as "two cards". You also don't need to specify the pci port in xorg.conf. edit: this is the general case with laptops, might be different for desktops.
When I do lspci -v I get:
00:02.0 VGA compatible controller: Intel Corporation Mobile 945GME Express Integrated Graphics Controller (rev 03) (prog-if 00 [VGA controller])
Subsystem: Micro-Star International Co., Ltd. Device 0110
Flags: bus master, fast devsel, latency 0, IRQ 16
Memory at dfe80000 (32-bit, non-prefetchable) [size=512K]
I/O ports at d0f0 [size=8]
Memory at c0000000 (32-bit, prefetchable) [size=256M]
Memory at dff00000 (32-bit, non-prefetchable) [size=256K]
Expansion ROM at <unassigned> [disabled]
Capabilities: <access denied>
00:02.1 Display controller: Intel Corporation Mobile 945GM/GMS/GME, 943/940GML Express Integrated Graphics Controller (rev 03)
Subsystem: Micro-Star International Co., Ltd. Device 0110
Flags: bus master, fast devsel, latency 0
Memory at dfe00000 (32-bit, non-prefetchable) [size=512K]
Capabilities: <access denied>
And it doesn't matter if it errs in trying to sli up with it self. That's just not a possibility.
Last edited by gog (2009-10-15 23:59:49)

How to restore or backup Apex application from Command line ? URGENT

We have Oracle apex 4.1 installed in Oracle 11g R2 database (windows 64-bit) 2008 R2
For some reason our database dictionary objects are corrupted.
We wanted to backup our Apex applications in some workspaces ASAP.
We are not able to access apex from http://localhost:7777/pls/apex/htmldb_login
We have an underlying database schema export (expdp).
1) Is there a way to export or backup the apex application without logging into the apex URL ? if yes how ?
2) Does Oracle has any of its own native tool to backup and restore from command line ?
Thanks in advance

My (MS Windows) experience, if I may; perhaps you'll find something useful.
You'll find the README.TXT file in /apex/utilities directory. Read it.
In order to use APEXExport, you need JDK version 1.5 or higher. Check your version by typing (and viewing the result):
C:\>java –version
java version "1.6.0_06"
Java(TM) SE Runtime Environment (build 1.6.0_06-b02)
Java HotSpot(TM) Client VM (build 10.0-b22, mixed mode, sharing)Its directory should be part of the PATH environment variable: on my computer, directory name isC:\Program Files\Java\jre1.6.0_06\binFurthermore, Oracle JDBC class libraries must be part of the CLASSPATH environment variable. Check whether it exists (in Control Panel - System - Advanced - Environment Variables). For my 10gXE, it is here:C:\oraclexe\app\oracle\product\10.2.0\server\jdbc\lib\ojdbc14.jarI couldn't make it work; didn't know that ".\" directory must be entered into CLASSPATH as well (found that information in Arie Geller's book). Therefore, my final CLASSPATH version is:.\;C:\oraclexe\app\oracle\product\10.2.0\server\jdbc\lib\ojdbc14.jarOK, setup is done. Now, go to your /apex/utilities directory and, from the command prompt, run (mind the upper case!)java oracle.apex.APEXExportwhich will show a short help.
I chose to export the whole workspace. In order to do that, I need the workspace ID (got it from Apex's SQL Workshop; that might be a problem as you can't get there, can you? I can't tell how to find that information apart from SQL Workshop, but I'm pretty sure someone, who is much more experienced than me, will know it). OK, here's how you find it:select v('WORKSPACE_ID') from dual;Finally, here's the final step - export:C:\apex\utilities>java oracle.apex.APEXExport -db localhost:1521:xe -user scott -password tiger -workspaceid 1038408092496568The result are fxxx.sql files (where "xxx" represents application number).
I hope you'll manage to export your applications; basically, nothing special here (except that ".\" directory in the CLASSPATH variable).
Best of luck!

Problem with tokenized input from command line

I am trying to take an input from the command line, parse it to tokens and perform whatever operation is needed depending on the name of the token, on a binary tree of stacks for example, if i type 1 2 1 3 printLevelOrder, then the root of the tree should have 3, 2,1 in the stack, the left child should have 1 and the right child should be empty. and then a level order print of the tree should be performed.
however what is happening when i run this code is the numbers are being put into the right stacks of the tree, but any commands such as printLevelOrder or PrintPopRoot are entering the code that is for placing numbers onto the stack instead of executing that command and skipping past this piece of code.
so my question is, why is the if statement if (word =="printLevelOrder") not being executed when thats whats in the word ?
example input and output shown below code fragment.
          try {
              BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
             String line = "";
             while (line != "***") {
                  System.out.print("> prompt ");
                  line = in.readLine();
                  StringTokenizer tokenizer = new StringTokenizer(line," ");
                  String word = new String();
                  while (tokenizer.hasMoreTokens()) {
                         word = tokenizer.nextToken();
                         boolean notCommand = true;
                         if (word =="printLevelOrder") {
                              theTree.printLevelOrder();
                              System.out.println("(word ==printLevelOrder)");
                              notCommand=false;
                         if (word == "printPopLevelOrder") {
                              theTree.printPopLevelOrder();
                              notCommand=false;
                         if (word == "printPopInorder") {
                              theTree.printPopInorder();
                              notCommand=false;
                         if (word == "printPopPreorder") {
                              theTree.printPopPreorder();
                              notCommand=false;
                         if (word == "printPopRoot") {
                              theTree.printPopRoot();
                              notCommand=false;
                         if (word == "***") {
                              notCommand=false;
                         if (notCommand == true) {
                              System.out.println("(notCommand == true)");
                              boolean notPlaced = true;
                              int v = 1;
                              while ((notPlaced==true) && (v < theTree.size())) {
                                   if (theTree.element(v).isEmpty()) {
                                        theTree.element(v).push(Integer.valueOf(word));
                                        System.out.println("Inserting"+word);
                                        System.out.println("in empty stack at location: "+v);
                                        notPlaced=false;
                                   if (notPlaced==true) {
                                        if ( Integer.valueOf(word) >= Integer.valueOf( theTree.element(v).top().toString() ) ) {
                                             theTree.element(v).push(Integer.valueOf(word));
                                             System.out.println("Inserting"+word);
                                             System.out.println("in stack at location: "+v);
                                             notPlaced=false;
                                   v++;
          }valid inputs: int value, printLevelOrder, printPopLevelOrder, printPopInorder, p
rintPopPreorder, printPopRoot, *** to quit
prompt 1 3 2 4 2 printLevelOrder(notCommand == true)
Inserting1
in empty stack at location: 1
(notCommand == true)
Inserting3
in stack at location: 1
(notCommand == true)
Inserting2
in empty stack at location: 2
(notCommand == true)
Inserting4
in stack at location: 1
(notCommand == true)
Inserting2
in stack at location: 2
(notCommand == true)
Exception in thread "main" java.lang.NumberFormatException: For input string: "printLevelOrder"
at java.lang.NumberFormatException.forInputString(NumberFormatException.java:48)
at java.lang.Integer.parseInt(Integer.java:447)
at java.lang.Integer.valueOf(Integer.java:553)
at TreeStack.main(TreeStack.java:73)
Press any key to continue . . .

lol aww, shame that you forgot to do that. i had 10 / 10 for mine, and seing as the deadline is now well and trully over,
here is the entire source for anybody who was following the discussion or whatever and wanted to experiment.
additional files needed >
http://users.cs.cf.ac.uk/Paul.Rosin/CM0212/Stack.java
http://users.cs.cf.ac.uk/Paul.Rosin/CM0212/ArrayStack.java
http://users.cs.cf.ac.uk/Paul.Rosin/CM0212/StackEmptyException.java
http://users.cs.cf.ac.uk/Paul.Rosin/CM0212/StackFullException.java
/*TreeStack.java - reads command line input of values and assigns them to stacks in a binary tree and performs
operations on the ADT. valid inputs: <int>,   printLevelOrder,   printPopLevelOrder,
printPopInorder,   printPopPreOrder,   printPopRoot.         Terminates on invalid input.
Written by George St. Clair.
S/N:0208456         22/11/2005
import java.util.Vector;
import java.io.*;
import java.util.StringTokenizer;
public class TreeStack {
     private final int TREE_CAPACITY = 7 + 1;
     private final int STACK_CAPACITY = 10;
     Vector tree = new Vector(TREE_CAPACITY) ;
     //collect input from command line, add values to stacks at nodes of the teee
     //and perform required operations on the treestack
     public static void main (String [] args) {
          //create a tree of stacks
          TreeStack theTree = new TreeStack ();
          try {
               //collect standard input
              BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
             String line = "";
             while (line != null) {
                    System.out.print("");
                  line = in.readLine();
                  //tokenise input
                  StringTokenizer tokenizer = new StringTokenizer(line," ");
                  String word = new String();
                  while (tokenizer.hasMoreTokens()) {
                         //assign word to the token
                         word = tokenizer.nextToken();
                         boolean notCommand = true;
                         //perform operation on treestack depending on what word is
                         if (word.equals("printLevelOrder")) {
                              System.out.println("printLevelOrder");
                              theTree.printLevelOrder();
                              notCommand=false;
                         if (word.equals("printPopLevelOrder")) {
                              System.out.println("printPopLevelOrder");
                              theTree.printPopLevelOrder();
                              notCommand=false;
                         if (word.equals("printPopInorder")) {
                              System.out.println("printPopInorder");
                              theTree.printPopInorder();
                              notCommand=false;
                         if (word.equals("printPopPreorder")) {
                              System.out.println("printPopPreorder");
                              theTree.printPopPreorder();
                              notCommand=false;
                         if (word.equals("printPopRoot")) {
                              System.out.println("printPopRoot");
                              theTree.printPopRoot();
                              notCommand=false;
                         //if word was not a command it must be a number
                         if (notCommand == true) {
                              boolean notPlaced = true;
                              int v = 1;
                              //starting at the root, find suitable place for number
                              while ((notPlaced==true) && (v < theTree.size())) {
                                   //if the stack at v is empty, number goes here
                                   if (theTree.element(v).isEmpty()) {
                                        theTree.element(v).push(Integer.valueOf(word));
                                        System.out.println("inserting: "+word);
                                        System.out.println("in empty stack at location: "+(v-1));
                                        notPlaced=false;
                                   //if the stack is not empty
                                   if (notPlaced==true) {
                                        //if the value on the top of the stack is smaller than number, number goes onto the stack
                                        if ( Integer.valueOf(word) > Integer.valueOf( theTree.element(v).top().toString() ) ) {
                                             theTree.element(v).push(Integer.valueOf(word));
                                             System.out.println("inserting: "+word);
                                             System.out.println("in stack at location: "+(v-1));
                                             notPlaced=false;
                                   //if that node was no good, check the next one for suitability
                                   v++;
          catch (Exception e) {
               //occurs when user inputs something that is neither a command, or a number, or upon EOF, or stack is full
     public TreeStack () {
          //create the TreeStack ADT by adding stacks in the vector, note vector 0 is instantiated but not used.
          for (int i = 1;i<=TREE_CAPACITY;i++)
               tree.add(new ArrayStack(STACK_CAPACITY));
     public int size() {
          //return the size of the tree +1 (as 0 is not used)
          return tree.size();
     public ArrayStack element (int v) {
          //return the ArrayStack at v
          return (ArrayStack)tree.get(v);
     public int leftChild (int v ) {
          //return left child of v
          return v*2;
     public int rightChild (int v ) {
          //return the right child of v
          return v*2+1;
     public boolean children (int v ) {
          //search for children of v and return true if one exists
          for (int i =v;i<size();i++) {
               if (i/2==v ) {
                     //left child found at i
                     return true;
               if ((i-1)/2==v ) {
                    //right child found at i
                    return true;
          //no children found
          return false;
     public boolean isInternal (int v ) {
          //test whether node v is internal (has children)
          if (children (v)== true) {
               //has children
               return true;
          return false;
     //print the top value in each stack encountered on a level-order traversal of tree
     public void printLevelOrder() {
          //for every node of tree v
          for (int v = 1;v<size();v++) {
               if (!element(v).isEmpty() ) {
                    //print the top value in stack v
                    System.out.println(" "+element(v).top());
               else {
                    //stack at v is empty
                    System.out.println(" -");
     //pop off and print the top value in each stack encountered on a level-order traversal of tree
     public void printPopLevelOrder () {
          //pop off and print the top value in stack v
          for (int v = 1;v<size();v++) {
          //for each node of tree v
               if (!element(v).isEmpty() ) {
                    //if v isnt empty print the top value in stack v
                    System.out.println(" "+element(v).top());
                    //pop the top value in the stack at v
                    element(v).pop();
               else {
                    //stack at v is empty
                    System.out.println(" -");
     //pop off and print the top value in each stack encountered on an in-order traversal of tree
     public void printPopInorder () {
          printPopInorder (1);
     public void printPopInorder (int v) {
          boolean isInternal = false;
          if (isInternal (v)) {
               //use a boolean for isInternal to save on running the method twice
               isInternal = true;
               //recursively search left subtree
               printPopInorder (leftChild(v));
          //pop off and print the top value at v
          if (element(v).isEmpty() ) {
               //stack at v is empty
               System.out.println(" -");
          else {
               //if v isnt empty print the top value in stack v then pop
               System.out.println(" "+element(v).top());
               element(v).pop();
          if (isInternal ) {
               //recursively search right subtree
               printPopInorder (rightChild(v));
     //pop off and print the top value in each stack encountered on an pre-order traversal of tree
     public void printPopPreorder() {
          printPopPreorder(1);
     public void printPopPreorder(int v) {
          //pop off and print the top value at v
          if (!element(v).isEmpty() ) {
               //if v isnt empty print the top value in stack v then pop
               System.out.println(" "+element(v).top());
               element(v).pop();
          else {
               //stack at v is empty
               System.out.println(" -");
          if (isInternal (v)) {
               //recursively search left and right subtrees
               printPopPreorder (leftChild(v));
               printPopPreorder (rightChild(v));
     //pop off and print all values from the stack at the root
     public void printPopRoot (){
          //while the root stack has values left
          while (!element(1).isEmpty()) {
               //print, then pop
               System.out.println(" "+element(1).top());
               element(1).pop();
}

How to open an online pdf from command-line

Hi,
I'm trying to get my application to open a pdf file from an url like http://xxxx.dk/xxx.aspx?CID=xxx
it work from inside adobe reader so the pdf file is a functionel file, but when i try to open it from command line like: AcroRd32.exe /n /A "pagemode=none" "http://xxxx.dk/xxx.aspx?CID=xxx" i keep getting an error telling me "There was an error opening this document. The filename, directory name, or volume label syntax is incorrect"
does anyone have an idea of what i need to do? i could also make a public test if someone needs to see the issue "live"

it works with the browser, so no problems there.. i just wanted the pdf file to open in adobe reader instead of browser window, as it opens from a windows application.. but perhaps i need to look more into merging a embedded pdf viewer in the application instead..

Read Command from Command Line

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