Reading Command Line

How to read the DOS command line by JAVA.
for example when i type on DOS DIR, want to save all output to Text file.
Thanks and best regards

I found somthing to help, but i need to make a process which let me to type a command into the Concole and the output will appeare like i am working with Dos Wndows ( Start--> Run--> cmd)
Thanks and best regards

Similar Messages

Acrobat reader command line switch - password

Hello everybody,
I am a developer for macromedia director applications.
I need to open a password protected PDF-file from within a
director-projector-application with any suitable
xtra-extension (not the
problem discussed here!).
all I would need is the complete command line for acrobat
reader to do
this.
A complete list of command line switches for Acrobat Reader
would be helpful
in respect to further needs.
where can i get this.
By the way, the solution for Windows and Mac OS would be
welcome. Are they
the same?
Thanks
Peter Grambitter

Hello everybody,
I am a developer for macromedia director applications.
I need to open a password protected PDF-file from within a
director-projector-application with any suitable
xtra-extension (not the
problem discussed here!).
all I would need is the complete command line for acrobat
reader to do
this.
A complete list of command line switches for Acrobat Reader
would be helpful
in respect to further needs.
where can i get this.
By the way, the solution for Windows and Mac OS would be
welcome. Are they
the same?
Thanks
Peter Grambitter

Read command line arguments with an ActiveX step

Hi
I would like to read the command line parameters from TestStand startup. I did find an ActiveX resulting in a Object Reference (See Locals.CommandsRef). How do I use this reference to really get the arguments and their count? See also screenshot.
Solved!
Go to Solution.
Attachments:
Screenshot.jpg ‏160 KB

Hi Paulus,
Via this link, you find an forumthread that describes the same issue. testStand does not support this, but there is a workaround. Attached you find the code.
The attachment includes a LV vi with the command line. If you doen't use Labview, here is the command line:
C:\Program Files (x86)\National Instruments\TestStand 2012\Bin\SeqEdit.exe /goto "Parameter1 = test" /runEntryPoint "Test UUTs" D:\Testsequence.seq
Regards,
Bas
Attachments:
Command line TestStand.zip ‏10 KB

Acrobat Reader command line problem

In windows xp professional I'm programatically creating a batch file and executing it (shell command in visual basic) to convert pdf files to Microsoft xps.
The batch command looks like this one:
"C:\Program Files\Adobe\Reader 10.0\Reader\AcroRd32.exe" /t "D:\MyDir\Microsoft XPS Document\x.pdf" "Microsoft XPS Document Writer" /t "D:\MyDir\Microsoft XPS Document\x.xps".
When the user logged in on the machine is an administrator, acrobat reader does the operation silently. When a normal user (not belonging to administrators group) is logged in on the machine, acrobat reader opens the save as dialog window requiring user interaction.
The normal user has full control over the destination directory. I already tested giving the normal user full control over AcroRd32.exe and over cmd.exe with no success. I also tried in visual basic 2008 executing the command through System.Diagnostics.Process.Start with the exact same curious results.
Can someone help.
Thank you.

Hi.
I couldn't find a solution within Adobe for the problem I reported Oct 9, 2012, so I went to a fallback solution aimed to complete the needed stages. I'm posting here the visual basic 2008 code I wrote then. It is not a graceful solution and has some coarse code but was designed as part of an application that must keep processing files without user intervention. The procedure "followAcroRd32PDFtoXPS" must be called after the execution of a batch command like the described in the previous post:
Module fallback
 Declare Function FindWindow Lib "user32" Alias "FindWindowA" (ByVal lpClassName As String, ByVal lpWindowName As String) As Integer
 Declare Function FindWindowEx Lib "user32" Alias "FindWindowExA" (ByVal hwndParent As Integer, ByVal hwndChildAfter As Integer, ByVal lpszClass As String, ByVal lpszWindow As String) As Integer
 Declare Function GetDlgCtrlID Lib "user32" (ByVal hDlg As Integer) As Integer
 Declare Function SendDlgItemMessage Lib "user32" Alias "SendDlgItemMessageA" (ByVal hDlg As Integer, ByVal nIDDlgItem As Integer, ByVal Msg As Integer, ByVal wParam As Integer, ByVal lParam As String) As Integer
 Declare Function PostMessage Lib "user32" Alias "PostMessageA" (ByVal hwnd As Integer, ByVal wMsg As Integer, ByVal wParam As Integer, ByVal lParam As Integer) As Integer
 Const WM_SETTEXT = &HC
 Const BM_CLICK = &HF5
 Function FileInUse(ByVal filepath As String) As Boolean
 Dim f001 As Integer
 If System.IO.File.Exists(filepath) Then
 Try
 f001 = FreeFile()
 FileOpen(f001, filepath, OpenMode.Binary, OpenAccess.ReadWrite, OpenShare.LockReadWrite)
 FileClose(f001)
 Catch
 Return True
 End Try
 End If
 End Function
 'outpfile <-- path to the XPS Document to be created
 'starttime <-- system date and time when the batch command line was executed
 Sub followAcroRd32PDFtoXPS(ByVal outpfile As String, ByVal starttime As System.DateTime)
 Dim p As System.Diagnostics.Process, q As System.Diagnostics.Process, proc() As System.Diagnostics.Process
 Dim i As Integer, j As Integer
 Dim l As Long, memusage() As Long
 Dim t000 As System.DateTime
 Dim t999 As System.DateTime
 Dim hwnd As Integer, lObjhWndTB As Integer, lObjhWndBu As Integer
 Dim nIDDlgItem As Integer
 Dim resu As Integer
 dim maximumacrobatwaittime = 60 'seconds
 dim memoryusageinactivity = 12 'seconds
 dim acrord32pdftoxpstimelimit = 12 'seconds
 'Identify necessary Adobe Reader process
 t000 = DateTime.Now
 Do
 System.Threading.Thread.Sleep(1000)
 i = 0
 For Each p In System.Diagnostics.Process.GetProcesses
 If LCase(p.ProcessName) = LCase("AcroRd32") Then
 If Not p.StartTime < starttime Then
 ReDim Preserve proc(i)
 proc(i) = p
 i = i + 1
 End If
 End If
 Next
 If i > 0 Then Exit Do
 t999 = DateTime.Now
 If DateDiff(DateInterval.Second, t000, t999) > maximumacrobatwaittime Then
 Exit Sub
 End If
 Loop
 'Identify necessary window
 t000 = DateTime.Now
 Do
 System.Threading.Thread.Sleep(1000)
 hwnd = FindWindow(vbNullString, "Save the file as")
 If hwnd <> 0 Then
 Exit Do
 End If
 t999 = DateTime.Now
 If DateDiff(DateInterval.Second, t000, t999) > maximumacrobatwaittime Then
 Exit Sub
 End If
 Loop
 'Send click message to button save
 t000 = DateTime.Now
 Do
 System.Threading.Thread.Sleep(1000)
 lObjhWndTB = FindWindowEx(hwnd, 0, "ComboBoxEx32", "")
 If Not lObjhWndTB = 0 Then
 nIDDlgItem = GetDlgCtrlID(lObjhWndTB)
 resu = SendDlgItemMessage(hwnd, nIDDlgItem, WM_SETTEXT, 0, outpfile)
 If resu > 0 Then
 lObjhWndBu = FindWindowEx(hwnd, 0, "Button", "&Save")
 If Not lObjhWndBu = 0 Then
 resu = PostMessage(lObjhWndBu, BM_CLICK, 0, 0)
 If Not resu = 0 Then
 Exit Do
 End If
 End If
 End If
 End If
 t999 = DateTime.Now
 If DateDiff(DateInterval.Second, t000, t999) > maximumacrobatwaittime Then
 Exit Sub
 End If
 Loop
 'Adobe Reader eventually will enter inactivity after printing to XPS Document
 ReDim memusage(0)
 Do
 System.Threading.Thread.Sleep(1000)
 ReDim Preserve memusage(UBound(memusage) + 1)
 For Each p In proc
 p.Refresh()
 memusage(UBound(memusage)) = memusage(UBound(memusage)) + p.WorkingSet64
 Next
 If Not UBound(memusage) < memoryusageinactivity Then
 j = 0
 l = memusage(UBound(memusage))
 For i = UBound(memusage) - 1 To UBound(memusage) - memoryusageinactivity + 1 Step -1
 If l = memusage(i) Then j = j + 1
 Next
 Select Case j
 Case memoryusageinactivity - 1
 Exit Do
 Case Else
 End Select
 End If
 Loop
 'Wait for the new XPS Document
 t000 = DateTime.Now
 Do
 System.Threading.Thread.Sleep(1000)
 Select Case My.Computer.FileSystem.FileExists(outpfile)
 Case True
 If Not FileInUse(outpfile) Then Exit Do
 Case Else
 End Select
 t999 = DateTime.Now
 If DateDiff(DateInterval.Second, t000, t999) > acrord32pdftoxpstimelimit Then
 Exit Do
 End If
 Loop
 'Kill Adobe Reader process
 For Each p In proc
 p.Refresh()
 Try
 p.Kill()
 Catch ex As Exception
 End Try
 Next
 'Kill eventual MS Windows error reporting system process
 For Each p In System.Diagnostics.Process.GetProcesses
 If LCase(p.ProcessName) = LCase("WerFault") Then
 If LCase(p.MainWindowTitle) = LCase("Print driver host for 32bit applications") Then
 For Each q In System.Diagnostics.Process.GetProcesses
 If LCase(q.ProcessName) = LCase("splwow64") Then
 Try
 q.Kill()
 Catch ex As Exception
 End Try
 End If
 Next
 Try
 p.Kill()
 Catch ex As Exception
 End Try
 End If
 End If
 Next
 End Sub
End Module

Adobe reader command line search

Hello everyone,
I am opening a PDF file using command line arguments and perform a search.
My command looks like this:
"C:\Program Files (x86)\Adobe\Reader 11.0\Reader\AcroRd32.exe" /A search="word" "C:\File.pdf"
The command is working, but I have the issue that it looks like the search is only performing with option "Match whole words only".
Does anybody know if I can change this option for command line search to get all search results?
Thanks in advance.
Regards,
ajay311

Does anyone have an idea?
Thanks!

Trying SSH CLI , reading command line method is infinte loop problem!

I am trying excute command and reading result. but reading result part has problem.
below source is a part of my method.
try{
               SessionChannelClient sessionChannel = ssh.openSessionChannel();
               sessionChannel.startShell();
               OutputStream out = sessionChannel.getOutputStream();
               String cmd = s + "\n";
               out.write(cmd.getBytes());
               out.flush();
               InputStream in = sessionChannel.getInputStream();
               BufferedReader br = new BufferedReader(new InputStreamReader(in));
               byte buffer[] = new byte[255];
               String read= "";
               while (true) {
                    String line = br.readLine();
                    if (line == null)
                         break;
                    str += line;
                    str += "\n";
               System.out.print(str); //print result
               sessionChannel.close();
               in.close();
               out.close();
          }catch(IOException ee){
               System.out.println(ee);
          }finally{
               System.out.println("=============end cmd=============");
while loop has problem. While statement has infinite loop problem.
why has this problem?
anybody, help me please. Thanks for reading .
Edited by: BreathAir on Aug 5, 2008 12:16 AM

That loop will loop until readLine() returns null, which will only happen when the other end closes its end of the connection, and it will block while no data is available.

What do these Reader command line parms mean?

--channel=4956.0037FA0C.303535326
--type=renderer
/o /eo /l /b /w 984644 /id 1476
TIA, Pete

That did the job!....Thanks so much!!!
seeren wrote:
Those indicate control surfaces. Go into control surface setup to change color or delete those which you may have inadvertantly configured or don't use anymore. Right click on the header to configure header and deselect the box that shows those, if you want.
Message was edited by: Torrid41

Invoke Labview application from Command line

hi,
I have a labview program which does some analysis on my Test data.
My application is that,i have a Test sequencer program(Different application) which collects data and stores it in .dat file.
After this i invoke exe of Labview Analysis program from Test sequencer & i enter the Test data filename as a command line argument.
My first step in analysis program is read command line argument(thru App.Args property) & get filename(the command line gives array output , index 0 will be Labview,index 1 will show filename)
This works absolutely fine.
I made a copy of this analysis prog to include some more functionalities and renamed it as different Labview program(prog structure is same) & trying to do the same abovesaid process.
But somehow im not able to get Command line arg(basically here filename) passed to labview.
The error im getting is that it's showing the path of my application (say if my application is in C)."C:\xxxx.dat is not a LABVIEW data file".
My question is:
Is there any settings changes to be done for Command line args property node when we make a copy from one prog to other prog.? Im not having clue why this should occur?
-Murali

Just to confirm I understand what you are asking... you copied the App.Args property from one vi to another, compiled the new vi to an exe, new exe doesn't receive the command line parameters.
Did you make sure the "Pass all command line arguments to application" check box (in the 'Advanced' category of the application builder) was checked for the new application?
Troy
CLDEach snowflake in an avalanche pleads not guilty. - Stanislaw J. Lec
I haven't failed, I've found 10,000 ways that don't work - Thomas Edison
Beware of the man who won't be bothered with details. - William Feather
The greatest of faults is to be conscious of none. - Thomas Carlyle

Problem with tokenized input from command line

I am trying to take an input from the command line, parse it to tokens and perform whatever operation is needed depending on the name of the token, on a binary tree of stacks for example, if i type 1 2 1 3 printLevelOrder, then the root of the tree should have 3, 2,1 in the stack, the left child should have 1 and the right child should be empty. and then a level order print of the tree should be performed.
however what is happening when i run this code is the numbers are being put into the right stacks of the tree, but any commands such as printLevelOrder or PrintPopRoot are entering the code that is for placing numbers onto the stack instead of executing that command and skipping past this piece of code.
so my question is, why is the if statement if (word =="printLevelOrder") not being executed when thats whats in the word ?
example input and output shown below code fragment.
 try {
 BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
 String line = "";
 while (line != "***") {
 System.out.print("> prompt ");
 line = in.readLine();
 StringTokenizer tokenizer = new StringTokenizer(line," ");
 String word = new String();
 while (tokenizer.hasMoreTokens()) {
 word = tokenizer.nextToken();
 boolean notCommand = true;
 if (word =="printLevelOrder") {
 theTree.printLevelOrder();
 System.out.println("(word ==printLevelOrder)");
 notCommand=false;
 if (word == "printPopLevelOrder") {
 theTree.printPopLevelOrder();
 notCommand=false;
 if (word == "printPopInorder") {
 theTree.printPopInorder();
 notCommand=false;
 if (word == "printPopPreorder") {
 theTree.printPopPreorder();
 notCommand=false;
 if (word == "printPopRoot") {
 theTree.printPopRoot();
 notCommand=false;
 if (word == "***") {
 notCommand=false;
 if (notCommand == true) {
 System.out.println("(notCommand == true)");
 boolean notPlaced = true;
 int v = 1;
 while ((notPlaced==true) && (v < theTree.size())) {
 if (theTree.element(v).isEmpty()) {
 theTree.element(v).push(Integer.valueOf(word));
 System.out.println("Inserting"+word);
 System.out.println("in empty stack at location: "+v);
 notPlaced=false;
 if (notPlaced==true) {
 if ( Integer.valueOf(word) >= Integer.valueOf( theTree.element(v).top().toString() ) ) {
 theTree.element(v).push(Integer.valueOf(word));
 System.out.println("Inserting"+word);
 System.out.println("in stack at location: "+v);
 notPlaced=false;
 v++;
 }valid inputs: int value, printLevelOrder, printPopLevelOrder, printPopInorder, p
rintPopPreorder, printPopRoot, *** to quit
prompt 1 3 2 4 2 printLevelOrder(notCommand == true)
Inserting1
in empty stack at location: 1
(notCommand == true)
Inserting3
in stack at location: 1
(notCommand == true)
Inserting2
in empty stack at location: 2
(notCommand == true)
Inserting4
in stack at location: 1
(notCommand == true)
Inserting2
in stack at location: 2
(notCommand == true)
Exception in thread "main" java.lang.NumberFormatException: For input string: "printLevelOrder"
at java.lang.NumberFormatException.forInputString(NumberFormatException.java:48)
at java.lang.Integer.parseInt(Integer.java:447)
at java.lang.Integer.valueOf(Integer.java:553)
at TreeStack.main(TreeStack.java:73)
Press any key to continue . . .

lol aww, shame that you forgot to do that. i had 10 / 10 for mine, and seing as the deadline is now well and trully over,
here is the entire source for anybody who was following the discussion or whatever and wanted to experiment.
additional files needed >
http://users.cs.cf.ac.uk/Paul.Rosin/CM0212/Stack.java
http://users.cs.cf.ac.uk/Paul.Rosin/CM0212/ArrayStack.java
http://users.cs.cf.ac.uk/Paul.Rosin/CM0212/StackEmptyException.java
http://users.cs.cf.ac.uk/Paul.Rosin/CM0212/StackFullException.java
/*TreeStack.java - reads command line input of values and assigns them to stacks in a binary tree and performs
operations on the ADT. valid inputs: <int>, printLevelOrder, printPopLevelOrder,
printPopInorder, printPopPreOrder, printPopRoot. Terminates on invalid input.
Written by George St. Clair.
S/N:0208456 22/11/2005
import java.util.Vector;
import java.io.*;
import java.util.StringTokenizer;
public class TreeStack {
 private final int TREE_CAPACITY = 7 + 1;
 private final int STACK_CAPACITY = 10;
 Vector tree = new Vector(TREE_CAPACITY) ;
 //collect input from command line, add values to stacks at nodes of the teee
 //and perform required operations on the treestack
 public static void main (String [] args) {
 //create a tree of stacks
 TreeStack theTree = new TreeStack ();
 try {
 //collect standard input
 BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
 String line = "";
 while (line != null) {
 System.out.print("");
 line = in.readLine();
 //tokenise input
 StringTokenizer tokenizer = new StringTokenizer(line," ");
 String word = new String();
 while (tokenizer.hasMoreTokens()) {
 //assign word to the token
 word = tokenizer.nextToken();
 boolean notCommand = true;
 //perform operation on treestack depending on what word is
 if (word.equals("printLevelOrder")) {
 System.out.println("printLevelOrder");
 theTree.printLevelOrder();
 notCommand=false;
 if (word.equals("printPopLevelOrder")) {
 System.out.println("printPopLevelOrder");
 theTree.printPopLevelOrder();
 notCommand=false;
 if (word.equals("printPopInorder")) {
 System.out.println("printPopInorder");
 theTree.printPopInorder();
 notCommand=false;
 if (word.equals("printPopPreorder")) {
 System.out.println("printPopPreorder");
 theTree.printPopPreorder();
 notCommand=false;
 if (word.equals("printPopRoot")) {
 System.out.println("printPopRoot");
 theTree.printPopRoot();
 notCommand=false;
 //if word was not a command it must be a number
 if (notCommand == true) {
 boolean notPlaced = true;
 int v = 1;
 //starting at the root, find suitable place for number
 while ((notPlaced==true) && (v < theTree.size())) {
 //if the stack at v is empty, number goes here
 if (theTree.element(v).isEmpty()) {
 theTree.element(v).push(Integer.valueOf(word));
 System.out.println("inserting: "+word);
 System.out.println("in empty stack at location: "+(v-1));
 notPlaced=false;
 //if the stack is not empty
 if (notPlaced==true) {
 //if the value on the top of the stack is smaller than number, number goes onto the stack
 if ( Integer.valueOf(word) > Integer.valueOf( theTree.element(v).top().toString() ) ) {
 theTree.element(v).push(Integer.valueOf(word));
 System.out.println("inserting: "+word);
 System.out.println("in stack at location: "+(v-1));
 notPlaced=false;
 //if that node was no good, check the next one for suitability
 v++;
 catch (Exception e) {
 //occurs when user inputs something that is neither a command, or a number, or upon EOF, or stack is full
 public TreeStack () {
 //create the TreeStack ADT by adding stacks in the vector, note vector 0 is instantiated but not used.
 for (int i = 1;i<=TREE_CAPACITY;i++)
 tree.add(new ArrayStack(STACK_CAPACITY));
 public int size() {
 //return the size of the tree +1 (as 0 is not used)
 return tree.size();
 public ArrayStack element (int v) {
 //return the ArrayStack at v
 return (ArrayStack)tree.get(v);
 public int leftChild (int v ) {
 //return left child of v
 return v*2;
 public int rightChild (int v ) {
 //return the right child of v
 return v*2+1;
 public boolean children (int v ) {
 //search for children of v and return true if one exists
 for (int i =v;i<size();i++) {
 if (i/2==v ) {
 //left child found at i
 return true;
 if ((i-1)/2==v ) {
 //right child found at i
 return true;
 //no children found
 return false;
 public boolean isInternal (int v ) {
 //test whether node v is internal (has children)
 if (children (v)== true) {
 //has children
 return true;
 return false;
 //print the top value in each stack encountered on a level-order traversal of tree
 public void printLevelOrder() {
 //for every node of tree v
 for (int v = 1;v<size();v++) {
 if (!element(v).isEmpty() ) {
 //print the top value in stack v
 System.out.println(" "+element(v).top());
 else {
 //stack at v is empty
 System.out.println(" -");
 //pop off and print the top value in each stack encountered on a level-order traversal of tree
 public void printPopLevelOrder () {
 //pop off and print the top value in stack v
 for (int v = 1;v<size();v++) {
 //for each node of tree v
 if (!element(v).isEmpty() ) {
 //if v isnt empty print the top value in stack v
 System.out.println(" "+element(v).top());
 //pop the top value in the stack at v
 element(v).pop();
 else {
 //stack at v is empty
 System.out.println(" -");
 //pop off and print the top value in each stack encountered on an in-order traversal of tree
 public void printPopInorder () {
 printPopInorder (1);
 public void printPopInorder (int v) {
 boolean isInternal = false;
 if (isInternal (v)) {
 //use a boolean for isInternal to save on running the method twice
 isInternal = true;
 //recursively search left subtree
 printPopInorder (leftChild(v));
 //pop off and print the top value at v
 if (element(v).isEmpty() ) {
 //stack at v is empty
 System.out.println(" -");
 else {
 //if v isnt empty print the top value in stack v then pop
 System.out.println(" "+element(v).top());
 element(v).pop();
 if (isInternal ) {
 //recursively search right subtree
 printPopInorder (rightChild(v));
 //pop off and print the top value in each stack encountered on an pre-order traversal of tree
 public void printPopPreorder() {
 printPopPreorder(1);
 public void printPopPreorder(int v) {
 //pop off and print the top value at v
 if (!element(v).isEmpty() ) {
 //if v isnt empty print the top value in stack v then pop
 System.out.println(" "+element(v).top());
 element(v).pop();
 else {
 //stack at v is empty
 System.out.println(" -");
 if (isInternal (v)) {
 //recursively search left and right subtrees
 printPopPreorder (leftChild(v));
 printPopPreorder (rightChild(v));
 //pop off and print all values from the stack at the root
 public void printPopRoot (){
 //while the root stack has values left
 while (!element(1).isEmpty()) {
 //print, then pop
 System.out.println(" "+element(1).top());
 element(1).pop();
}

Retrieving command line parameters

How I can retrieve the command line parameters generated by following JSP?
<HTML>
<Head>
<Title> Reading command line parameters </title>
</head>
<Body>
<H1> Press here to try the test command line string</H1>
</body>
</html>
Zulfi

hi,
ur url should have a name/value pair
something like this
thread.jsp?forum=45&thread=279067
and then get these values from request object.
vasanth

Question about reading a string or integer at the command line.

Now I know java doesn't have something like scanf/readln buillt into it, but I was wondering what's the easiest, and what's the most robust way to add this functionality? (This may require two separate answers, sorry).
The reason I ask is because I've been learning java via self study for the SCJA, and last night was the first time I ever attempted to do this and it was just hellish. I was trying to make a simple guessing game at the command line, I didn't realize there wasn't a command read keyboard input.
After fighting with the code for an hour trying to figure it out, I finally got it to read the line via a buffered reader and InputStreamReader(System.in), and ran a try block that threw an exception. Then I just used parseInt to get the integer value for the guess.
Another question: To take command line input, do you have to throw an exception? And is there an easier way to make this work? It seems awfully complicated to take user input without a jframe and calling swing.
Edited by: JGannon on Nov 1, 2007 2:09 PM

1. Does scanner still work in JDK1.6?Try it and see. (Hint: the 1.6 documentation for the class says "Since: 1.5")
If you get behaviour that doesn't fit with what you expect it to do, post your code and a description of our expectations.
2. Are scanner and console essentially the same thing?No.
Scanner is a class that provides methods to break up its input into pieces and return them as strings and primitive values. The input can be a variety of things: File InputStream, String etc (see the Scanner constructor documentation). The emphasis is on the scanning methods, not the input source.
Console, on the other hand, is for working with ... the console. What the "console" is (and whether it is anything) depends on the JVM. It doesn't provide a lot of functionality (although the "masked" password input can't be obtained easily any other way). In terms of your task it will provide a reader associated with the console from which you can create a BufferedReader and proceed as you are at the moment. The emphasis with this class is the particular input source (and output destination), not the scanning.
http://java.sun.com/javase/6/docs/api/java/util/Scanner.html
http://java.sun.com/javase/6/docs/api/java/io/Console.html

We are trying to implement a process so that any document that needs to be printed through our Java application will be printed as PDF using Adobe Reader. For which, We created and execute the below command line to call Adobe Reader and print the PDF on a

We are trying to implement a process so that any document that needs to be printed through our Java application will be printed as PDF using Adobe Reader. For which, We created and execute the below command line to call Adobe Reader and print the PDF on a printer."C:\Program Files (x86)\Adobe\Reader 11.0\Reader\AcroRd32.exe" /T "\\<Application Server>\Report\<TEST.PDF>" "<Printer Name>". Current Situation: The above command line parameter when executed is working as expected in a User's Workspace. When executed in a command line on the Application Server is working as expected. But, the same is not working while executing it from Deployed environment.Software being used: 1. Adobe 11.0 enterprise version. 2. Webshpere Application Server 8.5.5.2. Please let us know if there is a way to enable trace logs in Adobe Reader to further diagnose this issue.

This is the Acrobat.com forum. Your question will have a much better chance being addressed in the Acrobat SDK forum.

Adobe Reader 11 (XI) won't open file via command line

Hello,
I have posted this question to probably inapropriate topic earlier today, so I am repeating it again.
I installed newest Adobe Reader XI today and when I tried to open certain pdf file via command line, it reported a syntax error. Now, this syntax worked so far on versions 9 and 10 (I checked today with them and it is working), so my question is - where can I find new syntax, if there is any? Googling didn't help. Or what else could wrong?
In previous versions I was able to open pdf file (on page 5) like this (all was taken from Help file "Open parameters")
"CompletePathToAdobeReader"/A"page=5""CompletePathToPDF",
ie
"C:\Program Files (x86)\Adobe\Reader 11.0\Reader\AcroRd32.exe"/A"page=5""d:\V2\DataSheet.pdf"
but now - not that it doesn't open specific page, but it doesn't want to open file at all.
edit:
Operating systems running: Windows 7, Windows XP
Thank you.
Message was edited by: v604

Yes, it reported correctly becuase there is a syntax error in your command. Try spaces between the /A switch and open parameter. Try this:
"C:\Program Files (x86)\Adobe\Reader 11.0\Reader\AcroRd32.exe" /A "page=5" "d:\V2\DataSheet.pdf"
Hope this helps.
-Sumit

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