Reading Java files from a EAR file

I want to read all Java files from a EAR file and from inner (inside EAR) EAR or WAR file with out unpacking.
suppose "Demo.ear" contaions the following files:
abc.java
programs / a.java
programs / b.java
src / index.java
src / com / myFolder / main.java
src.war
and suppose "src.war" again contains some java files inside differenet folders.
The main problem is that i can read all java files from "Demo.ear" but unable to reading from "src.war" b'coz my program is using JarFile class constructor which needs a archive file path, So only top level archive having the path but not the inner archives.
So, pls help me out to this problems
Thanks in advance

Maybe you can use java.util.zip.ZipInputStream to
open the Ear and recursively to open the files in
it; I'm not sure whether this will result in a full
unpacking of the file in some temporary directory,
though.
Please let me know if it worked the way you wanted,
I'm curious about it.This jerk just created the third thread about the same topic, because he didn't understand your suggestion, which I already provided earlier.
http://forum.java.sun.com/thread.jspa?threadID=790015

Similar Messages

  • Java files from a EAR file and from inner (inside EAR)

    I want to read all Java files from a EAR file and from inner (inside EAR) EAR or WAR file with out unpacking.
    suppose "Demo.ear" contaions the following files:
    abc.java
    programs / a.java
    programs / b.java
    src / index.java
    src / com / myFolder / main.java
    src.war
    and suppose "src.war" again contains some java files inside differenet folders.
    The main problem is that i can read all java files from "Demo.ear" but unable to reading from "src.war" b'coz my program is using JarFile class constructor which needs a archive file path, So only top level archive having the path but not the inner archives.
    So, pls help me out to this problems
    Thanks in advance

    Firstly Sorry to writing long letter. but i was unable to express my problem.
    see my code==============================
    JarFile jarFile = new JarFile("Demo.ear");
    Enumeration e=jarFile.entries();
    while (e.hasMoreElements())
    JarEntry entry=(JarEntry)e.nextElement();
    if (entry.getName().endsWith(".war"))
    // Then what Next to do...........
    ===========================================
    you have mentioned "theFile" , What is this?...............
    InputStream in = theFile.getInputStream(theEntryOfTheWAR);
    This line is not a compatible type casting in Java..........
    ZipOutputStream theWar = new ZipInputStream(in);

  • Java files from a EAR file

    I want to read all Java files from a EAR file and from inner (inside EAR) EAR or WAR file with out unpacking.
    suppose "Demo.ear" contaions the following files:
    abc.java
    programs / a.java
    programs / b.java
    src / index.java
    src / com / myFolder / main.java
    src.war
    and suppose "src.war" again contains some java files inside differenet folders.
    The main problem is that i can read all java files from "Demo.ear" but unable to reading from "src.war" b'coz my program is using JarFile class constructor which needs a archive file path, So only top level archive having the path but not the inner archives.
    So, pls help me out to this problems
    Thanks in advance

    please help me
    I am waiting for ur response
    thanking you

  • How to read some lines from a text file using java.

    hi,
    i m new to java and i want to read some lines from a text file based on some string occurrence in the file. This file to be read in steps.
    we only want to read the file upto the first Occurrence of "TEXT" string.
    How to do it ,,,
    Kinldy give the code
    Regards,
    Sagar
    this is the text file
    dfgjdjj
    sfjhjkd
    ghjkdg
    hjkdgh TEXT
    ikeyt
    ujt
    jk
    tyk TEXT
    rukl
    r

    Hendawy wrote:
    Since the word "TEXT" is formed of 4 letters, you would read the text file 4 bytes by four bytes. Wrong on two counts. First, the file may not be encoded 1 byte per character. It could be utf-16 in which case it would be two byte per character. Second, even if it were 1 byte per character, the string "Text" may not start on a 4 byte boundary.
    Consider a FileInputStream object "fis" that points to your text file. use fis.read(byte[] array, int offset, int len) to read every four bytes. Convert the "TEXT" String into a byte array "TEXT".getBytes(), and yous the Arrays class to compare the equality of the read bytes with your "TEXT".getBytes()Wrong since it relies on my second point and will fail when fis.read(byte[] array, int offset, int len) does not read 4 bytes (as is no guaranteed to). Check the Javadoc. Also, the file may not be encoded with the default character encoding.
    The problem is easily solved by reading a line at a time using a BufferedReader wrapping an InputStreamReader wrapping a FileInputStream and specifying the correct character encoding.
    Edited by: sabre150 on Apr 29, 2009 2:13 PM

  • Reading Each String From a text File

    Hello everyone...,
    I've a doubt in File...cos am not aware of File.....Could anyone
    plz tell me how do i read each String from a text file and store those Strings in each File...For example if a file contains "Java Tchnology forums, File handling in Java"...
    The output should be like this... Each file should contains each String....i.e..., Java-File1,Technology-File2...and so on....Plz anyone help me

    The Java� Tutorials > Essential Classes: Basic I/O

  • Populate a table reading the data from a TXT file

    how can I populate a table reading the data from a TXT file?
    thanks

    Hey Kevin!
    Using FORMS.TEXT_IO to bulk load data from a file strikes me as re-inventing the wheel. It is just about justifiable in a self-service environment, but I regard the EXTERNAL TABLE is a better solution for that situation as well.
    The same applies to UTL_FILE. I think the ability to read text with UTL_FILE is primarily intended for read file-based configuration or file manipulation/processing rather than data loading.
    Re-writing a text file into SQL statements is too much like hard work (even with an editor that supports macro definition and regular expressions) for no real benefit. You lose all the bulk load peformance you would get from SQL*Loader. But for QAD I'd probably let you off with it.
    You missed out one obvious alternative: using Java to turn the contents of an XML file into a CLOB and inserting it into a table which is read by a PL/SQL procedure that parses the XML records and insert the retrieved data into a table.
    Stay lucky, APC

  • How to read every line from a text file???

    How can i read every line from my text file ("eka.txt")
    now it only reads the first line and prints it out.
    What is wrong with this?
    import java.io.*;
    import java.util.*;
    class Testi{
         public static void main(String []args)throws IOException {
         BufferedReader stdin=new BufferedReader(new InputStreamReader(System.in));
    File inputFile = new File ("eka.txt");
    FileReader fis =new FileReader(inputFile);
    BufferedReader bis = new BufferedReader(fis);
    String test=bis.readLine();
    String tmp= "";
    while((bis.readLine().trim() != null)) {
    int spacefound=0;
    int l=test.indexOf(" ");
         for(int i=0;i<test.length();i++){
         char c=test.charAt(i);
         if(c!=' ') tmp+=""+c;
         if(c==' ' && (spacefound<1) && !(tmp.equals(""))){
         tmp+=""+c;
         spacefound++;
         if(tmp.length()==l) {
         System.out.println(tmp);
         tmp="";
         spacefound=0;
         if(tmp.length()<l){
         for(int i=0;i<=(l-tmp.length());i++)
         tmp+=""+' ';
         System.out.println(tmp);

    Try this code, Hope it servers your purpose.
    import java.io.*;
    import java.util.*;
    class Testi {
         public static void main(String []args)throws IOException {
              BufferedReader stdin=new BufferedReader(new InputStreamReader(System.in));
              File inputFile = new File ("Eka.txt");
              FileReader fis =new FileReader(inputFile);
              BufferedReader bis = new BufferedReader(fis);
              String test=bis.readLine();
              while(test != null) {
                   StringTokenizer st = new StringTokenizer(test," ");
                   while(st.hasMoreTokens())
                        System.out.println(st.nextToken());
                   test = bis.readLine();
    }Sudha

  • Reading an xml file from a jar file

    Short question:
    Is it possible to read an xml file from a jar file when the dtd is
    placed inside the jar file? I am using jdom (SAXBuilder) and the default
    sax parser which comes with it.
    Long Question:
    I am trying to create an enterprise archive file on Weblogic 6.1. We
    have a framework that is similar to the struts framework which uses it's
    own configuration files
    I could place the dtd files outside the jar ear file and specify the
    absolute path in an environment variable in web.xml which is
    configurable through the admin console.
    But I want to avoid this step and specify a relative path within the jar
    file.
    I have tried to use a class which implements the entityresolver as well
    as try to extend the saxparser and set the entity resolver within this
    class explicitly, but I always seem to sun into problems like:
    The setEntityresolver method does not get called or there is a
    classloader problem. i.e. JDOM complains that it cannot load My custom
    parser which is part of the application
    Vijay

    Please contact the main BEA Support team [email protected]
    They will need to check with product support to determine
    the interoperatablity of Weblogic Server with these other
    products.

  • Reading a Compressed File from a ZIP File, which is an entry of ZIP File

    Hello, Experts,
    Would it be possible somebody to help me with code example for the following problem?
    I want to read a compressed file from a ZIP file, which is an entry of ZIP File, without extacting/writing files on file system. Is this possible?
    Lets say we have a ZipFile1. There is ZipFile2 inside ZipFile1. And inside ZipFile2 is FileA. The scenario is reading FileA without extracting on file system.
    Thank you in advance for your help.
    Cheers
    RADY

    The classes you want to be using are java.util.zip.ZipInputStream and and ZipEntry from the same package. Construct the ZipInputStream with the input you have for the outer zip. Loop with ZipInputStream.getNextEntry until you find the inner zip you're looking for - that method returns a ZipEntry, and you get the name of the zip entry with ZipEntry.getName. Read the ZipInputStream from that point into some buffer, and read that buffer into a new ZipInputStream - rinse and repeat until you have the contents of the file in the zip in the zip...

  • Reading rule sets from an XML file

    Hi all,
    How can I read rule sets from an XML file? I have been given some rules in XML
    format and using those I have to query some content. I am using WLP4.0
    Also how can I code rules in java?
    Thanks in advance.

    You can have the following classes:
    Players class deriving from Vector (or containing a vector), and then
    Player class with attribute 'name'.
    class Players
               Vector myVector = new Vector();
                void addPlayer(Player p)
                      myVector.add(p);
                Player getPlayer(int index)
                      myVector.get(index);
    class Player
             private String myName = null;
             Player(String name)
                    this.myName = name;
             String getName()
                    return myName;
    }Then while handling the SAX events you can do the following:
    class MySAXHandler implements ContentHandler (or whatever the itnerface is)
                 public void startElement(String name,....)
                          Players p = null;
                          if(name.equals("Players"))
                                 p = new Players();
                         else if (name.equals("Name"))
                                p.add(new Player(value));
    }HTH,
    Kalyan.

  • Extracting file from a TAR file with java.util.zip.* classes

    Is there a way to extract files from a .TAR file using the java.util.zip.* classes?
    I tried in some ways but I get the following error:
    java.util.zip.ZipException: error in opening zip file
    at java.util.zip.ZipFile.<init>(ZipFile.java127)
    at java.util.zip.ZipFile.<init>(ZipFile.java92)
    Thank you
    Giuseppe

    download the tar.jar from the above link and use the sample program below
    import com.ice.tar.*;
    import java.util.zip.GZIPInputStream;
    import java.io.*;
    public class untarFiles
         public static void main(String args[]){
              try{
              untar("c:/split/20040826172459.tar.gz",new File("c:/split/"));
              }catch(Exception e){
                   e.printStackTrace();
                   System.out.println(e.getMessage());
         private static void untar(String tarFileName, File dest)throws IOException{
              //assuming the file you pass in is not a dir
              dest.mkdir();     
              //create tar input stream from a .tar.gz file
              TarInputStream tin = new TarInputStream( new GZIPInputStream( new FileInputStream(new File(tarFileName))));
              //get the first entry in the archive
              TarEntry tarEntry = tin.getNextEntry();
              while (tarEntry != null){//create a file with the same name as the tarEntry  
                   File destPath = new File(
                   dest.toString() + File.separatorChar + tarEntry.getName());
                   if(tarEntry.isDirectory()){   
                        destPath.mkdir();
                   }else {          
                        FileOutputStream fout = new FileOutputStream(destPath);
                        tin.copyEntryContents(fout);
                        fout.close();
                   tarEntry = tin.getNextEntry();
              tin.close();
    }

  • How do I get the java code from a class file ?

    I want to know how to findout the java code from a .class file . Is there any utility or any way to get the java code from a .class file. If so , please let me know the step by step procedure .
    Thanks
    Shiva

    Check out Mocha (http://www.brouhaha.com/~eric/computers/mocha.html)
    It's free!

  • Retrieve the jdev project from the ear file

    I have an ear file, but I've lost the original jdev project.
    How can I retrieve the project from the ear file?
    I would know if there's a function in jdev or with another tool to convert an ear file to the original project in jdeveloper.
    Thanks.

    Try the File->Import menu option.

  • I have a VI and an attched .txt data file. Now I want to read the data from the .txt file and display it as an array in the front panel. But the result is not right. Any help?

    I have a VI and an attched .txt data file. Now I want to read the data from the .txt file and display it as an array in the front panel. But the result is not right. Any help?
    Attachments:
    try2.txt ‏2 KB
    read_array.vi ‏21 KB

    The problem is in the delimiters in your text file. By default, Read From Spreadsheet File.vi expects a tab delimited file. You can specify a delimiter (like a space), but Read From Spreadsheet File.vi has a problem with repeated delimiters: if you specify a single space as a delimiter and Read From Spreadsheet File.vi finds two spaces back-to-back, it stops reading that line. Your file (as I got it from your earlier post) is delimited by 4 spaces.
    Here are some of your choices to fix your problem.
    1. Change the source file to a tab delimited file. Your VI will then run as is.
    2. Change the source file to be delimited by a single space (rather than 4), then wire a string constant containing one space to the delimiter input of Read From Spreadsheet File.vi.
    3. Wire a string constant containing 4 spaces to the delimiter input of Read From Spreadsheet File.vi. Then your text file will run as is.
    Depending on where your text file comes from (see more comments below), I'd vote for choice 1: a tab delimited text file. It's the most common text output of spreadsheet programs.
    Comments for choices 1 and 2: Where does the text file come from? Is it automatically generated or manually generated? Will it be generated multiple times or just once? If it's manually generated or generated just once, you can use any text editor to change 4 spaces to a tab or to a single space. Note: if you want to change it to a tab delimited file, you can't enter a tab directly into a box in the search & replace dialog of many programs like notepad, but you can do a cut and paste. Before you start your search and replace (just in the text window of the editor), press tab. A tab character will be entered. Press Shift-LeftArrow (not Backspace) to highlight the tab character. Press Ctrl-X to cut the tab character. Start your search and replace (Ctrl-H in notepad in Windows 2000). Click into the Find What box. Enter four spaces. Click into the Replace With box. Press Ctrl-V to paste the tab character. And another thing: older versions of notepad don't have search and replace. Use any editor or word processor that does.

  • Reading one line from a text file into an array

    i want to read one line from a text file into an array, and then the next line into a different array. both arays are type string...i have this:
    public static void readAndProcessData(FileInputStream stream){
         InputStreamReader iStrReader = new InputStreamReader (stream);
         BufferedReader reader = new BufferedReader (iStrReader);
         String line = "";          
         try{
         int i = 0;
              while (line != null){                 
                   names[i] = reader.readLine();
                   score[i] = reader.readLine();
                   line = reader.readLine();
                   i++;                
              }catch (IOException e){
              System.out.println("Error in file access");
    this section calls it:
    try{                         
         FileInputStream stream = new FileInputStream("ISU.txt");
              HighScore.readAndProcessData(stream);
              stream.close();
              names = HighScore.getNames();
              scores = HighScore.getScores();
         }catch(IOException e){
              System.out.println("Error in accessing file." + e.toString());
    it gives me an array index out of bounds error

    oh wait I see it when I looked at the original quote.
    They array you made called names or the other one is prob too small for the amount of names that you have in the file. Hence as I increases it eventually goes out of bounds of the array so you should probably resize the array if that happens.

Maybe you are looking for

  • Usage of Checkboxes in RTF templates

    Hi Tim, I see that we can use checkboxes with XMLP 5.5 onwards, but i don't see any documentation/example on this in the user guide. Can you please explain me how can i make a checkbox which has the following values in the Checkbox-form-field text op

  • Error while using a cursor on select

    Hello, I am using a cursor for a select statement below is the code.   OPEN CURSOR g_cursor FOR     SELECT bkpf~blart            bkpf~budat            bkpf~usnam            bsegc~bukrs            bsegc~belnr            bsegc~rfzei            bsegc~ku

  • BT is blocking specific traffic - Connection probl...

    I started having this problem about two weeks ago, after multiple phonecalls to BT and a couple of emails nothing has been done, so hopefully someone on the forum can help. The problem is the BT server that my hub connects to runs software to block s

  • Movie downloaded off of iTunes not authorized

    I downloaded o movie off of iTunes and when I go to watch it it says cannot open content because it's not authorized, what should I do?!

  • Problem during hierarchy load from ECC 6.0 to BW

    Hello, I encountered a problem during hierarchy loads from ECC to BW: I get the following in BW: Error when updating Idocs in Source System Diagnosis Errors have been reported in Source System during IDoc update: Once I go into ERP and look at the ID