Regarding a query that gives a count of a certain combination of characters

Hi all,
I had a query to be created that gives a count of a certain combination of characteristics from a cube.
Say a cube has 4 characteristics , Say A, B, C, D.
Now amongst all the records that occured in the Cube I need a report of the following A, B and be able to see the count of the number of times a combination of A B occured i.e. variations of C and D for a certain A and B.
For example say in the cube the A B C D has the following contents
a1,b1,c1,d1
a1,b1,c1,d2
a1,b1,c1,d3
a1,b1,c2,d1
a1,b2,c1,d1
a1,b2,c1,d2
a1,b2,c2,d1
a1,b2,c2,d2
a2,b1,c1,d1.
the report should show
a1,b1,4 ,where 4 is the number of combination of a1 & b1.
a1,b2,4 ,where 4 is the number of combination of a1 & b2.
a2,b1,1 ,where 1 is the number of combination of a2 & b1.
i want a help from all regarding this query.
Thanking you in advance

If you are in BW 3.5 or SEM I'd do this with a BPS-Exit that fills a key figure 'Combination Count' with 1 for each combination. If you need any details programming a BPS exit function feel free to ask.
If you are in BW 3.0 or 3.1 without BPS-functions or you don't want to do BPS-setup just to create a user exit I'd suggest the following.
1. Create an ODS CCOUNT that contains A,B,C,D and a key figure COUNT.
2. Create an export data source for your cube.
3. Create uodate rules from your cube to the ODS and set the key figure to constant 1 (with overwrite).
4. Load your cube data into the ODS object.
5. Load the ODS values back into the cube.
This could lead to problems if you have other InfoObjects in your cube like time or version where you want to filter.
Final method would be a virtual key figure but I'd try it this way first.
B est regards
Dirk

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Garth Jones | My blogs: Enhansoft and
Old Blog site | Twitter:
@GarthMJ

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Since I don't know how to explain this easily, I'm using the
table below as an example.
I want to create a MySQL query that will return only records
that have matching counter-parts where 'col1' = 'ABC'.
Notice the 'ABC / GHI' record does not have a
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returned because there is no matching counter-part. With this
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the query.
How can I create a query that will do this?
id | col1 | col2
1 | ABC | DEF
2 | DEF | ABC
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*Please let me know if you have no idea what I'm trying to
explain.

AngryCloud wrote:
> Since I don't know how to explain this easily, I'm using
the table below as an
> example.
>
> I want to create a MySQL query that will return only
records that have
> matching counter-parts where 'col1' = 'ABC'.
>
> Notice the 'ABC / GHI' record does not have a
counter-matching 'GHI / ABC'
> record. This record should not be returned because there
is no matching
> counter-part. With this table, the 'ABC / GHI' record
should be the only one
> returned in the query.
>
> How can I create a query that will do this?
>
>
> id | col1 | col2
> --------------------
> 1 | ABC | DEF
> 2 | DEF | ABC
> 3 | ABC | GHI
> 4 | DEF | GHI
> 5 | GHI | DEF
>
>
> *Please let me know if you have no idea what I'm trying
to explain.
>
Please be more clear. You say that 'ABC / GHI' should not be
returned,
and then you say that 'ABC / GHI' should be the only one
returned. Can't
have both...

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Hello buddies:
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For example :
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The Main trouble are :
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Jason

Hi,
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customer     product    quantity   date
cust001       prod001        10       2007.06.06
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the two line items above means one sales record for the customer "cust001".
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Best Regards,
Jason

Reg: sql query that prints all sundays in the year

Hi all,
Please give me sql query that prints all sundays in year. And when ever we execute that query then that will prints the sysdate(that is execution date).
Thanks in Advance,
-prasad.
Edited by: prasad_orcl on Jun 5, 2009 9:13 PM

Hi,
Plz try this and let me know this works or not...
SELECT DATE DATES,TO_CHAR(DATE,'DAY') DAYS FROM FISCAL_CALENDAR
WHERE DATE_YEAR = 2009 AND
DATE BETWEEN TRUNC(SYSDATE,'YEAR') AND
ADD_MONTHS(TRUNC(SYSDATE,'YEAR'),12) -1 AND
TRIM(TO_CHAR(DATE,'DAY')) = 'SUNDAY'
ORDER BY DATE
OUTPUT:
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1/4/2009     SUNDAY
1/11/2009     SUNDAY
1/18/2009     SUNDAY
1/25/2009     SUNDAY
2/1/2009     SUNDAY
2/8/2009     SUNDAY
2/15/2009     SUNDAY
2/22/2009     SUNDAY
3/1/2009     SUNDAY
3/8/2009     SUNDAY
3/15/2009     SUNDAY
3/22/2009     SUNDAY
3/29/2009     SUNDAY
4/5/2009     SUNDAY
4/12/2009     SUNDAY
4/19/2009     SUNDAY
4/26/2009     SUNDAY
5/3/2009     SUNDAY
5/10/2009     SUNDAY
5/17/2009     SUNDAY
5/24/2009     SUNDAY
5/31/2009     SUNDAY
6/7/2009     SUNDAY
6/14/2009     SUNDAY
6/21/2009     SUNDAY
6/28/2009     SUNDAY
7/5/2009     SUNDAY
7/12/2009     SUNDAY
7/19/2009     SUNDAY
7/26/2009     SUNDAY
8/2/2009     SUNDAY
8/9/2009     SUNDAY
8/16/2009     SUNDAY
8/23/2009     SUNDAY
8/30/2009     SUNDAY
9/6/2009     SUNDAY
9/13/2009     SUNDAY
9/20/2009     SUNDAY
9/27/2009     SUNDAY
10/4/2009     SUNDAY
10/11/2009SUNDAY
10/18/2009SUNDAY
10/25/2009SUNDAY
11/1/2009     SUNDAY
11/8/2009     SUNDAY
11/15/2009SUNDAY
11/22/2009SUNDAY
11/29/2009SUNDAY
12/6/2009     SUNDAY
12/13/2009SUNDAY
12/20/2009SUNDAY
12/27/2009SUNDAY
Regards
Thiyag

Query that only returns items that will produce a result

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What this leads to is the ability to select a group of tags for which there are no query results. What I want to do is only show those that will generate results and how many results they'll show. Like this, select "fluency" by itself there are 310 entries
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Once fluency is selected, there are 13 articles that ALSO are tagged by "digital", but none that are tagged by writing:
fluency | digital (12) | writing
I have a table called blogTagLinks, that is just for tying a tag to a blog. It lists a blogID and a tagID. Here is a sample of it for reference:
blogTagLinkID
blogID
tagID
4
2
2
5
2
3
6
2
5
39
1
18
49
1
1
42
1
9
44
1
19
47
5
14
48
1
22
54
16
22
I'm including all my sql, but the spot that I need help with is marked in red below:

<cfquery name="rsAllTags" datasource="">
SELECT tagsID, tagName
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        WHERE tagActive = 'y'
</cfquery>
<cfset allTags = ValueList(rsAllTags.tagsID)>
<cfif isDefined("URL.blogTags")>
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</cfif>

<cfquery name="rsAvailableTags" datasource="">
SELECT tagsID, tagName
        FROM tags
        WHERE tagActive = 'y'
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</cfquery>

<cfif isDefined("SESSION.sb") AND SESSION.sb EQ "tg">
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        FROM tags
        WHERE tagsID <cfif SESSION.blogTags NEQ "">IN(#SESSION.blogTags#)
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</cfif>

<cfquery name="rsBlog" datasource="">
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There might be a single query solution but here's a query that you
will need to run for each tag in the database (cfloop over all the
tags) and will give you the number of blogs that have the selected
tags + the current tag
SELECT Count(*) AS blog_count
FROM (
    SELECT blogID
    FROM blogTagLink
    WHERE tagID IN(<cfqueryparam cfsqltype="cf_sql_integer"
value="#SESSION.blogTags#" list="true">)
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         OR count(tagID) = #ListLen( SESSION.blogTags )# + 1
    ) AS blogs
Mack

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Hello All --
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Thanks!
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Hi Mike ,
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Thanks. There's a few problems though.
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In the previous version, the menu table in table options, there is an option that gives me the option: the Return key moves to next cell. I do not see this option in the new number. can you help me please?

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Hi silvano,
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Regards,
Ian.

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http://www.enhansoft.com/

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hello,
is there any T-code that resets the counts in the storage bins.
As we do our weekly counts it keeps a running total of how many bin are completed and allows us to track the warehouse's progress.
Regards
Goutham

Of cource, very sorry to waste your time,
I didn't even notice LOL
But your question is a easy question so I am sure some one will respond with a good answer for you.
our program name is RLREOLPQ
not sure if the program is custon or just t-code
gl
Edit: may be a bad sign for you, maybe no standard t-code if we had to create a custum one
Edited by: Arakish on Apr 1, 2010 10:32 PM

Regarding a query that gives a count of a certain combination of characters

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