Regexp_like function

Hi ,
I am trying to match a column from another table using regular expressons, following is the query i am using but its not working.
select * from table1 t1, table2 t2 where regexp_like(t1.ind_code,'^'(t2.ind_code))Can someone please suggest how can we achive results.
Thanks

shavetachawla wrote:
Hi ,
I am trying to match a column from another table using regular expressons, following is the query i am using but its not working.
select * from table1 t1, table2 t2 where regexp_like(t1.ind_code,'^'(t2.ind_code))Can someone please suggest how can we achive results.
ThanksYour code has syntax error because you are not concatenating the '^' with t2.ind_code.
The correct syntax is this one:
select * from table1 t1, table2 t2 where regexp_like(t1.ind_code,'^'||t2.ind_code);However in order to see if you are doing things correctly you should post some sample data (CREATE TABLE and INSERT statement).
Please read SQL and PL/SQL FAQ
Regards.
Al

Similar Messages

Function to allow only printable ASCII in data

Hi,
In my CSV upload utility, I've implemented various error checking functions (not a number, not a valid date, not null... etc.), but today I found some strange characters in customer's DB, which was uploaded previously by someone else using sqlldr. Those characters look like small squares from sql developer, so I'm guessing the users had cut-and-paste characters from a different language or special symbols (like the trademark character cut out from Word).
I'd like to make a function or procedure to check for such characters. Basically I want to only include printable characters found only on an English keyboard. Are there any SQL or PL/SQL functions to check for this? Would the regexp_like function be helpful? If so then I'll probably need a reference table that translate between a character and it's chr(x) number for checking.
Many thanks.

Have you tried writing a loop to identify the squares in your character set?
declare
begin
for i in 0...255 loop
dbms_output.put_line(i);
dbms_output.put_line(chr(i));
end loop;
/

Error in Package containing function

Hi, Here is my package that i am getting error - "PLS-00103: Encountered the symbol "=" when expecting one of the following"
create or replace package pre_pkg
is
FUNCTION FUN_DATE (a_date date)
RETURN number;
end pre_pkg;
create or replace package body pre_pkg
is
function FUN_DATE (a_date date)
return number
is
BEGIN
IF REGEXP_LIKE(a_date,'^\d{1}|d{2}/\d{1}|d{2}/\d{4} \d{2}:\d{2}:\d{2}.\d{3}$')
AND (REGEXP_INSTR(a_date,'[AP]M',1)=0
AND LENGTH(a_date) > 11
AND LENGTH(TRUNC(to_char(TO_TIMESTAMP(a_date,'MM/DD/YYYY HH24:MIS.FF'),'YYYY')))=4)
THEN
return := 0;
ELSIF REGEXP_LIKE(a_date,'^\d{1}|d{2}/\d{1}|d{2}/\d{4} \d{2}:\d{2}:\d{2} [AP]M$')
AND (REGEXP_INSTR(a_date,'[AP]M',1) > 0
AND LENGTH(TRUNC(to_char(TO_DATE(a_date,'MM/DD/YYYY HH:MIS AM'),'YYYY')))=4)
THEN
return := 0;
ELSIF REGEXP_LIKE(a_date,'^\d{1}|d{2}/\d{1}|d{2}/\d{4}$')
AND (REGEXP_INSTR(a_date,'[AP]M',1)=0
AND LENGTH(TRIM(a_date)) < 11
AND LENGTH(TRUNC(to_char(TO_DATE(a_date,'MM/DD/YYYY'),'YYYY')))=4)
THEN
return := 0;
ELSE
return := 1;
END IF;
EXCEPTION
WHEN OTHERS THEN
return := 1;
END FUN_DATE;
END pre_pkg;
Can any one help me in this regard. I am using oracle 10g.

Good practice for writing functions it so have a single exit point at the end of the function, rather than embedding return statements throughout it e.g.
create or replace package pre_pkg is
FUNCTION FUN_DATE (a_date date) RETURN number;
end pre_pkg;
create or replace package body pre_pkg is
function FUN_DATE (a_date date) return number is
    v_retval number;
BEGIN
    IF REGEXP_LIKE(a_date,'^\d{1}|d{2}/\d{1}|d{2}/\d{4} \d{2}:\d{2}:\d{2}.\d{3}$')
       AND (REGEXP_INSTR(a_date,'[AP]M',1)=0
       AND LENGTH(a_date) > 11
       AND LENGTH(TRUNC(to_char(TO_TIMESTAMP(a_date,'MM/DD/YYYY HH24:MIS.FF'),'YYYY')))=4)
    THEN
      v_retval := 0;
    ELSIF REGEXP_LIKE(a_date,'^\d{1}|d{2}/\d{1}|d{2}/\d{4} \d{2}:\d{2}:\d{2} [AP]M$')
       AND (REGEXP_INSTR(a_date,'[AP]M',1) > 0
       AND LENGTH(TRUNC(to_char(TO_DATE(a_date,'MM/DD/YYYY HH:MIS AM'),'YYYY')))=4)
    THEN
      v_retval := 0;
    ELSIF REGEXP_LIKE(a_date,'^\d{1}|d{2}/\d{1}|d{2}/\d{4}$')
       AND (REGEXP_INSTR(a_date,'[AP]M',1)=0
       AND LENGTH(TRIM(a_date)) < 11
       AND LENGTH(TRUNC(to_char(TO_DATE(a_date,'MM/DD/YYYY'),'YYYY')))=4)
    THEN
      v_retval := 0;
    ELSE
      v_retval := 1;
    END IF;
    RETURN v_retval;
EXCEPTION
    WHEN OTHERS THEN
      return := 1;
END FUN_DATE;
END pre_pkg;
/Other things to note:
WHEN OTHERS exception is considered poor practice, especially if it doesn't raise an exception itself. Exception handlers should be written to cater for whatever exceptions you are expecting to happen, not a capture-all. Looking at your code, I wouldn't expect it to be raising any exceptions from the code itself.
Curiously, your function seems very odd. It looks like you are trying to validate that a date is valid, but by virtue of the fact that it's a DATE datatype it will (with very few exceptions e.g corrupt dates) be valid. The fact that you pass a DATE datatype as the first parameter of your REGEXP_LIKE functions means that it is doing an implicit conversion of that DATE datatype to a VARCHAR2 datatype based on your sessions NLS_* settings, which could vary and cause your function to fail in other sessions. If the date were actually being passed into the funciton as a string (varchar2) then there are simpler ways to validate whether it's a valid date or not, simply by trying to turn the string into a DATE datatype and capturing the exception for invalid dates.

Query to apply regexp_like for patterns specified in different table

Hi all,
with table trap_store as ( vb clob) and table conf as (patten varchar2(20))
Need to retrieve records from trap_store where data in vb column matches patterns in conf table.
Presently planning to use regexp_like function ie; regexp_like(vb,'Start').
In the above query, have hardcoded the pattern as 'Start'. But, Patterns are present in different conf table. Each row of trap_store table ie; each value of vb column in trap_store table should be matched with all the patterns of conf table.
How to apply all the patterns of conf table ?

It's possible to write a script with a LOOP over the pattern table to generate queries or generate a filter, and then execute it via Dynamic SQL (depends on the pattern table size)

Find a number in a string

Hi all,
I've got a text field in my source table that can contain both numbers and characters, like any normal varchar2. The issue is with a field that should contain insurance numbers, but also thinks "hello world" will do! A change to the application will not help, nor any constraints on database level will do!
I want to determine if a record has any numbers, if it has, than i validate it to ok, if not, so only characters are in the field, than i want to validate it to not ok.
My solution so far is that I use a case statement with a translate, which translates all characters to a zero and leaves numbers untouched. When result is larger than zero it is valid
So 'ABC123 ' would return 0001230 and evaluate to true, even so '0 123 ABC' would translate 001230000 and will also evaluate to true, and ABC will evaluate to false, exactly how I like it to be.
But...the translate function has all charaters that are directly visible on my keyboard, in upper and lower case, and now i bumped into a special character. An E with two dots above (alt 137).
now to prevent me from building a solution that has all the characters in it which I could ever produce in my translate is there any smarter sollution?
Hope you guys (or girls) can help!
Cheers,
Gilles

Gilles,
What you need is a regular expression. Below is a simple example using the Oracle regexp_like function to determine if the function's input has any numeric characters in it, and returns 1 if it does, otherwise it returns 0:
create or replace function find_digit(p_string varchar2) return number is
l_ret boolean;
begin
l_ret := regexp_like(p_string, '[[:digit:]]');
if l_ret then return 1; else return 0; end if;
end;
You should be able to use something like this. you can use the regexp_like function in the WHERE clause of your SQL or wrap it in to a function like this you need it in the SELECT clause (as the return type of regexp_like is boolean which isn't supported in the SELECT clause).
hope this helps,
Borkur

Regular expression fro date time format

Hi
im trying to use regexp_like() function in my where clause as
select 1 from dual where REGEXP_LIKE(''31/12/2003 11:59:59 PM',regular expr pattern)
I tried this pattern using the following regular expresion which i found on a web site. but this didnt work.
'^(?=\d)(?:(?:31(?!.(?:0?[2469]|11))|(?:30|29)(?!.0?2)|29(?=.0?2.(?:(?:(?:1[6-9]|[2-9]\d)?(?:0[48]|[2468][048]|[13579][26])|(?:(?:16|[2468][048]|[3579][26])00)))(?:\x20|$))|(?:2[0-8]|1\d|0?[1-9]))(\/)(?:1[012]|0?[1-9])\1(?:1[6-9]|[2-9]\d)?\d\d(?:(?=\x20\d)\x20|$))?(((0?[1-9]|1[012])(:[0-5]\d){0,2}(\x20[AP]M)?)|([01]\d|2[0-3])(:[0-5]\d){1,2})?$'
can some one suggest me an alternative regular expression for this.
P.S : i donot want to use to_char/ to_date functions.
Regards
Vibhuti

Hi elic
I tried with your suggestion yet it didnt work. This is my query
select 1 from dual where regexp_like('03/02/2000 02:59:59 AM','^(?=[0-9])(?:(?:31(?!.(?:0?[2469]|11))|(?:30|29)(?!.0?2)|29(?=.0?2.(?:(?:(?:1[6-9]|[2-9][0-9])?(?:0[48]|[2468][048]|[13579][26])|(?:(?:16|[2468][048]|[3579][26])00)))(?: |$))|(?:2[0-8]|1[0-9]|0?[1-9]))(\/)(?:1[012]|0?[1-9])\1(?:1[6-9]|[2-9][0-9])?[0-9][0-9](?:(?= [0-9]) |$))?(((0?[1-9]|1[012])(:[0-5][0-9]){0,2}( [AP]M)?)|([01][0-9]|2[0-3])(:[0-5][0-9]){1,2})?$')
this should return 1 as output. but its not returning any thing. Im currently working on 10g R2 database. Please help me out, its very critical. Im trying to learn regualr expressions but im unable to crack this code.
Regards
Vibhuti

String check problem

I have a doozy of a problem on my hands. My company has introduced a password policy that every user must me now. Some of my criteria is that a password must contain at least one symbol and at least one number. In 10g I can use REGEXP_LIKE function, but I am running 9i. I have tried to use translate, OWA_PATTERN function, everthing. How can I take a string variable, and test to see if there is a symbol in the text or a number. I want to be able to return a true/false value?
Please advise?

Like Kamal says, use built-in functionality FIRST.
Failing that, presumably you would write something like this (I forget the exact naming standard for the password verify function).
CREATE FUNCTION valid_password (
   p_password IN VARCHAR2)
   RETURN BOOLEAN
IS
   FUNCTION contains_at_least_one (
      p_string IN VARCHAR2,
      p_characters IN VARCHAR2)
      RETURN BOOLEAN
   IS
   BEGIN
      RETURN LENGTH (TRANSLATE (p_string, 'X' ||
        p_characters, 'X')) < LENGTH (p_string);
   END;
BEGIN
   RETURN contains_at_least_one (p_password, '0123456789')
      AND contains_at_least_one (p_password, '!Â£$%^&*(){}~@??|<>');
END;

Multiple like statements in a query

Hi,
I wonder if it's possible to have multiple like statements in a query.
suppose instead of
select * from someTable where remarks like '%ab%'
I want to search for many string patterns such as '%edi%' '%odi%' '%di%' '%gf%' '%od%' '%podi%' etc. in one query.
BTW, the table contains many millions of records.
Regards
Crusoe
Edited by: Crusoe on 19-Jan-2009 00:25

Crusoe wrote:
This regexp_like function does not work with the development server to which I have rights to create tables etc. I guess it only works in 10g or greater. However i tried a quick test in the production server and it worked. It returned rows where the values between the | characters were found anywhere in the field ( I must learn this regex syntax sometime). Yes, regular expressions are 10g upwards. (You really should have your development server reflect your production server)
There was a thread a while back giving an introduction to regular expressions...
Introduction to regular expressions ...

Locating row with invalid number from table with few million rows

We need to query the a table or a view of same to obtain a id of type VARCHAR with bind value being NUMBER. Any attempts in this regard I try seem to result ORA-01722: invalid number. Once case is below here
SQL> select TEXT_ID FROM ATT_TABLE where to_number(TEXT_ID) = 9411956;
select TEXT_ID FROM ATT_TABLE where to_number(TEXT_ID) = 9411956
ERROR at line 1:
ORA-12801: error signaled in parallel query server P010
ORA-01722: invalid number
1. TEXT_ID column is meant to have numeric values in VARCHAR type. It is possible that some record / row is not complying. How can I locate the non-complying records ?
2. What would be a VIEW definition that would return only records with valid numeric data in TEXT_ID column.
Edited by: bonjonbovi on Feb 13, 2009 3:58 PM

Of course the regexp_like is really cpu expensive, but there's no other solution in your situation
The only way to differ numberic value from character, is REGEXP_LIKE function
But you can do it using PL/SQL
BEGIN
   FOR c IN (SELECT TO_NUMBER (ID) ID
               FROM test_number)
   LOOP
      DBMS_OUTPUT.put_line (c.ID);
   END LOOP;
EXCEPTION
   WHEN OTHERS
   THEN
      NULL;
END;

Regular Expression in SELECT

Purpose : Write a query that will identify patterns in a fiels.
It will recognize that 801 can be written as 80[1,2,3] or [8,9]01 or 80[1:5]
WITH t AS
          SELECT column_value AS col1
               FROM TABLE (SYS.dbms_debug_vc2coll
('80[1,2,3]', '81[1-5]9', '[8,9]01', '80[1:5]')
SELECT * FROM t;
I tried a few different things, but couldn't get the right expression. I am not even sure if I can do this in one statement, because there are multiple ways that the expression in the column could be written in.
Any hel will be great.

In 10g you can use REGEXP_LIKE function, prior to that there are functions in OWA_PATTERN which may be of use
Oracle Database 10g Enterprise Edition Release 10.2.0.2.0 - Production
With the Partitioning, OLAP and Data Mining options
SQL> SELECT b.column_name, a.column_value
2 FROM   TABLE (varchar2_table (
3            '80[1,2,3]', '81[1-5]9', '[8,9]01', '80[1:5]')) a,
4        (SELECT '801' column_name
5         FROM   dual) b
6 WHERE REGEXP_LIKE (b.column_name, a.column_value);
COLUMN_NAME          COLUMN_VALUE
801                  80[1,2,3]
801                  [8,9]01
801                  80[1:5]
SQL>

Validation General Questions

I have a couple of general questions on validation.
1) I have a text field defined as a "Required" field (it is using the form_required template). Must I also create a NOT NULL validation on this field as well? It seems that I should not have to do this. However, if I do not create this NOT NULL validation, then clicking on a Submit button while this field is empty is not generating any error message. But when I include a NOT NULL validation, then I do get an error message.
2) This question is related to the first. I tried creating a regular expression validation on my field in which I use the pattern
[[:alnum:]]{1,}[|$#&_?]+
The field should allow the user to type-in a string consisting of 1 or more alphanumeric characters (it could be a foreign language characters as well)
and 1 or more special characters like $ or #.
I thought this would also generate an error message if the user clicks the Submit button while leaving the field empty. But, again, I get no error message. Why?
Thank you in advance for any insight on this.

Thanks very much, Justin.
When I saw the regexp_like() function in your reply, I am wondering if, perhaps, you might also have some insight into how I can ckeck if a field contains non-English type characters (i.e., mult-byte characters). I already posted a question about this an hour ago but have not gotton any replies as yet. In my post I asked about using the regular expression pattern [[:alnum:]] since the docs state that this will check for mult-byte characters. And so, I thought if perhaps there is some function I might use to return a boolean TRUE if a field contains non-English characters versus a FALSE if it contains only English characters.
Any insight in this would be most appreciated.
Thanks again for your help.

How to create function based index on REGEXP_LIKE funtion

Dear Gurus,
I have below table CDR
Name Null Type
STARTTIME NOT NULL DATE
SUBSCRIBERNUMBER NOT NULL NUMBER
CALLINGNUMBER NOT NULL VARCHAR2(20)
CALLEDNUMBER NOT NULL VARCHAR2(20)
I am regularly firing below query
SELECT count(*)
FROM CDR data
WHERE STARTTIME BETWEEN '01-Jul-2009 00:00:00' and '31-May-2012 23:59:59'
AND REGEXP_LIKE(data.SUBSCRIBERNUMBER, '^98721[0-9]*[5]+[0-9]*$');
since there is REGEXP_LIKE is being used, Can I use function based index to improve performance.
Thanking in advance
Sanjeev

Hi,
you can do it that way :Scott@my11g SQL>create table test (name varchar2(30));
Table created.
Scott@my11g SQL>create index myfbi on test(case when regexp_like(name,'^98721[0-9]*[5]+[0-9]*$') then 1 else 0 end);
Index created.
Scott@my11g SQL>explain plan for
2 select * from test where case when regexp_like(name,'^98721[0-9]*[5]+[0-9]*$') then 1 else 0 end = 1;
Explained.
Scott@my11g SQL>/
PLAN_TABLE_OUTPUT
Plan hash value: 140237472
| Id | Operation                   | Name | Rows | Bytes | Cost (%CPU)| Time     |
|   0 | SELECT STATEMENT            |       |     1 |    20 |     1   (0)| 00:00:01 |
|   1 | TABLE ACCESS BY INDEX ROWID| TEST |     1 |    20 |     1   (0)| 00:00:01 |
|* 2 |   INDEX RANGE SCAN          | MYFBI |     1 |       |     1   (0)| 00:00:01 |
Predicate Information (identified by operation id):
   2 - access(CASE WHEN REGEXP_LIKE ("NAME",'^98721[0-9]*[5]+[0-9]*$')
              THEN 1 ELSE 0 END =1)
Note
   - dynamic sampling used for this statement (level=2)
19 rows selected.

REGEXP_LIKE help with literal single-quote

I'm trying to write a check constraint to validate email addresses that may include an apostrophe in the email address. Such as joe.o'[email protected] Here is my sample setup:
create table emails
( email_address varchar2(150)
insert into emails values('[email protected]') ;
insert into emails values('[email protected]') ;
insert into emails values('joey.o''[email protected]') ;
commit;
sql> select * from emails;
EMAIL_ADDRESS
[email protected]
[email protected]
joey.o'[email protected]
alter table emails add constraint email_address_format_ck
CHECK ( REGEXP_LIKE ( email_address, '^[a-z0-9._%-]\'?+@[a-z0-9._%-]+\.mil$','c'));
ERROR at line 2:
ORA-00911: invalid characterIt doesn't like *\'?*
My understanding is this means one or more single-quotes. Anyone know the correct syntax to accept apostrophes?

Hi,
jimmyb wrote:
... insert into emails values('joey.o''[email protected]') ;
That's the correct way (actually, that's one correct way) to include a single-quote in a string literal: use 2 single-quotes in a row.
... alter table emails add constraint email_address_format_ck
CHECK ( REGEXP_LIKE ( email_address, '^[a-z0-9._%-]\'?+@[a-z0-9._%-]+\.mil$','c'));Here, the 2nd argument to REGEXP_LIKE is a string literal, just like 'joey.o''[email protected]' was a string literal.
To include a single-quote in the middle of this string literal, do the same thing you did before: use 2 of them in a row:
CHECK ( REGEXP_LIKE ( email_address, '^[a-z0-9._%''-]+@[a-z0-9._%-]+\.mil$','c'));There were a couple of other problems, too.
I'm sure you meant for the apostrophe to be inside the square brackets. Inside square brackets, \ does not function as an escape character. (Actually, single-quote has no special meaning in regular expressions, so there's no need to escape it anyway.)
I'm not sure what the '?' mark was doing; I left it out.
Of course, you'll have trouble adding the CHECK constraint if any existing rows violate it.
Edited by: Frank Kulash on Feb 10, 2012 6:52 PM

How to find Unused variables in procedure,function or package

Hi all,
I want find out unused variables in procedure, function and package.
I have written below script for doing this ,but i am not getting the expected result.
Kindly help me to improve the below code ,so that it works as expected.
{code}
version details
Oracle Database 11g Enterprise Edition Release 11.2.0.3.0 - 64bit Production
PL/SQL Release 11.2.0.3.0 - Production
"CORE    11.2.0.3.0    Production"
TNS for Linux: Version 11.2.0.3.0 - Production
NLSRTL Version 11.2.0.3.0 - Production
{code}
{code}
What i Have tried is This.
DECLARE
V_OBJECT_NAME VARCHAR2(30) :='PR_PRINT';
V_OBJECT_TYPE VARCHAR2(30) :='PROCEDURE';
CURSOR C1(CP_OBJECT_NAME VARCHAR2,CP_OBJECT_TYPE VARCHAR2)
IS
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      US.TYPE,
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      REGEXP_SUBSTR(US.TEXT,'.* ') AS var_name
    FROM user_source US
    WHERE name=CP_OBJECT_NAME
    AND type =CP_OBJECT_TYPE
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    AND REGEXP_LIKE (TEXT,'^[^--]') ;
v_count NUMBER ;
BEGIN
FOR i IN C1(V_OBJECT_NAME,V_OBJECT_TYPE)
LOOP
    SELECT COUNT( *)
    INTO V_COUNT
    FROM USER_SOURCE US
    WHERE US.NAME=I.NAME
    AND REGEXP_LIKE(US.TEXT,i.var_name,'i' )
    AND US.LINE<>I.LINE;
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      DBMS_OUTPUT.PUT_LINE('variable '||I.VAR_NAME||'Is declared at line#'||I.LINE||' But no where used');
    END IF ;
END LOOP;
EXCEPTION
WHEN OTHERS THEN
DBMS_OUTPUT.PUT_LINE('p_err_code := '||SQLCODE||dbms_utility.format_Error_backtrace());
DBMS_OUTPUT.PUT_LINE('p_err_msg := '||sqlerrm);
END ;
{code}
Thanks,
P Prakash

Hello,
as suggested by padders you can use PL/Scope, an example:
ALTER SESSION SET PLSCOPE_SETTINGS='IDENTIFIERS:ALL';
CREATE OR REPLACE PACKAGE ui_test1 AS
    global_number   NUMBER := 9;
FUNCTION get_number
    RETURN NUMBER;
END ui_test1;
CREATE OR REPLACE PACKAGE BODY ui_test1 AS
PROCEDURE setNull
     p_varchar          IN OUT VARCHAR2
IS
BEGIN
    p_varchar := NVL(p_varchar,'NULL');
END setNull;
FUNCTION get_number
    RETURN NUMBER
IS
    FUNCTION setZero
         p_number       IN NUMBER
        RETURN NUMBER
    IS
    BEGIN
        RETURN NVL(p_number,0);
    END setZero;
BEGIN
    RETURN global_number;
END get_number;
END ui_test1;
SELECT DISTINCT
        object_name
       ,object_type
       ,name
       ,type
       ,line
       ,col
FROM    all_identifiers obj
WHERE   obj.owner = USER
AND     obj.usage = 'DECLARATION'
AND     obj.object_name = 'UI_TEST1'
AND     NOT EXISTS (
            SELECT 1
            FROM    all_identifiers with_rh
            WHERE   obj.signature = with_rh.signature
            AND     with_rh.usage IN ('REFERENCE','CALL','ASSIGNMENT')
ORDER BY TYPE
        ,object_name
        ,object_type
        ,name;
OBJECT_NAME OBJECT_TYPE   NAME       TYPE       LINE COL
UI_TEST1     PACKAGE       GET_NUMBER FUNCTION     11 10
UI_TEST1     PACKAGE BODY SETZERO    FUNCTION     35 14
UI_TEST1     PACKAGE       UI_TEST1   PACKAGE       1   9
UI_TEST1     PACKAGE BODY SETNULL    PROCEDURE    12 11
Regards
Marcus

Validate PO Box with RegExp_Like

I'm trying to validate strings with variations of PO BOX, P.O. BOX 3232, Post Office Box 2323. The functions is like so:
CREATE or REPLACE FUNCTION FN_CHK_PO_BOX (v_str in VARCHAR2)
RETURN VARCHAR2
AS
BEGIN
   IF REGEXP_LIKE (v_str, '^[p|P][\s]*[o|O][\s]*[b|B][\s]*[o|O][\s]*[x|X][\s]*[a-zA-Z0-9]*|\b[P|p]+(OST|ost|o|O)?\.?\s*[O|o|0]+(ffice|FFICE)?\.?\s*[B|b][O|o|0]?[X|x]+\.?\s+[#]?(\d+)*(\D+)*\b$') THEN
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   ELSE
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   END IF;
END FN_CHK_PO_BOX;
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The patterns depends on how flexible you want to be with the string, take a look at those rows that were left out:
SQL> with t as (
2 select 1 num, 'P.O. BOX 2323' expr from dual union
3 select 2, 'POST OFFICE BOX 2323' from dual union
4 select 3, 'P O BOX 2323' from dual union
5 select 4, 'P O BOX 2323' from dual union
6 select 5, 'PO BOX 2323' from dual union
7 select 6, 'p.o boX 2323' from dual union
8 select 7, 'pO. BoX 2323' from dual union
9 select 8, 'P. OFFICE BOX 2323' from dual union
10 select 9, 'POST O. BOX 2323' from dual union
11 select 10, 'POST OFF. BOX 2323' from dual union
12 select 11, 'P.O OFFICE BOX 2323' from dual union
13 select 12, 'POST OFFICE BOX 2323' from dual union
14 select 13, 'POST OFFICE BOX ' from dual union
15 select 13, 'POST OFFICE BOX ABC' from dual
16 )
17 select expr
18    from t
19 where regexp_like(expr
20        , '^((P\.?\s*O\.?)|(POST\s+OFFICE))\s*B\s*O\s*X\s*\d+$','i')
21 /
EXPR
P.O. BOX 2323
POST OFFICE BOX 2323
P O BOX 2323
P O BOX 2323
PO BOX 2323
p.o boX 2323
pO. BoX 2323
POST OFFICE BOX 2323
8 rows selected
SQL>

Regexp_like function

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