Regexp_replace, but not enclosed in quotas

select regexp_replace(q'#Can I use 'ORACLE :regular :expressions' to replace all :words starting with a :colon with an :asterisk but only if they are not enclosed in 'single quotas'?#',':\w+','*') txt from dual;
TXT
Can I use 'ORACLE * *' to replace all * starting with a * with an * but only if they are not included in 'single quotas'?the simple code above replaces too much for my purpose. Is it possible to modify the regular expression in a way that it ignores the words ':regular' and ':expressions' because they are in a part of the text enclosed in quotas?
By the way: When I run this query in SQL*Developer I get a strange error message:
SQL-Fehler: Fehlender IN- oder OUT-Parameter auf Index:: 1 (something like SQL-Error: missing IN or OUT parameter on index::1)but when I run it in SQL*Plus it works as expected. Has someone here an explantion for this message or should I start a new thread in the SQL*Developer forum?

No, expected output is this:
Can I use 'ORACLE :regular :expressions' to replace all * starting with a * with an * but only if they are not included in 'single quotas'?the first two words with a colon should not be replaced, because they are between the single quotas.

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