Regular Expression to capture user's input string

Question

I am writing a helper class to split user input string into String array according to the following pattern:
import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class TestDelimiter {
static Pattern p = Pattern.compile("(.*?)[,;]{1}");
static Matcher m;
    public static void main(String[] args) {
        String input = "AAA111111,BBB222222;CCC333333";
        m = p.matcher(input);
        while(m.find()){
            String output = m.group(1);
            System.out.println(output);
}Output:
AAA111111
BBB222222My question is, how can I modify the regular expression string so that the CCC333333 (last element) can also be included?

Answer 1

roamer wrote:
Ok, let's don't argue on this point.Who's arguing?
I think I got the answer. For simplicity, I can just manually add a ";" or "," string after each user input. Just like:You never said anything about that before. You asked how to split "AAA111,BBB222;CCC333" into its components and you were given a correct answer.
Maybe you should rephrase your question including this added requirement. Do you need to have the separator included in the final outputs or why do you want to suddenly add things to user input?