Remove regular expression from a string

Hello,
I have a string like this
@1test;'"{input+
Please help me to remove special characters from the string.

A: remove regular expression from a string

Hi Krishna,
DATA : str TYPE STRING VALUE '@1test;"{}]input+',
            char,
            length TYPE i,
            index TYPE i.
length = STRLEN( str ).
WHILE length > index.
char = str+index(1).
WRITE char.
if char CA '+-*/!`@#$%^&()_=[]{};'.               " Add/Remove here to include numbers
    REPLACE ALL OCCURRENCES OF char in str WITH ''.
    REPLACE ALL OCCURRENCES OF '"' in str WITH ''. " characters "{}[] are not comparable
    REPLACE ALL OCCURRENCES OF '{' in str WITH ''.
    REPLACE ALL OCCURRENCES OF '}' in str WITH ''.
    REPLACE ALL OCCURRENCES OF '[' in str WITH ''.
    REPLACE ALL OCCURRENCES OF ']' in str WITH ''.
    length = STRLEN( str ).
    ENDIF.
add 1 to index.
ENDWHILE.
WRITE str.
Add or remove special char from '+-*/!`@#$%^&()_=[]{};' in if part as per your requirement.
Hope it meets your requirement.
Do not forget to mark helpful/correct if ma answer is useful .
Thanks,
Karthik

Similar Messages

Remove HTML tags from a string

I have a string that contains a couple of HTML or XHTML tag, for example
lv_my_string = 'Hello World!'.
For a special use case, I want to remove all HTML from that string and process only the plain text
lv_my_new_string = 'Hello World!'.
Is there any method, function module, XSLT or anything else for that already?

Hi Daniel,
I tried using the FM (SWA_STRING_REMOVE_SUBSTRING) but I guess it is expecting a particular pattern which is not so apparent in your case. Iu2019ve written a small piece of code which you can try using in a FM or a PERFORM and that should do the trick. Please let me know if you have any questions.
PARAMETER: P_LINE(100).
TYPES: BEGIN OF TY_LINE,
 LINE(100),
 END OF TY_LINE.
DATA: T_LINE TYPE STANDARD TABLE OF TY_LINE,
 WA_LINE LIKE LINE OF T_LINE.
DATA: W_LINE(100),
 W_LEN(100),
 W_COUNT TYPE I,
 W_FLAG,
 W_FLAG1,
 W_I TYPE I.
W_COUNT = STRLEN( P_LINE ).
DO W_COUNT TIMES.
IF P_LINE+W_I(1) = '<'.
 W_FLAG = 1.
 W_I = W_I + 1.
 IF NOT WA_LINE-LINE IS INITIAL.
 APPEND WA_LINE-LINE TO T_LINE.
 CLEAR WA_LINE.
 ENDIF.
 CONTINUE.
ELSEIF P_LINE+W_I(1) = '>'.
 W_FLAG = 0.
 W_I = W_I + 1.
 CONTINUE.
ENDIF.
IF W_FLAG = 1.
 W_I = W_I + 1.
 CONTINUE.
ELSE.
 CONCATENATE WA_LINE-LINE P_LINE+W_I(1) INTO WA_LINE-LINE.
 W_I = W_I + 1.
ENDIF.
ENDDO.
LOOP AT T_LINE INTO WA_LINE.
CONCATENATE W_LINE WA_LINE-LINE INTO W_LINE SEPARATED BY SPACE.
ENDLOOP.
SHIFT W_LINE LEFT DELETING LEADING SPACE.
WRITE: W_LINE.
Input:
Hello World!
Output:
HELLO WORLD !
Regards,
Pritam

How to remove HTML tags from a String ?

Hello,
How can I remove all HTML Tags from a String ?
Would you please to give me a simple example ?
Best regards,
Eric

Here's some code I cooked up. I have created an object that processes code so that it can be incorporated directly into a project. There is some redundancy so that the it can be used in more than one way. Depending on your situation you might have to make the condition statement a little more sophisticated to catch stray ">" tags.
I have also included a Tester application.
//This removes Html tags from a String either by submitting the String during construction and then
// calling getProcessedString() or
// by simply calling " stringwithoutTags=removeHtmlTags(stringWithTagsSubmission); "
//Note: This code assumes that all"<" tags are accompanied by a ">" tag in the proper order.
public class HtmlTagRemover
 private String stringSubmission,processedString,stringBeingProcessed;
 private int indexOfTagStart,indexOfTagEnd;
 public HtmlTagRemover()
 public HtmlTagRemover(String s)
 removeHtmlTags(s);
 public String removeHtmlTags(String s)
 stringSubmission=s;
 stringBeingProcessed=stringSubmission;
 removeNextTag();
 return processedString;
 private void removeNextTag()
 checkForNextTag();
 while((!(indexOfTagStart==-1||indexOfTagEnd==-1))&<indexOfTagEnd)
 removeTag();
 checkForNextTag();
 processedString=stringBeingProcessed;
 private void checkForNextTag()
 indexOfTagStart=stringBeingProcessed.indexOf("<");
 indexOfTagEnd=stringBeingProcessed.indexOf(">");
 private void removeTag()
 StringBuffer sb=new StringBuffer("");
 sb.append(stringBeingProcessed);
 sb.delete(indexOfTagStart,indexOfTagEnd+1);
 stringBeingProcessed=sb.toString();
 public String getProcessedString()
 return processedString;
 public String getLastStringSubmission()
 return stringSubmission;
public class HtmlRemovalTester
 static void main(String[] args)
 String output;
 HtmlTagRemover h=new HtmlTagRemover();
 output="The processed String: "+h.removeHtmlTags("<Html tag>This is a test<another Html tag> string<yet another Html tag>.");
 output=output+"\n"+" The original string:"+h.getLastStringSubmission();
 System.out.print(output);

Removing leading zeros from a string value

Hi All,
i have a Requirement like , i need remove leading zeros from a string value,
like , 00Raj00Shekar==>Raj00shekar,
how can i do this ?
if it is only with the custom functions ,where can add the fuction in Jdeveloper and SOA Middle ware?
Thanks in Advance,
Raj

Hi Raj,
you can use below function to get the desired output in xsl.
<xsl:value-of select='translate(oraext:left-trim(translate(<inpString>,"0"," "))," ","0")'/>
HTH,
Regards,
Vikas Manchanda

Regular expression - splitting a string

I have a long string that I'm trying to split into a series of substrings. I would like each of the substrings to start with "TTL.. I'm fairly certain that I'm missing something very basic here. I've attached my code which yield NO GROUPS. I didn't see another method for returning the text that the regular expression matched.
String finalLongstring="TTL1,clip1+TTL2+clip3,TTL4,clip4,TTL5,clip5+TTL6+"+
 "clip6+TTL7+clip7,TTL8,clip8,TTL9,clip9,TTL10,clip10,TTL11,clip11,TTL12,clip12,"+
 "TTL13,clip13+TTL14+clip14,TTL15,clip15,TTL16,clip16,TTL17,clip17,"+
 "TTL18,clip18,TTL19,clip19,TTL20,clip20,TTL21,clip21,TTL22,clip22,"+
 "TTL23,clip23,TTL24,clip24,TTL25,clip25,TTL26,clip26,TTL27,clip27,"+
 "TTL28,clip28,TTL29,clip29"
List<String> chapters = new ArrayList<String>();
 chapters.clear();
 Pattern chapter=null;
 chapter=Pattern.compile("(TTL\\d+([+,]|clip\\d+)*)");
 // || | | | | | | |
 // || | | | | | | Repeat (commas pluses and clips group) 0 or more times
 // || | | | | | one or more digits following 'clip'
 // || | | | | clip
 // || | | | or..
 // || | | plus or comma symbols
 // || | group the +, and clip information together
 // || one or more digits
 // |Match clips starting with TTL
 // |
 Matcher cp = chapter.matcher(finalLongstring); //NO MATCHES!!
 String [] temp = chapter.split(finalLongstring); //temp =EMPTY STRING ARRAY
 do{
 String chapterPlus=cp.group(1);
 if(cp.hitEnd()){break;}
 chapters.add(chapterPlus);
 }while(true);Thanks in advance for the help.
Icesurfer

The main reason your matcher didn't work is because you never told it to do anything. You have to call one of the methods matches(), find() or lookingAt(), and make sure it returns true, before you can use the group() methods. When I did that, your regex worked, but then I modified it to demonstrate a better use of capturing groups, as shown here: import java.util.regex.*;
public class Test
public static void main(String... args)
 String str="TTL1,clip1+TTL2+clip3,TTL4,clip4,TTL5,clip5+TTL6+clip6+"+
 "TTL7+clip7,TTL8,clip8,TTL9,clip9,TTL10,clip10,TTL11,clip11,TTL12,clip12,"+
 "TTL13,clip13+TTL14+clip14,TTL15,clip15,TTL16,clip16,TTL17,clip17,"+
 "TTL18,clip18,TTL19,clip19,TTL20,clip20,TTL21,clip21,TTL22,clip22,"+
 "TTL23,clip23,TTL24,clip24,TTL25,clip25,TTL26,clip26,TTL27,clip27,"+
 "TTL28,clip28,TTL29,clip29";
 Pattern p = Pattern.compile("(TTL\\d+)[+,](clip\\d+)[+,]");
 Matcher m = p.matcher(str);
 while (m.find())
 System.out.printf("%6s %s%n", m.group(1), m.group(2));
}The reason your split() attempt didn't work is because the regex matched all of the text; the split() regex is supposed to match the parts you don't want. In fact, it did split the text, creating a list of empty strings, but then it threw them all away, because split() discards trailing empty fields by default.
Finally, the hitEnd() method is not appropriate in this context. It and the requireEnd() method were added to support the Scanner class in JDK 1.5. If you want to see how they work, look at the source code for Scanner, but for now, just classify them as an advanced topic. When you're iterating through text with the find() method, you stop when find() returns false, plain and simple.

Mining for regular expressions from text

Hi all
I have a situation where I need to develop a set of regular expressions from lists.
I have lists of files uploaded and downloaded, and when the event happened. I need to analyze these and boil them down to a set of regular expressions.
The regular expressions will be used in the future to check the logs for activities. For example:
foo*.zip is downloaded every night. Has it been downloaded tonight.
I am looking for help in analyzing the lists of files and deriving regular expressions to describe them.
Any ideas?
Thanks all

check the url http://java.sun.com/developer/technicalArticles/releases/1.4regex/index.html

Replace a string using regular expression from powershell

I want to replace the following:
'browserName': 'firefox'
with :
'browserName': 'chrome'
then I tried this:
(get-content $conffile) -replace "^('browserName': ')\S+","browserName': 'chrome' |set-content $conffile
But nothing happened.
Could someboby tell me how to write the regular expression here? Thanks a lot.

Second person today with the same question.
get-content $conffile |%{$_ -replace "'browserName':\s+'firefox'","'browserName': 'chrome'" | set-content $conffile
\_(ツ)_/

Migrating Regular Expression from apache to Java1.4

Did any one out there migrate from apache regular expressions to the new Java regular expressions? Are the two compatible? How much work is it to do this? What are the pitfalls? Are there any resources on this topic?
Thanks,

I did migrate some Jakarta regexp to java 1.4's. If ur old codes just used match() method to see if a string matches the pattern, then search/replace using any decent text edit could quickly migrate all of them. However, if you used lots of the Apache regexp's APIs, the fastest way is to write a wrap class for each class you used in the regexp pacakage, and use the new regexp package to implement all the Apach regexp APIs, then, the only thing you need to do is to replace the import statement to import those wrapper classes. I personally think this is the best and common way to migrate from an old API package to a new one.

How to use regular expression to find string

hi,
who know how to get all digits from the string "Alerts 4520 ( 227550 ) ( 98 Available )" by regular expression, thanks
br, Andrew

Liu,
You can use RegEx as
d+
Whether you are using CL_ABAP_REGEX class then
report zars.
data: regex   type ref to cl_abap_regex,
      matcher type ref to cl_abap_matcher,
      match   type c length 1.
create object regex exporting pattern = 'd+'
                              ignore_case = ''.
matcher = regex->create_matcher( text = 'Test123tes456' ).
match = matcher->match( ).
write match
You can find more details regarding REGEX and POSIX examples here
http://www.regular-expressions.info/tutorial.html
a®

Email Regular Expression with a String.Match()

I'm currently using a RichTextEditor for a user to build HTML
for a site. However, I want the application to scan for emails and
encode them so they are protected from spam bots when they go to
the live site. I've written a regular expression to find an email
and it seems to work, but it only returns one email at a time from
the string. I have had to revert to a while loop to traverse the
string until I'm satisfied. I don't particularly like that method
and would like to just do one String.match() query to retrieve all
of the emails. Can anyone see something here that I'm missing?

Try adding the global flag (g):
var emailPattern:RegExp =
/[a-z][\w.-]+@\w[\w.-]+\.[\w.-]*[a-z][a-z]+/g;
TS

Regular expression with delimited string

Hi,
I'm trying extract all characters in a string (as word or words) which is delimited by ' -- '
Been playing around with regular expression and got as far as this;
with t_vw
as (select 'hello -- world' txt from dual
union all
select 'hello-world' from dual
union all
select 'hello' from dual
union all
select 'hello -- world -- bye' from dual
union all
select 'hello--worldbye' from dual
select txt, regexp_substr(txt,'[^ -- ]+',1,1) word1,
regexp_substr(txt,'[^ -- ]+',1,2) word2,
regexp_substr(txt,'[^ -- ]+',1,3) word3
from t_vw;
It's returning;
"TXT","WORD1","WORD2","WORD3"
"hello -- world" "hello","world",""
"hello-world"          "hello","world",""
"hello"               "hello","",""
"hello -- world -- bye"     "hello","world","bye"
"hello--worldbye"      "hello","worldbye",""
So it seems to work in all cases apart from when there are no spaces before/after "--".
Any ideas?

Please enclose your code in *{noformat}{noformat}* tags to preserve your formatting and to prevent the forum software from mangling your regular expressions.
Also, you've given your input and show the output that you are getting, but I don't know what your issue is. If you could include the desired output and explain how it differs from what you are getting so far that would help.

Removing Null values from character string

Hi All,
Can i remove NULL values (hexadecimal - 0000) from character string. I am uploading a file from presentation layer (shared server) and getting NULL values in many fields which i want to remove.
please assist.
Thanks for you help..
Regards,
Mohaiyuddin

Hi,
Most likely, nobody needed it, but if anybody in future will need the solution for related problem - here's solution:
data: lv_nullchar type xstring value '0'.
shift lv_xstring right deleting trailing lv_nullchar in byte mode.
shift lv_xstring left deleting leading lv_nullchar in byte mode.
This hack deleting null chars in lv_xstring at end file and at begining of file. Works perfect for me, where i also worked with files.

Regular expression - find if string does NOT contain text....

I have a string that I want to tokenize. The string can contain basically anything. I want to produce tokens for each "word" found, and for each "<=" or "," found. There does not need to be whitespace around a "<=" or a "," to consider it a token. So for example:
joe schmoe<=jack, jane
should become
joe
schmoe
<=
jack
jane
As a constraint, I do not want to use StringTokenizer at all, as "its use is discouraged in new code". http://java.sun.com/j2se/1.4.2/docs/api/java/util/StringTokenizer.html
Here's the code I plan on using for this:
 public String[] getWords(String input) {
 Matcher matcher = WORD_PATTERN.matcher(input);
 ArrayList<String> words = new ArrayList<String>();
 while (matcher.find()) {
 words.add(matcher.group());
 return (String[]) words.toArray(new String[0]);
 }The trick, though, is coming up with a working regular expression. The closest I've found yet is:
([^\s]|^(,)|^(<=))+|,|<=
but that produces the following:
joe
schmoe<=jack,
jane
I think what I need is to be able to find if a string does not contain the substring "<=" or "," using a regular expression. Anyone know how to do this, or another way to do this using regular expressions?

Try:
* Tokenizer.java
* version 1.0
* 01/06/2005
package samples;
import java.util.regex.Matcher;
import java.util.regex.Pattern;
* @author notivago
public class StrangeTokenizer {
 public static void main(String[] args) {
 String text = "joe schmoe<=jack, jane";
 Pattern pattern = Pattern.compile( "((?:<=)|(?:,)|(?:\\w+))");
 Matcher matcher = pattern.matcher(text);
 while( matcher.find() ) {
 System.out.println( "Item: " + matcher.group(1) );
}May the code be with you.

ALC-FUT-001-007: Syntax error in the regular expression *. from File Utilities - Find in ES2

Has anyone encountered the above error when trying to use the Foundation - File Utilities service Find?
This is occuring in ES2, and I have tried using an asterisk, as well as the exact file name I know exists.
I have tried literals in the Process Properties, as well as passing it in via string variables.
Any help is appreciated.
Thanks
Mark

Thanks for your response.
Here is what we have learned:
We should not put the regular expression value in single quotes - eliminates the error.
The problem is, the Find operation always returns an empty list no matter what criteria we enter - even C:\ with criteria = *.*
ES 2 is running on a Windows 2003 machine.
Thanks Again
Mark

Getting the regular expression from the given text

Hi
I need to develope an application which can convert the given text into the regular expression. I need that when i enter any text in textarea that should be translated into regular expression in another panel. but i could not find the method or technique which can do so. plz help me to resolve this issue.
Thanks Imran khan.

well, there are an infinite number of regular expressions for an arbitrary piece of text, so you will have to qualify in your mind what the purpose of the regular expression is.
For instance, it is trivial to create a regex for a string just by copying the input text, and inserting \ before any special characters. But this pattern would probably be quite silly.

Remove regular expression from a string

Similar Messages

Maybe you are looking for