Return statement inside try block

what is wrong if i write code like as below...please explain me since i am new to java
class sample{
public String method(){
try{
String str="abc";
return abc;
catch(Exception e){}
}

veldhanas wrote:
return abc;In your code there is no varible declared as abc. It is a value assigned in str.
Suppose if the code in try statement throws exception the return statement is skipped and the
associated catch block will get executed. So your catch block must return a result of type String.... or throw another (or the same) exception.
In this case, since there's no way the code in the given "try" block can throw an exception, it would have been better to not even have a try/catch block in the first place.
And almost never just swallow exceptions like that (an empty catch block). There are only a few cases where it's ok to swallow them (such as in finally blocks where you're cleaning up resources which may throw exceptions while cleaning up, and you want to continue cleaning up and ignore those kinds of exceptions).

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  • Return statement in catch block !

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  • Posiibility for terminating jvm inside try block so that finally block wont

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  • Can't throw exception inside try block!

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    I need to correct myself: I've re-read the spec, and actually the behaviour is conformant with the JLS: JLS says that the return statement completes abruptly, and an abrupt return in a finally block that didn't have a (applicable or any) catch block will result in the original exception being 'forgotten'.
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  • Return statement and Try Catch problem

    Hi!!
    I've got the next code:
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    But I need a return statement in the catch-block, but I don't know what's the best option.
    Help...
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    The error message is: "missing return statement", Yes, I know.
    You have to either return from the catch statement, or throw from the catch statement, or return or throw after the catch statement.
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    So, like I said: What would you return from within or after catch? There's no good value to return. The only remotely reasonable choice would be null, but that sucks because now the caller has to explicitly check for it.
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  • Return statement in exception and consequences

    Hi,
    Can any one give me the explanation for my doubt?
    Case 1:
    I am having some code throwing some exception lets say arithematic exception in my try block.
    I caught it in the catch block and at last I am having one finally?
    as per normal order try block next catch block and at last finally will execute.
    I execute the above code by putting a return statement inside catch block.I got the same order of execution irrespective of return statement inside catch?
    What is the significance of return inside catch?
    Case 2:
    Lets take the scenario.
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                   System.out.println("the value is: "+(i/j));
                   System.out.println("Inside try block");
                   catch(ArithmeticException e)
                   System.out.println("hi in ame");
                   //return;
              finally
              System.out.println("inner finally");
                                            System.out.println("outer try");
              catch(Exception e)
                             e.printStackTrace();
                   System.out.println("in exception");
              finally
                   System.out.println("plz wait");
    If return statement is there inside the inner try and catch the code out of inside outer try not getting executed Why So?
    Any clarifications?
    Thanking you,
    Murthy.

    First, please format your code as per http://forum.java.sun.com/features.jsp#Formatting
    I'm not sure what part you don't understand.
    .    public static void main(String[] args) {
    .        try {
    .            try {
    .                throw new ArithmeticException();
    .                System.out.println("Inside try block"); // #1
    .            catch(ArithmeticException e) {
    .                System.out.println("hi in ame"); // #2
    .                return;
    .            finally {
    .                System.out.println("inner finally"); // #3
    .            System.out.println("outer try"); // #4
    .        catch(Exception e) {
    .            System.out.println("in exception"); // #5
    .        finally {
    .            System.out.println("plz wait"); // #6
    .    }#1 -- You won't get here because you throw AME.
    #2 -- You will get here because you caught the AME you just threw.
    #3 -- You will get here because it's a finally
    #4 -- You won't get here. I think that this is what you're asking about: Why don't we get here? Because we've already done 'return' and this line is NOT inside a finally. The only things that can get executed after a return are finally blocks.
    #5 -- You won't get here because you already caught the AME and didn't rethrow it or any other exception.
    #6 -- You will get here because it's a finally.
    Once you do a return, the only code you can execute before exiting the method are finally blocks. First the one corresponding to the try/cathc block where your return is, then the finally for the try/catch that encloses that one, and so on outward. The code between one finally and the next (#4 here) is NOT executed.
    If you still have a question, please try to clarify exactly what behavior you don't understand.
    Don't return from inside t/c/f.

  • Doubts reg try block and return statements

    hi
    public int test()
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                   return 1;
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              System.out.println("err");
              return 2;
              finally
                   System.out.println("final");
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              //return 4;
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    and also compilation error is coming when i put return statement after final block.. why is it so??

    but if commented the return statements in catcch and finally then it iam not getting any compilation error.
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                   System.out.println("final");
              //     return 3;
              System.out.println("after");
              return 4;
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  • Txt file read in- StringTokenizer- Try Block Catch for errors

    Hello
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    I am also stuck on the logic on the try block catch statement. How does a person set up a �custom� try block that looks for errors like the ones below? I have attempted to start in the commented code.
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    2.use delimiter separated by �;�
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    d.�
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    XYG726;Smith,Mr. John M.;29.96;comedy;101008;100604
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    Lu15;Will, Mark;50.00;Science;030305;030807
    The file should then be printed out in the program not to a text file. It only needs to print the invoice number and error code letter assignment.
    If you have any questions feel free to let me know. Thanks for all or any help you have to offer.
    Invoice
    Three upper case letters followed by three digits
    Regular Expression "[A-Z]{3}[0-9]{3}"
    Customer Name
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    Sale Price
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    Regular Expression [0-9]{2}*./[0-9]
    Genre
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    ShipDate and Order Date-
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    import java.util.StringTokenizer;
    import java.util.regex.Matcher;
    import java.util.regex.Pattern;
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    import java.util.Scanner;
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    Scanner scanner = new Scanner(aLine);
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    String value = scanner.next();
    else {
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    String fname = st.nextToken();
    String lname = st.nextToken();
    String price = st.nextToken();
    String genre = st.nextToken();
    String orderDate = st.nextToken();
    String shipDate = st.nextToken();
    String invoiceCode;
    invoiceCode = "A" checkInvoiceCode(String invoiceCode);
    Pattern p = Pattern.compile("[a-z]{6}[A-Z]{6}[0-9]{6}");
    Matcher m = p.matcher(invoiceCode);
    p.matcher(invoiceCode);
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    else {
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    try
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    catch (NumberFormatException e)
    { System.out.println ("B"); System.exit(1); }
    */

    I have made a quite a few updates to my code. Please look it over again. I have also made many comments to help with the logic. Once again if you have any questions please feel free to ask. Sorry about not using the tags before- I was no aware of them. Thanks for the advice sabre150.
    package Project3;
    import java.util.StringTokenizer;
    import java.util.regex.Matcher;
    import java.util.regex.Pattern;
    import java.io.*;
    import java.util.Scanner;
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         private final File fFile;
         public static void main (String args[]){
                   //read in text file from directory currently it can not read the file
                  Scanner in = new Scanner(new File("e:\\work_space_java\\Project\\Package3\\movie.txt"));
                  //Scans each line of the text in
                  Scanner.processLineByLine();
                //assigns new file name to file
                public ReadWithScanner(String aFileName){
                  fFile = new File(aFileName); 
                public final void processLineByLine(){
                  try {
                    //use a Scanner to get each line from the processLineByLine
                    Scanner scanner = new Scanner(fFile);
                    while ( scanner.hasNextLine() ){
                      processLine( scanner.nextLine() );
                    scanner.close();
                  catch (IOException ex){
                protected void processLine(String aLine){
                  //use a second scanner again to read the content of each line
                   //delmiter should then break each line in the text file into seperate "tokens"
                  Scanner scanner = new Scanner(aLine);
                  scanner.useDelimiter(";");
                  if (scanner.hasNext() ){
                       //reads each line from scanner
                    String name = scanner.next();
                  else {
                  scanner.close();
               /*Convert Tokens from Scanner into String Tokenizer with assigment to each variable
                * I am missing something
                * Need to convert each line read from the scanner (name variable) to the String
                * Tokenizer class
              //Tokens names now assigned a varaible
              StringTokenizer st;
              String invoice = st.nextToken();
              String name = st.nextToken();
              String price  = st.nextToken();
              String genre = st.nextToken();
              String orderDate = st.nextToken();
              String shipDate = st.nextToken();
          /*If statments (Try Block Statements?) with Regular Expressions
          * This is where I have the most issues on how to set up
          * "custom" try and block errors trying to match what I have
          * in the regular expressions. 
          * I believe try and catch statements
          * make this easier but I have used 'match' and 'pattern' with if
          * statments.  If try block statements are easier please show!
          * Regular Expressions may not be correct either
           invoice = checkInvoiceCode(invoice);
           //Defined cerita for Inovice are:
           //Error A = Invoice code is too short  
           //Error B = Invoice code does not have the right characters 
           //Error C = Invoice code digits are all zero
           //Checks for error A
           //Has at least six characters
            Pattern invoiceShort = Pattern.compile("{6}");
            Matcher shortInvoice = invoiceShort.matcher(invoice);
            p.matcher(invoiceCode);
            if(m.matches()) {
                 System.out.println(invoice);      
            else {
                 System.out.println ("A");
            //Checks for error B
            //3 Upper Case Letters followed by three numbers,
            Pattern rightChar = Pattern.compile("[A-Z]{3}[0-9]^0{3}");
            Matcher charRight = rightChar.matcher(invoice);
            p.matcher(invoiceCode);
            if(m.matches()) {
                 System.out.println(invoice);
            else {
                     System.out.println ("B");
            //Checks for error C
            //Where the last three digits are not all zeros
            Pattern notZero = Pattern.compile("*{3}^0{3}");
            Matcher ZeroNot = notZero.matcher(invoice);
            p.matcher(invoiceCode);
            if(m.matches()) {
                 System.out.println(invoice); 
                 else {
                     System.out.println ("C");
         //name = checkFullName(name);
         //Error D = Name field has fewer than two words
         //Error E = Name field has more than four words
         //Error F = Name field has no comma
         //Error G = Name field has a bad title 
         //Error H = Name field has a bad initial 
        /*Have a lot more to do...
        * Still need to go through the same if statement or Try Block statements with this data:
        *      String fname = st.nextToken();
              String lname = st.nextToken();
              String price  = st.nextToken();
              String genre = st.nextToken();
              String orderDate = st.nextToken();
              String shipDate = st.nextToken();
        * But for now I would like to see an example of an if statement I could use
        * (if mine is even right) or catch statement- the rest of the project we look
        * for similar certia as defined in the reg exp for invoice
         /*Writes to Report in the Console
         * Prints data into two columns:
         * Invoice Code and Error Type
         //Prints both column Headings
         private void columnHeadings ()
         System.out.println (padL("",5) +
         padL("Invoice",20) +padL("",20)+
         padL("Error Code",40));
         //movie is the name of the text file
         private void printMovie(Movie aReport) {
         System.out.println(aReport.getInvoiceCode()+"\t"+
               aReport.getErrorType()+"\t");
      *This method pads the string start to the length newLength leaving the
      *string left justified and returning the result.
      private String padL (String start, int newLength)
         String result = new String (start);
         while (result.length() <= newLength) result += " ";
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      } // end padL
       * This method pads the string start to the length newLength leaving the
       * string right justified and returning the result.
      private String padR (String start, int newLength)
         String result = new String (start);
         while (result.length() <= newLength) result = " " + result;
         return result;
    // end padRThanks a lot.

  • Return statement in a try catch block

    Hi friends
    Take a look in the code bellow
    try
    return (true)
    finally
    System.out.println("blabla");
    If nothing strange hapens in the try code, the return statement will be achieved. In this case, what will hapen ? The code in the finally block will be executed ??
    thanks

    If nothing strange hapens in the try code, the return
    statement will be achieved. In this case, what will
    hapen ? The code in the finally block will be executed
    ??Yes. Hence the word "finally".

  • Return statement at the end of try or after catch blocks

    Hi
    Can anyone tell me which is the better practice - to put the return statement at the end of try block or after all the catch blocks ie at the end of method.
    Eg
    Method A()
    String str;
    try{
    str= [some code]
    return str
    catch(Exception e)
    System.out.println("Exception");
    } // end of method
    OR
    Method B()
    String str;
    try{
    str= [some code]
    }catch(Exception e)
    System.out.println("Exception");
    return str
    } // end of method

    I always try to work with only one exit point for each method.
    For readability I always put the return statement as close to the end of the method as possible.
    In this particular question,
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    familiar with), but when I have a try-catch clause, I usually have an unrecoverable error and
    should throw this further down the tree, so it usually becomes
    try{
       return   
    }catch(...){
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       rethrow exception or throw another exception
    }I think you should NEVER reflect the occurence of an error in the return-value of the
    method when an unrecoverable exception occurs. Just rethrow this exception or throw another method.
    Other methods look like
       Object result = new...
       return result;As for the specific case of a repetitive if-case:
    This is possible in two versions:
    With one return and a result-object
    Object result = new ...
    if(..)
       result = ...
    else if(..)
       result = ...
    return result;With every time a return
    if(...)
       return ...;
    else if(...)
       return ...;For me the above two possibilities make no difference,
    but I find the second version (which I hated when I began programming)
    to be somewhat more of a (self-made) standard nowadays.
    But I do not think this particular case makes much of a difference.
    kind regards,

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    When a method returns a value, you must make sure that even if an exception is thrown and caught a value will be returned (or just throw the exception out of the method).
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    It should be coded as you have it. There should (ideally)
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