Rounding a double to a nearest 5000

HI Guys,
I wanted to know the easy way to rounding a double number to nearest to multiples of 5000.
Thanks
-nicedude

Thank you . This is sure not a swing question at all, I should not have posted it here.
Thanks you anyway for your answer. I did exactly the same thing. i thought somebody may come up with even a brighter idea, so i posted it.
Thank you once again for your anwer.

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Rounding off double

how do you round off a double to the nearest hundredth place?

You can't because a double is typically not capable of representing an exact 100th place.
Sylvia.

Need some help in Rounding a double value to a whole number

Hey Peeps,
Need some help here, I got a method that returns a value in double after a series of calculation.
I need to know how can I round the double value, so for example,
1. if the value is 62222.22222222, it rounds to 62222 and
2. if the value is 15555.555555, it rounds to 15556
How can i do this
Zub

Hi Keerthi- Try this...
1. if the value is 62222.22222222, it rounds to 62222 and
double d = 62222.22222222;long l = (int)Math.round(d * 100); // truncatesd = l / 100.0;
double d = 62222.22222222;
System.out.println(d);
long l = (int)Math.round(d * 100);
// truncatesSystem.out.println(l);
d = l / 100.0;System.out.println(d);
for (int i = 0; i < 1000; i++)
{ d -= 0.1;}
for (int i = 0; i < 1000; i++)
{ d += 0.1;}System.out.println(d);
regards- Julie Bunavicz
Output:
62222.22222222
62222
62222.22
62222.22000000000001

Rounding up doubles to 2 decimal places

I'm currently rounding up a double in my program using Math.round(double)
However I want to strip any trailing zeros from the output, so:
1.235 would round to 1.24
but 1.00 would round to 1
How would I go about doing this?

Also I'm making my own function to round the doubles,
and they are returning doubles so I cannot return a
string.If they are returning doubles that the number of "trailing zeros" is irrelevant, as that is formating. Really you should keep the precision until you want to display it, then use the formatter above.
What are you doing?
I'm going to take a shot in the dark; has this got something to do with money?

Round up double to 2 decimals

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e.g., Book (including tax) :14.99 + 14.99 * 10% = 16.489 ---> 16.49

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     * @param value Decimal value.
     * @param scale New scale.
     * @return Scaled number.
     * @since 1.8.3
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        double result = value; //default: unscaled
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Round a double value to a specific number of decimal places?

Hello,
Is there standard java function which will round a double value to a specified number of decimal places? Something like:
double d = 4.34523;
d = round(d, 2);
where d is finally assigned the value of 4.34?
Thanks!
-exits

No, because doubles hold values in binary (as do all values in a computer, of course, but there's no additional stuff to indicate decimal values).
If you want values with specific rounding rules in decimal, use java.math.BigDecimal.
If you just want to format the number with a specified number of decimal digits, use java.text.DecimalNumber.

What's the best way to round a double to 12 decimals?

What's the best way to do it? The math functions don't seem quite right...

I'm doing three different algoritms that are mathematically identical. I'm working with precisions from 2 to 12 significants digits (working with a function I got from a book), but the results are no exctly what I expect... For example, the one with 12 significant digits is 97.45322134230000001, or something like that... I'm making a method that receiving a double and an n makes a string with the correct number of significant digits... However, rounding the double beforehand would come in handy.

Rounding a double

Hi,
What's the best (and fastest since I got lots of values) way to perform a rounding on a double value?
I think what I'd like to do is half-up rounding, so when it should round up to 2 digits e.g., it should cut off the rest when the third position is a 0;1;2;3 or 4 and should add one to the second digit, when the third is one out of them: 5;6;7;8;9.
I tried it myself this way. Now this has happened - at the end (converting int to double) it screws at some values - why and how can I fix that or what is a better way to do this, since this solution looks kind of goofy to me?
    public double roundValue( double dTemp, int iDigits){
         // splitting up into the pure int part of the NOT rounded value
         System.out.println("****   dTemp to round: " + dTemp);
         System.out.println("iDigits to round to: " + iDigits);
          int iIntPart = (int) dTemp;
          dTemp -= (double) iIntPart;
          System.out.println("iIntPart: " + iIntPart);
          System.out.println("dTemp - only minor digits: " + dTemp);
          // calculation of a factor for the lower digits
          double dDigits = 1.0;
          for(int cnt = 0; cnt < iDigits; ++cnt)
              dDigits *= 10.0;
          System.out.println("dDigits: " + dDigits);
          System.out.println("dTemp * dDigits: " + (dTemp * dDigits));
          System.out.println("Math.round: " + Math.round(dTemp * dDigits));
          System.out.println("Math.round/dDigits: " + ((Math.round(dTemp * dDigits)) / dDigits));
          // processing Math.round()
          dTemp = (Math.round(dTemp * dDigits)) / dDigits;
          System.out.println("dTemp - after: " + dTemp);
          // dTemp is now rounded
          dTemp += (double) iIntPart;
          /* here sometimes, the value returns results like this - why?
           * 4.941519877284079 -> iDigits == 2 -> 4.9399999999999995
           * 5.94004582533272 -> iDigits == 2 -> 5.9399999999999995
          System.out.println("****   dTemp after adding the int part: " + dTemp);
          return dTemp;
    }

Thanx I tried it out and I thought I had to use Math.round() the way I did. But still what happens at the conversion from an int to a double - just curious?
I did it now this way - I thought Math.round has some probs, with the digits in front of the point:
    public double roundValue(double iValue, int iDecimalPlace) {
        double dPowerOfTen = 1;
        while (iDecimalPlace-- > 0){
           dPowerOfTen *= 10.0;
        return (Math.round(iValue * dPowerOfTen) / dPowerOfTen);
     }

Rounding xs:double value

Hi in bea xquery function pallette we only foung round() for decimal type.But we had a requirement to round xs:double values.
How can i achive this ,any method for round double values or to convert double to decimal.

does round( $someDouble ) not work?
Can you please try a few things yourself before posting?
If you already have, can you please post what you have tried?

Rounding a double value

What is the easiest way to round a Double variable to 2 significant figures?
Cheers Mike

Oh, classical and very typical question on this forum.
The short answer is nope. You don't do that and you don't need to do that. If you really really have to must doing that, you used the wrong type - double.
By definition, double is an approximation. No gurantee on precision lose.
--lichu

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hi,
i want to round a BigDecimal number to its nearest number
eg. if my calculation result is 75.3 then it has to be rounded to 75
if my calculation result is 75.6 then it has to be rounded to 76
if my calculation result is 75.5 then it has to be rounded to 76
can anyone help me out resolving this
thanks in advance

public class MyBigDecimal {
     public static void main(String [] args){
          double d = 75.3;
          System.out.println("d = " +d + ", " + Math.round(d));
          d= 75.6;
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          d=75.5;
          System.out.println("d = " +d + ", " + Math.round(d));
          d=75.99;
          System.out.println("d = " +d + ", " + Math.round(d));
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Rounding of Qty to the nearest whole no in PO

Hi All,
We have material whose base unit of measure is say centimetres. and it has purchase unit as metres.
Our requirment for procurement is generated through MRP run which creates the Purchase requistion and in PR the UOM considered is the base unit of measure ie centimetres.
When this Purchase req is converted to Purchase Orders we get qty sometimes in decimals for ex: if in Pur req the qty is 150 centimetres , in PO it is shown as 1.5 metres.
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Vengal

in MRP view of material master you have two fields to care about rounding. rounding profile and rounding value
http://help.sap.com/saphelp_46c/helpdata/en/f4/7d28c844af11d182b40000e829fbfe/content.htm

Rounding up doubles

Just wondering if anyone knows how to round up a double so that for instance 100.232323 can be up to 100.
This is due to trying to convert a price in pence to a meaningful price.
Also is there anyway to represent a figure in pounds and pence???
Regards.

If you are working with money you shouldn't do floating point arithmetic. You should either use one of the following:
1. java.math.BigDecimal. See example: double monthlyInterest = 5.5d / 1200d;
double monthlyPayment = 700.25d;
BigDecimal interestAmount = new BigDecimal(monthlyInterest).setScale(5,BigDecimal.ROUND_HALF_UP);
BigDecimal principalAmount = new BigDecimal(monthlyPayment).setScale(2,BigDecimal.ROUND_HALF_UP);
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double i = interestAmount.doubleValue();
double p = principalAmount.doubleValue();
double payment = appliedPayment.doubleValue();2. Multiply all numbers by a power of 10 (for example 100) and then truncate or round the decimals, then do your arithmetic, then divide by the same number. To truncate, just cast your double value to an int.int newValue = (int) someDoubleValue;To round, you can use any of the java.lang.Math methods.Math.ceil(someDoubleValue);
Math.floor(someDoubleValue);
Math.round(someDoubleValue);You can do your own research. :)
The reason why you should not do floating point arithmetic is because it is not accurate.

Rounding a double to a format

Hi,
I'm trying to get a result for a formula in the format of ##.##. The result for one equation, for example, is 10.637129724208375 and I want it to be 10.64 (round to the nearest tenth, pretty much).
Any suggestions?

aeternaly wrote:
I'm trying to get a result for a formula in the format of ##.##. The result for one equation, for example, is 10.637129724208375 and I want it to be 10.64 (round to the nearest tenth, pretty much).If it's just for display, look at DecimalFormat or String.format().
If you actually need to store values to two decimal places, you're generally better off using BigDecimal.
You can find the explanation why [url http://www.eason.com/library/math/floatingmath.pdf]here (the original) or [url http://floating-point-gui.de/]here (mybe a bit friendlier).
Winston

May I know how to round a double number to 2 decimal points?

if I have a double number 135.25689951591, how can I round this number to make it output as 135.26?

double number = 135.25689951591;
java.text.DecimalFormat df = new java.text.DecimalFormat("#.00");
System.out.println(df.format(number));Alll this will do is display the value 135.26, number will still hold 135.25689951591

Rounding a double to a nearest 5000

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