Scanner input question.

I have an scanner which prompts the user to
type some data into it.
for example
Lets say I have four strings.
String id
string name // this includes first and last name
string address //this includes the full address.
string price...
When the first scanner prompts the user they type in
DW123 and hits return
the next scanner prompts the user to type i the name
James Brown. and hits return.
when this happens I will get the next scanner running together
example
enter your address==>,enter the price==>
yet if I were to enter the name as JamesBrown it will work.
is there away around this.
any help would be great
red

Probably because you are calling the next method, which only returns a single token, not the nextLine method.
Further, if you were to print out the address, I'm sure it would display "Brown".

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Barcode scanner input

Hi .
I have an application that needs to receive bar code scanner input (the DS6707 from motorola). This application also discusses with 3 or 4 boards that run in parallel (using serial port com). So I have at least 5 threads that are running in parallel: one for each port com, one supervisor, and the main for the user interface.
I created a control to get the data coming from the barcode scanner, but sometimes I lose some number on my barcode, or sometimes I receive ‘?’ instead of a number.
If I create a thread that read the standard input, it works, I always receive all my numbers, but the problem is that I have the standard input that is visible and I don’t want.
I tried to used keyboard methods from the windows library , but I don’t know how to proceed.
Thanks for your help.

I have a question about a keyboard wedge scanner input.
I have a single panel with several text boxes placed in a grid.
I post the output from 8 flash programmers in the boxes.
I have a single wide text box below these to display general program status.
My problem is when I scan the barcodes from the panel array, all data goes
through the Upper Left text box. i want the data to go through the big box on the bottom.
The reason I am using the text box in the upper left, is because that is where the data went
when I scanned the bar codes. I was desperate to get the project moving forward.
And the StdIO window caused too many problems.
Question, How do I move the cursor to the other text box ? I have tried many Set / Get
Attribute parameters. If there exists any "how-To" example code I would be grateful.
void ReadSerialNumber1 (char* BigBuffer9)
statspanelHandle = TESTER_DialogGetSubPanelCVIHandle(&StatsHandle);
statspanelHandle = GetCtrlVal (StatsHandle, STATSPANEL_TEXTBOX_2, BigBuffer9);
DisplayPanel(StatsHandle);
fprintf(Stream1,"Serial Number..~%s~\n",BigBuffer9);
code in main section
sprintf(LittleBuffer1,"\n -- SCAN Serial Number Nest 1-- ");
WriteTextBox1(LittleBuffer1);
PN_Size = strlen(LittleBuffer1);
for(x=0;x<128;x++){ LittleBuffer1[x] = '\0';}
PN_Size = strlen(LittleBuffer1);
while(PN_Size != 10){
     int Stat_Val;
     Delay(0.5);
ReadSerialNumber1(LittleBuffer1);
     PN_Size = strlen(LittleBuffer1);
if(TEST_CHECK_BREAK) break;
if(PN_Size == 10) Ready_Go = 1;
strcpy(sSerialNum1,LittleBuffer1);
strcpy(Scan_Buffer[0],LittleBuffer1);
if(!strcmp(ModuleType2,"DSM")) strcpy(Scan_Buffer[1],LittleBuffer1);
ResetTextBox2();
if(TEST_CHECK_BREAK) break;
sprintf(LittleBuffer1,"____%s____",Scan_Buffer[0]);
WriteTextBox1(LittleBuffer1);
Ready_Go = 0;

Follow Up to Scanner Input from File

Alright, I have another problem. My code is this:
for (int j = 0; j < username.length; j++) {
     String line = input.nextLine();          // Create a temporary String that will store each line
     // Check if the temporary line isn't empty
     if (line.length() > 1) {
             numAccounts++;
             username[j] = line.substring(10);
             password[j] = input.nextLine().substring(10);
             System.out.println(username[j]);
     } else {     // If the temporary line is empty, go back on the loop to prevent empty array entries
              j--; }
     }It runs through once, and then stops. Here are the declarations:
static int numAccounts = 1;
static String[] username = new String[numAccounts];
static String[] password = new String[numAccounts];
static Scanner input = new Scanner(new BufferedReader(new FileReader("account.txt")));Which was done outside of the main method.
Why does the loop iterate only once?

Woah, don't need to get all heated up about something I'm doing wrong. I'm just trying to figure this out. Sorry if I'm getting on your nerves.
So anyways, I did the ArrayList method with your suggestion of making it an ArrayList of Objects. This is what I have so far:
// Declare the ArrayList that will store all the Account Objects retrieved from the database
static ArrayList<Account> accounts = new ArrayList<Account>();
while (input.hasNextLine()) {
    String line = input.nextLine();          // Create a temporary String that will store each line
    // Check if the temporary line isn't empty
    if (line.length() > 0) {
         //System.out.println(line);
         String currentName = line.substring(10);
         String currentPass = input.nextLine().substring(10);
         Account current = new Account(currentName, currentPass);
         accounts.add(current);
}Yes, I stuck with using the line.length() > 0, because trying to use line != null doesn't work properly for me. Not entirely sure why. Just throws IndexOutOfBoundsException when it's called.
And my Account Object class is as so:
class Account {
     static String username, password;
     Account(String username, String password) {
          this.username = username;
          this.password = password; }
}I tried to print out the username and passwords to the indexes of 0, 1, and 2, and they're all the same.
System.out.println(accounts.get(0).username);
System.out.println(accounts.get(0).password);
System.out.println(accounts.get(1).username);
System.out.println(accounts.get(1).password);
System.out.println(accounts.get(2).username);
System.out.println(accounts.get(2).password);What is also interesting, is that it only fetched (or copied) the last two lines in the text document. It ignores all the entries before that.
Do you know what I did wrong? I think I did a logic error in there somewhere.

Scanner Input from File

I'm trying to read from an external file using the Scanner class and to store the input in the applicable arrays, but I don't know how to skip lines.
For example, if a text file has this in it:
Name: Bob
Age: 30
Job: Engineer
Name: Joe
Age: 40
Job: ManagerIt reads fine, and stores fine. But, if I have this instead:
Name: Bob
Age: 30
Job: Engineer
Name: Joe
Age: 40
Job: ManagerWith the empty line, the String class throws an index out of range exception. Same goes for if the very first line of the file is also blank.
Here is my code:
String[] name = new String[100];
int[] age = new int[1000];
String[] job= new String[1000];
     try {
              Scanner input = new Scanner(new BufferedReader(new FileReader("test.txt")));
              for (int i = 0; input.hasNext(); i++) {
                   name[i] = input.nextLine().substring(6);
                   age[i] = Integer.parseInt(input.nextLine().substring(5));
                   job[i] = input.nextLine().substring(5);
                   System.out.println("Name: " + name);
               System.out.println("Age: " + age[i]);
               System.out.println("Job: " + job[i]);
          input.close();
     } catch (FileNotFoundException error) {}Thank you all very much!

I already have something else that is handling non-existent files, so I don't need to do anything there.
And thank you very much, I figured out how to do it! I just needed to temporarily store the line, see if it was longer than 1 in length, and perform based on that.
Thank you very much!
Edited by: ManiKatti on Dec 31, 2009 7:14 PM

Problem with Scanner input

I want to take an int as first input and string with spaces as 2nd input via scanner input method... it takes int input and immediatly prints the output
without taking string input.... where is the bug.... here is the code...
import java.util.*;
import java.io.*;
public class Ud2
public static void main(String[] args)
Scanner in=new Scanner(System.in);
int x=in.nextInt();
String s=in.nextLine();
System.out.print("the no is "+x+" and name is "+s);
if the prob is due to new line charcter in the stream then how to remove or
ignore it..?
plzzz help.......................

in.nextLine();Insert the above line after your nextInt call. Why? Because nextInt() does not consume the end of line(EOL) character. So when you call nextLine() you assign the EOL to s

Scanner input being forgotten

I am new to Java and playing around with Scanner input instead of BufferedReader. In the following code the Scanner input appears to be forgotten at the end. When asking if the user wants to repeat another person, if I omit the 2nd Scanner input, the nextLine is not executed or at least ignored. Is there a time limit or input limit for how long Scanner input will work?
import java.util.Scanner;
public class Java0504
     public static void main (String args[])
          String repeat = "Y";
          while (repeat.equals("Y"))
               System.out.println();
               Scanner input = new Scanner(System.in);
               System.out.print("Enter 1st Name ===>> ");
               String firstName = input.nextLine();
               System.out.print ("Enter last name ===>> ");
               String lastName = input.nextLine();
               System.out.print ("Enter your area code ===>> ");
               String areaCode = input.nextLine ();
               System.out.print ("Enter your prefix ===>> ");
               String prefix = input.nextLine ();
               System.out.print ("Enter the last four digits of your phone number ===>> ");
               String lastFour = input.nextLine ();
               System.out.print ("Enter your age ===>> ");
               int age = input.nextInt ();
               System.out.println ();
               System.out.print ("Do you have another person Y/N ===>> ");
               Scanner input2 = new Scanner(System.in);
               repeat = input2.nextLine ();
          System.out.println ();
}

I think you probably need this:
String dummy = input.nextLine();after the line:
int age = input.nextInt();And then, add the following (and eliminate the input2, as suggested):
repeat = input.nextLine(); after the "another person Y/N".
Otherwise, I think the input.nextLine() after the "Y/N" will just consume the "return" that was pressed when the user entered the age.
That is, the last few lines would be:
int age = input.nextInt ();
System.out.println ();
String dummy = input.nextLine();
System.out.print ("Do you have another person Y/N ===>> ");
repeat = input.nextLine();

Scanner input error

I want to make a very simple program that allows the user to enter a key/character and have the corresponding unicode value returned. The problem is that I receive an error after the input of any character.
Here is the code:
import java.util.Scanner;
public class KeyMap
public static void main (String args[])
int number; //the future unicode value.
          System.out.print ("Enter the key you want the unicode number of: ");
          Scanner scan = new Scanner (System.in);
          number = scan.nextInt();
          char key = (char)number;
          System.out.print ("The number for key " + key + " is " + number);
And I get this error in the run log after the character is entered:
Exception in thread "main" java.util.InputMismatchException
     at java.util.Scanner.throwFor(Scanner.java:819)
     at java.util.Scanner.next(Scanner.java:1431)
     at java.util.Scanner.nextInt(Scanner.java:2040)
     at java.util.Scanner.nextInt(Scanner.java:2000)
     at KeyMap.main(KeyMap.java:11)
KeyMap has exited with status 1.
Thanks for any help!

Exception in thread "main"
java.util.InputMismatchException
     at java.util.Scanner.throwFor(Scanner.java:819)
     at java.util.Scanner.next(Scanner.java:1431)
     at java.util.Scanner.nextInt(Scanner.java:2040)
     at java.util.Scanner.nextInt(Scanner.java:2000)
     at KeyMap.main(KeyMap.java:11)Well that's coz your listening for an Integer input.
the error should happen if you input non-integer data type.
Nywled

Mandatory User input question

Hello,
I am trying to write a script that I can use to list out all permissions in a SharePoint site (site).
I had a mandatory parameter set : [string]$SiteCollection
Where the user would need to type the site collection and then my command would use that input to find the permisssions for the site collection.
For my test I used our site collection called service. It never ran. After checking the variable $SiteCollection it took the name I typed in 'service' and actually ran the command, thus the variable $SiteCollection was filled with a list of all
the current services on the machine.
2 questions
1) How can I set the input of the mandatory variable to be literally what I type in, not running an alias such as 'service'
2) I though this might be better if I gave the user a list of site collections to pick from, thus they would not need to know the correct spelling. Is there a way to list out all the sites (Get-SPSite) in a list with a number next to them and the user
could then select the number that corresponds with the correct site collection as their input?
Thanks for you help

Hi Robert,
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Built-in Input question

I know this might sound like I'm new to iMac, but I am so I'm sorry for such a lame silly question.
I have a 27" iMac I use at work and I have an iPhone. I plug in my iPhone to my iMac input on the back of the computer to listen to music from my iPhone.
Oddly, I see the Input Level indicator showing sound input but I cant get it to actually play on the internal speakers on my iMac.
OUTPUT SETTING is set to Internal Speakers
INPUT SETTING is set to Line In
...and nothing...

Mac OS X does not automatically play audio directly from the line input to the speakers. Try the free app LineIn:
http://www.rogueamoeba.com/freebies/
Regards.

Scanner Input Validation

Hi, I hope Im posting to the right place.
I want to check to see if the user input is an integer and keep asking for one if the input is not an integer. Should be very simple but I cant do it because I just dont know how. Im not willing to use a "try and catch" since I dont know how to use that either.
This is what I got...
     int num;
     System.out.print("Please enter a number? ");
     Scanner sc = new Scanner(System.in);
     while (!sc.hasNextInt())
          System.out.println("That is NOT an Integer!");
          System.out.print("Please enter a number? ");
     num = sc.nextInt();
     System.out.println(num + " is an Integer!");Thank you...

This is what I did in a recent project(I use BufferedReader, not Scanner). There are actually quite a few ways to do it. You can check the each char to see if they are between 0-9, but a try/catch right in main but I found this to be most effective to keep the program running. It's not the fastest running time from what I've tried(checking each char to be 0-9 was probably fastest) but if you want full proof do something like this.
public class Test{
     public static boolean isInteger(String string){
          try{
               Integer.parseInt(string);
               return true;
          catch(NumberFormatException nfe){
               return false;
           public static void main(String[] args){
                String input;
                int n;
                BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
          //gets the number of students to input
          System.out.println("How many students are there?");
          try{
               input = in.readLine();
          catch (IOException ioe){
               System.out.println("IO error trying to read input");
                   System.exit(1);
               while(!isInteger(input) || input.equals("")){
                  System.out.println("Not a number, please input a number");
               try{
                    input = in.readLine();
               catch (IOException ioe){
                    System.out.println("IO error trying to read input");
                        System.exit(1);
             n = Integer.parseInt(input);

Classes and subclasses given as String input - question

Hello, I am new in Java so please don't laugh at my question!!
I have a method as the following and I am trying to store objects of the type Turtle in a vector. However the objects can also be of Turtle subclasses: ContinuousTurtle, WrappingTurtle and ReflectingTurtle. The exact class is determined by the String cls which is input by the user.
My question is, how can I use cls in a form that I don't have to use if-else statements for all 4 cases? (Imagine if I had 30 subclasses).
I have tried these two and similar methods so far but they return an error and Eclipse is not of much help in this case.
Simplified methods:
//pre: cls matches exactly the name of a valid Turtle class/subclass
//post: returns vector with a new turtle of type cls added to the end
private Vector<Turtle> newturtle(Vector<Turtle> storage, String cls){
     Turtle t = new cls(...);
     storage.add(t);
     etc.
private Vector<Turtle> newturtle(Vector<Turtle> storage, String cls){
     Turtle t = new Turtle<cls>(...);
     storage.add(t);
     etc.
}Thanks for your help.
p.s.: I didn't know whether to post this question here or under Generics.

a Factory is atually very simple (100x simpler than reflection).
example:
class TurtleFactory
public Turtle makeTurtle(String typeOfTurtle)
    if (typeOfTurtle.equals("lazy") { return new LazyTurtle(); }
    else if (typeOfTurtle.equals("fast") { return new FastTurtle(); }
    <etc>
}While at first this doesn't look any better than your original problem, what we've done is made a class that is responsible for all the types of turtles. This will also benefit in case some turtles need initialization or need something passed to their constructor. You encapsulate all that knowledge in one place so you rcode doesn't become littered with it else ladders.

Adobe form barcode scanner input

I made an Adobe form with X Pro. The purpose of the form is to inventory equipment. I use a barcode scanner to enter serial numbers into the form. When I scan the barcode (Code 39) of an item the serial number entered into the form is truncated. To ensure that the scanner was reading the barcode correctly I scanned a code while having notepad open, it input the entire serial number correctly. I did the same thing with Word and the serial was also input correctly. Why is the form truncating my serial number? I can type more in the field if I so wish so I know that a character limit is not the issue. I checked all of the text box's properties but see nothing incorrect or limiting.
Thanks for the help,
Goob

Sorry for never replying to your post. The problem is: I do not know why this is happening.
Your last sentence "on the Text Area the scan seems to stop before entering all digits but when I scroll back through, they are accurate" makes me think. As I wrote earlier, "A barcode scanner is basically just an input device like a keyboard", but very much faster. Somehow it seems that the software acts like it is encountering the carriage return before all the data digits have been processed.
But somehow it also seems to correct itself in a text area that allows multiple lines, but not in a single-line text field.
Yet that does not happen with my barcode scanner, but with yours and the o/p's.
Very confusing! Does anybody else have some thoughts on this?

Data Input Question

Hi!
I'm trying to input numbers from the console using "System.in". However, the numbers are never read right. I want to read one number per line. Let the code do the explaining as my explanations are usually not clear...
DataInput = new DataInputStream(System.in);
int Number = DataInput.readInt();What did I do wrong? Does "DataInputStream" only read binary data?

The question isn't about Java Native Interface programming so this isn't the right forum. Try the generic Java Programming forum instead.
But to answer it anyway, you are correct that java.io.DataInputStream.readInt treats the input as binary rather than as user-typed digit characters. See the docs for java.io.DataInput.readInt for details.
(Also suggest not naming local variables with an initial capital letter like DataInput or Number. It's confusing for an experienced Java programmer to read and can collide with class names.)
-slj-

Scanner input from other class

i have the following scanner class
import java.util.Scanner;
public class Input {
   // Prompted input of an int
   public static int getInt( String prompt ) {
      Scanner in = new Scanner(System.in);
       System.out.print( prompt + " : " );
       int result = in.nextInt();
       return result;
   // Prompted input of a float
   public static float getFloat( String prompt ) {
      Scanner in = new Scanner(System.in);
       System.out.print( prompt + " : " );
       float result = in.nextFloat();
       return result;
   // Prompted input of a word/token
   public static String getToken( String prompt ) {
      Scanner in = new Scanner(System.in);
       System.out.print( prompt + " : " );
       String result = in.next();
       return result;
however i want to edit the code to get the following things from a different class to be displayed when run.
String name = cname.getText();
int length = Integer.parseInt(length.getText());
any ideas on how to do this

Edit: Nevermind. I guess for the prompts.
ANY-who...
float f = Input.getFloat(/*prompt string */);
String s = Input.getText(/* prompt string */);
Input. ...etc.
Message was edited by:
jGardner

Scanner input VS keyboard input

Dear all,
We have a webdynpro application that receives it's input from a usb barcode scanner. The screens are working fine, but now there's an extra requirement, that for some input fields, it's mandatory that the input is coming from the scanner, and not from manual input with the keyboard.
Is it possible?
The barcode scanner behaves as an input device, without triggering events or so, so at this moment, we don't really know if the input is coming from a scanned barcode or from manual input with the keyboard.
Kind regards,
J.
PS: the scenario is where the web dynpro application runs on a desktop or laptop, so the alternative for handheld with barcodereader UIElement is not an option to solve this.

Hi
Please explain this point again : the scenario is where the web dynpro application runs on a desktop or laptop, so the alternative for handheld with barcodereader UIElement is not an option to solve this.
With external hardware device(Thumb print reader , Signature pad ) it has set of API which we can incorporate inside our application , challenging part is whether
such sort of solution is there in webdynpro or not , alternatively we can use JSP with java script to handle this with using IFRAME UI (which is deprecated) or webwidgetUI element (might available in 7.2 ).
further with your point
The barcode scanner behaves as an input device : Yes by default is get its place to write , we have to highlight that input field with current cursor position.
Hope you get some help?
Best Regards
Satish Kumar

Scanner input question.

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