Searching arrays using ascii

Question

I am trying to solve a book problem. I created an array with letters and numbers and I'm supposed to figure out how to count the number of letters in the array. I tried the following code:
public class ArrayBasics1
  public static void main(String[] args)
     char[] myChar = {'1','2','3','a','b','c','d','e','f'};
     int count = 0, uncount = 0, x = 0;
     for(x = 0; x < myChar.length; ++x)
       //myChar[x] = (char)x; Doesn't work
       if(myChar[x] > 96 && myChar[x] < 123)
          count += 1;
       else
               uncount += 1;
       System.out.println("The number of letters in myChar is " + count);
       System.out.println("The number of characters in myChar which are not letters is " + uncount);
}  I think I'm searching the subscripts rather than the content of the array. Any help would be appreciated.

Answer 1

I just ran your code and it gave the output:
The number of letters in myChar is 6
The number of characters in myChar which are not letters is 3
This looks good to me - what were you expecting? I'm not sure what you were trying to do with "//myChar[x] = (char)x; Doesn't work", but you don't need that line.
One improvement you might want to make is to use the Character.isLetter() method which also includes upper case letters. e.g. replace
if(myChar[x] > 96 && myChar[x] < 123)with
if (Character.isLetter(myChar[x]))Good Luck