Searching through directory looking for browser

Question

Hello all,
I was wondering if there is any way to search for the location of a file in your Java application and then launch the .exe file that is at that location.
(example: look for where Iexplore.exe is located on the current machine and then open up Internet Explorer using the the Runtime and Process classes.)
The way I have it now is a hardcoded path to Iexplore.exe. If it is not at that location, it will fail and I will display message "File not found at that location."
Thanks for all your help ahead of time,
jmschrei

Answer 1

You can launch explorer/navigator by
Runtime.getRuntime().exec("start http://www.web.com");
About searching a file:
public void searchFile(String dirName, String file)
throws IOException {
File directory = new File(dirName);
String path;
if (directory.exists() == true) {
path = directory.getPath();
if (directory.isDirectory() == true) {
File [] fileList = directory.listFiles();
for (int i = 0; i < fileList.length; i++) {
path = fileList.getPath();
if (fileList[i].isDirectory())
searchFile (path, file);
else if (fileList[i].isFile()) {
if(fileList[i].getName().equals(file))
Runtime.getRuntime().exec(fileList[i].getPath());
else {
if(fileList[i].getName().equals(file))
Runtime.getRuntime().exec(fileList[i].getPath());
This method should be called like:
searchFile("C:\", "iexplore.exe");
I hope it helps you.