Select distinct...again

I have data that contains a column of emails, a column of
names and
addresses... and so on.
some of the emails are the same and I don't want those to
show up.
I want to be able to pull a column of emails, a column of
names and a
column of adresss but I want to pull only those that have
distinct email
addresses.
When I
SELECT Distinct email, FName, LName
FROM table1
WHERE (MailList = 1)
It doesn't filter out the distinct. I'm guessing that you're
going to
say it's pulling from the row...
How would I make it so that I only see rows with distinct
emails?
Thanks
Lionstone?

Philo wrote:
> for MSSQL: The DISTINCT keyword is optional with SUM,
AVG, and COUNT.
> When DISTINCT is used, duplicate values are eliminated
before the sum,
> average, or count is calculated.
>
> Basically it eleminiates duplicates. That does not seem
to be what you
> are doing. By distinct do you mean none null emails
addresses? If so
> than something like "where email is not null" is what
you want.
>
> Art wrote:
>
>> I have data that contains a column of emails, a
column of names and
>> addresses... and so on.
>>
>> some of the emails are the same and I don't want
those to show up.
>>
>> I want to be able to pull a column of emails, a
column of names and
>> a column of adresss but I want to pull only those
that have distinct
>> email addresses.
>>
>> When I
>>
>> SELECT Distinct email, FName, LName
>> FROM table1
>> WHERE (MailList = 1)
>>
>> It doesn't filter out the distinct. I'm guessing
that you're going to
>> say it's pulling from the row...
>>
>> How would I make it so that I only see rows with
distinct emails?
>>
>> Thanks
>>
>> Lionstone?
It sounds like he wants to email all the unique email
addresses, so
DISTINCT should work as it avoids duplicates.
Maybe try:
SELECT DISTINCT TOP 100 email, FName, LName
FROM table1
WHERE MailList = 1
Steve

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    I have no clue why is this happening. I might be doing something wrong since a similar query with a nested cursor works with the scott/tiger schema. Your help is greatly appreciated. Thank you in advance.
    Alfonso.

    I was able to reproduce this error. This looks like a bug in the RDBMS; I would suggest posting on their newsgroup or working with support to handle this problem.

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