Select from partition, will it work ?

Hi, I have a partiotined TT_table:
CREATE TABLE RYBATEMP.T_STAT
( ACTDATE DATE,
COL_LIST, FORMAT_LIST..
TABLESPACE "RYBA_DATA" PARTITION BY RANGE
("ACTDATE" )
( PARTITION "D_20100901" VALUES LESS THAN (TO_DATE(' 2010-09-02 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIAN')) ....
I just want somehow to check that the following select will directly refer to wanted partition as expected not browsing thru whole table:
SELECT COL_LIST FROM T_STAT WHERE
ACTDATE >= to_date('01-SEP-10 00:00:00','DD-Mon-YY HH24:MI:SS') AND
ACTDATE <= to_date('01-SEP-10 21:01:16','DD-Mon-YY HH24:MI:SS')
This time on date parameter confuses me, even after reading thru defintionis where partition difined with HH:MI:SS format. Is there anay way to track it in Plan or something, never did it on Oracle.
Will it take greater/less/ signs ?
Thanks
Trent

Hi Trent,
Yes you will be able how things work with partitions in the explain plans.
I don't know your version but a few explanations in 9.2 for example :
http://download.oracle.com/docs/cd/B10500_01/server.920/a96533/ex_plan.htm#7211
If you want to know how to have complete trace etc. (example in 10.2) :
http://download.oracle.com/docs/cd/B19306_01/server.102/b14211/sqltrace.htm
(notice partitioning does not avoid the need of indexes)
Best regards
Phil

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Selecting from partition is taking too much time

The SEARCH_MEMBE_PROVIDER_ROLLUP is partitioned with range-list partition
ROLLUP_ID --range (about 30 partitions ) and other column with list subpartitioned (about 48)
*indexes on columns
b-tree global index on ROLLUP_ID
bitmap local index on ROLLUP_ID, MEMBERONE_ID_1010
bitmap local index on MEMBERONE_ID_1010*
I could not figured it out as some partition's data is coming fast and some partition's data is not coming at all(taking 18 minutes)
any help would be greatly appreciated and please let me know if need more information
Please see the following information
SQL> select * from v$version;
BANNER
Oracle Database 10g Enterprise Edition Release 10.2.0.4.0 - 64bi
PL/SQL Release 10.2.0.4.0 - Production
CORE     10.2.0.4.0     Production
TNS for HPUX: Version 10.2.0.4.0 - Production
NLSRTL Version 10.2.0.4.0 - Production
SQL> explain plan for SELECT COUNT (1)
2 FROM (SELECT LY.MEMBERONE_ID_1010
3          FROM (SELECT *
4                  FROM (SELECT dr.*
5                          FROM MEMBERONE_last1year dr)) ly
6         WHERE 1 = 1
7               AND LY.MEMBERONE_ID_1010 IN (SELECT RP.MEMBERONE_ID_1010
8                                              FROM SEARCH_MEMBE_PROVIDER_ROLLUP RP
9                                             WHERE RP.rollup_id = 7));
Explained.
SQL> @utlxplp
PLAN_TABLE_OUTPUT
Plan hash value: 677376773
| Id | Operation                       | Name                           | Rows | Bytes | Cost | Pstart| Pstop |
|   0 | SELECT STATEMENT                |                                |     1 |    18 |    84 |       |       |
|   1 | SORT AGGREGATE                 |                                |     1 |    18 |       |       |       |
|   2 |   NESTED LOOPS SEMI             |                                |   154K| 2707K|    84 |       |       |
|   3 |    INDEX FULL SCAN              | IX1_MEMBERONE_LAST1YEAR        | 2701K|    20M|    75 |       |       |
|   4 |    PARTITION RANGE SINGLE       |                                | 64749 |   632K|    84 |     7 |     7 |
|   5 |     PARTITION LIST ALL          |                                | 64749 |   632K|    84 |     1 |    48 |
|   6 |      BITMAP CONVERSION TO ROWIDS|                                | 64749 |   632K|    84 |       |       |
|* 7 |       BITMAP INDEX SINGLE VALUE | IX3_SEARCH_MEMBE_PROVIDER_ROLL |       |       |       |   289 |   336 |
Predicate Information (identified by operation id):
   7 - access("RP"."ROLLUP_ID"=7 AND "DR"."MEMBERONE_ID_1010"="RP"."MEMBERONE_ID_1010")
Note
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*THE ABOVE QUERY is taking more than 18 minutes*
========================
*THE BELOW QUERY is taking not even two seconds*
SQL> SELECT COUNT (1)
2 FROM (SELECT LY.MEMBERONE_ID_1010
3          FROM (SELECT *
4                  FROM (SELECT dr.*
5                          FROM MEMBERONE_last1year dr)) ly
6         WHERE 1 = 1
7               AND LY.MEMBERONE_ID_1010 IN (SELECT RP.MEMBERONE_ID_1010
8                                              FROM SEARCH_MEMBE_PROVIDER_ROLLUP RP
9                                             WHERE RP.rollup_id = 11));
COUNT(1)
    131575
Elapsed: 00:00:01.53
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2 FROM (SELECT LY.MEMBERONE_ID_1010
3          FROM (SELECT *
4                  FROM (SELECT dr.*
5                          FROM MEMBERONE_last1year dr)) ly
6         WHERE 1 = 1
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8                                              FROM SEARCH_MEMBE_PROVIDER_ROLLUP RP
9                                             WHERE RP.rollup_id = 11));
Explained.
Elapsed: 00:00:00.03
SQL> @utlxplp
PLAN_TABLE_OUTPUT
Plan hash value: 3092271485
| Id | Operation                 | Name                         | Rows | Bytes | Cost | Pstart| Pstop |    TQ |IN-OUT| PQ Distrib |
|   0 | SELECT STATEMENT          |                              |     1 |    18 |    80 |       |       |        |      |            |
|   1 | SORT AGGREGATE           |                              |     1 |    18 |       |       |       |        |      |            |
|   2 |   PX COORDINATOR          |                              |       |       |       |       |       |        |      |            |
|   3 |    PX SEND QC (RANDOM)    | :TQ10002                     |     1 |    18 |       |       |       | Q1,02 | P->S | QC (RAND) |
|   4 |     SORT AGGREGATE        |                              |     1 |    18 |       |       |       | Q1,02 | PCWP |            |
|* 5 |      HASH JOIN RIGHT SEMI |                              | 70780 | 1244K|    80 |       |       | Q1,02 | PCWP |            |
|   6 |       PX RECEIVE          |                              |   208K| 2034K|     6 |       |       | Q1,02 | PCWP |            |
|   7 |        PX SEND HASH       | :TQ10001                     |   208K| 2034K|     6 |       |       | Q1,01 | P->P | HASH       |
|   8 |         PX BLOCK ITERATOR |                              |   208K| 2034K|     6 |     1 |    48 | Q1,01 | PCWC |            |
|* 9 |          TABLE ACCESS FULL| SEARCH_MEMBE_PROVIDER_ROLLUP |   208K| 2034K|     6 |   481 |   528 | Q1,01 | PCWP |            |
| 10 |       BUFFER SORT         |                              |       |       |       |       |       | Q1,02 | PCWC |            |
| 11 |        PX RECEIVE         |                              | 2701K|    20M|    75 |       |       | Q1,02 | PCWP |            |
| 12 |         PX SEND HASH      | :TQ10000                     | 2701K|    20M|    75 |       |       |        | S->P | HASH       |
| 13 |          INDEX FULL SCAN | IX1_MEMBERONE_LAST1YEAR      | 2701K|    20M|    75 |       |       |        |      |            |
Predicate Information (identified by operation id):
   5 - access("DR"."MEMBERONE_ID_1010"="RP"."MEMBERONE_ID_1010")
   9 - filter("RP"."ROLLUP_ID"=11)
Note
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30 rows selected.
Elapsed: 00:00:00.54
SQL> spool offthanks again

Hi
1) there are two major differences between the plans: serial vs parallel and NESTED LOOPS SEMI vs HASH JOIN SEMI
2) NESTED LOOPS look like a bad choice here, and it also looks like the optimizer badly underestimates it's real cost. Which is a bit odd, because it knows that the outer rowsource has 2701K, i.e. the inner operation would have to be executed 2701K times. Looks like an optimizer glitch, which brings us to the point that Dan has already raised here: you shouldn't be running on an old unsupported version
3) regarding serial vs parallel: it could be due to difference in session settings (ALTER SESSION ENABLE/DISABLE PARALLEL QUERY)
4) the two plans have different values of the filter against rollup_id (7 vs 11), so one possible reason for different behavior is the histogram on SEARCH_MEMBE_PROVIDER_ROLLUP.rollup_id. If you can reproduce the issue on a test database, re-gather stats on this table without histograms (method_opt=>'for all columns size 1', no_invalidate=>false) and see if the problem goes away
Best regards,
Nikolay

Select from partition problem

hi all,
hope i'm in the right forum. i have 2 databases sitting in 2 separate machines. 1 installed with Oracle 9i and 1 with Oracle 10g. I'm trying to select a partitioned table in 9i remotely (from the 10g db). In order to do that, I've created a synonym in 10g pointing to the partitioned table in 9i.
In 9i, if i do a select "select count(*) from tableA partition (p1)", i'm able to grab the correct count of the partition. But when i use the same select statement in 10g, it's grabbing all the data of the table, sum of all partitions. it looks like the partition qualifier specified in the select statement has no effect. Can i know what is the problem? hope to get some response a.s.a.p. tq
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Select from partition, will it work ?

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