Select list -null value?

When you create a select list on a column, and run the page for the first time, the drop down doesn't show any value. I realized that once you click on the drop down to see what the values are, at the bottom of the list there is a blank value. But you can only see this the first time you load the page. Once you click on any other value, that blank value is gone. How does this work? How can I select the blank value even after you had selected other values previously?
Thanks,

Modify the Item Definition's List of Values options (Edit Page Item->LOV)
Display Null: Yes
Null Display Value:  

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    Hi
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  • How-To populate SELECT LIST default value from SQL Query

    OK, I've done my homework, and did not find my answer in the Forum, so here it is.
    I have a Page that displays fields from a SQL Query. The Page also has below that radiogroups, checkboxes, and Select Lists to allow the user to change values in the fields that are displayed at the top of the Region. I am able to pre-populate the radiogroups and checkboxes by performing a SELECT in the 'Source value or expression' of the Source area of the Page Item.
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    Thank you for the suggestion.
    I had considered that, but cannot do so, because we are using Oracle Application Express more for development than for data containment.
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    I have wondered about this for a while but haven't found an answer, maybe because I haven't searched for the right thing.
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    Denes Kubicek
    http://deneskubicek.blogspot.com/
    http://www.opal-consulting.de/training
    http://apex.oracle.com/pls/otn/f?p=31517:1
    -------------------------------------------------------------------

  • Dynamic Select List Allowed Values

    Howdy Folks,
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    Mike,
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    Jim

  • Select list display value in javascript function

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  • On button click of Infopath forms select multi select list box values...

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    http://www.bizsupportonline.net/infopath2007/programmatically-select-all-items-multi-select-list-box.htm
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    Regards,
    Please remember to mark the replies as answers if they help and unmark them if they provide no help. If you have feedback for TechNet Subscriber Support, contact
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  • Selection of Null Value in Transformation file

    Hi Guru's,
    I've been trying to select NULL values of a field in transformation file but unfortunately system always gets both null and filled values of the field ALTHOUGH i had maintained the Selection Option.
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    The technical name of field: 0FLAG
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    SELECTION: 0FLAG, *STR()
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    SELECTION: 0FLAG, "#"
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    Hi Sadi,
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    I hope, it will help you.
    Thanks.

  • SELECT LIST - with values after have values in other Select List

    My friends.
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    pesquisar

    Good afternoon,
    Try this for the definition of your select list:
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      from employees emp
    where emp.department = :P1_DEPT_NO
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    REWARDS: Please remember to mark helpful or correct posts on the forum, not just for my answers but for everyone! :)

  • Select List multiple values

    All,
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    bbbb, dddd

    No worries, I've found a way.
    You need to create a pl-sql function that generates the necessary HTML code that will render the select list using the selected="selected" attribute when the option value is selected.
    This is an example of the expected HTML code for a multiple selection list:
    <select name="favoritefood" id="favoritefood" multiple=true; size=4;>
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    <option value=2 selected="selected">Egg</option>
    <option value=3>Cabbage</option>
    <option value=4 selected="selected">Ham</option>
    </select>
    I created this function in order to find the matches within the saved code and the option value. And then include the selected="selected" string in the returned HTML code.
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    Regards
    Edited by: user9982480 on Jul 30, 2012 8:32 AM
    Edited by: user9982480 on Jul 30, 2012 8:33 AM
    Edited by: user9982480 on Jul 30, 2012 8:34 AM

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    The subject pretty much defines it. I have 3 items on a page select list, displays as text (based on LOV), and a text box. My idea is to display a control number in the select list. When the user selects the number that they want I would like the return value to fill in the displayed as text item. Then user can then use the text box to update that information.
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    Derek

    Try to compute that item.
    Denes Kubicek

  • Select List Display Value

    Hello All,
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    Hi,
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    I've been testing something here: [http://apex.oracle.com/pls/otn/f?p=33642:9] Click on a link for an employee on the right to see the data on the left - try ones with and without an entry in the MGR column.
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  • Select lists - remember values after submit not working in IE7

    I have two dynamic select lists that are populated using .csv
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  • Select a null value

    Hi to all , if anybody knows how to tackle with the following situation, please reply urgently. Thanx in advance.
    Suppose I have a table EMPLOYEE , with EMPLOYEE_ID as primary key , as:
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    1                        abc
    3                      pqr
    6                      xyz
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    6
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    Here's how i understand your problem. You have a table with n records. You run a query with an IN argument list. Rows that match the argument list should be returned by the query as they are, but for arguments that have no corresponding row in the table a row should be returned indicating the status. I have come up with a solution, though a bit complicated one. To test it first run following script and then execute the query at the end.
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    INSERT INTO employee
    values(3,'C')
    CREATE OR REPLACE TYPE emp_type AS OBJECT
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    EMPLOYEE_NAME varchar2(30));
    CREATE OR REPLACE TYPE emp_tab_typ AS TABLE OF emp_type;
    CREATE OR REPLACE TYPE arg_list_typ AS VARRAY(20)
    OF NUMBER;
    CREATE OR REPLACE FUNCTION emp_fun(p_arg arg_list_typ) RETURN emp_tab_typ
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      v_emp_tab emp_tab_typ:=new emp_tab_typ();
      v_cnt number:=0;
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       FOR r IN 1..p_arg.count LOOP
               v_cnt:=0;
               FOR x IN (SELECT E_ID,EMPLOYEE_NAME
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                       v_emp_tab(v_emp_tab.count):=emp_type(x.E_ID,x.EMPLOYEE_NAME);
                       v_cnt:=1;
               END LOOP;
               IF v_cnt=0 THEN
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             v_emp_tab(v_emp_tab.count):=emp_type(null,null);
               END IF;
       END LOOP;
       RETURN v_emp_tab;
    END;
    SQL> SELECT E_ID,nvl(EMPLOYEE_NAME,'Not Found')
      2  FROM TABLE(CAST(emp_fun(arg_list_typ(1,3,4)) AS emp_tab_typ))
      3  /
          E_ID NVL(EMPLOYEE_NAME,'NOTFOUND')
             1 A
             3 C
               Not Found
    3 rows selected.--------------
    Anwar

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