Selection Sort and arrays

Question

Hey im trying to pass a selection sort into an array. Here is my code....
public class SortTest {
     public static void main(String args[]) {
          int[] array = new int[20];
          SelectionSort ss = new SelectionSort();
          InsertionSort is = new InsertionSort();
          BubbleSort bs = new BubbleSort();
          System.out.println("Normal Array: ");
          System.out.println();
          for (int i = 0; i < 20; i++) {
               array[i] = (int) (Math.random() * 60 + 40);
               System.out.println(array);
               ss.sort(array);
               System.out.println(array[i]);
the ss.sort(array) is a method that has the selection sort code in it. I knwo the codes right too..My code prints out 10 sorted items and 10 items are 0. Anyone know why this is happening?

Answer 1

ok here is what my output is:
0
0
0
0
0
0
0
0
0
0
45
52
66
66
69
69
69
79
79
79
here is the selectino sort code:
public class SelectionSort {
     public void sort (int numbers[])
          int min, temp;
          for (int index = 0; index < numbers.length - 1; index++)
               min = index;
               for (int scan = index + 1; scan < numbers.length; scan++){
                    if (numbers[scan] < numbers[min])
                              min = scan;
               temp = numbers[min];
               numbers[min] = numbers[index];
               numbers[index] = temp;
}here is my test class updated a little:
public class SortTest {
     public static void main(String args[]) {
          int[] array = new int[20];
          SelectionSort ss = new SelectionSort();
          InsertionSort is = new InsertionSort();
          BubbleSort bs = new BubbleSort();
          for (int i = 0; i < 20; i++) {
               array[i] = (int) (Math.random() * 60 + 40);
               ss.sort(array);
               System.out.println(array);
sorry i didn't provide it earlier..