Session: Waiting and Working Chart

I am using OEM 10g (Grid control) to monitor my database.
But I don know what does the Y axis on the chart (Session: Waiting and Working) mean ?
Thanks for your help.
Note: Click Home page -> Database -> Performance -> Sessions: Waiting and Working.

2 store the user name in the session to display as a welcome message to the user when they are logged in.]
in class where you match the username and password .if given user is exist in records then set it into session
HttpSession session =request.getSession();
session.setAttribute("",);
3 tell the user they dont exist in the database or that there password is wrong and give them the option to either A) reset the password or B) create a user
in same class if user does not exist the redirect the request to different pages in that pages you put these two like A) reset the password or B) create a user

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Wait and notify in servlets?

i am having a servlet , which is implementing wait and notify of java.lang.Object.
when serving it for single request , its waiting and working fine...
but for multiple requests its not serving properly. works one by one means the second request is waiting for finishing the first request just like SingleThreadModel (after finishing the first request only second request entering inside servlet)
please help me to solve this?
or is there any other way to call wait method without synchronized block??

Shynihan wrote:
or is there any other way to call wait method without synchronized block??No, and that's partly because if wait or notify is the only thing in the synchronized block then you probably aren't using them right. The problem is blocking the server thread. Servlet engines use a thread pool to execute transactions, when a new transaction comes in a thread is taken from the pool to run it, and there's usually a limited number of threads in the pool. If there's no threads left then the transaction will wait for another to finish.
If your servlets freeze up, then that's a thread gone from the pool.
And remeber the unlocking transaction may never arive. The client could go down at any time, leaving the server thread permanently hung.
You need to move this waiting to the client side. If the transaction cannot proceed then return a "come back later" response immediately. The client can then retry after a decent interval.

Hi I am having problems downloading and updating apps on my iPad and iPhone. The message cycles between waiting and loading then I get an error message saying unable to download app. Eventually,after many attempts it works.

Hi Guys - for a few days I have been having problems downloading and updating apps on my iPad and iPhone. The message cycles between waiting and downloading then eventually says unable to download app. Sometimes after many attempts it wil eventually work. I tested it on an old iPhone 3G and got the same problem so it is not an iOS 5 issue. My WI-FI connection is working fine. I was wondering if this is an App Store problem? Anyone else in the UK having this problem?

Hi John
iTunes Support wasn't of any use to me.
I have also been having another problem - with BBC iPlayer and other video streaming not working due to insufficient bandwidth, despite my overall download speed being consistently around 50Gb. This is also affecting AppleTV downloads
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*http://www.superantispyware.com/ - SuperAntispyware
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Amadeusz
BTW This report bug is probably for Apple Developers/Apple Staff, however even as I'm registered developer, I can't find a way to contact them/you

This problem was already described (2011/08/11) here and I reported it as Bug # 9937633
Yvan KOENIG (VALLAURIS, France) mardi 13 septembre 2011 10:26:23
iMac 21”5, i7, 2.8 GHz, 4 Gbytes, 1 Tbytes, mac OS X 10.6.8 and 10.7.0
My iDisk is : <http://public.me.com/koenigyvan>
Please : Search for questions similar to your own before submitting them to the community

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Here are a bunch of things that you can try to get the downloads to resume.
Reboot the iPad by holding down on the sleep and home buttons at the same time for about 10-15 seconds until the Apple Logo appears - ignore the red slider - let go of the buttons.
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Ipad 3 ios5.1 apps categories and top charts stopped working.

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Synchronize work from multiple threads using wait() and notifyAll() help

Hello folks,
(Sorry for my bad english)
My current project handles multiple access requests to a shared collection from multiple threads originating from different classess and methods. Therefor I need to keep track of the order in which the Threads access that collection. I wrote a sort of Buffer class that has a static instance entry which initiate a new Instance of my Buffer class, attributes the instance a cue number and return the instance to the caller Thread.(Just like when you go to a supermarket and draw a number to wait to get served at the cheese counter).The callerThread then uses this instance to execute a method within the buffer class. Inside the buffer class method, I want to set a while loop on wait() just like this:
while(currentCue != myCueState)
wait();
when all other prior method calls within my Buffer class are done, the loop should wake up using a notifyAll() call and check the condition "currentCue != myCueState" agen to see if its turn has come.
I am new to the wait() and notifyAll() stuff and are therefor not sure what I am dooing wrong here: The only way this buffer class finishes all it's cues is when the caller Threads are beeing executed in the same order than they have checked in to the Buffer class. Otherwise I get some sort of dead-lock in the middle. Here is my code for the Buffer class:
public class Buffer{
    private static int currentCue = 0;
    private static int lastCued = 0;
    private int myCueState;
    private Buffer myInstance = null;
    synchronized void doTaskOne(){
        try{
            while(currentCue != myCueState)
                wait();
            //Do your task now
            System.out.println("doTaskOne got Executed: "+currentCue);
            currentCue++;
            notifyAll();
        catch(Exception a){}
    synchronized void doTaskTwo(){
         try{
            while(currentCue != myCueState)
                wait();
            //Do your task now
            System.out.println("doTaskTwo got Executed: "+currentCue);
            currentCue++;
            notifyAll();
        catch(Exception a){}
    synchronized void doTaskThree(){
        try{
            while(currentCue != myCueState)
                wait();
            //Do your task now
            System.out.println("doTaskThree got Executed: "+currentCue);
            currentCue++;
            notifyAll();
        catch(Exception a){}
    synchronized Object getSomething(){
        try{
            while(currentCue != myCueState)
                wait();
            //Do your task now
            System.out.println("getSomething got Executed");
            currentCue++;
            notifyAll();
        catch(Exception a){}
        return "something";
    //Access the buffer class through a single static synchronized instance and draw a turn number
    public synchronized Buffer instance(){
        myInstance = new Buffer();
        myInstance.setMyCueState();
        return myInstance;
    private void setMyCueState(){
         myCueState = lastCued;
         lastCued++;
}and here for the Test class I have coded to test this:
public class TestBuffer{
     private Buffer accessOne;
     private Buffer accessTwo;
     private Buffer accessThree;
     private Buffer accessFour;
     public TestBuffer(){
                //Instantiate different instances from Bufferclass and draw a number
          accessThree = new Buffer().instance();
          accessOne = new Buffer().instance();
          accessTwo = new Buffer().instance();
          accessFour = new Buffer().instance();
          Thread one = new Thread(){
               public void run(){
                    accessOne.doTaskOne();
          Thread two = new Thread(){
               public void run(){
                    accessTwo.doTaskTwo();
          Thread three = new Thread(){
               public void run(){
                    accessThree.doTaskThree();
          Thread four = new Thread(){
               public void run(){
                    accessFour.getSomething();
          try{
               one.start();
               two.start();
               three.start();
               four.start();
          catch(Exception f){}
     public static void main(String args[]){
          TestBuffer myTest = new TestBuffer();
}What am I doing wrong here??
Maby this is not how I should use the notifyAll() method, but how then?
Please give me a solution!
Thanks

Ok, so if I get you guys right, the following should do it:
public class Buffer{
    private static Object sharedLock = new Object();
    public void doTaskOne(){
          synchronized(sharedLock) {
            System.out.println("doTaskOne got Executed: ");
    public void doTaskTwo(){
         synchronized(sharedLock) {
            System.out.println("doTaskTwo got Executed: ");
    public void doTaskThree(){
         synchronized(sharedLock) {
              System.out.println("doTaskThree got Executed: ");
    public Object getSomething(){
        synchronized(sharedLock) {
            System.out.println("getSomething got Executed");
            return "something";
}Lets say that each method accesses the same ressources (in this case a table model) to retreave values, delete rows and set some existing values vith new values and all this 20-30 times a minute, all processing will stay synchronised and collision is not possible?
And lets say I would update the Table model directly from the buffer Class using MyTableModel.instance().setValueAt() or watever methods I implemented on my Table model, could I safely do that using "SwingUtilities.invokeLater();" from my BufferClass just like this:
public void doTaskThree(){
        synchronized(sharedLock) {
               Runnable runme = new Runnable(){
                     public void run(){
                            MyTableModel.instance().setValueAt("abc", 5,5);
               SwingUtilities.invokeLater(runme);
}Thanks in advance for your help guys!

In-memory replication of http session is not working in BEA7 cluster

 Hi everyone,
 I have 3 managed servers in Bea7.0 SP4 in a cluster. The client requests are sent
 through apache web server. I have given cluster address as URL in httpd.conf of
 apache server which sends the client requests for dynamic pages such as JSPs and
 servlets to the weblogic cluster.
 Load balancing is working fine. I ensured this from the log files of all the 3
 servers. All the 3 servers are getting different client requests and thus load
 balancing is working.
 Now, I wanted to achieve Fail-over. I do not think that i should use proxy plug-in
 for this. I feel the cluster itself will handle fail-over provided i make the
 http session as memory replicated.
 I updated the weblogic.xml with the following entry :
 <session-descriptor>
 <param-name>PersistentStoreType</param-name>
 <param-value>replicated</param-value>
 </session-param>
 </session-descriptor>
 I guess this is sufficient to make the http session as cluster aware.
 But when I shutdown server1, the user connected to server1 will be kicked out
 of the session and come to login page through server2 or server3 which are running
 fine.
 Could anyone help me to achieve http session as cluster aware. Does it indicate
 that I have to go for WLS proxy – HttpClusterServlet to achieve fail over for
 http session ?
 BTW, for your info, i am using setAttribute() and getAttribute() while manipulating
 the session.
 thanks in advance.


 Hi Ryan,
 Thanks for ur valuable input.
 I can see failover working.
 But, I can not continue with the same session in my application.
 I printed session Ids before and after failover, I found both are different.
 I guess session replication is a responsibility of weblogic/apache plugin.
 If not please let me know which all settings I should do to make failover working?
 Thanks again.
 Plad
 "ryan upton" <ryanjupton at learningvoyage dot com> wrote:
 >Plad,
 >
 >Are you trying to gracefully shut down the server? If you are then the
 >problem that you say you can't identify is simply the server's default
 >behavior which is to wait for all non-replicated sessions to be dropped
 >or
 >timed out before killing the process. Try forcing the shutdown: kill
 >-9 the
 >PID or CTRL-C if you started the server from the command line. You can
 >also
 >check the ``Ignore Sessions During Shutdown" checkbox under the server's
 >control tab in the admin console, this should allow you to shut down
 >gracefully without waiting for session timeout. BTW your sequence is
 >off
 >in #5 below, the replication doesn't occur upon failure, the replication
 >has
 >already happened once you created the session object on the first server,
 >I
 >think maybe you're confusing replication with failover.
 >
 >~RU
 >
 >"Plad" <[email protected]> wrote in message
 >news:[email protected]...
 >>
 >> Hi,
 >> I have 2 managed servers in a cluster.
 >>
 >> 1. I have got a DNS name configured which maps to these 2 managed server's
 >IP
 >> addresses.
 >> 2. I can browse my site using this DNS name.
 >> In HTTPD.conf I have :
 >>
 >> ServerName dev.a.b.net
 >>
 >> <IfModule mod_weblogic.c>
 >> WebLogicCluster 10.1.38.232:7023,10.1.34.51:7023
 >> MatchExpression *.*
 >> </IfModule>
 >>
 >> LoadModule weblogic_module modules/mod_wl_20.so
 >>
 >> 3. I have adeded session descriptor in weblogic.xml , also enabled
 >proxy
 >plugin
 >> in weblogic console.
 >>
 >> 4. I tested accessing my application using DNS url after shutting down
 >alternatively
 >> each manaed server. I can access application.
 >>
 >> 5. Now, problem comes when I access a managed server1 , keeping server2
 >down.
 >> I am able to access my application.
 >> Now, I start the server2.
 >> (Here I am supposing that replication should occur)
 >> Then I am shutting down server1.
 >> But, this time the server log shows me following:
 >>
 >>
 >> 9:58:51 AM GMT+05:30 NOTICE Web application(s) chlist still have
 >non-replicated
 >> sessions after 2 minutes of initiating SUSPEND. Waiting for non-replicated
 >sessions
 >> to finish.
 >> 10:00:51 AM GMT+05:30 NOTICE Web application(s) chlist still have
 >non-replicated
 >> sessions after 4 minutes of initiating SUSPEND. Waiting for non-replicated
 >sessions
 >> to finish.
 >>
 >> I am unable to make out where the problem is?
 >> Can it be a problem of Liecense? Is there any specialcluster liecense
 >for
 >weblogic8?
 >>
 >> Hoping to get replies.
 >> Thanx.
 >> Plad
 >>
 >> "ryan upton" <ryanjupton at learningvoyage dot com> wrote:
 >> >See my reply to your first post, but I've also added a few comments
 >here.
 >> >
 >> >"jyothi" <[email protected]> wrote in message
 >> >news:[email protected]...
 >> >>
 >> >> I guess someone from bea support team only can answer both your
 >question
 >> >and mine.
 >> >> As per my knowledge, we do not need to do any setup at Apache
 >side
 >> >regarding
 >> >> cluster other than mentioning cluster address as URL while
 >contacting
 >> >WLS
 >> >> from apache.
 >> >>
 >> >> I hope someone from Bea, will help us. I do not think that we
 >> >go for
 >> >WLS
 >> >> proxy plug-in using HttpClusterServlet for making session replication.
 >> > I
 >> >strongly
 >> >> feel that the cluster itself be able to manage the fail-over of
 >> >http
 >> >sessions
 >> >> provided we put the entry "PersistentStoreType" in weblogic.xml
 >> >regarding
 >> >> the session replication.
 >> >>
 >> >
 >> >The cluster does handle the management of Sessions. The clustered
 >> >applications still create the Session objects and the cluster manages
 >> >them
 >> >as per your deployment descriptor settings (replicated, JDBC, File)
 >however
 >> >the proxy has to be aware of which server the client has an affinity
 >> >for
 >> >(only with replicated sessions) and it does that by reading a cookie
 >> >passed
 >> >back from the server that handled the initial request and created
 >the
 >> >primary session object. The proxy has a list of both the primary
 >and
 >> >secondary server locations from this cookie that it can use to failover
 >> >the
 >> >request if the primary server fails. Clusters _DO NOT_ failover nor
 >> >do they
 >> >load balance, that's the job of your proxy, whether you're using the
 >> >HTTPClusterServlet, WLS Plug-in or a more sophisticated hardware load
 >> >balancer like Big IPs F5
 >> >
 >> >> jyothi
 >> >>
 >> >
 >> >~RU
 >> >
 >> >
 >>
 >
 >

Session state and browser cache - Back button problem

Hi all,
I have a problem (and unless I'm missing something I think we all do) with session state and use of the browser's Back button. I really hope I'm just being dumb...
Background scenario:
Page P has a sidebar list allowing the user to select what content is displayed (e.g. 'stuff relating to X, Y or Z' where X, Y and Z are rows in, say, a table of projects). When a list entry is clicked, we branch to page P with the value of the list item placed in an application-level item (call it G_PROJECT). Reports on page P use G_PROJECT in their WHERE clauses.
So, click list entry X and G_PROJECT is set to X and page P shows reports for project X.
Page P also has a set of buttons which branch to various edit pages which allow attributes of page P's current project to be updated. These pages similarly use G_PROJECT in their WHERE clauses.
Problem scenario:
1. The user goes to page P and picks project X off the list. Project X's stuff is displayed (G_PROJECT = X).
2. The user then picks project Y off the list. Project Y's stuff is displayed (G_PROJECT = Y).
3. The user then clicks the browser's Back button. The page is served from browser cache, so project X's stuff is displayed, but G_PROJECT still = Y.
4. The user clicks an 'Edit' button; we submit, and branch to an edit page which displays (and will edit) data for project Y because G_PROJECT still = Y.
This is SERIOUSLY BAD NEWS - apart from being confusing, the user's edit permissions on projects X and Y may differ, and so the user may be able to perform 'illegal' updates.
I've read what I can on this forum and the rest of the web looking for ways to a) inhibit browsers' 'Back' functions and/or b) prevent pages being cached by the browser, but none of them have worked for me.
Short of waiting for browser manufacturers to recognise that the web is now full of applications as well as static pages, and enable robust programmatic control of cache behaviour, does anybody know how the problem can be avoided - or at least detected?
Thanks,
jd
Failed attempts to date:
<meta http-equiv="cache-control" content="no-cache">
<meta http-equiv="cache-control" content="no-store">
<meta http-equiv="cache-control" content="private">
<meta http-equiv="cache-control" content="max-age=0, must-revalidate">
<meta http-equiv="expires" content="Wed, 09 Aug 2000 01:01:01 GMT">
<meta http-equiv="pragma" content="no-cache">
Disallowing duplicate submission (page attribute).
window.history.go(1);

Thanks Scott,
I may be being dumb here but I don't see how that would help...
P250_PROJECT and G_PROJECT are currently kept in sync by app logic. Whichever is used to drive, if the page is rendered from cache then the app logic is not executed, so the rendered page contents are not those keyed by P250_PROJECT, as illustrated in steps 1-4 of the problem above.
The user sees X, the session items say Y. The engine doesn't know what the user is seeing.
when page P is POSTed, its hidden item P250_PROJECT should always be used to derive the application item G_PROJECT. Then whether the page was pulled from cache or rendered anew via a click from the sidebar link, the project ID is determined by the contents of that page.
As I said above I tried this, with the 'Edit' branch set to:
Set these items: G_PROJECT
With these values: &P250_PROJECT.
but it makes no difference. The project ID is not determined by the rendered page contents - the engine gets the value of P250_PROJECT from session state.
I can code the 'Edit' pages such that they check permissions and if necessary redirect back to p250 (conditional before-header branch), but that's a clunky cure rather than the prevention I was hoping for.
Please tell me if my understanding is incorrect.
jd

"read by other session" wait

Hi all,
I have a query with very little cost, it only access one row of the table from a primary key and joins it another table again on primary key column. It doesn't even take a second to complete.
But the problem is when there is another session that accesses data from one of the tables, I encounter "read by other session" wait event, so I wonder if there is a hint to overcome this wait, that will force query to make a disk read without waiting any other working session to put it into buffer cache. Or any other suggestions?
Thanks

seth2 wrote:
Hi all,
I have a query with very little cost, it only access one row of the table from a primary key and joins it another table again on primary key column. It doesn't even take a second to complete.
You also say in a later post that the cost of the plan is 11 - if this is correct then your two indexes must have a blevel of about 5 to get that cost from that plan. It seems highly likely that your query doesn't always take the plan you expect and that the "10 minute" versions of this query (which should take less than 0.1 seconds on any reasonable system) is doing a large tablescan to spend so much extra time and report "read by other session". I would check v$sql for multiple child cursors and v$sql_plan (using dbms_xplan.display_cursor if you're on 10g) to check executions plans.
Regards
Jonathan Lewis
http://jonathanlewis.wordpress.com
http://www.jlcomp.demon.co.uk
To post code, statspack/AWR report, execution plans or trace files, start and end the section with the tag {noformat}{noformat} (lowercase, curly brackets, no spaces) so that the text appears in fixed format.
"Science is more than a body of knowledge; it is a way of thinking"
Carl Sagan

RAC 10.2.0.5 - Session waiting forever

Hi, i feel alone
The database has several sessions that are waiting forvever.
Sometimes these sessions are wainting for "direct path read", or "read by other session"
The objects on which the sessions are waiting are never the same (user table, or LOB, ...)
The OS process associated with the database session doesn't exists anymore on the system.
The connection is made with JDBC THIN CLIENT.
NO error messages as the session is just waiting indefinitly
If a start a new session and issue a simple SQL SELECT on the waited objects on both instance.
The first instance return the resultset. The second instance just wait forever.
After the blocked objects is rebuilt, SQL SELECT works fine from both instance.
Killing the waiting sessions doesn't solve the probleme as next same SQL QUERY from the other instance, will be blocked too ...
Rebuild the object solve the problem ...
BUT THIS IS FAR NOT A GOOD SOLUTION !
The database is Oracle 10.2.0.5 SE RAC for LInux RHEL5 x64.
ASM is used.
Thank you for any suggestions !

Hi,
thank you for your response.
This is a STANDARD EDITION with all tables degree set to 1, and all indexes degrees set to 1 or 0.
I kill the session selected with the following query (the ones with high last_call_et)
select inst_id, username, last_call_et, event, row_wait_obj# from gv$session where status='ACTIVE' and state='WAITING' and username is not null;
Sometime, just kill the session solve the problem
Now, i got 1 session waiting forever on "read by other session" on table SYSTEM.SQLPLUS_PRODUCT_PROFILE the SQL executed is
"analyze table infomed2.dm_ligne ....;" .
The same problem appears on 2 differents databases on the same RAC cluster (all in 10.2.0.5)
i guess a bug with dictionnary latch, or with gcs, or with sqlnet( session closed but not realeased), ... but cannot find any information

Session timeout and custom sso

Hi,
can anyone tell me how the session and idle timeout feature in Apex exactly works?
I built several applications in a workspace and do a sso authorization by setting a common cookie name. In addition to that i set the values for session length and idle timeout and assumed that the session length would be synchronized over all applications. But this doesn't seem to work. For instance, i set the idle timeout to 10 minutes in all applications and now i work for 15 minutes continously in application A and after that i switch over to application B (using the same session id!), the session is already expired in B.
Is this behavior correct? And, if yes, how can i set up a synchronization over all applications?
Jens

Anyone?

Session: Waiting and Working Chart

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