SQl Developer - making multiple tables

I have the following code:
CREATE TABLE "STAFF"
"STA_ID" VARCHAR2(20 BYTE) NOT NULL ENABLE,
"STA_SURNAME" VARCHAR2(20 BYTE),
"STA_FIRSTNAME" VARCHAR2(20 BYTE),
"STA_STARTDATE" DATE,
"STA_JOBTITLE" VARCHAR2(20 BYTE),
"STA_SALARY" NUMBER,
"STA_ACTIVE" VARCHAR2(20 BYTE),
"STA_STAMP" VARCHAR2(20 BYTE),
PRIMARY KEY ("STA_ID"),
CONSTRAINT staff_ck_sta_salary CHECK (STA_SALARY>0 AND STA_SALARY<100000.00)
CREATE TABLE "HIRE"
"HIR_ID" VARCHAR2(20 BYTE) NOT NULL ENABLE,
"HIR_BRA_ID" VARCHAR2(20 BYTE),
"HIR_CUS_ID" VARCHAR2(20 BYTE),
"HIR_STA_ID" VARCHAR2(20 BYTE),
"HIR_HIREDATE" DATE,
"HIR_DUEDATE" DATE,
"HIR_RETURNDATE" DATE,
"HIR_CHARGE" VARCHAR2(20 BYTE),
"HIR_PENALTY" VARCHAR2(20 BYTE),
"HIR_TOTALPAID" NUMBER,
"HIR_COMMENTS" VARCHAR2(50 BYTE),
"HIR_STAMP" VARCHAR2(20 BYTE),
PRIMARY KEY ("HIR_ID")
In SQL Developer, if I select the SQL code for each table individually, I can run the statement and create each table. My question is this... can I select both lots of code and then create the tables with one press of the run statement button. I am asking this because I have many tables, and it is slow to do each one, one at a time.
thanks
Canning

Hi,
that is possible in sql * plus. but i don't know that option is there in sql developer or not.
i think you have the sql plus so you can execute from that also.

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Regards,
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http://download-west.oracle.com/docs/cd/B14117_01/server.101/b10825/ldr_control_file.htm#sthref852
Distinguishing Different Input Record Formats
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Hi gurus,
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This is the Output I hope for:
0
- 10, 'Company Blue1', 0
-- 101, 'Part Blue1', 10
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---- 10001, 'Hans Mueller', 1001
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Table1:
tbl_company (c_id, company_name)
Values:
10, 'Company Blue1'
20, 'Company Red1'
30, 'Company Green1'
Table2:
tbl_company_parts (cp_id, part_name, company_id)
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101, 'Part Blue1', 10
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2, 'Special Problems Blue', 101
3, 'Information Technology Blue', 102
4, 'Accounting Red',201
5, 'Accounting Green',301
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Values:
1, 'Hans Mueller', 1
2, 'Stephen Meyer', 2
3, 'Carlos AncetoÄ, 2
4, 'Carl Van Deser',4
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Hi Tobias,
It was not exactly clear how the id's had to be calculated, but this example will get you going:
SQL> create table tbl_company (c_id, company_name)
2 as
3 select 10, 'Company Blue1' from dual union all
4 select 20, 'Company Red1' from dual union all
5 select 30, 'Company Green1' from dual
6 /
Table created.
SQL> create table tbl_company_parts (cp_id, part_name, company_id)
2 as
3 select 101, 'Part Blue1', 10 from dual union all
4 select 102, 'Part Blue2', 10 from dual union all
5 select 201, 'Part Red1',20 from dual union all
6 select 301, 'Part Green1',30 from dual
7 /
Table created.
SQL> create table tbl_departments (d_id, dept_name, part_id)
2 as
3 select 1, 'Accounting Blue', 101 from dual union all
4 select 2, 'Special Problems Blue', 101 from dual union all
5 select 3, 'Information Technology Blue', 102 from dual union all
6 select 4, 'Accounting Red',201 from dual union all
7 select 5, 'Accounting Green',301 from dual union all
8 select 6, 'Special Problems Green',301 from dual
9 /
Table created.
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2 as
3 select 1, 'Hans Mueller', 1 from dual union all
4 select 2, 'Stephen Meyer', 2 from dual union all
5 select 3, 'Carlos Anceto', 2 from dual union all
6 select 4, 'Carl Van Deser',4 from dual union all
7 select 5, 'Geromel Boats', 4 from dual union all
8 select 6, 'Loui Van Ecke',5 from dual union all
9 select 7, 'Peter Finnighan',6 from dual union all
10 select 8, 'Tobias Tries',3 from dual
11 /
Table created.
SQL> select coalesce
2         ( case when e.department_id is null then null else
3             trunc(d.part_id,-2) * 100 + dense_rank() over (partition by d.part_id order by e.e_id)
4           end
5         , trunc(d.part_id,-2) * 10 + dense_rank() over (partition by d.part_id order by d.d_id)
6         , p.cp_id
7         , c.c_id
8         , 0
9         ) id
10       , coalesce
11         ( e.emp_name
12         , d.dept_name
13         , p.part_name
14         , c.company_name
15         ) name
16       , coalesce
17         ( trunc(d.part_id,-2) * 10 + dense_rank() over (partition by d.part_id order by d.d_id)
18         , d.part_id
19         , p.company_id
20         , case grouping(c.c_id) when 0 then 0 end
21         ) parent_id
22    from tbl_company c
23       , tbl_company_parts p
24       , tbl_departments d
25       , tbl_employees e
26   where c.c_id = p.company_id
27     and p.cp_id = d.part_id
28     and d.d_id = e.department_id
29   group by rollup
30         ( ( c.c_id,c.company_name)
31         , ( p.cp_id,p.part_name,p.company_id)
32         , ( d.d_id,d.dept_name,d.part_id)
33         , ( e.e_id,e.emp_name,e.department_id)
34         )
35   order by c.c_id nulls first
36       , p.cp_id nulls first
37       , d.d_id nulls first
38       , e.e_id nulls first
39 /
        ID NAME                                                                               PARENT_ID
         0
        10 Company Blue1                                                                              0
       101 Part Blue1                                                                                10
      1001 Accounting Blue                                                                         1001
     10001 Hans Mueller                                                                            1001
      1002 Special Problems Blue                                                                   1002
     10002 Stephen Meyer                                                                           1002
     10003 Carlos Anceto                                                                           1002
       102 Part Blue2                                                                                10
      1001 Information Technology Blue                                                             1001
     10001 Tobias Tries                                                                            1001
        20 Company Red1                                                                               0
       201 Part Red1                                                                                 20
      2001 Accounting Red                                                                          2001
     20001 Carl Van Deser                                                                          2001
     20002 Geromel Boats                                                                           2001
        30 Company Green1                                                                             0
       301 Part Green1                                                                               30
      3001 Accounting Green                                                                        3001
     30001 Loui Van Ecke                                                                           3001
      3002 Special Problems Green                                                                  3002
     30002 Peter Finnighan                                                                         3002
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Rob.

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Ex.
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Hello I am learning PL/SQL. I have a simple procedure where I need to find number of employees and departments per location as per user input of location_id.
I have 3 Tables:
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location_name
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department_id (pk)
location_id (fk)
department_name
EMPLOYEES
employee_id (pk)
department_id (fk)
employee_name
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Here is the query I came up with for PL/SQL procedure:
/*Ecount, Dcount are NUMBER variables */
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Thanks in advance for helping a newbie out.

Hi,
Welcome to the forum!
Something like this will be more efficient:
SELECT    COUNT (employee_id)               AS ECount
,       COUNT (DISTINCT department_id)     AS DCount
FROM       employees
WHERE       department_id IN (     SELECT     department_id
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Hi,
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