SQL elements int an array?

I want to get the names from each record in the following table and store them in an array according to their club.
The database looks like this:
PlayerID     PlayerPosition     PlayerFirstName     PlayerLastName     Club
1     GK     S     Taylor     ARS
2     GK     J     Lehmann     ARS
3     GK     S     Postma     AV
4     GK     T     Sorensen     AV
5     GK     N     Vaesen     BIR
class GetPlayersFromDatabase
     public GetPlayersFromDatabase() throws IOException
               String [] ClubNames = {"ARS", "AV", "BIR", "BLA", "BOL", "CHA", "CHE", "EVE", "FUL", "LEE", "LEI", "LIV", "MC", "MID", "MU", "NEW", "POR", "SOT", "TOT", "WOL"};
               String tempClubName = "";
               int size = ClubNames.length;
               for ( int index=0; index < size; index++)
                    String sql = " SELECT Club FROM PlayerTable WHERE Club ='" +tempClubName+ "';
                    String []ARSNames = {};
                    String []AVNames = {};
                                                                                      //all the way to
                     String []WOLNames = {};
     }I want ARSNames = {Taylor,Lehmann,<->,Henry,etc.} , AVNames = {Postma,Sorensen,<->,Solano,etc.}
all the way to WOLNames = {}.
Basically once I've got what I want from the SQL statement above how do I insert each field into the array?
Any help plese guys and girls???

Ugh. I used "Club" because that's what your SQL statement is retrieving. My guess is that you will want to restructure that query so it grabs the name, rather than the Club; otherwise, you're going to get a big List of the same string....
P.S. look at creating a "Player" class to encapsulate that information...

Similar Messages

How do you assign multiple values to a single element in an array?

I'm probably not wording the question right.
I have an array, let's call it M[], and for each element in the array (we'll say M[1]), I need assign three integers: row, col and value.
I need to set it up so I can do something like this:
A.row = M[i].col;
A[i].col = M[i].row;
A[i].value = M[i].value;
The algorithm isn't what I need help with, it's assigning .col, .row and .value to an index of an array.
Please help if you can.

You are right. You did not word your question perfectly, but I still think I get what you want.
First of all: A single element in an array always has exactly one value. No more, no less.
But that's not a problem. The element in an array is either of a primitive type (boolean, byte, char, short, int, long, float, double) or it's a reference (to a Object, String, MyClass, ...).
You can simply write a class that holds your three values and create an array of that type:
public class SomeData {
public int row;
public int col;
public int value;
// somewhere else:
SomeData[] a = new SomeData[10];
a[0] = new SomeData();
a[0].row = 10;
a[0].col = 5;
a[0].value = 42;Note how you only assign a single value to the element (a[0]) itself. All other assignment actually go to fields of the object refered to by that element in the array.
Also note that in Java types (such as classes, interfaces, ...) should start with a upper-case letter, while variables (local variables, members, parameters) and method names should start with a lower-case letter.
Edit: I'm getting old ...

How do I extract the length of an element in an Array List

Hello there,
I am facing this problem with an Array List of elements. I am trying to extract the individual length of a particular element in the array list . Now if I know the element is a String is this valid?
int lengthOfElement = 0;
lengthOfElement = ((String)parms.get(i)).length();
Your answer is much appreciated
Regards

Snap!I don't know how many times I've seen people post
saying that they have a list where each element is a
String, but they keep on getting ClassCastException :)Damn those Integers!
� {�

Sort an an arrayList by the first element of an array

Hi,
I am really struggling trying to sort an arratList of arrays. I have an arrayList
ArrayList<String[]> myArrayList = new ArrayList<String []>(100);
Within this array I have may arrays with 2 elements
String[] myArray1 = {"Peter", "London"};
String[] myArray2 = {"John", "London"};
String[] myArray3 = {"Tony", "Birmingham"};
I add all these arrays to the arrayList and want to sort by the first element of the array. Basically I expect the final arrayList to be in the order of:
"John", "London"
"Peter", "London"
"Tony", "London"
Thanks
Peter

Hi,
I am really struggling trying to sort an arratList of
arrays. I have an arrayList
ArrayList<String[]> myArrayList = new
ArrayList<String []>(100);
Within this array I have may arrays with 2 elements
String[] myArray1 = {"Peter", "London"};
String[] myArray2 = {"John", "London"};
String[] myArray3 = {"Tony", "Birmingham"};
I add all these arrays to the arrayList and want to
sort by the first element of the array. Basically I
expect the final arrayList to be in the order of:
"John", "London"
"Peter", "London"
"Tony", "London"
Thanks
PeterThis can be done by using
Collections.sort(myArrayList, new Comparator<String[]>() {
public int compare(String[] s1, String[] s2) {
if (s1.length() <1) {
return -1;
if (s2.length() <1) {
return 1;
return s1[0].compareTo(s2[0]);
});

Number of elements in an array

Hi,
I have been trying looking for a simple function to get number of elements is an array. Have gone though older posts but could not find answer to it.
The function should work for following examples:
char* name = "nInstruments"
float state[] = {1.0, 2.0}
I tried sizeof but it returns size of "type" in bytes. For example in example 2, it will just return 4.
Does someone know a way to do it?
Ciao
RB
Solved!
Go to Solution.

RB,
In C, if an array is declared on the heap, as opposed to on the stack as in your example above, the sizeof operator only returns the length of the pointer that holds the array which, in a 32-bit program, is always 4 bytes. This is because the compiler has no way of knowing how many elements that array actually holds. The length of a C array is a fairly fluid concept. The real size of the array is usually determined by some memory manager somewhere (usually, malloc), but it's not something that the language itself has anything to say about.
When you declare the entire array as a local variable, however, the compiler must create room for the full array on the stack, and therefore it is able to return the true size of the array via the sizeof operator. (The same is true if it's a global variable, even if it's not on the stack, in that case)
For this reason, using the sizeof(array) / sizeof(array[0]) trick is iffy. It might work, or it might not work, depending on how the array is declared.
For this reason, most C APIs that accept or return arrays, will usually also have some method of communicating the length of the array, usually as an additional parameter of some function. Because .NET APIs usually have no need to do this, the C wrapper for a .NET API in CVI does this for you when it handles .NET arrays. For example, here's what a function signature might look like:
int CVIFUNC Namespace1_Class1_Test1DArrays (Namespace1_Class1 __instance, int * inA, int __inALength, char *** outA, int * __outALength, Namespace1_Class2 ** refA, int * __refALength, double ** __returnValue, int * ____returnValueLength, CDotNetHandle * __exception);
Luis

How Do I Print the Number of Elements in An Array

How do I print: "There are ____ number of elements in the array?"

If you have a String holding a sentence, and if you split on non-empty sequences of whitespace (if the string has newlines in it, you'd probably need to pass the argument that makes \s match newlines, and for that you would probably need to use java.util.regex.Pattern -- see the docs and try some tests), when you'd get an array of Strings that were the non-whitespace parts of the original String. That makes for a reasonably good definition of the words in the sentence, although you could arguably get into some gray areas (does "isn't" count as one or two words? Does a sequence of numbers or punctuation qualify as a word?). In that case, counting the number of elements in the resulting array of String. using .length, would be a reasonable way to get the number of words in that sentence, yes.
But rather than asking for confirmation on forums, why don't run some tests?
import java.io.*;
public class TestWordCount {
public static void main(String[] argv) {
    try {
      BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
      String line;
      while((line = in.readLine()) != null) {
        int count = // your code here, to count the words
        System.out.println("I see " + count + " words.");
    } catch (IOException e) {
      e.printStackTrace();
}Put your word-counting code in there, then run it from the command line. Type in a sentence. See how many words it thinks it found. Does it match with your expectation, or the examples given (hopefully) with your homework assignment?

Counting number of elements in an array which aren't empty?

i tried using this method to count an array which has 100 elements but it doesn't go past the while statement which i cant figure out?
public static void countCust()
int cntr = 0;
int z;
for (int c = 0; c < 100; c++)
while (customer[c].indexOf(':') != -1)
cntr++;
javax.swing.JOptionPane.showMessageDialog(null, "There are " + cntr + " customers on record");
}

Are you getting NullPointerExceptions?
Are you sure customer[] has been allocated?
Are you sure each element in the array is non-null?
BTW, it's traditional to use variables in loops that are closer to their mathematical usage. I mean, for an array index, usually you'd use variables named i or j, unless the indices map to coordinates in space, in which case you'd use x, y, and z.
If neither of these is applicable, use a variable with a more meaningful name.

Can;t find what is wrong. Trying to add elements in two arrays

Hello everyone
I'm trying to take as input two numbers, convert them to arrays and add all the element of the array one by one. I want the result to be the sum of every element of the array. Let's say array1={1,2,3,4} and array2={2,6,4,3} I want the final result to be 3877.
If the sum of one element of the array is greater than nine, then I would put zero and add 1 to the element on the left.
Here is the code:
import javax.swing.JOptionPane;
public class Main {
    public static void main(String[] args) {
        String numberOne = JOptionPane.showInputDialog
                                ("Enter the first number: ");
     String numberTwo = JOptionPane.showInputDialog
                                ("Enter the second number: ");
        //compare string length and make them equal length
        int[]n1 = toArray(numberOne); // my first array
     int[]n2 = toArray(numberTwo); // my second array
     //call the method that ads both strings
     int[]finalArray = arrSum(n1,n2);
       JOptionPane.showMessageDialog(null, "The sum of the two numbers is: "
               + finalArray);
    }//end of main
    //method to create an array from a string
    public static int[] toArray(String str)
            int[]arr = new int[str.length()];
            arr[0]=0;
            for (int i=1; i<str.length(); i++)
          arr= Character.digit(str.charAt(i),10);
return arr;
}//end of toArray
//method to add arrays by elements
public static int[]arrSum (int[]arr1, int[]arr2){
for (int i = arr1.length-1; i >=1; i--)
int sum = arr1[i] + arr2[i];
if (sum > 9)
          { sum -= 10;
          arr1[i-1]++;
return arr1;
}//end of arrSum method
}Edited by: designbc01 on Feb 16, 2010 1:15 AM

The best advice I can give you is to break your problem up into smaller pieces. First, focus on a method that converts an input String into an array. When you have that working perfectly, then focus on creating a method that "adds" two arrays with the logic you described. When you have that working perfectly, then combine the two different pieces.
Why does your for loop in toArray( ) start with 1? The first index of a String, array, or pretty much anything else, is zero.

Shifting elements in multidementional array

Hello,
I'm working on a boardgame project which uses an int[][] to represent the board. The elements in this array are numbers which represent vehicles. The equal numbers are one vehicle. A vehicle can perform a step left/right, or a step up/down (if there is no other vehicle blocking the way of course).
I've read about the arraycopy method, but I don't know how to use it with an array of arrays.
So an example of the matrix would look like this:
111002
300502
344502
300500
000000
666000
After a step of one vehicle the matrix could be:
011102
300502
344502
300500
000000
666000
I need to get matrices for all possible moves, for all vehicles.
I couldn't find any documentation about the use of copyarray with an array of arrays. Hope someone can point me in the right direction.
Thanks in advance

Ceylor wrote:
Hello all,
thanks very much for the quick replies.
prometheuzz, I've read the topic you mentioned and your explanation is great. Your UML makes it very clear.You're welcome.
I allready use OOP as much as possible. In my project I use a playField class (the board, also GUI), a node class (extends from rectangle, a cell in the field), a vehicle class (contains a collection of nodes and some other properties), a class for my algoritm and a state class.Good to hear that.
The state class is used for storing all possible states of the playField. (ie all valid moves). These states are needed for a shortest path algoritm, and are not automatically a state the playField gets. Therefor I can't use the vehicles stored in the playField class because this class only contains the initial state of the game. The playField only get's updated when the algoritm is done and a shortest path is found. So would it be a good solution to store a collection of vehicles inside my state class?I'm don't quite follow you here, I'm afraid.
The thing I'm a bit worried about is that there can be a lot of states. When adding the vehicles to each state object, doesn't this slow things down?
...Don't worry about inefficient code too soon. First get your logic correct: check your algorithm against a small puzzle, ensure that it works. After that, try some larger puzzles to see if a solution is found within the required time frame. If it takes too long, only then adjust your algorithm.
Feel free to post back if you have any questions.
Good luck.

Getting the sum of the elements in an array

Hello all,
Any ideas on how to easily get the sum of the elements of an array of floating points (or any data type for that matter ) this is to be part of a method.
arrayName (float [] floaters)
Thanks

int total=0;
for(int a=0; a<array.length; a++){
total=total+array[a];
}now is that so hard?
or even as a method
public int addUp(int[] array){
   int total=0;
   for(int a=0; a<array.length; a++){
      total=total+array[a];
   return total;
}to be used as
int total=addUp(array);just write your own!

Printing every possible pair combination of elements in two arrays??

Hi there,
I'm trying to implement the problem of printing every possible pair combination of elements in two arrays. The pattern I have in mind is very simple, I just don't know how to implement it. Here's an example:
g[3] = {'A', 'B', 'C'}
h[3] = {1, 2, 3}
...code...??
Expected Output:
A = 1
B = 2
C = 3
A = 1
B = 3
C = 2
A = 2
B = 1
C = 3
A = 2
B = 3
C = 1
A = 3
B = 1
C = 2
A = 3
B = 2
C = 1
The code should work for any array size, as long as both arrays are the same size. Anybody know how to code this??
Cheers,
Sean

not a big fan of Java recursion, unless tail recursion, otherwise you are bound to have out of stack error. Here is some generic permutation method I wrote a while back:
It is generic enough, should serve your purpose.
* The method returns all permutations of given objects. The input array is a two-dimensionary, with the 1st dimension being
* the number of buckets (or distributions), and the 2nd dimension contains all possible items for each of the buckets.
* When constructing the actual all permutations, the following logic is used:
* take the following example:
* 1    2    3
* a    d    f
* b    e    g
* c
* has 3 buckets (distributions): 1st one has 3 items, 2nd has 2 items and 3rd has 2 items as well.
* All possible permutaions are:
* a    d    f
* a    d    g
* a    e    f
* a    e    g
* b    d    f
* b    d    g
* b    e    f
* b    e    g
* c    d    f
* c    d    g
* c    e    f
* c    e    g
* You can see the pattern, every possiblity of 3rd bucket is repeated once, every possiblity of 2nd bucket is repeated twice,
* and that of 1st is 4. The number of repetition has a pattern to it, ie: the multiplication of permutation of all the
* args after the current one.
* Therefore: 1st bucket has 2*2 = 4 repetition, 2nd has 2*1 = 2 repetition while 3rd being the last one only has 1.
* The method returns another two-dimensional array, with the 1st dimension represent the number of permutations, and the 2nd
* dimension being the actual permutation.
* Note that this method does not purposely filter out duplicated items in each of given buckets in the items, therefore, if
* is any duplicates, then the output permutations will contain duplicates as well. If filtering is needed, use
* filterDuplicates(Obejct[][] items) first before calling this method.
public static Object[][] returnPermutation(Object[][] items)
     int numberOfPermutations = 1;
     int i;
     int repeatNum = 1;
     int m = 0;
     for(i=0;i<items.length;i++)
          numberOfPermutations = numberOfPermutations * items.length;
     int[] dimension = {numberOfPermutations, items.length};
     Object[][] out = (Object[][])Array.newInstance(items.getClass().getComponentType().getComponentType(), dimension);
     for(i=(items.length-1);i>=0;i--)
          m = 0;
          while(m<numberOfPermutations)
               for(int k=0;k<items[i].length;k++)
                    for(int l=0;l<repeatNum;l++)
                         out[m][i] = items[i][k];
                         m++;
          repeatNum = repeatNum*items[i].length;
     return out;
/* This method will filter out any duplicate object in each bucket of the items
public static Object[][] filterDuplicates(Object[][] items)
     int i;
     Class objectClassType = items.getClass().getComponentType().getComponentType();
     HashSet filter = new HashSet();
     int[] dimension = {items.length, 0};
     Object[][] out = (Object[][])Array.newInstance(objectClassType, dimension);
     for(i=0;i<items.length;i++)
          filter.addAll(Arrays.asList(items[i]));
          out[i] = filter.toArray((Object[])Array.newInstance(objectClassType, filter.size()));
          filter.clear();
     return out;

How to find the elements of an array

I want to find the number of elements in an array, and I can't find the tutorial that shows how to find it. If anyone could point me in the right direction, it would be greatly appreciated.

warnerja wrote:
flounder wrote:
DrLaszloJamf wrote:
You mean x.length?<pbs>
Depends upon your interpretation of "number of elements in the array"
int[] numbers = new int[10];
numbers[0] = 42;
numbers[1] = 666;Number of elements in the array is 2 not 10.
</pbs>If you used something other than a primitive type for the array element type you could have a case. A value of integer zero for the other elements is still a value, so there are indeed 10 elements there.Even if it were not primitive, every element would have a value. That value would either be null or a reference.

Is there a way of determining what element in an array is being clicked on?

Hi all. I would like to setup an event to determine what element in an array is being clicked on/hovered over. I think I tried this before and found it wasn't working due to limitations of LV 7.0. If this code already exists, it would be great if I don't have to do a scavenger hunt for the solution.
I think one possibility I nixed was to use the refnum of the elements to determine which one it is. IIRC, this is not possible because the refnum of the element is for the edit box only.
The second possiblity is to get the on click event, and somehow determine which element in the array it is. This doesn't sound too difficult as it should be a simple calculation, but may get in to some hairryness based on if the indicies are visible or not, and if I am using a new or old array with new or old control (calc would change based on boarder size of the controls). I might just simplify it by removing indicies and using older control set which has minimal boarder size.
And just for fun, can I force a tool tip to show up?
Thanks all,
A
Using LV7.0 on WinXP.

blawson wrote:
Been bitten by LabVIEW wrote:
I think one possibility I nixed was to use the refnum of the elements to determine which one it is. IIRC, this is not possible because the refnum of the element is for the edit box only.
Using LV7.0 on WinXP.
This is indeed possible, at least in the newer versions I use.
Take the array refnum from the click event data terminal and get a reference to the array element. This refers to the element that was clicked, but you do need to work out how to get the index. My method is to use property nodes to get the screen position and size of the element and the screen position and size of the array, as well as the array's Visible Index property. For each direction, take the quotient of the relative position of the element (account for padding!) over the size of an element.
I suspect that taking the mouse coords and comparing to the array's sizes in pixels is similar, although I trust my method for events that don't have mouseclicks (what coords does Array:shortcut menu selection(User) return if you used the keyboard?)
Here's an old version I happened to have open. I've posted about this before, I suspect I have a clearer version in my gallery. I use this method in my example code contest entry to work out which square of the chessboard is clicked.
Thank you for that one!
I am currently "locked up behind a down-rev fence" (working an old app in an old version) so I had not heard of that.
Ben
Ben Rayner
I am currently active on.. MainStream Preppers
Rayner's Ridge is under construction

How can I change the properties of only one element in an array of booleans?

I'm displaying an array of booleans to my operators, with each boolean in the array representing some system status check. Some of these checks are critical and some are not, therefore I want some of these booleans to have a different color when in the TRUE state (Red for the critical ones and Yellow for the non-critical ones). I can change the boolean colors with a property node, but that effects every element in the array. Is there any way to change a property of an individual element in an array? I know that I could take the incoming array and break it into two arrays - one for critical and one for non-critical, but this system is replacing an older system and the operators are accustomed to seeing their indicator lights a certain way and I'm trying to replicate what they had exactly.

Here's what I had in mind
Of course you can use as many colors as you want.
Message Edited by altenbach on 12-21-2005 04:53 PM
LabVIEW Champion . Do more with less code and in less time .
Attachments:
LEDarray.png ‏7 KB
ColorArray3.vi ‏23 KB

In LabVIEW6i, is there a way to make particular elements of an array invisible while the others stay visible (without losing any element's info.)?

I have an array of clusters. Each cluster pertains to a certain oscilloscope I am controlling. There is another control which specifies which oscilloscopes I have "on".
If a particular oscilloscope is "on" I want its cluster to be VISIBLE in the array. If a particular oscilloscope is "off" I want its cluster to be INVISIBLE in the array.
How can I implement this in my program without losing ANY of the info. in my array?

I suggest to use two arrays; one for user interface holding the ON clusters,
and one for internal use holding all clusters. The diagram periodically
updates the internal array with user interface array data.
By INVISIBLE do you mean "skipped from the array" or displayed as an empty
placeholder? To hide an OFF cluster you could put in the cluster a flat
button boolean that is small and transparent when ON and large enough to
cover the whole cluster area (and other controls) when OFF.
Jean-Pierre Drolet
Scientech R&D
"mcmastal" a écrit dans le message news:
[email protected]..
> In LabVIEW6i, is there a way to make particular elements of an array
> invisible while the others stay visible (without losing any element's
> info.)?
>
> I have an array of clusters. Each cluster pertains to a certain
> oscilloscope I am controlling. There is another control which
> specifies which oscilloscopes I have "on".
> If a particular oscilloscope is "on" I want its cluster to be VISIBLE
> in the array. If a particular oscilloscope is "off" I want its
> cluster to be INVISIBLE in the array.
> How can I implement this in my program without losing ANY of the
> info. in my array?
LabVIEW, C'est LabVIEW

SQL elements int an array?

Similar Messages

Maybe you are looking for