SQL Query between two dates

Hi,
Please could someone help me on how to write a query to retrieve the data between two dates.
created_date format stored in the database column: 9/18/2007 11:34:03 AM
I tried below but it didn't work
select * from work_table where created_date beween '9/18/2007' and '03/29/2008'
I get 'literal doesn't match format string'
Thanks,

date datatype is nls dependent -> folllows the nls_date_format database parameter setting inherited by your session.
Making it short you'll be always safe if you
select * from work_table where created_date beween to_date('9/18/2007','MM/DD/YYYY') and to_date('03/29/2008','MM/DD/YYYY')Having the time component included you must add + 1 - 1 / 24 / 60 / 60 (plus one day minus one second) to the upper limit if you want to include the last day as a whole
*** not tested
Regards
Etbin

Similar Messages

Query between two date columns ?

Oracle 11g R2
I'm trying too create a query between two date columns. I have a view that consists of many columns. There are two columns in question called valid_to and valid_from
Part Number     Valid_from        valid_to
100                    01/01/2000       01/01/9999
200                    01/01/2000       01/01/9999
300                    01/01/2000       01/01/9999
etc
If I want to only see rows between with a date range of 01/01/2000 and 01/01/2013 how can I put this as SQL ?
Thanks in advance

Hi,
Whenever you have a problem, please post a little sample data (CREATE TABLE and INSERT statements, relevant columns only), so that the people who want to help you can re-create the problem and test their ideas.
Also post the results you want from that data, and an explanation of how you get those results from that data, with specific examples.
See the forum FAQ: https://forums.oracle.com/message/9362002
If you want to find rows that have that exact range, then you can do something like
SELECT *
FROM    table_x
WHERE   valid_from = DATE '2000-01-01
AND     valid_to    = DATE '2013-01-01'
If you want to find rows where any or all or the range on the row overlaps any or all of the 200-2013 target range, then
SELECT *
FROM    table_x
WHERE   valid_from <= DATE '2013-01-02
AND     valid_to    >= DATE '2000-01-01'
If you want rows that are enritely within the target range, it's something else.
If you want rows that entirely enclose the target range, it's something else again.

Select Query Between two dates...

Hi Guru's,
I need a Select Query between two dates, also if the record not found for any in between date then it should return NULL or 0 ...
for Example
1. I am having two records in DB for date 2-10-2008 & 4-10-2008
2. Now suppose I have given Query for date between 1-10-2008 to 5-10-2008
Then it should return me 5 records with valid values for 2 & 4 and NULL for other 1,3,5
Thanks.

Try like this:
with
t as
      select date '2008-10-02' as dt, 'Record #1 (in DB)' as str from dual union all
      select date '2008-10-04' as dt, 'Record #2 (in DB)' as str from dual
select v.dt, t.str
from (
         select date '2008-10-01' + level - 1 as dt
           from dual
         connect by level <= (date '2008-10-05' - date '2008-10-01') + 1
       ) v
left join t
    on v.dt = t.dt
order by 1

Query between two dates

Hi,
I have table like this.
Id           in_date               value
2          05-Jun-08          5.3
3          08-Jun-08          5.2
4          08-Jun-08          5.3
5          08-Jun-08          5.8
6          10-Jun-08          7
7          10-Jun-08          5.6
8          11-Jun-08          2.6
When I query for average value between two dates, it should return average and if there is no entry for any dates it should return 0 for that date. Here is sample output for dates between 05-Jun-08 and 12-Jun-08.
In_date           value
05-Jun-08     5.3
06-Jun-08     0.0
07-Jun-08     0.0
08-Jun-08     5.43
09-Jun-08     0
10-Jun-08     6.3
11-Jun-08     2.6
12-Jun-08     0
Please help me to write query on thisThanks,
Sujnan

SQL> with t as (
2             select 2 id,to_date('05-Jun-08','dd-mon-rr') in_date,5.3 val from dual union all
3             select 3,to_date('08-Jun-08','dd-mon-rr'),5.2 from dual union all
4             select 4,to_date('08-Jun-08','dd-mon-rr'),5.3 from dual union all
5             select 5,to_date('08-Jun-08','dd-mon-rr'),5.8 from dual union all
6             select 6,to_date('10-Jun-08','dd-mon-rr'),7 from dual union all
7             select 7,to_date('10-Jun-08','dd-mon-rr'),5.6 from dual union all
8             select 8,to_date('11-Jun-08','dd-mon-rr'),2.6 from dual
9            )
10 select t2.in_date,
11          nvl(t1.val,0) + t2.val val
12    from (
13           select in_date,
14                   avg(val) val
15             from t
16             group by in_date
17          ) t1,
18          (
19           select min_in_date + level - 1 in_date,
20                   0 val
21             from (
22                    select min(in_date) min_in_date,
23                            max(in_date) max_in_date
24                      from t
25                   )
26             connect by level <= max_in_date - min_in_date + 1
27          ) t2
28    where t2.in_date = t1.in_date(+)
29    order by t2.in_date
30 /
IN_DATE      VAL
05-JUN-08   5.30
06-JUN-08    .00
07-JUN-08    .00
08-JUN-08   5.43
09-JUN-08    .00
10-JUN-08   6.30
11-JUN-08   2.60
7 rows selected.
SQL> SY.

Using pl/sql function for each day between two dates.

Hi,
create TABLE EMP(
ID_EMP NUMBER,
DT_FROM DATE,
DT_TO DATE,
CREATE_DATE DATE);
into EMP(ID_EMP, DT_FROM, DT_TO, CREATE_DATE)
Values(100, TO_DATE('07/01/2008 00:00:00', 'MM/DD/YYYY HH24:MI:SS'), TO_DATE('04/30/2010 00:00:00', 'MM/DD/YYYY HH24:MI:SS'),TO_DATE('05/08/2009 14:11:21', 'MM/DD/YYYY HH24:MI:SS'));
I have a function called elig_pay_dates(date p_date), which returns the code for person payment eligibility for a particular date. For paid dates it's 'P' and for unpaid dates it's 'N'.
How can I check this function between two dates for each day. Example : 07/01/2008 to 04/30/2010.
By using this function with select I needs to display the dates when there is a change in status.
I am expecting data in following manner from above logic(this is example):
07/01/2008 --- 07/01/2009 ---'P'
07/02/2009 -- 07/25/2009 ----'N'
07/26/2009 -- 01/01/2010 ---'P'
01/02/2010 -- 01/13/2010 --'N'
01/14/2010 -- 01/18/2010 --'P'
01/19/2010 -- 04/30/2010 -- 'N'
I thought of looping for each day date but that seems to be expensive for online application. Is there any way that I can achieve this requirement with sql query ?
Thanks for your help,

Certainly not the best way to code the requirement, but it does achieve the result you are looking for in a fairly quick time
create or replace
function test_ret_paid_unpaid (p_date in date)
return varchar2
is
v_ret     varchar2(1);
begin
if ( (p_date between to_date('07/02/2009', 'MM/DD/YYYY') and to_date('07/25/2009', 'MM/DD/YYYY') ) or
       (p_date between to_date('01/02/2010', 'MM/DD/YYYY') and to_date('01/13/2010', 'MM/DD/YYYY') ) or
       (p_date between to_date('01/19/2010', 'MM/DD/YYYY') and to_date('04/30/2010', 'MM/DD/YYYY') )
    then v_ret := 'N';
else
    v_ret := 'Y';
end if;
return v_ret;
end;
Wrote file afiedt.buf
1 with get_paid_unpaid as
2 (
3    select dt_from start_date, dt_to end_date, dt_from + level - 1 curr_date, test_ret_paid_unpaid(dt_from + level - 1) paid_unpaid,
4           row_number() over (order by dt_from + level - 1) rn_start,
5           row_number() over (order by dt_from + level - 1 desc) rn_end
6      from test_emp
7    connect by level <= dt_to - dt_from + 1
8 ),
9 get_stop_date as
10 (
11 select start_date init_date, end_date, curr_date, paid_unpaid,
12         case when paid_unpaid != lag(paid_unpaid) over (order by curr_date) or rn_start = 1 or rn_end = 1
13          then curr_date
14          else null
15         end start_date,
16         case when paid_unpaid != lead(paid_unpaid) over (order by curr_date) or rn_start = 1 or rn_end = 1
17          then curr_date
18          else null
19         end stop_date
20    from get_paid_unpaid
21 )
22 select period, paid_unpaid
23    from (
24 select init_date, curr_date, start_date, end_date, stop_date,
25         case when paid_unpaid = lead(paid_unpaid) over (order by curr_date)
26                then nvl(start_date, init_date) || ' - ' || lead(stop_date, 1, end_date) over (order by curr_date)
27              else null
28         end period,
29         paid_unpaid
30    from get_stop_date
31   where stop_date is not null or start_date is not null
32         )
33* where period is not null
12:06:10 SQL> /
PERIOD                                             PAID_UNPAID
01-JUL-08 - 01-JUL-09                              Y
02-JUL-09 - 25-JUL-09                              N
26-JUL-09 - 01-JAN-10                              Y
02-JAN-10 - 13-JAN-10                              N
14-JAN-10 - 18-JAN-10                              Y
19-JAN-10 - 30-APR-10                              N
6 rows selected.
Elapsed: 00:00:00.35

How to calculate the month difference between two date char. in Query?

Customers would like to see how many months passed between two date type of characteristics (e.g., the month difference between the current date and the scheduled delivery date in the record) and put the result into the column as KF.
We would have to grab the fiscal year/period kind of value and then do the subtraction, e.g., if the current date value is 2/28/2008 and the scheduled delivery date value in the record is 12/01/2007, the correct result should be 2 month difference between these two date values, but could someone here give us the technical light on how to make this happen in query design?
Thanks and we will give you reward points for the correct anwsers!

Hi Kevin,
The Badi is RSR_OLAP_BADI.
You can create an implementation using Transaction SE18.
The implementation is per cube and is defined in the filters.
In the Implementation you have the following methods :
1. Define : Here you will provide the Keyfigure you need as a virtual one.
2. Initilialize : Any Init Function you want to do.
3. Compute. This is called per datarecord and here you can cimpute your value.
Hope this helps.
Pralay Ahluwalia

Query for between two dates.

Hi,
I've a column of date, and I want to select the records between two dates, the output of this columns is: 08/19/2003 2:11:00 AM
My query is:
SELECT DTM FROM ITEM
WHERE DTM BETWEEN '07/01/2012' AND '07/15/2012'
Please help.
Thanks,

>
I've a column of date, and I want to select the records between two dates, the output of this columns is: 08/19/2003 2:11:00 AM
My query is:
SELECT DTM FROM ITEM
WHERE DTM BETWEEN '07/01/2012' AND '07/15/2012'
Please help.
>
Help with what? You didn't ask a question or indicate if you are having a problem of some sort.
Did you need to know how to use TO_DATE instead of literals in the WHERE clause?
SELECT DTM FROM ITEM
WHERE DTM BETWEEN TO_DATE('07/01/2012', 'MM/DD/YYYY') AND TO_DATE('07/15/2012', 'MM/DD/YYYY');

How to query the number of working days between two dates

I'm looking for a solution to calculate the number of <i>working</i> days between two dates that I can use in a formated search.
Calculating the total number of days is pretty straight forward but does anyone know how to take into account the settings in the HLD1 (Holiday Dates) table?

Hi Eric,
If you are purely looking to exclude holidays defined in the HLD1 table, then you should be able to do it with the following query
NOTE: The following query is an example using OINV table and the fields DOCDATE and DOCDUEDATE for a Particular DOCNUM 'xxx'
If you planning to use within the SAP module then replace DOCDATE and DOCDUEDATE with dynamic field references $[$x.x.x]
SELECT DATEDIFF(DAY,T0.DOCDATE,T0.DOCDUEDATE)-
(SELECT COUNT(STRDATE) FROM HLD1 WHERE STRDATE >= T0.DOCDATE AND STRDATE <= T0.DOCDUEDATE)
FROM OINV T0
WHERE T0.DOCNUM = xxx
Best Wishes
Suda

Difference between two date in bex query

Hi all,
I need to do a difference between two date using formula variable processing type customer exit beaucause I must use factory calendar in the formula.
How can I do it?
Can you give me an example of the routine?
Thanks a lot
Gianmarco

Hi,
You can still use the same code to copy it and customize as per your need. All you need to do is to subract the dates using the class: CL_ABAP_TSTMP after converting to timestamp and resulting seconds you convert back to days....Please get help from the developers to do this...
Also, ensure that you write back this difference value to your variable so you get it on the reports for your calculations...
Cheers,
Emmanuel.

SQL query to group data by Code and dates

Hi There,
I have the following table structure
col1 col2 col3
code1 21-jan-2012 tested
code1 20-jan-2012 tested
code1 01-jun-2012 tested
code2 01-jun-2012 tested
code3 04-jun-2012 tested
so on
The output should be some thing like
code Week1 week2 week 3 week4 week5 till about last 14 weeks from the date we are running
code1 1 0 0 0 0
code2 1 0 0 0 0
code 3 0 1 0 0 0
where 1, 0 is actually the counts and not sum and the week in this case, should have maybe been since we are in the second week it should have been
code .....................week3 may week4 may week1 jun week2june
Was looking for suggestions on how to get this done.
I am assuming this would require some sort of a pivot query?
Thanks,
Sun

Hi, Sun,
sun1977 wrote:
Thanks EKH,
Yes, in lines of the output of this query. Is it possible to,
1. In the query, if condition is met, the it simply displays 1 else 0. Basically, we need to get the count of the number of the codes in that week. So if code 1 happened 5 times, it should show 5.Sure; use COUNT instead of MAX.
2. Provide the output between two dates. Lets say, I have to do it for the last 14 weeks from sysdate. Then will the logic of week1 = 1 work?Use date arithmetic to get the number of days between the starting date and col2, then divide by 7 to get the number of weeks. Use that number instead of the value returned by TO_CHAR.
3. any suggestions if the counts have to be changed to percentages. How can we have the percentage value showingYou can do that. Exactly how depends on exactly what you want. It may involve using the analytic RATIO_TO_REPORT function in a sub-query. Post the exact results you want from the sample data that Ekh posted (or new sample data that you post), and explain how you get those results from that data.
4. Would we also be able to add a date bind value. Lets say, if the user selects start date as may, 1st, 2012 and end date as jun5th. It sort of shows the same data but in weekly format for the weeks between the period selected?Sure, just use those values in a WHERE clause. The output needs to have a fixed number of columns, however. Say that number is 14. You can give a range that only covers 5 weeks, but the output will have 9 0's at the end of every row. You can give a range that covers 15 or more weeks, but the weeks after 14 will not be shown. To get around that requires dynamic SQL (if you want each week in a real column) or string aggregation. See {message:id=3527823}
Point 3 is different from point 1 as in, the first one would be maybe using your logic but hardcoding for 14 weeks. Point three would be a little more dynamic.
Thanks for your time.
Sun
Edited by: sun1977 on Jun 7, 2012 2:28 AM
EXEC :start_dt_txt := '01-May-2012';
EXEC :end_dt_txt   := '05-Jun-2012';
WITH got_week_num AS
     SELECT col1, col2
     ,     1 + FLOOR ( (col2 - TO_DATE (:start_dt_txt, 'DD-Mon-YYYY'))
                     / 7
                 )     AS week_num
     FROM    t
     WHERE     col2     >= TO_DATE (:start_dt_txt, ':DD-Mon-YYYY')
     AND     col2     < TO_DATE (:end_dt_txt,   ':DD-Mon-YYYY') + 1
SELECT       col1
,       COUNT (CASE WHEN week_num = 1 THEN 1 END)     AS week_1
,       COUNT (CASE WHEN week_num = 2 THEN 1 END)     AS week_2
,       COUNT (CASE WHEN week_num = 3 THEN 1 END)     AS week_3
,       COUNT (CASE WHEN week_num = 4 THEN 1 END)     AS week_4
,       COUNT (CASE WHEN week_num = 5 THEN 1 END)     AS week_5
,       COUNT (CASE WHEN week_num = 6 THEN 1 END)     AS week_6
,       COUNT (CASE WHEN week_num = 14 THEN 1 END)     AS week_14
FROM       got_week_num
GROUP BY col1
ORDER BY col1
;Edited by: Frank Kulash on Jun 7, 2012 5:53 AM

Find gap between two dates from table

Hello All,
I want to find gap between two dates ,if there is no gap between two dates then it should return min(eff_dt) and max(end_dt) value
suppose below data in my item table
item_id    eff_dt           end_dt
10         20-jun-2012     25-jun-2012
10         26-jun-2012     28-jun-2012 There is no gap between two rows for item 10 then it should return rows like
item_id eff_dt end_dt
10 20-jun-2012 28-jun-2012
item_id    eff_dt           end_dt
12         20-jun-2012     25-jun-2012
12         27-jun-2012     28-jun-2012 There is gap between two rows for item 12 then it should return like
item_id eff_dt end_dt
12 20-jun-2012 25-jun-2012
12 27-jun-2012 28-jun-2012
I hv tried using below query but it giv null value for last row
SELECT   item_id, eff_dt, end_dt, end_dt + 1 AS newd,
         LEAD (eff_dt) OVER (PARTITION BY ctry_code, co_code, item_id ORDER BY ctry_code,
          co_code, item_id) AS LEAD,
         (CASE
             WHEN (end_dt + 1) =
                    LEAD (eff_dt) OVER (PARTITION BY ctry_code, co_code, item_id ORDER BY ctry_code,
                     co_code, item_id, eff_dt)
                THEN '1'
             ELSE '2'
          END
         ) AS new_num
FROM item
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ORDER BY ctry_code, co_code, item_id, eff_dtI m using oracle 10g.
please any help is appreciate.
Thanks.

Use start of group method:
with sample_table as (
                      select 10 item_id,date '2012-6-20' start_dt,date '2012-6-25' end_dt from dual union all
                      select 10,date '2012-6-26',date '2012-6-26' from dual
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        max(end_dt) end_dt
from (
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                 end_dt,
                 sum(start_of_group) over(partition by item_id order by start_dt) grp
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                          start_dt,
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                            when start_dt - 1 then 0
                            else 1
                          end start_of_group
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group by item_id,
           grp
order by item_id,
           grp
   ITEM_ID START_DT END_DT
        10 20-JUN-12 26-JUN-12
SQL> SY.

How to retrieve day between two dates?

Hi all,
Hope doing well,
sir i am retrieving day between two dates in sql server like this.
select datediff(day,'2012-10-03 00:00:00.000','2012-10-05 00:00:00.000')
and getting result that is: 2
but how this type of query i'll use in oracle?
thanks,

Just do minus
diff := date_variable2-date_variable1;The difference sill be in days.
If you want just the differences in days (Neglecting time part)
diff := trunc(date2)-trunc(date1);

As to the data type of the data type of the difference between two date type of datas

Hi,
I have a question about the data type of the difference between two date type of datas.
There are two date type of datas as:
SSHIPMENTS.RECEIVEDATETIME
SSHIPMENTS.PROMISEDATETIME
I try to use the following SQL Script in Oracle SQL*Plus as:
SELECT CASE
WHEN (SSHIPMENTS.RECEIVEDATETIME - SSHIPMENTS.PROMISEDATETIME) < '000 01:00:00.000' THEN 'OnTime'
WHEN (SSHIPMENTS.RECEIVEDATETIME - SSHIPMENTS.PROMISEDATETIME) < '000 01:30:00.000' THEN '60-89 Minutes'
ELSE '3+ Hours'
END
FROM SSHIPMENTS;
The error message of "Invalid Number" for the '000 01:30:00.000' happens.
I don't know if the data type of the interval is wrong.
Many Thanks,
Cathy

SELECT CASE
WHEN (to_char(SSHIPMENTS.RECEIVEDATETIME,'hhmiss') - to_char(SSHIPMENTS.PROMISEDATETIME,'hh24miss')) < '010000' THEN 'OnTime'
WHEN (to_char(SSHIPMENTS.RECEIVEDATETIME,'hhmiss') - to_char(SSHIPMENTS.PROMISEDATETIME,'hh24miss'))< '000 01:30:00.000' THEN '60-89 Minutes'
ELSE '3+ Hours'
END
FROM SSHIPMENTS;
just try it out..

Date difference between two dates

hi All,
i have to right a stored proc to find the difference between two dates.
for example of i give
startdate as 4/1/2015 and enddate 14/1/2015
i should get 1 year , 10 days and 0 months .
i have tried the DateDiff function but it does not calculate the leap year.
please help.

DECLARE @from datetime
DECLARE @to datetime
SET @from = '20150104 8:00'
SET @to = '20150114 10:30'
SELECT DATEDIFF(minute,@from, @to) % 60 as Minutes
SELECT (DATEDIFF(minute,@from, @to) / 60) % 24 as Hours
SELECT DATEDIFF(minute,@from, @to) / (60 * 24) as Days
SELECT DATEDIFF(month,@from, @to) as Months
SELECT DATEDIFF(year,@from, @to) as Year
Best Regards,Uri Dimant SQL Server MVP,
http://sqlblog.com/blogs/uri_dimant/
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Find the difference between two dates for the specific month and year

Hi,
I have two dates, start date is 30/12/2012 and end date is 04/01/2013. Using datediff I found the difference of days between two dates. But I find the no of days in January 2013. ie output is 4 instead of 6. I input month and year to find the no of days
for that date. In this case I input Jan 2013. How can I sql this ?

I don't understand how most of the answers provided here not analytically solving the problem with many cases possible.
First let me understand you:
You have 2 dates range and you want to calculate day range for specific month and year between the original date range.
declare @for_month int = 1 --January
declare @for_year int = 2013
declare @StartDate date = '2012-12-20'
declare @EndDate date = '2013-01-04'
SELECT
CASE
WHEN (DATEPART(MONTH, @StartDate) = @for_month and DATEPART(MONTH, @EndDate) = @for_month) and ((DATEPART(YEAR, @StartDate) = @for_year or DATEPART(YEAR, @EndDate) = @for_year)) THEN
DATEDIFF(DAY, @StartDate,@EndDate)
WHEN (@StartDate < cast(CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as date)) and (@EndDate between (cast(CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as date)) and (cast(DATEADD(d, -1, DATEADD(m, DATEDIFF(m, 0, cast( CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as date)) + 1, 0)) as date))) THEN
DATEDIFF(DAY, DATEADD(MONTH, DATEDIFF(MONTH, -1, @EndDate)-1, 0),@EndDate)
WHEN (@EndDate > cast(DATEADD(d, -1, DATEADD(m, DATEDIFF(m, 0, cast( CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as date)) + 1, 0)) as date)) and (@StartDate between (cast(CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as date)) and (cast(DATEADD(d, -1, DATEADD(m, DATEDIFF(m, 0, cast( CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as date)) + 1, 0)) as date))) THEN
DATEDIFF(DAY, @StartDate,DATEADD(d, -1, DATEADD(m, DATEDIFF(m, 0, @StartDate) + 1, 0))) + 1
WHEN ((DATEDIFF(DAY, @StartDate, cast(DATEADD(d, -1, DATEADD(m, DATEDIFF(m, 0, cast( CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as date)) + 1, 0)) as date)) >= 0) and (DATEDIFF(DAY, cast(CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as date), @EndDate) >= 0)) THEN
DATEDIFF(DAY, cast( CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as datetime), DATEADD(d, -1, DATEADD(m, DATEDIFF(m, 0, cast( CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as datetime)) + 1, 0))) + 1
ELSE
0
END as [DD]
I don't know how you calculate day range between 01/01/2013 and 04/01/2013
is 4, it is actually is 3 but if that is the case, you can add 1 from the condition.

SQL Query between two dates

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