SQL Query for mapping a set of batches to a class rooms group

Hi All,
I am using Oracle 11g Release 2 database.
I have the following data set:
ClassRooms
ClassId ClassName                    Capacity     Group
1 Babbage/Software Engg Lab          24          1
2     Basement - PG Block               63          1
3     Classroom 1                    56          1
4     Classroom 10                    24          1
5     Classroom 11                    24          1
6     Classroom 12                    35          1
7     Classroom 13                    42          1
8     Classroom 14                    42          1
9     Classroom 15                    42          1
10     Classroom 2                    35          1
11     Classroom 3                    35          1
12     Classroom 4                     35          1
13     Classroom 5                    35          1
14     Classroom 6                    25          1
15     Classroom 7                    25          1
16     Classroom 8                    24          1
17     Classroom 9                    24          1
18     Control Sys Lab                    24          1
19     Dig & Embd Sys Lab               20          1
20     DSP & Comm Lab                    20          1
21     Electromechanical System Lab     28          1
22     Farabi/Web Tech Lab               36          1
23     Gen Purpose Lab                    40          1
24     Shirazi/DB Tech Lab               36          1
25     Adv Elect Lab                    30          2
26     Classroom 16                    42          2
27     Classroom 17                    49          2
28     Classroom 18                    56          2
29     Classroom 19                    42          2
30     Classroom 20                    49          2
31     Classroom 21                    35          3
32     Classroom 22                    35          3
33     MDA Lab                         20          3
DegreeBatches
BatchId      BatchName Strength
1          BIT-11          79
2          BIT-12          28
3          BS(CS)-1          35
4          BS(CS)-2          78
5          BE(SE)-1          69
6          BE(SE)-2          84
7          BE(SE)-3          64
8          BICSE-7          84
9          BICSE-8          43
10          BEE-1          112
11          BEE-2          151
12          BEE-3          157
13          BEE-4          157
I want to map a degree batch combination to a class rooms group in such away that they fully utilize maximum capacity of the class rooms within a group (Ideal case) or as close to it as possible. Can it be done with a SQL query?
Any response will be highly appreciated.
SQL Scripts to generate the required tables and populate data is below:
CREATE TABLE ClassRooms (ClassId NUMBER, ClassName     VARCHAR2(50), Capacity NUMBER, Group NUMBER);
INSERT INTO ClassRooms VALUES(1,'Babbage/Software Engg Lab',24,1);
INSERT INTO ClassRooms VALUES(2,'Basement - PG Block',63,1);
INSERT INTO ClassRooms VALUES(3,'Classroom 1',56,1);
INSERT INTO ClassRooms VALUES(4,'Classroom 10',24,1);
INSERT INTO ClassRooms VALUES(5,'Classroom 11',24,1);
INSERT INTO ClassRooms VALUES(6,'Classroom 12',35,1);
INSERT INTO ClassRooms VALUES(7,'Classroom 13',42,1);
INSERT INTO ClassRooms VALUES(8,'Classroom 14',42,1);
INSERT INTO ClassRooms VALUES(9,'Classroom 15',42,1);
INSERT INTO ClassRooms VALUES(10,'Classroom 2',35,1);
INSERT INTO ClassRooms VALUES(11,'Classroom 3',35,1);
INSERT INTO ClassRooms VALUES(12,'Classroom 4',35,1);
INSERT INTO ClassRooms VALUES(13,'Classroom 5',35,1);
INSERT INTO ClassRooms VALUES(14,'Classroom 6',25,1);
INSERT INTO ClassRooms VALUES(15,'Classroom 7',25,1);
INSERT INTO ClassRooms VALUES(16,'Classroom 8',24,1);
INSERT INTO ClassRooms VALUES(17,'Classroom 9',24,1);
INSERT INTO ClassRooms VALUES(18,'Control Sys Lab',24,1);
INSERT INTO ClassRooms VALUES(19,'Dig & Embd Sys Lab',20,1);
INSERT INTO ClassRooms VALUES(20,'DSP & Comm Lab',20,1);
INSERT INTO ClassRooms VALUES(21,'Electromechanical System Lab',28,1);
INSERT INTO ClassRooms VALUES(22,'Farabi/Web Tech Lab',36,1);
INSERT INTO ClassRooms VALUES(23,'Gen Purpose Lab',40,1);
INSERT INTO ClassRooms VALUES(24,'Shirazi/DB Tech Lab',36,1);
INSERT INTO ClassRooms VALUES(25,'Adv Elect Lab',30,2);
INSERT INTO ClassRooms VALUES(26,'Classroom 16',42,2);
INSERT INTO ClassRooms VALUES(27,'Classroom 17',49,2);
INSERT INTO ClassRooms VALUES(28,'Classroom 18',56,2);
INSERT INTO ClassRooms VALUES(29,'Classroom 19',42,2);
INSERT INTO ClassRooms VALUES(30,'Classroom 20',49,2);
INSERT INTO ClassRooms VALUES(31,'Classroom 21',35,3);
INSERT INTO ClassRooms VALUES(32,'Classroom 22',35,3);
INSERT INTO ClassRooms VALUES(33,'MDA Lab',20,3);
CREATE TABLE DegreeBatches (BatchId NUMBER, BatchName VARCHAR2(50), Strength NUMBER);
INSERT INTO DegreeBatches VALUES(1,'BIT-11',79);
INSERT INTO DegreeBatches VALUES(2,'BIT-12',28);
INSERT INTO DegreeBatches VALUES(3,'BS(CS)-1',35);
INSERT INTO DegreeBatches VALUES(4,'BS(CS)-2',78);
INSERT INTO DegreeBatches VALUES(5,'BE(SE)-1',69);
INSERT INTO DegreeBatches VALUES(6,'BE(SE)-2',84);
INSERT INTO DegreeBatches VALUES(7,'BE(SE)-3',64);
INSERT INTO DegreeBatches VALUES(8,'BICSE-7',84);
INSERT INTO DegreeBatches VALUES(9,'BICSE-8',43);
INSERT INTO DegreeBatches VALUES(10,'BEE-1',112);
INSERT INTO DegreeBatches VALUES(11,'BEE-2',151);
INSERT INTO DegreeBatches VALUES(12,'BEE-3',157);
INSERT INTO DegreeBatches VALUES(13,'BEE-4',157);
Best Regards
Bilal
Edited by: Bilal on 27-Dec-2012 09:52
Edited by: Bilal on 27-Dec-2012 10:07

Bilal, thanks for the nice problem! Another possibility for duplicate checking is to write a small PL/SQL function returning 1 if a duplicate id is found, then equate it to 0: 'Duplicate_Token_Found (p_str_main VARCHAR2, p_str_trial VARCHAR2) RETURN NUMBER'. This would parse the second string and might use p_str_main LIKE '%,' || l_id || ',%' for each id. Anyway the full query (without that) is given below:
Solution with names
SQL> WITH rsf_itm (con_id, max_weight, nxt_id, lev, tot_weight, tot_profit, path, root_id, lev_1_id) AS (
2 SELECT c.id,
3         c.max_weight,
4         i.id,
5         0,
6         i.item_weight,
7         i.item_profit,
8         ',' || i.id || ',',
9         i.id,
10         0
11    FROM items i
12   CROSS JOIN containers c
13   UNION ALL
14 SELECT r.con_id,
15         r.max_weight,
16         i.id,
17         r.lev + 1,
18         r.tot_weight + i.item_weight,
19         r.tot_profit + i.item_profit,
20         r.path || i.id || ',',
21         r.root_id,
22         CASE WHEN r.lev = 0 THEN i.id ELSE r.nxt_id END
23    FROM rsf_itm r
24    JOIN items i
25      ON i.id > r.nxt_id
26     AND r.tot_weight + i.item_weight <= r.max_weight
27   ORDER BY 1, 2
28 ) SEARCH DEPTH FIRST BY nxt_id SET line_no
29 , rsf_con (nxt_con_id, nxt_line_no, con_path, itm_path, tot_weight, tot_profit, lev) AS (
30 SELECT con_id,
31         line_no,
32         To_Char(con_id),
33         ':' || con_id || '-' || (lev + 1) || ':' || path,
34         tot_weight,
35         tot_profit,
36         0
37    FROM rsf_itm
38   UNION ALL
39 SELECT r_i.con_id,
40         r_i.line_no,
41         r_c.con_path || ',' || r_i.con_id,
42         r_c.itm_path || ':' || r_i.con_id || '-' || (r_i.lev + 1) || ':' || r_i.path,
43         r_c.tot_weight + r_i.tot_weight,
44         r_c.tot_profit + r_i.tot_profit,
45         r_c.lev + 1
46    FROM rsf_con r_c
47    JOIN rsf_itm r_i
48      ON r_i.con_id > r_c.nxt_con_id
49   WHERE r_c.itm_path NOT LIKE '%,' || r_i.root_id || ',%'
50     AND r_c.itm_path NOT LIKE '%,' || r_i.lev_1_id || ',%'
51     AND r_c.itm_path NOT LIKE '%,' || r_i.nxt_id || ',%'
52 )
53 , paths_ranked AS (
54 SELECT itm_path || ':' itm_path, tot_weight, tot_profit, lev + 1 n_cons,
55         Rank () OVER (ORDER BY tot_profit DESC) rnk,
56         Row_Number () OVER (ORDER BY tot_profit DESC) sol_id
57    FROM rsf_con
58 ), best_paths AS (
59 SELECT itm_path, tot_weight, tot_profit, n_cons, sol_id
60    FROM paths_ranked
61   WHERE rnk = 1
62 ), row_gen AS (
63 SELECT LEVEL lev
64    FROM DUAL
65 CONNECT BY LEVEL <= (SELECT Count(*) FROM items)
66 ), con_v AS (
67 SELECT b.itm_path, r.lev con_ind, b.sol_id, b.tot_weight, b.tot_profit,
68          Substr (b.itm_path, Instr (b.itm_path, ':', 1, 2*r.lev - 1) + 1,
69            Instr (b.itm_path, ':', 1, 2*r.lev) - Instr (b.itm_path, ':', 1, 2*r.lev - 1) - 1)
70             con_nit_id,
71          Substr (b.itm_path, Instr (b.itm_path, ':', 1, 2*r.lev) + 1,
72            Instr (b.itm_path, ':', 1, 2*r.lev + 1) - Instr (b.itm_path, ':', 1, 2*r.lev) - 1)
73             itm_str
74    FROM best_paths b
75    JOIN row_gen r
76      ON r.lev <= b.n_cons
77 ), con_split AS (
78 SELECT itm_path, con_ind, sol_id, tot_weight, tot_profit,
79         Substr (con_nit_id, 1, Instr (con_nit_id, '-', 1) - 1) con_id,
80         Substr (con_nit_id, Instr (con_nit_id, '-', 1) + 1) n_items,
81         itm_str
82    FROM con_v
83 ), itm_v AS (
84 SELECT c.itm_path, c.con_ind, c.sol_id, c.con_id, c.tot_weight, c.tot_profit,
85          Substr (c.itm_str, Instr (c.itm_str, ',', 1, r.lev) + 1,
86            Instr (c.itm_str, ',', 1, r.lev + 1) - Instr (c.itm_str, ',', 1, r.lev) - 1)
87             itm_id
88    FROM con_split c
89    JOIN row_gen r
90      ON r.lev <= c.n_items
91 )
92 SELECT v.sol_id,
93         v.tot_weight s_wt, v.tot_profit s_pr, c.id c_id, c.name c_name, c.max_weight m_wt,
94         Sum (i.item_weight) OVER (PARTITION BY v.sol_id, c.id) c_wt,
95         i.id i_id, i.name i_name, i.item_weight i_wt, i.item_profit i_pr
96    FROM itm_v v
97    JOIN containers c
98      ON c.id = To_Number (v.con_id)
99    JOIN items i
100      ON i.id = To_Number (v.itm_id)
101   ORDER BY sol_id, con_id, itm_id
102 /
    SOL_ID S_WT S_PR C_ID C_NAME          M_WT C_WT I_ID I_NAME     I_WT I_PR
         1 255 255     1 SEECS UG Block   100 100     1 BIT-10       35   35
                                                         2 BIT-11       40   40
                                                         6 BICSE-7      25   25
                         2 IAEC Building     70   70     4 BSCS-3       40   40
                                                         7 BESE-3       30   30
                         3 RIMMS Building    90   85     3 BSCS-2       35   35
                                                         5 BEE-4        50   50
         2 255 255     1 SEECS UG Block   100   95     4 BSCS-3       40   40
                                                         6 BICSE-7      25   25
                                                         7 BESE-3       30   30
                         2 IAEC Building     70   70     1 BIT-10       35   35
                                                         3 BSCS-2       35   35
                         3 RIMMS Building    90   90     2 BIT-11       40   40
                                                         5 BEE-4        50   50
         3 255 255     1 SEECS UG Block   100 100     3 BSCS-2       35   35
                                                         4 BSCS-3       40   40
                                                         6 BICSE-7      25   25
                         2 IAEC Building     70   65     1 BIT-10       35   35
                                                         7 BESE-3       30   30
                         3 RIMMS Building    90   90     2 BIT-11       40   40
                                                         5 BEE-4        50   50
         4 255 255     1 SEECS UG Block   100 100     3 BSCS-2       35   35
                                                         4 BSCS-3       40   40
                                                         6 BICSE-7      25   25
                         2 IAEC Building     70   70     2 BIT-11       40   40
                                                         7 BESE-3       30   30
                         3 RIMMS Building    90   85     1 BIT-10       35   35
                                                         5 BEE-4        50   50
         5 255 255     1 SEECS UG Block   100   95     2 BIT-11       40   40
                                                         6 BICSE-7      25   25
                                                         7 BESE-3       30   30
                         2 IAEC Building     70   70     1 BIT-10       35   35
                                                         3 BSCS-2       35   35
                         3 RIMMS Building    90   90     4 BSCS-3       40   40
                                                         5 BEE-4        50   50
         6 255 255     1 SEECS UG Block   100 100     2 BIT-11       40   40
                                                         3 BSCS-2       35   35
                                                         6 BICSE-7      25   25
                         2 IAEC Building     70   65     1 BIT-10       35   35
                                                         7 BESE-3       30   30
                         3 RIMMS Building    90   90     4 BSCS-3       40   40
                                                         5 BEE-4        50   50
         7 255 255     1 SEECS UG Block   100 100     2 BIT-11       40   40
                                                         3 BSCS-2       35   35
                                                         6 BICSE-7      25   25
                         2 IAEC Building     70   70     4 BSCS-3       40   40
                                                         7 BESE-3       30   30
                         3 RIMMS Building    90   85     1 BIT-10       35   35
                                                         5 BEE-4        50   50
         8 255 255     1 SEECS UG Block   100 100     1 BIT-10       35   35
                                                         4 BSCS-3       40   40
                                                         6 BICSE-7      25   25
                         2 IAEC Building     70   70     2 BIT-11       40   40
                                                         7 BESE-3       30   30
                         3 RIMMS Building    90   85     3 BSCS-2       35   35
                                                         5 BEE-4        50   50
         9 255 255     1 SEECS UG Block   100 100     1 BIT-10       35   35
                                                         4 BSCS-3       40   40
                                                         6 BICSE-7      25   25
                         2 IAEC Building     70   65     3 BSCS-2       35   35
                                                         7 BESE-3       30   30
                         3 RIMMS Building    90   90     2 BIT-11       40   40
                                                         5 BEE-4        50   50
        10 255 255     1 SEECS UG Block   100 100     1 BIT-10       35   35
                                                         3 BSCS-2       35   35
                                                         7 BESE-3       30   30
                         2 IAEC Building     70   65     2 BIT-11       40   40
                                                         6 BICSE-7      25   25
                         3 RIMMS Building    90   90     4 BSCS-3       40   40
                                                         5 BEE-4        50   50
        11 255 255     1 SEECS UG Block   100 100     1 BIT-10       35   35
                                                         3 BSCS-2       35   35
                                                         7 BESE-3       30   30
                         2 IAEC Building     70   65     4 BSCS-3       40   40
                                                         6 BICSE-7      25   25
                         3 RIMMS Building    90   90     2 BIT-11       40   40
                                                         5 BEE-4        50   50
        12 255 255     1 SEECS UG Block   100   95     1 BIT-10       35   35
                                                         3 BSCS-2       35   35
                                                         6 BICSE-7      25   25
                         2 IAEC Building     70   70     2 BIT-11       40   40
                                                         7 BESE-3       30   30
                         3 RIMMS Building    90   90     4 BSCS-3       40   40
                                                         5 BEE-4        50   50
        13 255 255     1 SEECS UG Block   100   95     1 BIT-10       35   35
                                                         3 BSCS-2       35   35
                                                         6 BICSE-7      25   25
                         2 IAEC Building     70   70     4 BSCS-3       40   40
                                                         7 BESE-3       30   30
                         3 RIMMS Building    90   90     2 BIT-11       40   40
                                                         5 BEE-4        50   50
        14 255 255     1 SEECS UG Block   100 100     1 BIT-10       35   35
                                                         2 BIT-11       40   40
                                                         6 BICSE-7      25   25
                         2 IAEC Building     70   65     3 BSCS-2       35   35
                                                         7 BESE-3       30   30
                         3 RIMMS Building    90   90     4 BSCS-3       40   40
                                                         5 BEE-4        50   50
98 rows selected.
Elapsed: 00:00:01.42Edited by: BrendanP on 20-Jan-2013 11:25
I found the regex needed to deduplicate:
AND RegExp_Instr (r_c.itm_path || r_i.path, ',(\d+),.*?,\1,') = 0

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WHERE
vPerf.DateTime >= DATEADD(Day, -1, GetDate())
AND vPerformanceRule.ObjectName like '%Processor Information%'
AND vPerformanceRuleInstance.InstanceName = '_Total'
AND (vPerformanceRule.CounterName IN ('% Processor Time'))
AND (vManagedEntity.Path IN (SELECT dbo.vManagedEntity.Name
FROM dbo.vManagedEntity INNER JOIN
dbo.vRelationship On dbo.vManagedEntity.ManagedEntityRowId = dbo.vRelationship.TargetManagedEntityRowId INNER JOIN
dbo.vManagedEntity As CompGroup On dbo.vRelationship.SourcemanagedEntityRowId = CompGroup.ManagedEntityRowId
WHERE CompGroup.DisplayName = 'bemis ibb prod'
ORDER BY path, vPerf.DateTime
Results
DateTime
SampleCount
AverageCPU
InstanceName
Path
ObjectName
CounterName
2/26/15 3:00 PM
2
1.98
_Total
servername.corp.com
Processor Information
% Processor Time
2/26/15 4:00 PM
2
2.09
_Total
servername.corp.com
Processor Information
% Processor Time
2/26/15 5:00 PM
2
1.72
_Total
servername.corp.com
Processor Information
% Processor Time
2/26/15 6:00 PM
2
1.83
_Total
servername.corp.com
Processor Information
% Processor Time
Thanks in Advance!
Mike Hanlon

Hi
Sql Query
SELECT TOP 10
vPerf.DateTime,
vPerf.SampleCount,
cast(vPerf.AverageValue as numeric(10,2)) as AverageCPU,
vPerformanceRuleInstance.InstanceName,
vManagedEntity.Path,
vPerformanceRule.ObjectName,
vPerformanceRule.CounterName
FROM Perf.vPerfHourly AS vPerf INNER JOIN
vPerformanceRuleInstance ON vPerformanceRuleInstance.PerformanceRuleInstanceRowId = vPerf.PerformanceRuleInstanceRowId
INNER JOIN
vManagedEntity ON vPerf.ManagedEntityRowId = vManagedEntity.ManagedEntityRowId INNER JOIN
vPerformanceRule ON vPerformanceRuleInstance.RuleRowId = vPerformanceRule.RuleRowId
WHERE
vPerf.DateTime >= DATEADD(Day, -1, GetDate())
AND vPerformanceRule.ObjectName like '%Processor Information%'
AND vPerformanceRuleInstance.InstanceName = '_Total'
AND (vPerformanceRule.CounterName IN ('% Processor Time'))
AND (vManagedEntity.Path IN (SELECT dbo.vManagedEntity.Name
FROM dbo.vManagedEntity INNER JOIN
dbo.vRelationship On dbo.vManagedEntity.ManagedEntityRowId = dbo.vRelationship.TargetManagedEntityRowId INNER
JOIN
dbo.vManagedEntity As CompGroup On dbo.vRelationship.SourcemanagedEntityRowId = CompGroup.ManagedEntityRowId
WHERE CompGroup.DisplayName = 'bemis ibb prod'
ORDER BY path, vPerf.DateTime
Regards
sridhar v

Problem writing a sql query for a select list based on a static LOV

Hi,
I have the following table...
VALIDATIONS
ID          Number     (PK)
APP_ID          Number
REQUESTED     Date
APPROVED     Date
VALID_TIL     Date
DEPT_ID          Number     (FK)
I have a search form with the following field item variables...
P11_DEPT_ID (select list based on dynamic LOV from depts table)
P11_VALID (select list based on static Yes/No LOV)
A report on the columns of the Validations table is shown based on the values in the search form. So far, my sql query for the report is...
SELECT v.APP_ID,
v.REQUESTED,
v.APPROVED,
v.VALID_TIL,
d.DEPT
FROM DEPTS d, VALIDATIONS v
WHERE d.DEPT_ID = v.DEPT_ID(+)
AND (d.DEPT_ID = :P11_DEPT_ID OR :P11_DEPT_ID = -1)
This query works so far. My problem is that I don't know how to do a search based on the P11_VALID item - if 'yes' is selected, then the VALID_TIL date is still valid. If 'no' is selected then the VALID_TIL date has passed.
Can anyone help me to extend my query to include this situation?
Thanks.

Hello !
Let's have a look at my example:create table test
id        number
,valid_til date
insert into test values( 1, sysdate-3 );
insert into test values( 2, sysdate-2 );
insert into test values( 3, sysdate-1 );
insert into test values( 4, sysdate );
insert into test values( 5, sysdate+1 );
insert into test values( 6, sysdate+2 );
commit;
select * from test;
def til=yes
select *
from test
where decode(sign(trunc(valid_til)-trunc(sysdate)),1,1,0,1,-1)
       =decode('&til','yes',1,-1);
def til=no
select *
from test
where decode(sign(trunc(valid_til)-trunc(sysdate)),1,1,0,1,-1)
       =decode('&til','yes',1,-1);
drop table test; It's working fine, I've tested it.
The above changes to my first idea I did because of time portion of the DATE datatype in Oracle and therefore the wrong result for today.
For understandings:
1.) TRUNC removes the time part of DATE
2.) The difference of to date-values is the number of days between.
3.) SIGN is the mathematical function and gives -1,0 or +1 according to an negative, zero or positiv argument.
4.) DECODE is like an IF.
Inspect your LOV for the returning values. According to my example they shoul be 'yes' and 'no'. If your values are different, you may have to modify the DECODE.
Good luck,
Heinz

Extracting the Logical sql query for the specified report in OBIEE 11g

Hi ,
I want to extract the logical SQL Query for the Particular report in OBIEE 11.1.1.5.
Any pointers related to this will be very helpful.
Thanks,
Sonali

for a try please add Logical sql view to ur report it will dispaly the Logical sql for that Report..
Hope it will helps you.

Oracle SQL query for getting specific special characters from a table

Hi all,
This is my table
Table Name- Table1
S.no    Name
1          aaaaaaaa
2          a1234sgjghb
3          a@3$%jkhkjn
4          abcd-dfghjik
5          bbvxzckvbzxcv&^%#
6          ashgweqfg/gfjwgefj////
7          sdsaf$([]:'
8          <-fdsjgbdfsg
9           dfgfdgfd"uodf
10         aaaa bbbbz#$
11         cccc dddd-/mnm
The output has to be
S.no    Name
3          a@3$%jkhkjn
5          bbvxzckvbzxcv&^%#
7          sdsaf$([]:'
8          <-fdsjgbdfsg
10         aaaa bbbbz#$
It has to return "Name" column which is having special characters,whereas some special chars like -, / ," and space are acceptable.
The Oracle query has to print columns having special characters excluding -,/," and space
Can anyone help me to get a SQL query for the above.
Thanks in advance.

You can achieve it in multiple ways. Here are few.
SQL> with t
2 as
3 (
4 select 1 id, 'aaaaaaaa' name from dual union all
5 select 2 id, 'a1234sgjghb' name from dual union all
6 select 3 id, 'a@3$%jkhkjn' name from dual union all
7 select 4 id, 'abcd-dfghjik' name from dual union all
8 select 5 id, 'bbvxzckvbzxcv&^%#' name from dual union all
9 select 6 id, 'ashgweqfg/gfjwgefj////' name from dual union all
10 select 7 id, 'sdsaf$([]:''' name from dual union all
11 select 8 id, '<-fdsjgbdfsg' name from dual union all
12 select 9 id, 'dfgfdgfd"uodf' name from dual union all
13 select 10 id, 'aaaa bbbbz#$' name from dual union all
14 select 11 id, 'cccc dddd-/mnm' name from dual
15 )
16 select *
17    from t
18   where regexp_like(translate(name,'a-/" ','a'), '[^[:alnum:]]');
        ID NAME
         3 a@3$%jkhkjn
         5 bbvxzckvbzxcv&^%#
         7 sdsaf$([]:'
         8 <-fdsjgbdfsg
        10 aaaa bbbbz#$
SQL> with t
2 as
3 (
4 select 1 id, 'aaaaaaaa' name from dual union all
5 select 2 id, 'a1234sgjghb' name from dual union all
6 select 3 id, 'a@3$%jkhkjn' name from dual union all
7 select 4 id, 'abcd-dfghjik' name from dual union all
8 select 5 id, 'bbvxzckvbzxcv&^%#' name from dual union all
9 select 6 id, 'ashgweqfg/gfjwgefj////' name from dual union all
10 select 7 id, 'sdsaf$([]:''' name from dual union all
11 select 8 id, '<-fdsjgbdfsg' name from dual union all
12 select 9 id, 'dfgfdgfd"uodf' name from dual union all
13 select 10 id, 'aaaa bbbbz#$' name from dual union all
14 select 11 id, 'cccc dddd-/mnm' name from dual
15 )
16 select *
17    from t
18   where translate
19         (
20            lower(translate(name,'a-/" ','a'))
21          , '.0123456789abcdefghijklmnopqrstuvwxyz'
22          , '.'
23         ) is not null;
        ID NAME
         3 a@3$%jkhkjn
         5 bbvxzckvbzxcv&^%#
         7 sdsaf$([]:'
         8 <-fdsjgbdfsg
        10 aaaa bbbbz#$
SQL>

How to create sql query for item master with operator LIKE with variables?

hi all,
How to create sql query for item master with
operator LIKE(Contains,Start With,End With) with variables using query generator in SAP B1 ?
Jeyakanthan

Hi Jeyakanthan,
here is an example (put the like statement into the where field)
SELECT T0.CardCode, T0.CardName FROM OITM T0 WHERE T0.CardName Like '%%test%%'
The %% sign is a wildcard. If you need start with write 'test%%' and otherwise ends with '%%test'. For contains you need '%%test%%'. You also could combinate this statements like 'test%%abc%%'. This means starts with test and contains abc.
Regards Steffen

How to write sql query for below example.

Hi,
I have requirement.
There are number of rows and I need the result through query as follows.Please help me to proved sql query for below mentioned requirement.
example: table TEST.
COLA COLB COLC COLD
MANAGER 5 NULL null
SR.MANAGE 6 3 NULL
VP 5 5 4
I have to write the sql query if COLA IS MANAGER THEN CONSIDER MANGER RECORD,AND IF ANY COLUMN FILED IS NULL FOR MANGER THEN CONSIDER COLA IS SR.MANGER, AND IF ANY COLUMN FILED IS NULL FOR SR,MANGER THEN CONSIDER VP records.
I need output as below.
COLB COLC COLD
5(MANGER) 3(sr.manger) 5(vp)
Please provide the for above mentioned output.
Thanks

<<if COLA IS MANAGER THEN CONSIDER MANGER RECORD>>
What does this sentence means? COLA does not cnatin a single record but the number of records with diffrent values.
Regards
Arun

How to write sql query for below mentioned eaxmple.

Hi,
I have requirement.
There are number of rows and I need the result through query as follows.Please help me to proved sql query for below mentioned requirement.
example: table TEST.
COLA COLB COLC COLD COLE COLF MANAGER 5 NULL NULL 3 NULL
SR.MANAGER 6 3 NULL NULL NULL
VP 5 5 4 5 5
I have to write the sql query if COLA IS MANAGER THEN CONSIDER MANGER RECORD,AND IF ANY COLUMN FILED IS NULL FOR MANGER THEN CONSIDER COLA IS SR.MANGER, AND IF ANY COLUMN FILED IS NULL FOR SR,MANGER THEN CONSIDER VP records.
I need output as below.
COLB COLC COLD COLE COLF
5(manager) 3(sr.manger) 4(vp) 3(manger) 3(vp)
Please provide the for above mentioned output.
Thanks

Duplicate thread. please view the answer posted in your first thread.
how to write sql query.
And, please don't post any duplicate thread.
Regards.
Satyaki De.

OIM sql Query for getting the status of the task which got failed

Hi Everyone,
We have a requirement like we need to get the status of a particular task(say Create User in OID resource - Completed\Rejected status) for the particular user.We are able to get the status of the resource provisioed to the user but not the status of the particular task getting trigerred for the user.can someone put some light on this.We need to get the SQL query for this.
Thanks in Advance.
Regards,
MKN

Hi
Use this sample query to get the task status, also check the cooments
SELECT USR.USR_LOGIN, OSI.SCH_KEY,SCH.SCH_STATUS,STA.STA_BUCKET FROM
OSI,SCH,STA,MIL,TOS,PKG,OIU,USR,OBJ,OST
WHERE OSI.MIL_KEY=MIL.MIL_KEY
AND SCH.SCH_KEY=OSI.SCH_KEY
AND STA.STA_STATUS=SCH.SCH_STATUS
AND TOS.PKG_KEY=PKG.PKG_KEY
AND MIL.TOS_KEY=TOS.TOS_KEY
AND OIU.USR_KEY=USR.USR_KEY
AND OIU.OST_KEY=OST.OST_KEY
AND OST.OBJ_KEY=OBJ.OBJ_KEY
AND OSI.ORC_KEY=OIU.ORC_KEY
AND OBJ.OBJ_NAME='AD User'
AND OST.OST_STATUS = 'Provisioning' -- filter accordinglly
AND STA.STA_BUCKET = 'Pending' -- filter accordinglly
AND PKG.PKG_NAME='AD User' -- filter accordinglly
AND MIL.MIL_NAME='System Validation' ---- filter accordinglly
Thanks,
Kuldeep

Provide sql query for below one

hi everyone,
in my source table [finanace_dept] contains two columns [finance_id,r_mature_kd] with 2 million records and sample data given below.
finance_id r_mature_kd
1 H
1 T
1 T
2 T
3 H
4 S
4 T
4 T
5 X
6 H
6 L
6 L
6 M
please provide sql query for below expected output.
expected output :
finance_id r_mature_kd
1 H
1 T
4 S
4 T
6 H
6 L
6 M
for column finance_id: '1', contains three records, but two distinct r_mature_kd hence it should retrive only two records with H,T
for column finance_id: '2','3', contains only one record hence this records should not retrive.
for column finance_id: '6', contains four records, but three distinct r_mature_kd hence it should retrive only two records with H,L,M
please help on this.

WITH T(finance_id,r_mature_kd) AS (
SELECT 1, 'H' FROM DUAL UNION ALL
SELECT 1, 'T' FROM DUAL UNION ALL
SELECT 1, 'T' FROM DUAL UNION ALL
SELECT 2, 'T' FROM DUAL UNION ALL
SELECT 3, 'H' FROM DUAL UNION ALL
SELECT 4, 'S' FROM DUAL UNION ALL
SELECT 4, 'T' FROM DUAL UNION ALL
SELECT 4, 'T' FROM DUAL UNION ALL
SELECT 5, 'X' FROM DUAL UNION ALL
SELECT 6, 'H' FROM DUAL UNION ALL
SELECT 6, 'L' FROM DUAL UNION ALL
SELECT 6, 'L' FROM DUAL UNION ALL
SELECT 6, 'M' FROM DUAL
SELECT DISTINCT finance_id,r_mature_kd,C FROM(
SELECT finance_id,r_mature_kd,COUNT(1) OVER (PARTITION BY finance_id) C
FROM T
WHERE C > 1
ORDER BY 1
FINANCE_ID
R_MATURE_KD
C
1
H
3
1
T
3
4
S
3
4
T
3
6
H
4
6
L
4
6
M
4
Ramin Hashimzade

Better SQL Query for clients without boundaries?

I've been using and modifying/experimenting with Chris Nackers' SQL query for missing boundaries (http://myitforum.com/myitforumwp/2011/12/07/sql-query-to-identify-missing-smsconfigmgr-boundaries/)
below (changed to add aliases)--but this seems to mainly be showing us non-clients, as several computers that were indeed missing boundaries (using SCCM 2007 SP2 R3, and all our boundaries are protected, most are IP Range, a few IP Subnet, none AD Site) are
not being listed, and everything in the listing has NULL SYS.Client0.
Is there a better query to pinpoint this issue, or maybe using something (error code or log?) that would show computers that can't find a distribution point or some other evidence of not having a boundary?
Thanks!
SELECT DISTINCT SYS.Name0, SYS.Client0, IPA.IP_Addresses0, IPS.IP_Subnets0, SMSAS.SMS_Assigned_Sites0
FROM dbo.v_R_System SYS
LEFT OUTER JOIN dbo.v_RA_System_IPSubnets IPS ON SYS.ResourceID = IPS.ResourceID
LEFT OUTER JOIN dbo.v_RA_System_IPAddresses IPA ON SYS.ResourceID = IPA.ResourceID
LEFT OUTER JOIN dbo.v_RA_System_SMSAssignedSites SMSAS ON SYS.ResourceID = SMSAS.ResourceID
LEFT OUTER JOIN dbo.v_RA_System_SystemOUName SOU ON SYS.ResourceID = SOU.ResourceID
WHERE (SMSAS.SMS_Assigned_Sites0 IS NULL)
AND (NOT (IPA.IP_Addresses0 IS NULL))
AND (NOT (IPS.IP_Subnets0 IS NULL))
AND SYS.Operating_System_Name_and0 LIKE 'microsoft%server%'
ORDER BY IPS.IP_Subnets0, SYS.Name0

I gotcha now... I think most people, myself included, rely on finding clients that are not assigned to determine if a boundary is missing. If you expect clients to not be assigned that's not going to work for you.
WHERE (SMSAS.SMS_Assigned_Sites0
IS NULL)
AND (NOT (IPA.IP_Addresses0
IS NULL))
AND (NOT
(IPS.IP_Subnets0 IS
NULL))
= This is saying show me all clients not assigned but they do have an IP address and they do have a subnet discovered.
In the case of CM12 it is actually possible for that not to work anyway because you can have separate boundaries for client assignment and content lookup.
I am not aware of any query that can compare the IP address, AD Site and IP subnet from each client to what's configured in boundaries and find machines that do not fall into any boundary.
John Marcum | http://myitforum.com/myitforumwp/author/johnmarcum/

I want sql query for this output

hi guys
could u tell how can i write sql query for this out put
i have one table like this
ID ACCOUTID TAX
1 1 A
2 1 B
3 2 C
4 2 D
5 3 E
7 NULL F
8 NULL G
MY OUT PUT MUST BE LIKE THIS
ID AID TAX
2 1 A
4 2 D
7 NULL F
8 NULL G
HERE IN THIS OUTPUT I SHOULD HAVE
MAXIMAM ID VALUE FOR A REPEATED AID VALUES
AND
THE ROWS AID VALUES IS NULL ALSO MUST PAPULATED IN THE OUTPUT.
I KNOW ONE SOLUTION LIKE THIS
SELECT MAX(ID),AID,TAX
FROM TABLE T
GROUP BY AID,TAX
UNION ALL
SELECT ID, AIC,TAX
FROM TABLE T
WHERE AID IS NULL;
BUT I WANT SAME RESULT WITH OUT USING LOGICAL OPERATORS.
COULD U PLZ TELL A SOL.

Will this help:
SQL> with t as
2    (
3      select 1 ID, 1 ACCOUTID, 'A' TAX from dual union all
4      select 2, 1, 'B' from dual union all
5      select 3, 2, 'C' from dual union all
6      select 4, 2, 'D' from dual union all
7      select 5, 3, 'E' from dual union all
8      select 7, NULL, 'F' from dual union all
9      select 8, NULL, 'G' from dual
10    )
11 --
12 select id, ACCOUTID AID, Tax
13 from
14 (
15    select t.*
16          ,count(1)       over (partition by t.ACCOUTID) cn
17          ,row_number()   over (partition by t.ACCOUTID order by id desc) rn
18    from t
19 )
20 where cn > 1
21 and (rn = 1 or ACCOUTID is null)
22 /
        ID        AID T
         2          1 B
         4          2 D
         8            G
         7            F
-- If I leave out the OR condition then you'll get this:
SQL> ed
Wrote file afiedt.buf
1 with t as
2    (
3      select 1 ID, 1 ACCOUTID, 'A' TAX from dual union all
4      select 2, 1, 'B' from dual union all
5      select 3, 2, 'C' from dual union all
6      select 4, 2, 'D' from dual union all
7      select 5, 3, 'E' from dual union all
8      select 7, NULL, 'F' from dual union all
9      select 8, NULL, 'G' from dual
10    )
11 --
12 select id, ACCOUTID AID, Tax
13 from
14 (
15    select t.*
16          ,count(1)       over (partition by t.ACCOUTID) cn
17          ,row_number()   over (partition by t.ACCOUTID order by id desc) rn
18    from t
19 )
20 where cn > 1
21* and rn = 1
SQL> /
        ID        AID T
         2          1 B
         4          2 D
         8            G
--which follows the description you've given, but not the output

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