SQL query to show collection paths and members

Hi guys, I'm after a sql query that will export all the collections along with their path and the members of those collections.
I already have something that will display all the collections and members but it's just a flat list. I'm really after something that will produce something like this:
Collection                        SystemName
Servers\Prod                      Server1
Servers\Prod\App1            Server2
Servers\Prod\App1            Server3
Servers\Test                       Server4
Servers\Dev                       Server5
Testing\Phase1                 Server6
Testing\Phase1\Stage2      Server7
Testing\Phase1\Stage2    Server8
etc
Can this be done?

Hi Garth, appreciate the feedback and I realise the report will probably be ridiculously long, however, the point is irrelevant. Whether it's 100 page or 10,000 pages is not the issue, it's something I've been asked to produce.
Actually I will 100% disagree with you. Your job as the subject matter expert (SME) is to guide people to what they truly want. Blindly giving them something that is useless
is not helping them do their job at all.
I have found that Manager and Management truly appreciate it when you say ”What you are asking for is not what you truly want. You will get a report will 10,000 pages and you
will be over loaded with data.” You then have to follow up and ask “How exactly will know this info help you do your job? What decisions will be made from this report” etc..
this is where you as a SME, will shine and can truly help them do their job.
This report is do able but it is not a 5 minute task. Best of luck with the report.
Garth Jones | My blogs: Enhansoft and
Old Blog site | Twitter:
@GarthMJ

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SQL Query to get collections with no members

So I have a query that I'm using to give me collection information (collection ID, collection name, count) but it only shows me collections that have at least 1 member.
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Sql query slowness due to rank and columns with null values:


Sql query slowness due to rank and columns with null values:
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Declaration:
create table PropertyOwners (
[Key] int not null primary key,
PropertyKey int not null,
BoughtDate DateTime,
OwnerKey int null,
GroupKey int null
go
[Key] is primary key and combination of PropertyKey, BoughtDate, OwnerKey and GroupKey is unique.
With the following index:
CREATE NONCLUSTERED INDEX [IX_PropertyOwners] ON [dbo].[PropertyOwners]
[PropertyKey] ASC,
[BoughtDate] DESC,
[OwnerKey] DESC,
[GroupKey] DESC
go
Description of the case:
For single BoughtDate one property can belong to multiple owners or single group, for single record there can either be OwnerKey or GroupKey but not both so one of them will be null for each record. I am trying to retrieve the data from the table using
following query for the OwnerKey. If there are same property rows for owners and group at the same time than the rows having OwnerKey with be preferred, that is why I am using "OwnerKey desc" in Rank function.
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select PropertyKey, BoughtDate, OwnerKey, GroupKey
from (
select PropertyKey, BoughtDate, OwnerKey, GroupKey,
RANK() over (partition by PropertyKey order by BoughtDate desc, OwnerKey desc, GroupKey desc) as [Rank]
from PropertyOwners
) as result
where result.[Rank]=1 and result.[OwnerKey]=@ownerKey
It is taking 2-3 seconds to get the records which is too slow, similar time it is taking as I try to get the records using the GroupKey. But when I tried to get the records for the PropertyKey with the same query, it is executing in 10 milliseconds.
May be the slowness is due to as OwnerKey/GroupKey in the table can be null and sql server in unable to index it. I have also tried to use the Indexed view to pre ranked them but I can't use it in my query as Rank function is not supported in indexed
view.
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create table #result (PropertyKey int not null, BoughtDate datetime, OwnerKey int null, GroupKey int null, [Rank] int not null)Create index idx ON #result(OwnerKey ,rnk)
insert into #result(PropertyKey, BoughtDate, OwnerKey, GroupKey, [Rank])
select PropertyKey, BoughtDate, OwnerKey, GroupKey,
RANK() over (partition by PropertyKey order by BoughtDate desc, OwnerKey desc, GroupKey desc) as [Rank]
from PropertyOwners
go
declare @ownerKey int = 1
select PropertyKey, BoughtDate, OwnerKey, GroupKey
from #result as result
where result.[Rank]=1
and result.[OwnerKey]=@ownerKey
go
Best Regards,Uri Dimant SQL Server MVP,
http://sqlblog.com/blogs/uri_dimant/
MS SQL optimization: MS SQL Development and Optimization
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Large scale of database and data cleansing
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Kind regards,
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Hi
Please Check this
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Hi,
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Jeffrey S. Patton Jeffrey S. Patton Systems Specialist, Enterprise Systems University of Kansas 1001 Sunnyside Ave. Lawrence, KS. 66045 (785) 864-0242 | http://patton-tech.com

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GO
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Please mark as answer, if this has helped you solve the issue.
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group by
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Kind regards,
Max

The solution for my problem:
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OINV.U_I_Imported = 'Y' and
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union all
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union all
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Hello
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See me reply to your other post with the exact same details, in the CM07 forum.
http://www.enhansoft.com/

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Please remember to mark the replies as answers if they help and unmark them if they provide no help. If you have feedback for TechNet Subscriber Support, contact [email protected]

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Hi friends,
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