SQL query using connect by clause

Question

Hi,
I have table:
SQL> col id for 999
SQL> col code for a30
SQL> select id,code from t1;
  ID CODE
704 ,2,3,7,8,
707 ,15,12,17,18,
742 ,23,25,27,28,
   5 ,53,65,67,58,
4 rows selected.---
When I run query:
select id,
       substr(code,instr(code,chr(44),1,level)+1,instr(code,chr(44),1,level+1)-instr(code,chr(44),1,level)-1) code
      from(
        select  id,
                code,
                length(code) - length(replace(code,',',''))-1 len
        from t1
        where id=5)
connect by level <= len;
  ID CODE
   5 53
   5 65
   5 67
   5 58
4 rows selected.How to modify my query to get this output:
ID CODE
5 53
5 65
5 67
5 58
704 2
704 3
704 7
704 8
707 15
707 12
707 17
707 18
742 23
742 25
742 27
742 28What is the best way to get this output?
My db:
SQL> select * from v$version;
BANNER
Oracle9i Enterprise Edition Release 9.2.0.6.0 - 64bit Production
PL/SQL Release 9.2.0.6.0 - Production
CORE    9.2.0.6.0       Production
TNS for Solaris: Version 9.2.0.6.0 - Production
NLSRTL Version 9.2.0.6.0 - Production
5 rows selected.Thanks for answers!
Regards,
Marko

Answer 1

Hi,
Generate a separate "counter table" that has the numbers 1, 2, 3, ... , x, where x is the greatest number you'll ever need.
Join to this table, using a join condition that gets the exact numbers you need for each row.
Use the number from the counter table where you are currently using LEVEL.
That is:
WITH     cntr      AS
     SELECT     LEVEL     AS n
     FROM     dual
     CONNECT BY     LEVEL <= ( SELECT  MAX ( LENGTH (code)
                                         - LENGTH (REPLACE (code, ','))
                       FROM        t1
                     ) - 1
select id,
       substr(code,instr(code,chr(44),1,n)+1,instr(code,chr(44),1,n+1)-instr(code,chr(44),1,n)-1) code
FROM   t1
JOIN   cntr     ON     cntr.n <= LENGTH (code) - LENGTH (REPLACE (code, ','))
;If you're using Oracle 10 (or higher) regular expressions would simplify this a lot.