Statspack report generation shell script?

Question

Does anyone have a shell script (unix/solaris) which does the following:
Gets the snap_ids from the 09:00 and 17:00 statspack snapshots (from today or yesterday), and runs spreport.sql, using these snapshot ids as begin_snap and end_snap.
I do not want to purge any snapshots from the database. I simply want to generate a daily "9 to 5" statspack report every day.
TIA,
Dave

Answer 1

Hi,
You can do the following way:
1. Write script to get the begin snap_id as:
$cat > begin_snap.sql
set head off
set echo off
set verify off
set termout off
spool begin_snap_id.log
SELECT snap_id
FROM stats$snapshot
WHERE TRUNC(snap_time) = TRUNC(SYSDATE-1)
AND TO_NUMBER(TO_CHAR(snap_time,'HH24')) =9;
spool off
2. write a script to get end snap id as same as above substituting 9 with 17 with script name as end_snap.sql and spool file name as end_snap_id.log.
3. write a script to pass arguments for spreport.sql as:
cat > statspack_report
#!/bin/ksh
ORACLE_HOME=/home/oratest
TODAY=`date '+%Y%m%d' `
REPORT=report_${TODAY}.txt
sqlplus -s perfstat/perfstat@database_name @$ORACLE_HOME/begin_snap.sql <<EOF
EOF
BEGIN_ID=`cat /home/oratest/begin_snap_id.log | sed '/^$/d' `
sqlplus -s perfstat/perfstat@database_name @$ORACLE_HOME/end_snap.sql <<EOF
EOF
END_ID=`cat /home/oratest/end_snap_id.log | sed '/^$/d' `
sqlplus -s perfstat/perfstat@database_name @$ORACLE_HOME/rdbms/admin/spreport.sql <<EOF
${BEGIN_ID}
${END_ID}
${REPORT}
EOF
you can schedule this statspack_report in a crontab.
thanks
srinivas.