Staying on the edit page after posting

Question

There's something that I can't get to work and probably is not difficult at all.
I want users to stay on the editpage after posting the form.
I thought to do it in the processEdit method.
By creating an url and give this as a return value. But I keep comming back to the default portal page.
My users can go to the edit page of a channel. On the editpage I have made a telephonebook in which the users can search.
The intention is that the users see their results on the edit page and they can select some of the results.
my code (which doesn't work):
String url = request.getRequestedURL().toString();
URL editpageURL = new URL(url);
return editpageURL;

Answer 1

I use the following piece of code to display error messages on the edit pages and to redirect to the user back to the same edit screen. It has been working for me for quite a while.
desktopUrl = context.getDesktopURL(request);
containerName = request.getParameter("containerName");
provider = request.getParameter("editChannelName");
targetprovider = request.getParameter("provider");
if (log.isDebugEnabled()) {
log.debug("desktopUrl: "+context.getDesktopURL(request));
log.debug("containerName: "+containerName);
log.debug("provider: "+ provider);
log.debug("targetprovider: "+ targetprovider);
log.debug("errorMessage: "+ errorMessage);
url = new StringBuffer();
url.append(desktopUrl);
url.append("?action=edit");
url.append("&provider="+provider);
url.append("&targetprovider="+targetprovider);
url.append("&containerName="+containerName);
if (errorMessage != null) url.append("&error="+URLEncoder.encode(errorMessage));
if (log.isDebugEnabled()) log.debug("errorUrl: "+ url.toString());
url = new StringBuffer(context.encodeURL(url.toString()));
errorUrl = new URL(url.toString());
return errorUrl;