Stoplight Format: How to show percent sign next to each value?

I need to show a percent sign next to each data value on a column that has a stoplight format. The calculation has been created and works perfectly. But when I add the stoplight format, the percent sign '%' disappears. For example, acolumn data value is 95.25%. After I add the stoplight formula, 95.25% becomes 95.25.

Thanks for your help, nearly worked but only returned results where the if statement was met ie where locked =0, so I used an additional statement to display something else when when locked=1
<?php
if($row_spec_rx['locked'] == 1) {
echo "button html goes here";
?>
<?php
if($row_spec_rx['locked'] == 0) {
echo "something else";
?>
I am sure there must be a more elegant way of doing this!

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<?php require_once('Connections/testmypms.php'); ?>
<?php
$currentPage = $_SERVER["PHP_SELF"];
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if (isset($_GET['pageNum_spec_rx'])) {
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<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1">
<title>Spec Rx3</title>
<script language="JavaScript" type="text/JavaScript">

</script>
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<tr>
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    <td> </td>
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    <td> </td>
    <td> </td>
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    <td> </td>
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<tr>
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    <td><?php echo $row_spec_rx['spec_rx_rvprism']; ?></td>
    <td><?php echo $row_spec_rx['spec_rx_rvprismbase']; ?></td>
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    <td><?php echo $row_spec_rx['spec_rx_rnhprismbase']; ?></td>
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    <td><?php echo $row_spec_rx['spec_rx_rintvprism']; ?></td>
    <td><?php echo $row_spec_rx['spec_rx_rintvprismbase']; ?></td>
</tr>
<tr>
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    <td><?php echo ($row_spec_rx['spec_rx_lsph']<>null) ? sprintf ("%+4.2f",$row_spec_rx['spec_rx_lsph']) : null; ?></td>
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    <td><?php echo $row_spec_rx['spec_rx_lnvprism']; ?></td>
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    <td><?php echo $row_spec_rx['spec_rx_linthprism']; ?></td>
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    <td><?php echo $row_spec_rx['spec_rx_lintvprism']; ?></td>
    <td><?php echo $row_spec_rx['spec_rx_lintvprismbase']; ?></td>
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    <td> </td>
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    <td> </td>
    <td> </td>
    <td> </td>
    <td> </td>
    <td> </td>
    <td> </td>
    <td> </td>
    <td> </td>
    <td> </td>
    <td> </td>
    <td> </td>
</tr>
</table>
<p> </p>
<?php } while ($row_spec_rx = mysql_fetch_assoc($spec_rx)); ?>
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<p> </p>
<p> </p>
</body>
</html>
<?php
mysql_free_result($spec_rx);
mysql_free_result($demographics);
?>

Thanks for your help, nearly worked but only returned results where the if statement was met ie where locked =0, so I used an additional statement to display something else when when locked=1
<?php
if($row_spec_rx['locked'] == 1) {
echo "button html goes here";
?>
<?php
if($row_spec_rx['locked'] == 0) {
echo "something else";
?>
I am sure there must be a more elegant way of doing this!

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