String parsing method

Question

Hi,
Lets suppose I have the following string inputs:
12345600
43121000
12093230
12340000
I need to write a methode that the input convert to the following output:
12.34.56
43.12.10
12.09.32.30
12.34
So if you have two (four) succesive zeros at the end, you have to eliminate them.

Answer 1

hi,
use following code, it can handle inner-double-zeros too
"123004500000" => "12.30.04.50"
* Convert a long-value to a pointed string
* "123450000" => "12.34.50"
* "12300450000" => "12.30.04.50"
* @author Oliver SCORP
public final static String PointedString(long parLong) {
   try{
      String s = String.valueOf(parLong);
      if (s == null)
         return null;
      int idx = 0, idx2 = 0, idxt = 0, mod = 0;
      boolean zero = false, zero2 = false, zerozero = false;
      char[] ca = s.toCharArray();
      char[] ca2 = new char[ca.length * 2];
      char[] ca_temp = new char[ca.length * 2];
      char[] pat = new char[2];
      for (idx = 0; idx < ca.length; idx++){
         mod = idx % 2;
         if (mod == 0){
            pat[0] = ca[idx];
            if (ca[idx] == '0')
               zero = true;
            } else {
               pat[1] = ca[idx];
               if (ca[idx] == '0')
                  zero2 = true;
               if ((zero == true)&&(zero2 == true))
                  zerozero = true;
               else
                  zerozero = false;
               zero = false;
               zero2 = false;
               ca_temp[idxt] = '.';
               ca_temp[idxt + 1] = pat[0];
               ca_temp[idxt + 2] = pat[1];
               idxt += 3;
               if (!zerozero){
                  System.arraycopy(ca_temp, 0, ca2, idx2, idxt);
                  ca_temp = new char[ca.length * 2];
                  idx2 += idxt;
                  idxt = 0;
               zerozero = false;
       char[] ca3 = new char[idx2 - 1];
       System.arraycopy(ca2, 1, ca3, 0, idx2 - 1);
       s = String.valueOf(ca3);
       return s;
       }catch(Exception e){
          System.err.println(e.toString());
          return null;
}cu
Oliver SCORP