String to XML Document

Can anyone say how to transform a XML String to XML document
(eg: String xmlstring="<root><main>Title</main></root>";
How can I transform this to XML Document??
Guhan

Right, my mistake, this is what happens when you type code in a browser... hard to compile.
Document XMLDoc=DocumentBuilderFactory.newInstance().newDocumentBuilder().parse(new InputSource(new StringReader("<root><main>Title</main></root&g t;")))PS. Consider following the online JAXP tutorial: http://java.sun.com/xml/tutorial_intro.html

Similar Messages

Converting string to xml Document object.

Hi all,
I having a string consiste of xml data.
I wants to convert this to an xml document object.
When i am trying to do this i am getting fatal error Premature End of file.
This is sample code from my program.
String xmlStr = " <TravelItineraryAddInfoRQ>
<POS>
<Source PseudoCityCode="A2PB"/>
</POS>
</TravelItineraryAddInfoRQ>";
DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
factory.setNamespaceAware( false );
DocumentBuilder builder = null;
char[] ch = new char[1200];
builder = factory.newDocumentBuilder();
StringReader sr = new StringReader(xmlStr);
InputSource is = new InputSource(sr);
Reader r = is.getCharacterStream();
r.read(ch);
System.out.println("String Starting ==== ");
for(int i=0;i<ch.length;i++)
System.out.print(ch);
Document XMLDoc = builder.parse(new InputSource(sr));
System.out.println("Document Object ==== "+XMLDoc);
thnx,
raj

Hi Rajaven,
use the below step, I think it could help u
StringBufferInputStream sb = new StringBufferInputStream(strBf));
doc = db.parse(sb);first conver a string to StringBufferInputStream then parse to doc Object
hope it will solve.
let me know if it's not working
With cheers,
PrasannA

String to xml object java

Hello,
can anyone suggest me how to convert string to xml object in java?
I have a string (Data) ant now I have to pass it as parameter as xml object, which structure should be:
<MGWData>Data</MGWData>
Where I surf I always see only solutions for converting string to xml document, but never to xml object.
maybe the problem is I don't completely understand what xml object is in first place :/
Any answer would help.
Thanks.

894871 wrote:
here is the method to call:
+/**+
* Sets the p_DATAXMLTYPEIN value for this SVARCHAR2INSERT_RECEIVESInput.
*+
* @param p_DATAXMLTYPEIN
*public void setP_DATAXMLTYPEIN(com.oracle.xmlns.orawsv.SISTEMA_MOKA.MGW_PUBLIC_FUNCTIONS.SVARCHAR2INSERT_RECEIVESInputP_DATAXMLTYPEIN p_DATAXMLTYPEIN) {*
this.p_DATAXMLTYPEIN = p_DATAXMLTYPEIN;
one of the classes contains:
*public class SVARCHAR2INSERT_RECEIVESInputP_DATAXMLTYPEIN implements java.io.Serializable, org.apache.axis.encoding.AnyContentType {*
*private org.apache.axis.message.MessageElement [] _any;*
this method and some classes where generated using eclipse and wsdl file by creating web service client.
wsdl says for that part: *<xsd:element name="P_DATA-XMLTYPE-IN">*
So I suppose it should involve smth org.apache.axis.message.MessageElement. But when I create any type of parameter, it gives me error:
+ ....cannot be cast to com.oracle.xmlns.orawsv.SISTEMA_MOKA.MGW_PUBLIC_FUNCTIONS.SVARCHAR2INSERT_RECEIVESInputP_DATAXMLTYPEIN+
I am new in web service stuff so thank you for response.Can you explain in plain English what you are trying to do? Or provide a [url http://sscce.org/]SSCE.

Error:SOAP: response message contains an error XIAdapter/PARSING/ADAPTER.SOAP_EXCEPTION - soap fault: Server was unable to read request. --- There is an error in XML document (1, 447). --- Input string was not in a correct format.

Hi All,
We have a scenario of FTP-->PI---> Webservice. While triggering the data in the FTP, it is failing in the PI with the below error
SOAP: response message contains an error XIAdapter/PARSING/ADAPTER.SOAP_EXCEPTION - soap fault: Server was unable to read request. ---> There is an error in XML document (1, 447). ---> Input string was not in a correct format.
Can you please help?

Hi Raja- It seems to be a data quality issue.
Check for the value @ 1447 position in the xml message that you are trying to send to web service..
may be a date filed/decimal value which is not in expected format.

Parseing an XML Document as a String

Hi all,
i am trying to parse an XML document to a parser. I get the file as a request parameter, which is filled in to at String variable.
But for some reason i get an SAXException, does anyone se the problem?
Thank you for your help...
Below is the code
import java.io.*;
import javax.servlet.*;
import javax.servlet.http.*;
import java.util.*;
import java.text.*;
import java.net.*;
import java.net.URL;
import java.sql.*;
import org.w3c.dom.Document;
import org.w3c.dom.NamedNodeMap;
import org.w3c.dom.Node;
import org.w3c.dom.NodeList;
import org.xml.sax.SAXException;
import org.xml.sax.SAXParseException;
import javax.xml.parsers.*;
import javax.xml.transform.stream.StreamSource;
public class StartServlet extends HttpServlet
private boolean debug = true;
private final static String CONTENT = "content";
private final static String COOKIES = "cookies";
String resp = new String();
private static String NODE_TYPES[] = new String[] {
     "ELEMENT",
     "ATTRIBUTE",
     "TEXT",
     "CDATA_SECTION",
     "ENTITY_REFERENCE",
     "ENTITY",
     "PROCESSING_INSTRUCTION",
     "COMMENT",
     "DOCUMENT",
     "DOCUMENT_TYPE",
     "DOCUMENT_FRAGMENT",
     "NOTATION" };
public static void println(String s, int indent) {
     for(int i = 0 ; i < indent; i++) {
               System.out.println(" ");
     System.out.println(s);
public static void println(String s) {
     System.out.println(s);
public static void print(Node node){
     printImpl(node, 0);
public static void printImpl(Node node, int indent){
     if(node == null) {
          return;
     String nodeType = NODE_TYPES[node.getNodeType()];
     String nodeName = node.getNodeName();
     String nodeValue = node.getNodeValue();
     if(nodeValue != null) {
          nodeValue = nodeValue.trim();
     if(nodeType.equals("TEXT") && nodeValue.equals("")) {
          ; //Ignore emty node
     else {
          println(nodeType + " - " + nodeName + " - " + nodeValue, indent);
     NamedNodeMap attributes = node.getAttributes();
     if (attributes != null) {
          for(int i = 0; i < attributes.getLength(); i++) {
               printImpl(attributes.item(i), indent + 1);
     NodeList children = node.getChildNodes();
     if(children != null) {
          for(int i = 0; i < children.getLength(); i++){
               printImpl(children.item(i), indent + 1);
public static DocumentBuilder newBuilder(boolean validation)
                    throws ParserConfigurationException {
     DocumentBuilderFactory domFactory = DocumentBuilderFactory.newInstance();
     domFactory.setValidating(validation);
     domFactory.setNamespaceAware(true);
     DocumentBuilder domBuilder = domFactory.newDocumentBuilder();
     //domBuilder.setErrorHandler(new PrintErrorHandler());
     return domBuilder;
public static Document newDocument()
                    throws ParserConfigurationException{
     DocumentBuilder domBuilder = newBuilder(false);
     Document document = domBuilder.newDocument();
     return document;
public static Document parse( String xml, boolean validation)
                    throws ParserConfigurationException, IOException, SAXException {
          DocumentBuilder domBuilder = newBuilder(validation);
          Document document = domBuilder.parse(xml);
          return document;
public void init() {
public void service( javax.servlet.http.HttpServletRequest req, javax.servlet.http.HttpServletResponse res) {
          String[] cookies = null;
          try{
               Hashtable document = getDocument("http://.../first.xml", cookies);
               resp = (String) document.get(CONTENT);
               debug(resp);
               print(parse(resp, false));
          catch (SAXParseException e){
               System.out.println("Saxfejl");
               //System.exit(1);
          catch (Exception e){
               e.printStackTrace();
               System.exit(1);
public void debug(String msg) {
     if(debug) {
          System.out.println(msg);
public void performTask(javax.servlet.http.HttpServletRequest request, javax.servlet.http.HttpServletResponse response) {
     try
          // Insert user code from here.
     catch(Throwable theException)
          // uncomment the following line when unexpected exceptions
          // are occuring to aid in debugging the problem.
          //theException.printStackTrace();
public void doGet(javax.servlet.http.HttpServletRequest request, javax.servlet.http.HttpServletResponse response) throws javax.servlet.ServletException, java.io.IOException {
     performTask(request, response);
public void doPost(javax.servlet.http.HttpServletRequest request, javax.servlet.http.HttpServletResponse response) throws javax.servlet.ServletException, java.io.IOException {
     performTask(request, response);
private Hashtable getDocument(String urlCode, String[] oldCookies) {
     Hashtable document = new Hashtable();
     HttpURLConnection http = null;
     try {
          URL httpURL = new URL(urlCode);
          // If HTTP Protocol, then open connection using the Request method indicated
          URLConnection conn = httpURL.openConnection();
          http = (HttpURLConnection) conn;
          //http.setRequestMethod("GET");
          http.setDoInput(true);
          http.setDoOutput(true);
          http.setUseCaches(false);
          http.setRequestProperty("Content-Type", "application/x-www-form-urlencoded");
          if (oldCookies != null) {
               for (int j = 0; j < oldCookies.length; j++) {
                    String cookie = oldCookies[j];
                    http.setRequestProperty("Cookie", cookie);
          http.connect();
          http.getContent();
          StringBuffer tsb = new StringBuffer("");
          if (http.getResponseCode() == 200) {
               InputStream cis = http.getInputStream();
               byte[] a = new byte[1024];
               int n = cis.read(a);
               while (n >= 0) {
                    tsb.append(new String(a, 0, n));
                    n = cis.read(a);
               cis.close();
               document.put(CONTENT, tsb.toString());
          String[] cookies = null;
          if (cookies == null) {
               int headerFieldIndex = 0;
               String headerFieldValue = http.getHeaderField(headerFieldIndex);
               Vector cookieValues = new Vector();
               while (headerFieldValue != null) {
                    String headerFieldName = http.getHeaderFieldKey(headerFieldIndex);
                    if ((headerFieldName != null) && headerFieldName.toLowerCase().equals("set-cookie")) {
                         int index = headerFieldValue.indexOf(";");
                         if (index > -1) {
                              headerFieldValue = headerFieldValue.substring(0, index);
                         cookieValues.addElement(headerFieldValue);
                    headerFieldValue = http.getHeaderField(++headerFieldIndex);
               cookies = new String[cookieValues.size()];
               cookieValues.copyInto(cookies);
          document.put(COOKIES, cookies);
     catch (Exception e) {
          debug("url problem" + e);
     finally {
          if (http != null) {
               http.disconnect();
     return document;
}

Hi,
Use this code it will helpful to you.
resultXMLDocument=(XmlDocument)documentDoc;
StringWriter sw = new StringWriter();
resultXMLDocument.write((Writer) sw);
xmlString=sw.toString();
thnaks,
suneel

How to create an XML document from a String.

Can anyone help,
     In the Microsoft XML Document DOM there is a load function load(string) which will create an XML document, but now we are switching to Java and I do not know how to create and XML document from a string, this string �xml document� is passed to my program from a webservice and I need to read several xml elements form it in a web server.
This string is a well formatted XML document:
<?xml version="1.0" encoding="UTF-8"?>
<Countries NumberOfRecords="1" LanguageID="en-us">
     <Country>
          <CountryCode>AU</CountryCode>
          <CountryName>AUSTRALIA</CountryName>
     </Country>
</Countries>

Thanks PC!
I made it work using:
DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
DocumentBuilder builder = factory.newDocumentBuilder();
factory.setIgnoringComments(true); // We want to ignore comments
// Now use the factory to create a DOM parser
DocumentBuilder parser = factory.newDocumentBuilder();
//TransformThisStringBuffer is a string buffer wich contain the 'XML document (String)'
InputStream in = new ByteArrayInputStream(TransformThisStringBuffer.toString().getBytes());
// Parse the InputStream and build the document
Document document = parser.parse(in);
But which one is faster InputSource or InputStream, were would you put the "new InputSource(new StringReader(yourString))" in the above code?

XML: How to convert xml string into Node/Document

I have a string in xml form.
<name>
<first/>
<second/>
</name>
I want to convert this string into DOM Node or Document.
How can I do this?
Any help or pointer?
TIA
Sachin

Try this :
DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
DocumentBuilder db = dbf.newDocumentBuilder();
Document doc = db.parse(new org.xml.sax.InputSource(new StringReader(strXml)));Hope this helps.

Converting XML Document to String

Dear All,
I am quite new to Java Web Services. I have made a Java Class which calls all the web services . I am displaying the results on a Command prompt. Below is my sample code:
import javax.xml.rpc.Service;
import javax.xml.rpc.Stub;
import horusWS.Horus_x0020_Web_x0020_Services_Impl;
import horusWS.Horus_x0020_Web_x0020_ServicesSoap;
public class JavaClient {
public static void main(String[] args)
Horus_x0020_Web_x0020_Services_Impl service = new Horus_x0020_Web_x0020_Services_Impl();
Horus_x0020_Web_x0020_ServicesSoap port = service.getHorus_x0020_Web_x0020_ServicesSoap();
String str;
str = port.getTextFeedbackLearner(1,"P001",1);
//where getTextFeedbackLearner is the my Web Service.
System.out.println(str);
System.out.println returns the web service in string format. Now I want to compare this string to my actual getTextFeedbackLearner.xml file. But I think I need to convert getTextFeedbackLearner.xml to string first. Please let me know
how can I convert an XML Document to String.
Thanking you in Anticipation.
cheers,
Sunil Sabir

You can read the XML document as you read any other file.
Read it into a String variable.
Check java.io.FileReader, java.io.BufferReader, etc.

How to get an xml string into a Document w/o escaping mark-up characters?

Hi,
I am using one of the latest xerces using Java. I am pretty sure I am using xerces-2.
I have an existing Document and I am trying to add more content to it. The new content itself is xml string. I am trying to insert this xml string into the document using document.createTextNode. I am able to insert, but somewhere it is escaping the mark-up characters (<,>,etc). When I convert the document into String, I can see, for example, <userData> instead of <userData>.
There is an alternative option to accomplish this by creating a new document with this xml string, get the root element, import this element into my document. Execution time for this procedure is very high - means, this is very bad in terms of time-wise performance.
Can any help on how to accomplish this (bringing an xml string into a document without escaping mark-up characters) in time-efficient way.

So you want to treat the contents of the string as XML rather than as text? Then you have to parse it.
Or if your reason for asking is just that you don't like the look of escaped text, then use a CDATA section to contain the text.

String representation of the xml document

hi, I have created the following xml document using the DOM api. I want to the "function" to return a "string" - which represents the xml document i created. How do u do that?
As of now it doesnt return anything...
How do u return the entire xml document as character data..? just like
<root><elements>data</elements></root>....
anyhelp would be great.
import java.io.*;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.parsers.DocumentBuilder;
import org.w3c.dom.*;
public class test1{
private static void function()throws IOException, DOMException{
DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance ();
DocumentBuilder db = dbf.newDocumentBuilder ();
Document doc = db.newDocument ();
Element record = doc.createElement ("record");
Element name = doc.createElement ("name");
Element address = doc.createElement ("address");
Element zip = doc.createElement ("zip");
Text nameText = doc.createTextNode("bill");
Text addressText = doc.createTextNode("128, washington");
Text zipText = doc.createTextNode("10000");
doc.appendChild(record);
record.appendChild(name);
name.appendChild(nameText);
record.appendChild(address);
address.appendChild(addressText);
record.appendChild(zip);
zip.appendChild(zipText);
public static void main (String argv [])throws Exception {
function();
}

Brent,
Looks like you're using the Sun Java Parser. I'll show you how to do it with the Oracle XML Parser and you can extrapolate...
Document doc = new XMLDocument();
// Stuff here to build up the DOM Doc
// with elements, etc.
// Print the Document to a String
StringWriter sw = new StringWriter();
// Wrap the stringwriter in a printwriter
PrintWriter pw = new PrintWriter(sw);
// Print to the printwriter
((XMLDocument)doc).print(pw);
// return the string from the stringwriter
return sw.toString();

How to write a string as an XML Document

I wrote a web service to receieve a string and then write as an XMl document . But In my writer.java program, I am not doing something right. Please let me know what I am doing wrong.
Below is writer program:
public class Writer
public Writer()
} public void WriteHabFile(String out, String fileName)
XMLDocument doc = new XMLDocument();
try
XMLPrintDriver output=new XMLPrintDriver(new FileOutputStream(new File(fileName)));
output.setEncoding("utf-8");
output.printDocument(doc);
output.close();
catch (Exception e)
System.out.println(e.toString());
public void WriteLanFile(String out2, String fileName2)
XMLDocument doc = new XMLDocument();
try
XMLPrintDriver output=new XMLPrintDriver(new FileOutputStream(new File(fileName2)));
output.setEncoding("utf-8");
output.printDocument(doc);
output.close();
catch (Exception e)
System.out.println(e.toString());
}

The problems is that your XML document is not parsed.

Parsing String XML Document

I didn't find a method that parses a XML document when it's not a file. I have a String that I want to parse and the method DocumentBuilder.parse only accepts a String that is a uri to a file.
I write this code:
String strXML = "<?xml version='1.0' ?><root><node>anything</node></root>";
DocumentBuilderFactory docBuilderFactory = DocumentBuilderFactory.newInstance();
DocumentBuilder docBuilder = docBuilderFactory.newDocumentBuilder();
domDoc = docBuilder.parse(strXML);
Please gimme a light!!
[]'s
Saulo

I have a similar problem, I'm trying to do the same BUT in a servlet, it compiles and it actually works if I use it outside my servlet, but, when I mount the servlet with the code similar to this one here it doesn't read the string (at least that's what appears to be, because it doesn't writes to my DB as it should and it doesn't display anything as I'm specifying as my servlet response). Any help? I'm posting my code here:
import javax.servlet.*;
import javax.servlet.http.*;
import java.io.BufferedReader;
import java.io.FileWriter;
import java.io.PrintWriter;
import java.io.File;
import java.io.IOException;
import java.io.InputStreamReader;
import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.parsers.FactoryConfigurationError;
import javax.xml.parsers.ParserConfigurationException;
import org.xml.sax.SAXException;
import org.xml.sax.SAXParseException;
import org.w3c.dom.*;
import org.apache.xml.serialize.*;
import java.net.URLDecoder;
import java.sql.*;
import org.xml.sax.InputSource;
import java.io.StringReader;
public class SMSConnector extends HttpServlet
//Public variables we will need
public String Stringid;
public String Stringpath;
public String st;
public int nid;
//Servlet service method, which permits listening of events
public void service(HttpServletRequest req, HttpServletResponse res)
throws ServletException, IOException
//Initialization for the servlet
ServletOutputStream salida = res.getOutputStream();
ServletInputStream entrada = req.getInputStream();
//Reading of the entering string
BufferedReader lector = new BufferedReader(new InputStreamReader (entrada));
res.setContentType("text/HTML");
try {
//Database handler
Class.forName("org.gjt.mm.mysql.Driver");
//DocumentBuilderFactory factory =
//DocumentBuilderFactory.newInstance();
//DocumentBuilder builder = factory.newDocumentBuilder();
InputSource inStream = new InputSource();
inStream.setCharacterStream(new StringReader(lector.readLine()));
DocumentBuilderFactory docBuilderFactory = DocumentBuilderFactory.newInstance();
DocumentBuilder docBuilder = docBuilderFactory.newDocumentBuilder();
Document doc1 = docBuilder.parse(inStream);
NodeList listasms = doc1.getElementsByTagName("sms");
for(int s=0; s<listasms.getLength() ; s++)
Connection Conn = DriverManager.getConnection ("jdbc:mysql://localhost:3306/smsdb","root", "");
Node nodosms = listasms.item(s);
if(nodosms.getNodeType() == Node.ELEMENT_NODE){
Element elementosms = (Element)nodosms;
NodeList listatelf = elementosms.getElementsByTagName("tlf");
Element elementotelf = (Element)listatelf.item(0);
NodeList textTelfList = elementotelf.getChildNodes();
String telefono = ((Node)textTelfList.item(0)).getNodeValue();
//String SendingAddress = ((Node)textAddressList.item(0)).getNodeValue().trim();
salida.println(telefono);
NodeList listaop = elementosms.getElementsByTagName("op");
Element elementoop = (Element)listaop.item(0);
NodeList textOpList = elementoop.getChildNodes();
String operadora = ((Node)textOpList.item(0)).getNodeValue();
NodeList listasc = elementosms.getElementsByTagName("sc");
Element elementosc = (Element)listasc.item(0);
NodeList textSCList = elementosc.getChildNodes();
String shortcode = ((Node)textSCList.item(0)).getNodeValue();
NodeList listabody = elementosms.getElementsByTagName("body");
Element elementobody = (Element)listabody.item(0);
NodeList textBodyList = elementobody.getChildNodes();
String body = ((Node)textBodyList.item(0)).getNodeValue();
Statement sta = Conn.createStatement();
sta.executeUpdate("INSERT INTO smstable (telf,op,sc,body) VALUES ('" + telefono + "','" + operadora + "','" + shortcode + "','" + body + "')");
Conn.commit();
Conn.close(); }
//Catching errors for the SAX and XML parsing
catch (SAXParseException err)
System.out.println ("** Parsing error" + ", line " + err.getLineNumber () + ", uri " + err.getSystemId ());
System.out.println(" " + err.getMessage ());
catch (SAXException e)
Exception x = e.getException ();
((x == null) ? e : x).printStackTrace ();
catch (Throwable t)
t.printStackTrace ();
}

XML document convert into String and Insert into Database

Hello all,
In the FIle to File Scenario I want to send the data to the Reciever System in xml Document and convert into String and insert into Database.
Please can you tell me exact way how to send it.
Thanks & Regards,
Raj

HI,
As per my understanding your scenario is File to file where you will get output fiel in XML format.
Now that XMl payload need to be passed as single string in the database via XI.
You cauld do this but you need to imply some manipulations such as
With the help of standard API you need to concatenate the XML tags and create the structre along with the data.
For e.g. in your outpuf file the XML structre contain data as
<field1>ABCD</field1>
Then in mapping
The source field will be mappeda s concat(<field1>) + value of Source field "ABCD" + concat(</field1>) to the target field.
This is the way that you could achive the requirments else there is no direct way avaialble for it.
thanks
Swarup

XML document - request string

Hi Experts,
Could you please tell me, how to pass XML document as a request string to the webservice scenario. Inside the service, I have to do the schema validation for the request . Please guide me, how to proceed further?
Regards
Sara

Hi SARA,
use following Code written in SAX parsing .this will fulfil your requirment.This handle Special character also.
import java.io.File;
import java.io.FileInputStream;
import java.io.FileOutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.OutputStream;
import java.io.OutputStreamWriter;
import java.io.Writer;
import java.util.ArrayList;
import java.util.Calendar;
import java.util.GregorianCalendar;
import java.util.HashMap;
import java.util.List;
import java.util.Map;
import javax.xml.parsers.FactoryConfigurationError;
import javax.xml.parsers.ParserConfigurationException;
import javax.xml.parsers.SAXParser;
import javax.xml.parsers.SAXParserFactory;
import org.xml.sax.Attributes;
import org.xml.sax.helpers.DefaultHandler;
import org.xml.sax.SAXException;
import com.sap.aii.mapping.api.StreamTransformation;
import com.sap.aii.mapping.api.StreamTransformationException;
public class SimpleForwardMappingString extends DefaultHandler implements StreamTransformation
     private List m_arlCurrent = new ArrayList();
     private List m_arlBOList = new ArrayList();
     private List m_arlObjectList = new ArrayList();
    public static int counter = 0;
     String listName = "newList";
     public StringBuffer m_totalElementsBuffer = new StringBuffer();
     String startData = "<inCanonStream>";
     String endData = "</inCanonStream>";
     private Map param = null;
     /** Constant Strings used in Forward Mapping */
     public static void main(String args[])
          try {
                  InputStream in = new FileInputStream(new File("C:
Documents and Settings
281152
Desktop
Cannonical12321.xml"));
               OutputStream out = new FileOutputStream(new File("C:
Documents and Settings
281152
Desktop
Cannonical21.xmlOut.xml"));
               SimpleForwardMappingString myMapping = new SimpleForwardMappingString();
          catch (Exception e)
               e.printStackTrace();
     public void execute(InputStream arg0, OutputStream arg1)
     throws StreamTransformationException
          Writer out;
          try
               out = new OutputStreamWriter(arg1, "UTF16");
               /** Building the SAX parser */
               getXMLDoc(arg0, arg1);
               arg1.write(m_totalElementsBuffer.toString().getBytes("UTF16"));
          catch (IOException e)
               System.out.println("Error : io" + e.getMessage());
          catch (Exception e)
               System.out.println("Error :" + e.getMessage());
     /* (non-Javadoc)
@see com.sap.aii.mapping.api.StreamTransformation#setParameter(java.util.Map)
     public void setParameter(Map arg0)
     public void getXMLDoc(InputStream inputStream, OutputStream outputStream)
Defines a factory API that enables applications to configure and
obtain a SAX based parser to parse XML documents. Once an application
has obtained a reference to a SAXParserFactory it can use the
factory to configure and obtain parser instances.
          SAXParserFactory factory = SAXParserFactory.newInstance();
          try
               factory.setNamespaceAware(true);
               factory.setValidating(true);
               SAXParser saxParser = factory.newSAXParser();
Parse the content of the given {@link java.io.InputStream}
instance as XML using the specified
{@link org.xml.sax.helpers.DefaultHandler}.
@param inputstream InputStream containing the content to be parsed.
@param cobject The SAX DefaultHandler to use.
@exception IOException If any IO errors occur.
@exception IllegalArgumentException If the given InputStream is null.
@exception SAXException If the underlying parser throws a
SAXException while parsing.
               saxParser.parse(inputStream, this);
          catch (FactoryConfigurationError e)
               System.out.println("Error");
          catch (ParserConfigurationException e)
               e.printStackTrace();
          catch (SAXException e)
               e.printStackTrace();
          catch (IOException e)
               e.printStackTrace();
     /** ===========================================================
                         Methods Overriding in SAX Default Handler
          ===========================================================
Receive notification of the beginning of the document.
By overriding this method in a subclass to take specific actions
at the beginning of a document (such as allocating the root node
of a tree or creating an output file)
     public void startDocument()throws SAXException
          if(m_totalElementsBuffer.length()>0)
                            m_totalElementsBuffer = new StringBuffer();
                            counter = 0;
          m_totalElementsBuffer.append(m_prologue);
          m_totalElementsBuffer.append(m_nameSpace);
          m_totalElementsBuffer.append(startData);     }
Receive notification of the end of the document.
By overriding this method in a subclass to take specific
actions at the end of a document (such as finalising a tree
or closing an output file)
     public void endDocument()throws SAXException
          m_totalElementsBuffer.append(endData);
          m_totalElementsBuffer.append(m_rootElementEnd);
Receive notification of the start of an element.
By overriding this method in a subclass to take specific
actions at the start of each element (such as allocating
a new tree node or writing output to a file)
     public void startElement(String namespaceURI, String name, String qName, Attributes attrs)
          throws SAXException
          /** If current List is not empty then append node to StringBuffer */
               m_totalElementsBuffer.append("<" + name + ">");
Receive notification of the end of an element.
By overriding this method in a subclass to take specific
actions at the end of each element (such as finalising
a tree node or writing output to a file)
     public void endElement(String uri, String name, String qName) throws SAXException
               m_totalElementsBuffer.append("</" + name + ">");
Receive notification of character data inside an element.
By overriding this method to take specific actions for each
chunk of character data (such as adding the data to a node
or buffer, or printing it to a file)
     public void characters(char buf[], int offset, int len)
          throws SAXException
          String s = new String(buf, offset, len);
          if (null != s && s.length() >0)
               if(s.equalsIgnoreCase("&"))
                     //System.out.println("FOUND AND SYMBOL");
                     String s1 = s.replaceAll("&","_-#_");
                     //System.out.println("s= " +s1);
                     s = s1;
               if(s.equalsIgnoreCase("<"))
                     //System.out.println("FOUND AND SYMBOL");
                     String s1 = s.replaceAll("<","_#-_");
                     //System.out.println("s= " +s1);
                     s = s1;
               m_totalElementsBuffer.append(s);
Thanks
Sunil Singh

Error while loading an XML document using a structured application

Hi,
I try to load an XML document using a structured application defined in the default structapps.fm
My code is shown down, extracted from the FDK API code sample.
Problem, I always have the same message :
"Cannot find the file named e:\xml\AdobeFrameMaker10\file. Make sure that the file exists. "
Where "e:\xml\AdobeFrameMaker10\" is my install directory.
So I assume that frame try to find the structapps.fm file but does not find it.
What else can it be ?
Does anyone knowns how to achieve this simple task using extendScript ?
Thanks for any comments, Pierre
function openXMLFile(myLastFile) {
    var filename = myLastFile.openDlg("Choose XML file ...", "*.xml", false);
    if (filename != null) {
        /* Get default open properties. Return if it can’t be allocated. */
        var params = GetOpenDefaultParams();
        /* Set properties to open an XML document*/
        /*Specify XML as file type to open*/
        var i = GetPropIndex(params, Constants.FS_OpenAsType)
        params[i].propVal.ival = Constants.FV_TYPE_XML;
        /* Specify the XML application to be used when opening the document.*/
        i = GetPropIndex(params, Constants.FS_StructuredOpenApplication)
        params[i].propVal.sval = "myApp";
        i = GetPropIndex(params, Constants.FS_FileIsOldVersion)
        params[i].propVal.ival = Constants.FV_DoOK
        i = GetPropIndex(params, Constants.FS_FontNotFoundInDoc)
        params[i].propVal.ival = Constants.FV_DoOK
        i = GetPropIndex(params, Constants.FS_FileIsInUse)
        params[i].propVal.ival = Constants.FV_DoCancel
        i = GetPropIndex(params, Constants.FS_AlertUserAboutFailure)
        params[i].propVal.ival = Constants.FV_DoCancel
        /*The structapps.fm file containing the specified application must have
        already been read. The default structapps.fm file is read when FrameMaker is
        opened so this shouldn't be a problem if the application to be used is
        listed in the structapps.fm file.*/
        var retParm = new PropVals()
        var fileObj = Open(filename, params, retParm);
        return fileObj
    } else {
        return null;

Pierre,
Depending on the object "myLastFile", the method openDlg might not even exist (if the myLastFile object is not a File object, for instance). And I do not see any need for the myLastFile anyhow, as you are presenting a dialog to select a file to open. I recommend using the global ChooseFile( ) method instead. This will give you a filename as string in full path notation, or null when no file was selected in the dialog. I am not sure what your ExtendScript documentation states about the return value for ChooseFile, but if that differs from what I am telling you here, the documentation is wrong. So, if you replace the first lines of your code with the following it should work:
function openXMLFile ( ) {
    var filename = ChooseFile ( "Choose XML file ...", "", "*.xml", Constants.FV_ChooseSelect );
While writing this, I see that Russ has already given you the same advice. Use the symbolic constant value I indicated to use the ChooseFile dialog to select a single file (it can also be used to select a directory or open a file - but you want to control the opening process yourself). Note that this method allows you to set a start directory for the dialog (second parameter). The ESTK autocompletion also gives you a fifth parameter "helplink" which is undocumented and can safely be ignored.
Good luck
Jang

String to XML Document

Similar Messages

Maybe you are looking for