Subject: extract the string before space

I have a string say "aquarium a". i want to extract the string appearing before the space and discard the string appearing after space.
that is the resultant string required is "aquarium". any number of characters can appear after space.
is it possible to solve using replace() method. i cant hardcode space+character in replace method because number of characters after space is not known.
Is there any easy way to get the required result

> i want to check if a string has space in between then
only this code should run otherwise this code should
not run. because if a string doesn't have any space
inbetween then the above code will give error.
String s = "aquarium a";
s = s.split("\\s")[0];
assert s.equals("aquarium");At this point, it would be a good idea to familiarize yourself with the String API. That way, you'll have a better idea how to accomplish your specific requirements.
~

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Oracle Text Index - Trailing Search when the String has spaces

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JOHN
FRED JOHNSON
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indextype is ctxsys.context
parameters('DATASTORE ctxsys.default_datastore');

You could use some method, like a multi_column_datastore or user_datastore to append some specific starting characters, then include those in your search, as shown below.
SCOTT@orcl12c> CREATE TABLE person
2    (name VARCHAR2(60))
3 /
Table created.
SCOTT@orcl12c> INSERT ALL
2 INTO person VALUES ('JOHN')
3 INTO person VALUES ('FRED JOHNSON')
4 INTO person VALUES ('JOHN ROBERTS')
5 SELECT * FROM DUAL
6 /
3 rows created.
SCOTT@orcl12c> BEGIN
2    CTX_DDL.CREATE_PREFERENCE ('test_ds', 'MULTI_COLUMN_DATASTORE');
3    CTX_DDL.SET_ATTRIBUTE ('test_ds', 'COLUMNS', '''start ''||name||'' end'' name');
4 END;
5 /
PL/SQL procedure successfully completed.
SCOTT@orcl12c> create index txt_idx1 on person (name)
2 indextype is ctxsys.context
3 parameters('DATASTORE test_ds')
4 /
Index created.
SCOTT@orcl12c> select * from person where CONTAINS(name,'start JOHN%',1) > 0
2 /
NAME
JOHN
JOHN ROBERTS
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SCOTT@orcl12c>

How to extract the string part by part

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take this code compile it and see for yourself.
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public static void main(String args[]){
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now an explanation of what is happening.
the method looks like this
private boolean veriChar(String toCheck){
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Replace string by space

I would like to replace all ',' appear in a strng by space. So, i use
replace all occurrences of ',' in tempStr with space.
But, the outcome is all pattern are replaced, and concatenate together. For example, i have string
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Hi,
Try this.
data : tempstr type string,
temp(2) type c.
tempStr = '1,2,3,4,5,6,7'
temp = ', '.
Translate tempstr using temp.
Write tempstr.
Regards,
Mohaiyuddin

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Is it possible to extract the subject line of an email as a string?
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I don't believe this is feasible with the standard output program, but you should be able to do this if you create a custom (Z) version and make that modification there. Not sure if it's worth it, but that's for your business users to decide.

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hi,
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i mean if the value is :
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There are several methods to achieve this:
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To extract the last word in a string

Hi
I am using BODS 14.1.1.210
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Hi,
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Atun

Started a similar string before. When I select a recipient in Messages on my Macbook Pro the name shows up in red and says the recipient is no longer registered on iMessage. I know that they are registered. Is there a problem with Contacts?

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Hi,
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On restart add back the Apple ID to the iMessages account settings.
I also just checked My wife's iPhone as she popped up red.
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Hello FOlks,
I have the sample data whichi is a string and it contains DateTime part inside it. I worked through half way but am not sure how to get the other part.
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I tried using
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If your sample data is representative for all the data, you could also try a regular expression:
SQL> -- generating sample data, pretending it's stored in a column called str in a table called t:
SQL> with t as (
2 select 'Note Added by AARON HILTON at 05/26/2010 14:53 MONEY NOTE ENTERED' str from dual union
3 select 'Note Added by DEBBIE BILL at 11/16/2009 23:12 MONEY ENTERED' from dual
4 )
5 --
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7 --
8 select trim(regexp_replace(str, '[[:alpha:]]')) str
9 ,      to_date(trim(regexp_replace(str, '[[:alpha:]]')), 'mm-dd-yyyy hh24:mi') dt
10 ,      to_timestamp(trim(regexp_replace(str, '[[:alpha:]]')), 'mm-dd-yyyy hh24:mi') ts
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STR                DT                        TS
05/26/2010 14:53   26-05-2010 14:53:00       26-05-10 14:53:00.000000000
11/16/2009 23:12   16-11-2009 23:12:00       16-11-09 23:12:00.000000000
2 rows selected.where column STR is, well, a string, DT will turn your string into date datatype and TS will turn it into a timestamp.
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In the NI Library VI: Extract Numbers, the string control is automatically loaded each time the VI is opened with "Counting to five: one 2 three 4.0 five. Where is this string data coming from?

Even after deleting the string "Counting to five: one 2 three 4. five." from the string control and replacing it with another string the original string returns after the VI is saved then reopened. Where is this string data coming from? I've attached a copy of the library function. I've been able in my application to get around the problem by replacing the string control with a string constant. But I'm still curious as to what's going on.
Thanks,
Chuck
Solved!
Go to Solution.
Attachments:
Extract Numbers Test.vi ‏9 KB

Chuck,
String control has been set to default with the string you are seeing. To change this, enter the new string, right click the control and select
Data Operations>>Make Current Value Default
Now save your vi.

Extract the numbers in string using regex

Hi,
How to extract the numers in string using regex?.
Already i tried split up the string using [\\s]
For ex: "Uting Tatk and Window Panet 15"
it gives the ans 15.
if the string is
For ex: "Uting Tatk and Window Panet 15 New!"
i can't find the number.
so plz give me some idea to get the number frm String.
Thanks

I am developing a java project to extract Table of
content in a particular
PDF.
i extracted all topics.
then i want 2 extract page number from dat extracted
TOC.
if the TOC ends with number then i can easily find
out the number
but in vain if the TOC ends with like this
"Uting Tatk and Window Panet 15 New!".
i could n't find the page number.What will you do if it says:
"15 ways to find topics 42 new"

Extracting the partial string from the string in oracle

Hello Friends,
I have a string like this
var str = '/G/CNH/CNHCornerstone/currentCode/data/Working/Images/ModelImages/png/7402203E-607D-E111-9CA5-005056875BD6.png'
I want to extract only 7402203E-607D-E111-9CA5-005056875BD6 from the string .
Please let me know how to implement this ..
thanks/kumar
Edited by: kumar73 on Apr 10, 2012 12:34 PM

hope this works
set serveroutput on
declare
str1 varchar(4000);
str2 varchar(4000);
begin
str1 := '/G/CNH/CNHCornerstone/currentCode/data/Working/Images/ModelImages/png/7402203E-607D-E111-9CA5-005056875BD6.png';
dbms_output.put_line('string 1 : ' || str1);
str2 := substr(str1,71);
dbms_output.put_line('string 2 : '||str2);
end;
output
string 1 : /G/CNH/CNHCornerstone/currentCode/data/Working/Images/ModelImages/png/7402203E-607D-E111-9CA5-005056875BD6.png
string 2 : 7402203E-607D-E111-9CA5-005056875BD6.png
PL/SQL procedure successfully completed

Breadcrumbs containing string with spaces - generating the anchor

so I have a website that contains a 'breadcrumbs' line that allows users to click on it, and take them back to the parent page
eg. "jewellery"
I simply suffix this string with ".cfm" to generate the anchor / filename
what's the best way to deal with strings containing spaces?
eg. "birthday cards"
As good practice I want to use a more compatiable filename that doesn't include spaces
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is the REPLACE command ok to use ? or is preferrable to add an additonal field to the table, called "filename" and store the exact filename in there ?

option 1
use quotes like href="http:\\....."
option 2
convert spaces to %2B

Subject: extract the string before space

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