Subtraction of a positive integer of a negative integer results a positive?

Hi
I have the next problem and I haven't found the reason...
I have the next Java code:
int a = -2147483648;
int b = 2147483647;
System.out.println(a - b);
The output of this lines is "1", but I don't understand why.
Thanks

>
My main issue was that I wasn't sure of the Java process for this operation, and I thought that maybe the result
-4294967295 = FFFFFFFF00000001
could throw an exception.
>
The answer to that concern is in the Java Language Spec.
http://docs.oracle.com/javase/specs/jls/se7/jls7.pdf
See sections 4.2.1 for the value ranges (you will see your MAX and MIN 'int' values there
>
4.2.1 Integral Types and Values
The values of the integral types are integers in the following ranges:
• For byte, from -128 to 127, inclusive
• For short, from -32768 to 32767, inclusive
• For int, from -2147483648 to 2147483647, inclusive
• For long, from -9223372036854775808 to 9223372036854775807, inclusive
• For char, from '\u0000' to '\uffff' inclusive, that is, from 0 to 65535
4.2.2 Integer Operations
The Java programming language provides a number of operators that act on integral
values:
• The comparison operators, which result in a value of type boolean:
◆ The numerical comparison operators <, <=, >, and >= (§15.20.1)
◆ The numerical equality operators == and != (§15.21.1)
• The numerical operators, which result in a value of type int or long:
◆ The unary plus and minus operators + and - (§15.15.3, §15.15.4)
◆ The multiplicative operators *, /, and % (§15.17)
◆ The additive operators + and - (§15.18)
◆ The increment operator ++, both prefix (§15.15.1) and postfix (§15.14.2)
◆ The decrement operator --, both prefix (§15.15.2) and postfix (§15.14.3)
◆ The signed and unsigned shift operators <<, >>, and >>> (§15.19)
◆ The bitwise complement operator ~ (§15.15.5)
◆ The integer bitwise operators &, ^, and | (§15.22.1)
• The conditional operator ? : (§15.25)
• The cast operator (§15.16), which can convert from an integral value to a value
of any specified numeric type
• The string concatenation operator + (§15.18.1), which, when given a String
operand and an integral operand, will convert the integral operand to a String
representing its value in decimal form, and then produce a newly created String
that is the concatenation of the two strings
>
These are the two statements that apply directly to your question and concern
>
Otherwise, the operation is carried out using 32-bit precision, and the result of the
numerical operator is of type int. If either operand is not an int, it is first widened
to type int by numeric promotion.
The integer operators do not indicate overflow or underflow in any way.
>
Yours are 'integer operators' operating on 'int' values.

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sabre150 wrote:
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>
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>
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>
Modifying your code (to a semi pseudo example)...
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>
>>>
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>
>>>
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>
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>
In the above how do you think that your solution is better, more complete, or substantially different than what I proposed? Do you think that a negative regex is more expressive than negating the result? Or perhaps more efficient?I never said that. I don't say that. As I keep saying - my solution does not require an explicit loop though behind the scenes there is a loop.
>
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 else if(s.equals("9"))
 secondint = 9;
 else if(s.equals("10"))
 secondint = 10;
 return secondint;
 public static int performMath(String m, int firstint, int secondint)
 int answer = 0;
 if (m.equals("+"))
 answer = add(m,firstint, secondint);
 if (m.equals("-"))
 answer = subtract(m,firstint, secondint);
 if (m.equals("*"))
 answer = multiply(m,firstint, secondint);
 if (m.equals ("/"))
 answer = divide(m,firstint, secondint);
 if (m.equals ("%"))
 answer = modulus(m, firstint, secondint);
 return answer;
 public static int add(String m, int firstint, int secondint)
 int answer;
 answer = (firstint + secondint);
 return answer;
 public static int subtract(String m, int firstint, int secondint)
 int answer;
 answer = (firstint - secondint);
 return answer;
 public static int multiply(String m, int firstint, int secondint)
 int answer;
 answer = (firstint * secondint);
 return answer;
 public static int divide(String m, int firstint, int secondint)
 int answer;
 answer = (firstint / secondint);
 return answer;
 public static int modulus (String m, int firstint, int secondint)
 int answer;
 answer = (firstint % secondint);
 return answer;
 public static void printMath(int answer)
 String message = "Your answer is:" + answer;
 JOptionPane.showMessageDialog(null, message, "Alert", JOptionPane.INFORMATION_MESSAGE);
 public static char verifyAnswer(Object[] options)
 char ans = 'N';
 int n = JOptionPane.showOptionDialog(null, "Would you like to enter another problem, Yes or No?", "Another Problem?", JOptionPane.YES_NO_OPTION, JOptionPane.QUESTION_MESSAGE, null, options, options[1]);
 switch(n)
 case 0:
 ans = 'Y'; break;
 case 1:
 ans = 'N'; break;
 return ans;


mstew1979 wrote:
Thank you! I actually just got it working :)Cool. Here's a bit of advice, just in case you "fixed" it by making a common mistake: Don't just initialize a variable to a dummy value to make the compiler happy. Those "not initialized" errors usually point to a logic error. But just initializing the variable to 0, null, etc. at declaration, usually you're just masking the logic error so the compiler doesn't see it. You haven't fixed anything.
public String signum (int x) {
String result;
if (x > 0) {
 result = "positive";
else if (x < 0) {
 result = "negative";
return result;
}Here we have a compiler error, brought on by my logic error of forgetting to account for x being 0. The wrong way to fix it would be to blindly change the declaration of result to String result = ""; or == null;. The logic error is still there, but now it's hidden from the compiler. So we have an error at runtime instead--we don't get a valid response if we pass in 0. Runtime errors are much harder to debug than compile-time errors.
The correct response to the compiler's "not initialized" error is to look at our code more carefully and see what we might have missed. In this case, we would add and else clause that returns "zero".

Subtraction of a positive integer of a negative integer results a positive?

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