Sum time spent for breaks

Question

name id timein timeout breakin breakout currentdate
karthik 1 9.40AM 5.20AM 11.00AM 11.10AM 20-APR-2007
karthik 1 9.40AM 5.20AM 12.00PM 12.10PM 20-APR-2007
karthik 1 9.40AM 5.20AM 1.30PM 1.45PM 20-APR-2007
karthik 1 9.40AM 5.20AM 2.30PM 2.45PM 20-APR-2007
karthik 1 9.40AM 5.20AM 4.00PM 4.30PM 20-APR-2007
my need is i want to sumt the total hours spent for breaks from morning to evening.
so please any one please give me query for this please.

Answer 1

Like that ?
SQL> with tbl as
  2  (select 'karthik' c1, 1 c2, '9.40AM' c3, '5.20AM' c4, '11.00AM' c5, '11.10AM' c6, to_date('20-A
PR-2007','DD-MON-YYYY') c7 from dual union all
  3   select 'karthik' c1, 1 c2, '9.40AM' c3, '5.20AM' c4, '12.00PM' c5, '12.10PM' c6, to_date('20-A
PR-2007','DD-MON-YYYY') c7 from dual union all
  4   select 'karthik' c1, 1 c2, '9.40AM' c3, '5.20AM' c4, '1.30PM'  c5, '1.45PM'  c6, to_date('20-A
PR-2007','DD-MON-YYYY') c7 from dual union all
  5   select 'karthik' c1, 1 c2, '9.40AM' c3, '5.20AM' c4, '2.30PM'  c5, '2.45PM'  c6, to_date('20-A
PR-2007','DD-MON-YYYY') c7 from dual union all
  6   select 'karthik' c1, 1 c2, '9.40AM' c3, '5.20AM' c4, '4.00PM'  c5, '4.30PM'  c6, to_date('20-A
PR-2007','DD-MON-YYYY') c7 from dual )
  7  select c1, c2, to_char(trunc(sysdate)+sum(to_date(c6,'HH12.MIAM')-to_date(c5,'HH12.MIAM')),'HH24:MI') sum_break_h_mi
  8  from tbl
  9  group by c1,c2;
C1              C2 SUM_B
karthik          1 01:20
SQL> Nicolas.