T-SQL how to set last row as first

Question

Hi,
I have the following query:
SELECT leveltmp, 'Level ' + CAST( leveltmp as varchar(5)) + ' (' +
STUFF((SELECT top(3) ', '+ BES.Name
FROM BESTB BES
WHERE BES.leveltmp = BE.leveltmp
AND BESId=2
FOR XML PATH('')), 1, 1, '') + ',...)' as 'level'
FROM BESTB as BE
WHERE BEId = 2
GROUP BY leveltmp
ORDER BY 1
and I get the following results:
1    Level 1 ( TestFirstLvl1, TestFirstLvl2, TestFirstLvl3,...)
2    Level 2 ( TestSecondLvl1, TestSecondLvl2, TestSecondLvl3,...)
3    Level 3 ( TestThirdLvl1, TestThirdLvl2, TestThirdLvl3,...)
4    Level 4 ( TestFourthLvl1, TestFourthLvl2, TestFourthLvl3,...)
5    Level 5 ( TestFifthLvl1,...)
However, I need the last one always to be the first one, but the others to remain as they are. I need my order to be 5,1,2,3,4 instead of 1,2,3,4,5.
So basically I need to get the following results:
1    Level 1 ( TestFifthLvl1,...)
2    Level 2 ( TestFirstLvl1, TestFirstLvl2, TestFirstLvl3,...)
3    Level 3 ( TestSecondLvl1, TestSecondLvl2, TestSecondLvl3,...)
4    Level 4 ( TestThirdLvl1, TestThirdLvl2, TestThirdLvl3,...)
5    Level 5 ( TestFourthLvl1, TestFourthLvl2, TestFourthLvl3,...)
Any idea on how to achieve this?
Thanks

Answer 1

create table #t (c char(1))
insert into #t values ('a'),('b'),('c'),('d')
select * from #t order by c ---now we need d to be first charachter 
declare @c char(1)=(select top 1 c from #t order by c desc)
select * from #t order by case when c =@c then '1' else c end
Best Regards,Uri Dimant SQL Server MVP,
http://sqlblog.com/blogs/uri_dimant/
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