Tables (part or no part) and their tablespaces in oracle 11g

Question

I need to list all the tables and their table spaces for non part tables along with partition tables, partition name and its table space , I am using the following query to find it however query result is not something what i am looking for as i see null in table space columns.
tablespace column has null for even non partition table.
in query result there are cases that null in all the tablespace_name columns.. ..
tablespace columns have nulls for even part tables in ALL_TAB_PARTITIONS ,ALL_PART_TABLES tables for few part tables ..
Should we generat object stats to correct name filled in tablespace column.. or am i using wrong tables in my query..? how come null in all the tablespace columns or should i include any other dictionary table?
select AT.OWNER, AT.TABLE_NAME, AT.TABLESPACE_NAME,AT.PARTITIONED,APT.PARTITIONING_TYPE,ATP.PARTITION_NAME, ATP.TABLESPACE_NAME,APT.DEF_TABLESPACE_NAME
From ALL_tABLES AT,
ALL_TAB_PARTITIONS ATP ,
ALL_PART_TABLES APT
WHERE AT.OWNER IN ('CISADM')
AND ATP.TABLE_OWNER(+)=AT.OWNER
AND APT.OWNER(+)=AT.OWNER
AND ATP.TABLE_NAME(+)=AT.TABLE_NAME
AND APT.TABLE_NAME(+)=AT.TABLE_NAME
ORDER BY ATP.TABLE_NAME,ATP.PARTITION_POSITION;
could you please suggest what wrong with this query or query to find table space used for both non part and each table partition table space. Thanks in advance..

Answer 1

For a partitioned table you should get tablespace_name from user_tab_partitions because it's possible to have different partitions stored in different tablespaces. This can't be shown in the single row of user_tables.
SQL> CREATE TABLE part_test
  2  (part_key    NUMBER
  3  )
  4  PARTITION BY RANGE(part_key)
  5  (PARTITION  part_test1 VALUES LESS THAN (100) tablespace users
  6  ,PARTITION  part_test2 VALUES LESS THAN (200) tablespace example
  7  );
Table created.
SQL> select table_name, tablespace_name from user_tables where table_name = 'PART_TEST';
TABLE_NAME                     TABLESPACE_NAME
PART_TEST
SQL> select table_name, partition_name, tablespace_name from user_tab_partitions where table_name = 'PART_TEST';
TABLE_NAME                     PARTITION_NAME                 TABLESPACE_NAME
PART_TEST                      PART_TEST1                     USERS
PART_TEST                      PART_TEST2                     EXAMPLEEdited by: SomeoneElse on Dec 9, 2012 10:07 AM
(OK, I see you tried that)