Text files and audio capture
Hello everyone!
I have a problem on a fairly complex VI and I'm not an expert.
In the main loop I have a capture of strings via serial port, I analyze some numeric values from these strings and when these values exceed the predefined I generate "alarms" with LED.
The point is that, once turned on the alarm, I have to save two files: the text string from the serial and the registration of 2-3 seconds of audio. These files must have the name taken from the "get date / time".
How can I do?
I tried to do three different loops at the same time:
1. Main
2. Text saving
3. Audio recording.
But unfortunately I can not exchange information on the file name and string read between the various loops, even though the "local variable".
Can anyone help me?
Thanks!!!
Ermanno wrote:
I wrote in 2 languages to get more answers.
That doesn't usually help. It just irritates people when you post the same question in multiple places. Plus, it leads people to ask you the same exact questions or give you the same exact suggestions when they don't know you've already asked the question somewhere else and are already being helped.
As for your code... you have a classic race condition. Actually more than one. You are reading the "appended path" via the local variable before it's actually been written to. The value is set inside the loop, but your program will read the value before either loop has even started.Your second race condition has to do with the Stringa local variable. Again, you are reading its value without actually knowing if it's been updated by the other loop.
Why do you have 2 loops? Why isn't the writing of the file in the same loop as the read operation?
Other comments:
Why are you creating the filename inside the loop? That makes no sense. Why would you want to create a new file each and every time you loop around?
There is a simpler way to create the filename: If you look at the help for the Format Into String function you will see that you can use format codes to convert the timestamp to a string:
Attachments:
Example_VI_BD.png 18 KB
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#19
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sample.txt 1 KBjcarmody wrote:
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String packetSeqno0, String packetSize0) {
this(Integer.parseInt(timeStamp0), Integer.parseInt(userId0),
Integer.parseInt(packetId0), Integer.parseInt(packetSeqno0),
Integer.parseInt(packetSize0));
public Packet(String[] a){
this(a[0], a[1], a[2], a[3], a[4]);
public void setTime(int aTimeStamp){
timeStamp = aTimeStamp;
public void setUserId(int aUserId){
userId = aUserId;
public void setPacketId(int aPacketId){
packetId = aPacketId;
public void setPacketSeqno(int aPacketSeqno){
packetSeqno = aPacketSeqno;
public void setPacketSize(int aPacketSize){
packetSize = aPacketSize;
public int getUserId(){
return userId;
public String toString(){
return String.format
("%2d %2d %2d %2d %4d", timeStamp, userId, packetId, packetSeqno, packetSize);
public int compareTo(Packet otherPacket){
return userId - otherPacket.getUserId();
/* main for test */
public static void main(String[] args){
String line;
ArrayList<Packet> alp;
alp = new ArrayList<Packet>();
try{
BufferedReader br = new BufferedReader(new FileReader("cnleafdata.txt"));
while ((line = br.readLine()) != null){
// if (! recordValid(line)){
// continue;
String[] ar = line.split("\\s");
alp.add(new Packet(ar));
catch (Exception e){
e.printStackTrace();
System.out.println("[original]");
for (Packet p : alp){
System.out.println(p);
System.out.println();
Collections.sort(alp);
System.out.println("[sorted by user ID]");
for (Packet p : alp){
System.out.println(p);
}
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