The coordinate of drawString()

Guys,
If I use Graphics2D to draw a String, how can I get the coordinate of the last character?
For example, If I:
Graphics2D comp2d= new Graphics2D (comp);
comp2d.drawString("Hello the world", 100, 100 );
How can I get the coordinate for the letter "d" as in "world"?
Thanks in advance!

try using the FontMetrics class
it has methods like stringWidth() and charWidth()
these would be helpful

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PhotoShop Automation PlugIn: How do I get the coordinates of a polygonal selection?

Hi.
I try to get the coordinates out of a selection, but I can't find out how to do that.
I tried to convert the selection into a path and get the coordinates from the path. That doesn't work either.
Can somebody give me a list of parameters inside the action descriptor of keyPathContent in classPath? I assume that the point infos are located there...
Thanx in advance,
Christian

found the answer myself. It might be helpfull to others.
btn.addMouseListener(new MouseAdapter(){
public void mouseClicked(MouseEvent e) {
Rectangle ret = btn.getBounds();
double y = ret.y + ret.getHeight();
pop.show((Component) e.getSource(), ret.x, (int)y);
}

[VBA] how to catch the coordinates of a value on a pivot

Hi to all
I have a pivot T (i.e. see below)
Suppose I click inside the cell with "16"... I need to have (in VB script) to have the coordinates of the pivot cell (as well as
GETPIVOTDATA give in formulas).
Do you know a way to obtain (in that example) the "CCC", "z","feb" values when I click on number 16?
I would like to have the text that is written inside the tool tip
thank you
Daniele.b75

I'm sure that there is a better way, but this should work:
Sub PivotTableReading()
Dim PT As PivotTable
Dim PF As PivotField
Dim PI As PivotItem
Dim rngC As Range
Dim strVal As String
Dim strValName As String
Set rngC = Selection.Cells(1)
On Error GoTo ErrHandler
For Each PT In ActiveSheet.PivotTables
If Intersect(rngC, PT.DataBodyRange) Is Nothing Then GoTo NextPT
For Each PF In PT.PivotFields
For Each PI In PF.PivotItems
If Not Intersect(rngC, PI.DataRange) Is Nothing Then
strVal = strVal & IIf(strVal = "", "", Chr(10)) & PF.Name & ": " & PI.Name
End If
Next PI
RHere:
Next PF
NextPT:
Next PT
If strValName <> "" Then strVal = strVal & Chr(10) & strValName & ": " & rngC.Value
MsgBox strVal
Exit Sub
ErrHandler:
strValName = PF.Name
Resume RHere
End Sub

A script that captures the coordinates of the mouse clicks and saves them into a file

Hello,
I'm trying to create a cartoon taking a movie (I've chosen blade runner) as base. I've got the real movie and I've exported all the pictures using VirtualDUB. Now I have a lot of images to modify. I would like to modify the actors faces with the faces generated by Facegen modeller. I'm thinking how to make the whole process automatic because I have a lot of images to manage. I've chosen to use Automate BPA,because it seems the best for this matter. I'm a newbie,so this is my first attempt using Adobe Photoshop and Automate BPA. I wrote a little script. It takes a face generated with Facegen modeller and tries to put it above the original actors faces. But it doesn't work very good and I'm not really satisfied,because the process is not fully automated. To save some time I need to write a script that captures the coordinates of the mouse when I click over the faces and that saves them into a file,so that Automate BPA can read these coordinates from that file and can put the face generated with Facegen Modeller above the original face. I think that Automate BPA is not good for this matter. I think that two coordinates are enough,X and Y. They can be the coordinates of the nose,because it is always in the middle of every face. It is relevant to knows how big should be the layer of the new face,too. This is the Automate BPA code that I wrote :
<AMVARIABLE NAME="nome_foto" TYPE="TEXT"></AMVARIABLE>
<AMVARIABLE NAME="estensione_foto" TYPE="TEXT"></AMVARIABLE>
<AMSET VARIABLENAME="nome_foto">br</AMSET>
<AMSET VARIABLENAME="estensione_foto">.jpeg</AMSET>
<AMVARIABLE NAME="numero_foto" TYPE="NUMBER"></AMVARIABLE>
<AMVARIABLE NAME="coord_x" TYPE="NUMBER"></AMVARIABLE>
<AMVARIABLE NAME="coord_y" TYPE="NUMBER"></AMVARIABLE>
<AMWINDOWMINIMIZE WINDOWTITLE="Aggiungere_layer - AutoMate BPA Agent
Task Builder" />
<AMWINDOWMINIMIZE WINDOWTITLE="AutoMate BPA Server Management Console
- localhost (Administrator)" AM_ONERROR="CONTINUE" />
<AMENDPROCESS PROCESS="E:\Programmi_\Adobe Photoshop
CS5\Photoshop.exe" AM_ONERROR="CONTINUE" />
<AMRUN FILE="%"E:\Programmi_\Adobe Photoshop CS5\Photoshop.exe"%" />
<AMPAUSE ACTION="waitfor" SCALAR="15" />
<AMSENDKEY>{CTRL}o</AMSENDKEY>
<AMPAUSE ACTION="waitfor" SCALAR="1" />
<AMINPUTBOX RESULTVARIABLE="numero_foto">Inserire numero FOTO di
partenza -1</AMINPUTBOX>
<AMINCREMENTVARIABLE RESULTVARIABLE="numero_foto" />
<AMPAUSE ACTION="waitfor" SCALAR="1" />
<AMMOUSEMOVEOBJECT WINDOWTITLE="Apri" OBJECTNAME="%nome_foto &
numero_foto & estensione_foto%" OBJECTCLASS="SysListView32"
OBJECTTYPE="ListItem" CHECKOBJECTNAME="YES" CHECKOBJECTCLASS="YES"
CHECKOBJECTTYPE="YES" />
<AMMOUSECLICK CLICK="double" />
<AMPAUSE ACTION="waitfor" SCALAR="10" />
<AMSENDKEY>{CTRL}+</AMSENDKEY>
<AMPAUSE ACTION="waitfor" SCALAR="20" />
<AMSENDKEY>l</AMSENDKEY>
<AMPAUSE ACTION="waitfor" SCALAR="2" />
<AMMOUSEMOVE MOVEX="429" MOVEY="281" RELATIVETO="screen" />
<AMMOUSECLICK />
<AMPAUSE ACTION="waitfor" SCALAR="2" />
<AMMOUSEMOVE MOVEX="659" MOVEY="281" RELATIVETO="screen" />
<AMPAUSE ACTION="waitfor" SCALAR="2" />
<AMMOUSECLICK />
<AMPAUSE ACTION="waitfor" SCALAR="2" />
<AMMOUSEMOVE MOVEX="659" MOVEY="546" RELATIVETO="screen" />
<AMPAUSE ACTION="waitfor" SCALAR="2" />
<AMMOUSECLICK />
<AMPAUSE ACTION="waitfor" SCALAR="2" />
<AMMOUSEMOVE MOVEX="429" MOVEY="546" RELATIVETO="screen" />
<AMPAUSE ACTION="waitfor" SCALAR="2" />
<AMMOUSECLICK />
<AMPAUSE ACTION="waitfor" SCALAR="2" />
<AMMOUSEMOVE MOVEX="429" MOVEY="281" RELATIVETO="screen" />
<AMPAUSE ACTION="waitfor" SCALAR="2" />
<AMMOUSECLICK />
<AMPAUSE ACTION="waitfor" SCALAR="2" />
<AMSENDKEY>v</AMSENDKEY>
<AMPAUSE ACTION="waitfor" SCALAR="2" />
<AMMOUSECLICK CLICK="hold_down" />
<AMPAUSE ACTION="waitfor" SCALAR="2" />
<AMMOUSEMOVE MOVEX="131" MOVEY="99" RELATIVETO="screen" />
<AMPAUSE ACTION="waitfor" SCALAR="2" />
<AMMOUSEMOVE MOVEX="99" MOVEY="162" RELATIVETO="screen" />
<AMPAUSE ACTION="waitfor" SCALAR="2" />
<AMMOUSECLICK CLICK="release" />
<AMPAUSE ACTION="waitfor" SCALAR="2" />
<AMINPUTBOX RESULTVARIABLE="coord_x">Inserire coordinata X</AMINPUTBOX>
<AMINPUTBOX RESULTVARIABLE="coord_y">Inserire coordinata Y</AMINPUTBOX>
<AMMOUSEMOVE MOVEX="200" MOVEY="200" RELATIVETO="screen" />
<AMMOUSECLICK CLICK="hold_down" />
<AMMOUSEMOVE MOVEX="%coord_x%" MOVEY="%coord_y%" RELATIVETO="position" />
<AMMOUSECLICK />
and this is a short video to explain better what I want to do :
http://www.flickr.com/photos/26687972@N03/5331705934/
In the last scene of the video you will see the script asking to input the X and the Y coordinates of the nose. This request is time consuming. For this reason I want to write a script that captures automatically the coordinates of the mouse clicks. The only thing to do should be click over the nose and the script should make the rest. As "c.pfaffenbichler" suggested here : http://forums.adobe.com/thread/775219, I could explore 3 ways :
1) use the Color Sampler Tool’s input with a conventional Photoshop Script.
2) use After Effects would provide a better solution.
3) Photoshop’s Animation Panel might also offer some easier way as it might be possible to load two movies (or one movie and one image) and animate the one with the rendered head in relation to the other.
Since I'm a totally newbie in graphic and animation,could you help me to explore these ways ? Thanks for your cooperation.

These are the coordinates of the contours of the face that you see on the picture. Can you explain to me how they are calculated ? The coordinates of the first colums are intuitive,but I'm not able to understand how are calculated the coordinates of the second one.
Thanks.
1 COL 2 COL (how are calculated these values ?)
307.5000 182.0000 m
312.5000 192.0000 l
321.5000 194.0000 l
330.5000 193.0000 l
335.0000 187.0000 l
337.0000 180.5000 l
340.0000 174.0000 l
338.5000 165.5000 l
336.0000 159.0000 l
331.5000 153.0000 l
324.5000 150.0000 l
317.0000 154.0000 l
312.5000 161.0000 l
309.0000 173.0000 l
307.5000 182.0000 l
Message was edited by: LaoMar

Get the Coordinates of a Character in a TextArea

Is there a way to determine what the coordinates of a given
character are in a TextArea control? One project I'm working on
presents a chunk of text cut off at some number of characters,
followed by a LinkButton control (e.g., to view "more"), and I'm
having trouble figuring where to place the LinkButton control
without knowing the coordinates of the last visible character of
the TextArea. Anyone dealt with this one before?
Thanks in advance...
Chris

Hm, thanks, but that just places the LinkButton next to the
TextArea control, beside and outside of it, not "inside" (or really
over) it, as my example should've implied.
I think I've found a workable solution -- see below, where
myCanvas is some Canvas control already defined in MXML somewhere,
and myText is a Text control already defined (and populated) as
well:
var numberOfLines:int =
myText.mx_internal::getTextField().numLines;
var lineMetrics:TextLineMetrics =
myText.getLineMetrics(numberOfLines - 1);
var targetX:int = lineMetrics.width + 10;
var targetY:int = (numLines - 1) * lineMetrics.height;
var myLinkButton:LinkButton = new LinkButton();
myLinkButton.label = "More...";
myCanvas.addChild(myLinkButton);
Still testing, but TextLineMetrics seems to have done the
trick.
If anyone has a better approach, let me know! Thanks much.

How to get the coordinate of a cell in the jtable?

How to get the coordinate of a cell in the jtable?
How to get the point of a cell in the jtable?
Thanks for help!

getCellRect(...);

How to find out the coordinates of rotated textframe

Hi All,
With the help of (idml) itemtransform horizontal / vertical distances and path point arrays, I can find out the coordinates of text frame (x1,y1), (x2,y2), (x3,y3), (x4,y4). If the textframe is rotated then item transform values are getting changed, but the path point array values are same. I can find rotation angle by the matrix [cos(θ) sin(θ) -sin(θ) cos(θ) 0 0], But I could not get the exact coordinates of rotated textframe. The textframes are given below.
Normal Text frame
<TextFrame Self="u136" ParentStory="u124" ItemTransform="1 0 0 1 101.72727272727272 -349.41818181818184">
            <Properties>
                <PathGeometry>
                    <GeometryPathType PathOpen="false">
                        <PathPointArray>
                            <PathPointType Anchor="-101.72727272727272 -46.581818181818164" LeftDirection="-101.72727272727272 -46.581818181818164" RightDirection="-101.72727272727272 -46.581818181818164"/>
                            <PathPointType Anchor="-101.72727272727272 -0.3272727272727103" LeftDirection="-101.72727272727272 -0.3272727272727103" RightDirection="-101.72727272727272 -0.3272727272727103"/>
                            <PathPointType Anchor="115.9090909090909 -0.3272727272727103" LeftDirection="115.9090909090909 -0.3272727272727103" RightDirection="115.9090909090909 -0.3272727272727103"/>
                            <PathPointType Anchor="115.9090909090909 -46.581818181818164" LeftDirection="115.9090909090909 -46.581818181818164" RightDirection="115.9090909090909 -46.581818181818164"/>
                        </PathPointArray>
                    </GeometryPathType>
                </PathGeometry>
            </Properties>
</TextFrame>
Rotated textframe
<TextFrame Self="u136" ParentStory="u124" ItemTransform="0 1 -1 0 320.3805483338268 -125.07900895050204">
            <Properties>
                <PathGeometry>
                    <GeometryPathType PathOpen="false">
                        <PathPointArray>
                            <PathPointType Anchor="-101.72727272727272 -46.581818181818164" LeftDirection="-101.72727272727272 -46.581818181818164" RightDirection="-101.72727272727272 -46.581818181818164"/>
                            <PathPointType Anchor="-101.72727272727272 -0.3272727272727103" LeftDirection="-101.72727272727272 -0.3272727272727103" RightDirection="-101.72727272727272 -0.3272727272727103"/>
                            <PathPointType Anchor="115.9090909090909 -0.3272727272727103" LeftDirection="115.9090909090909 -0.3272727272727103" RightDirection="115.9090909090909 -0.3272727272727103"/>
                            <PathPointType Anchor="115.9090909090909 -46.581818181818164" LeftDirection="115.9090909090909 -46.581818181818164" RightDirection="115.9090909090909 -46.581818181818164"/>
                        </PathPointArray>
                    </GeometryPathType>
                </PathGeometry>
            </Properties>
</TextFrame>
When I converted the values of rotated textframe in to coordinates and drawn in a screen then I am not getting the exact position where it drawn in the original.
Can anyone help me to find out the cordinates of rotated textframe.
Thanks in advance.

It seems pretty straightforward to me.
Your center point is (42.375 mm, 27.458 mm) and your box is 58.417 mm x 28.417mm.
IDML defines the rectangle by its corners, not its center, so let's find the upper-left corner. Divide the width by two and subtract from the x, same for the height and the y. You get (13.665 mm, 13.2495 mm).
That is in page coordinates relative to the upper-left corner of the page, we can see from your rulers.
But IDML coordinates are spread-relative from the center of the spread. Your spread is a single page that is 85 mm x 55 mm.
So if we translate your upper-left corner, it is (13.665, 13.2495) mm - (85/2, 55/2) => (29.3335 mm, 14.2505mm) in spread-relative coordinates.
But IDML coordinates are in points, not in mm. So we convert (multiply by 2.835). And we get (83.150 pt, 40.395 pt).
But that doesn't match up with your IDML file, which has (-82.650 pt, -39.890pt).
But look at the difference: (0.500 pt, 0.505 pt). That's really 1/2 point, because your box has a 1-pt border and that gets split evenly across all 4 sides. And there's 0.005 of round-off error, bceause floating point math sucks.
Any questions?

Is there a plugin that can copy the coordinates of a selection to the clipboard?

Is there a plugin in existance, that I can make a selection in Photoshop and then copy the coordinates of that selection to the clipboard?
I am a texture artist and frequently lay a number of graphics out in one file, before typing out the coordinates for each element. Currently this is a slow manual task, but could be made so much faster if I didn't have to type everything out.
Thanks,
Matt

I have to admit to not fully understanding your work flow, but to the extent I do Here is what I suggest:
I would open your image and create a new action and start recording. I would then create the rectangular selections in sequence and stop recording when you are done. Then I would save the action as a text file. The resulting text file for a test image, having created three different rectangular selections, looks like this:
Action: Action 1
        Set Selection
            To: rectangle
            Top: 0.451 Inches
            Left: 0.917 Inches
            Bottom: 0.559 Inches
            Right: 1.017 Inches
        Set Selection
            To: rectangle
            Top: 0.767 Inches
            Left: 0.892 Inches
            Bottom: 0.868 Inches
            Right: 0.986 Inches
        Set Selection
            To: rectangle
            Top: 1.108 Inches
            Left: 0.885 Inches
            Bottom: 1.201 Inches
            Right: 0.986 Inches
You can use this for the rest of your process.
To make things easier you should clear all actions before creating your new action or the text file will contain all of the active actions and you would have to hunt for the new action in the text file.
Hope this helps.
Paulo

How do I get the coordinates of the text block (TextFrame) help me please!

Dim myApp As New Illustrator.Application
Dim myDoc As Illustrator.Document
myDoc = myApp.ActiveDocument
Dim textRef = myDoc.TextFrames.Add
For Each ArtPageItems In myDoc.PageItems
If TypeName(ArtPageItems) = "TextFrame" Then
'========It is necessary to obtain the coordinates of the text block and move closer to the object (ie the text)============
Else
End If
Next

Hi Todd, you're welcome, please explain better, I don't understand the question.
are you trying to "move" a textframe (Dim textRef = myDoc.TextFrames.Add) closer to other text frames? or do you want to "zoom" to this textframe?

I want to know the coordinates of the mouse

I want to know the coordinates of the mouse when the mouse is outside my application?

Hi,
No, it is not possible... In order for a MouseListener to know when the mouse exited a component, it first needs to know the position of the application's GUI on the screen and also position of the cursor on the screen.
But in JDK 1.5 we have an option java.awt.MouseInfo.getPo..(); to get current mouse possition.
regards
Dhina

How to calculate the coordinate after implementing Affine Transformation?

Hi, guys!!
I am working on a Map makeing program, like MS Visio. Then, I need to put an icon on the working space. And the icon can be moved, rotated, and scaled, when mouse drags handles (8 small circles) around the icon. However, the problem is that after the icon is scaled or rotated using AffineTransform class, I do not know how to calculate the coordinate to paint the mouse handles.
Please give me your suggestions!! Thanks in advance!!

Sure. The idea is that you track your translations, scaling, and rotation separate from the AffineTransform. That way, you know what you need to revert:
AffineTransform at = new AffineTransform();
at.translate(20, 20);
at.scale(2, 2);
at.rotate(45, 10, 10);
At this point, let's assume you want to translate again. First you have revert the rotation and the scale:
at.rotate(-45, 10, 10);
at.scale(1/2, 1/2);
at.translate(10, 10);
In order to do this, you need to track your scaling and rotation values when you change them. If this isn't feasible, it's certainly possible to derive the values from the AffineTransform, but that's a bit tougher.
Michael

How to find the coordinates of a mouse click in a Tree node ?

Hello
I have a JTree that have few nodes. The nodes contain an icon and a label (using custom cell renderer) and I want to receive right clicks on the icon and show a popup menu.
The problem is I can only get the right click on the whole tree node, not only the icon.
I tried two approaches:
1. register the mouse listener directly with the icon in the cell renderer. That doesnt work since the events received by the tree node do not propagate to its sub-components.
2. Register the event with the JTree itself and then try to find which part of the tree node was clicked (see if it was within the coordinates of the icon).
But I cant get the node's coordinates or width.
I tried using SwingUtilities.convertPoint or SwingUtilities.ConvertMouseEvent but it just doesnt work with DefaultMutableTreeNode.
Any ideas how to do it ?

user11973359 wrote:
1. register the mouse listener directly with the icon in the cell renderer. That doesnt work since the events received by the tree node do not propagate to its sub-components.No, it doesn't work because a renderer isn't added to any component hierarchy. It isn't in any way a 'sub-component'.
Read about editor and renderer concepts in the Oracle tutorial on How to Use Tables.
user11973359 wrote:
2. Register the event with the JTree itself and then try to find which part of the tree node was clicked (see if it was within the coordinates of the icon).
But I cant get the node's coordinates or width.<tt>getPathForLocation(...) </tt>in conjunction with<tt> getPathBounds(...)</tt>.
db

Record the coordinate point of the max y value on chart

I am trying to figure out how to get labVIEW to record the x and y values at the coordinate point of the location of the max y value. In other words, at the max y value, record the x and y values at that point. I though of using the max and min fn under signal processing but it only records the maximum value on one axis. I am using labVIEW 8.6. Any suggestions? Also I am very new to LabVIEW so I appologize if this is a really simple problem.

What do you mean by : "My max/min array does not seem to store the max/min values."
An array is a serie of numbers, so unless they are all the same there has to be a minimum and a maximum.
What do you mean by : "...return to zero within a second or two..."
Does your vi hang for a second or two or what?
What do you mean by : '...to stay at the max value until I exceed it?"
Exceed what? A loop that acquire data continuously or what?
The solution provided by smercurio is ok for a static array but I start thinking that you acquire data and want to find the maximum value over different blocks of data.
Is that it?
If yes then you need a shift register that retain the maximum of passed blocks. With each new block compare the maximum of that block with the shift register value. If it's larger keep this one as a new maximum. If it isn't larger keep the original value.
Message Edited by Alain S on 07-03-2009 07:17 PM

How to determine the coordinate (intensity graph)

Hallo all,
is there a tool in labview, which enables me to determine the coordinates of a point in an intensity Graph? i mean, is it possible to determine these coordinates just by clicking on the desired point?
thanks

See the following code.
Ton
Message Edited by TonP on 09-25-2008 03:56 PM
Free Code Capture Tool! Version 2.1.3 with comments, web-upload, back-save and snippets!
Nederlandse LabVIEW user groep www.lvug.nl
My LabVIEW Ideas
LabVIEW, programming like it should be!
Attachments:
GetCoords.png ‏6 KB

SDO_ORDINATES how to get the coordinates?

Hello,
how can i get the individual x1,y1 and z1 coordinates of a box? when i use in an sql statement sdo_ordinates i just get an object sdo_ordinate_array. But how can i filter out the coordinates? To explain what i want to do here a pseudocode sql-statement:
select min(v.shape.sdo_ordinates.x1),min(v.shape.sdo_ordinates.y1),min(v.shape.sdo_ordinates.z1),max(v.shape.sdo_ordinates.x1),max(v.shape.sdo_ordinates.y1),max(v.shape.sdo_ordinates.z1) from veith.voxel v
Is there a way to get an sql-statement that gives me the min and max x1,y1 and z1 from a table and also a statement where i get the x1,y1 and z1 value from all tableentries? For any help thanks in advance.
Greetings,
Markus Veith

Markus,
If you are using 9i there are two functions: sdo_geom.max_mbr_ordinate and sdo_geom.min_mbr_ordinate which will return either the min or max ordinate values in a layer.
If you are using 8i, you will have to write a sql block or procedure to compare the x ordinates or y ordinates and retrieve the min or max values.
Hope that helps.
Dave
David R. Miller
Michael Baker Jr., Inc.
3601 Eisenhower Avenue
Alexanria, VA 22304
[email protected]
www.mbakercorp.com

The coordinate of drawString()

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