The pythagoren theorem

Question

I need help with printing out this formula.
a^2 + b^2 = hypotenus^2
heres a code I have been given for a little help, but it doesn't work
I keep getting an error (unexpected type).
a = sqrt (hypotenuse2 - b2 )
I figured it was because the 2's werent written in the power form so i tried...
a = sqrt (hypotenuse^2 - b^2 )
an i still get the error. If anyone can help me with nmaking the powers work, that would greatly be appreciated. Thanks!
Jbinks~ .

Answer 1

Actually, this will do:
int a=(int)Math.sqrt(hypotenuse*hypotenuse-b*b);There's an implicit conversion done for you.
Here's how I'd do it:
public class Pythagoras
    public static void main(String [] args)
        try
            if (args.length > 1)
                double c = Double.parseDouble(args[0]);
                double b = Double.parseDouble(args[1]);
                double a = Pythagoras.calculateSide(b, c);
                System.out.println("a: " + a);
                System.out.println("b: " + b);
                System.out.println("c: " + c);
        catch (Exception e)
            e.printStackTrace();
    public static double calculateHypotenuse(double a, double b)
        if ((a < 0.0) || (a < 0.0))
            throw new IllegalArgumentException("euclidian space triangle sides must be positive");
        if (a > b)
            double r = b/a;
            return a*Math.sqrt(1.0+r*r);
        else
            double r = a/b;
            return b*Math.sqrt(1.0+r*r);
    public static double calculateSide(double b, double c)
        if ((b < 0.0) || (c < 0.0))
            throw new IllegalArgumentException("euclidian space triangle sides must be positive");
        double r = b/c;
        if (r > 1.0)
            throw new IllegalArgumentException("hypotenuse is longer than either side");
        return c*Math.sqrt(1.0-r*r);
}%