To anyone who wants to know

I figured it out how to show a hidden dynamic table using JAVASCRIPT: just show the screen using location.href("XXXXXview.uix?event=<event name>), when the event name declared sets the data:rendered property of the dynamic table to "true".
Thanks anyway.

I feel your pain, but realistically you can't expect an item of software to go on working under operating systems that didn't exist years ago when the software came out. I'm quite surprised it ever worked under Vista - did you do any checks as to whether it would before you upgraded your OS?
You might be able to use your licence to move to Dreamweaver at a reduced rate, I don't know.

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HT6114 Joined problem labels Labels to color everyone in the line archives mp3 and selection in dots as it exists now can be anyone who wants to do what HELPS of how thoroughly enjoyable.

Joined problem labels Labels to color everyone in the line archives mp3 and selection in dots as it exists now can be anyone who wants to do what HELPS of how thoroughly enjoyable.

Sp188585 wrote:
Joined problem labels Labels to color everyone in the line archives mp3 and selection in dots as it exists now can be anyone who wants to do what HELPS of how thoroughly enjoyable.
Sorry, you will have to outline your issues more clearly.
Thanks
Pete

Hey guys I a teen who wants to know why my Iphone6 is having a fuzzy noise

Hey guys I wanted to hear or how to fix the fuzzy sound its driving me crazy even though I got the phone a little while ago.I also noticed on the iphone 5s does the same but only 5 to 10 sec, but on my iphone 6 like i mentioned did it for like 20 sec and wanted to know whats happening.There for i also hear other stuff i haven't dropped it or anything.
Can any one help me never heard this happened till now when i posted this question

FUzzy sound from using it how? Calls? Music? Always even when not using it? by pogster
I noticed that it only make a fuzzy sound through any sound like games or music on my iphone
it sounds like a radio but very quiet.

For anyone who wants a challenge....

I have an old imac that will not boot into any other form than the login screen. The computer person who set up the computer did not make me the admin, and I have no idea what the admin password is, so I cannot change what the startup disk is, nor disable the login screen from the system preferences. I also cannot boot from target disk mode, an installation CD/DVD or any other magical keyboard combinations. I tried resetting the PRAM, no bongs were heard, other than the original startup. All I want to do at this point is erase the hard drive and reinstall the system software, but as mentioned earlier, I cannot start up from the DVD. I do have the Al keyboard connected, but I highly doubt that changing that will fix things, but I will use another one tomorrow to see if that fixes anything. Does anyone else have any other suggestions?
It is designed to connect to our network, so I can login there, and get to my user interface, but again, I am not the admin - but I should also mention that I do own the computer... it is not stolen, hacked or whatever, I would just like it back to it's original state so it could function as a computer again. I am pretty sure my applecare has expired on this one too, which is unfortunate.
Any other ideas would be greatly appreciated!

So what does one do when you cannot login the single user mode?
You need to buy a license of Snow Leopard ($29.00) which is still available from Apple or Amazon and upgrade. Make sure your computer meets the minimum specifications for Snow Leopard which are:
System Requirements
Mac computer with an Intel processor
1GB of memory
5GB of available disk space
DVD drive for installation
Some features require a compatible Internet service provider; fees may apply.
Some features require Apple's MobileMeservice; fees and terms apply.
Once you have that you can use this video for instructions on how to do an Erase and Install. The kid is kind of annoying but he knows what he's doing. Clean Install Of Snow Leopard video

For anyone who wants to customize their IT Superhero...

You are persistent!!

i took the IT Superhero quiz, and it made me a girl! so i tried retaking it until i got what i wanted, and finally, i just decided to reverse engineer their logic answers! it ended up being (somewhat) simple, and yet tricky to decipher, and so i decided to share my findings here at the Water Cooler to anyone in a similar predicament as me :Di highly recommend taking the quiz FIRST to see what you get (it IS rather fun), but once that is out of the way, feel free to have fun (i know i did). and don't forget to use your avatar if you like it!so basically, you just take the address of the Superhero quiz:
http://community.spiceworks.com/careers/sysadminday/superhero-quizand add the appropriate keys after it. for example:...
This topic first appeared in the Spiceworks Community

A challenge for anyone who wants one : )

Hi, I am trying to write a method that basically takes in a vector containing short objects which have variable legnth codes in them. I want to manipulate these shorts and create a new Vector of shorts that contain fixed length code versions of these;
Right now you can think of the shorts as overlapping on its neighbour in the vector, some of the bits are spilling over into the next short.
Heres an example to make it clearer
every short should have two parts, a 3 bit 'id' that tells the algorithm how many bits folling these 3 bits are to be associated with the id. The id can be used to get this number of bits from an array:
indexlengths[] = {7, 6, 8, 5, 4, 7, 9, 8}
so, when the algorithm encounters id #2 (the in the 3 leftmost bits) it looks in this array in position 2 and then knows that following the id is 6 bits to be extracted. once this has been extracted a new short should created and, these 6 bits should be added but shifted over to the very right of the short(shifted 13-6 in this case) and this id should added but to the very leftmost 3 bits.
so:
010 1111110100000
(id:2) (6 bits)
should go to:
010 0000000111111
now this wouldn't be too much of a problem BUT the remaining bits that were discarded (in this case 0100000) must be kept and plugged to the next short in the vector
so if the next short in the vector is
1010000011111110
it will have this remainder from the previous short plugged into the right of it
010 0000101000001 and 'pushed' off is:1111110
now this process must continue making sure that this remainder that was 'pushed' off in plugged in to the next short BUT FIRST the process that we started with must be applied, a new short is created(for which the resulting fixed legnth code will be stored in), the ID is extracted from the leftmost 3 bits (id: 0) of the current short and the number of bits to follow is found from the above array indexLengths[0] which is 7 bits. these 7 bits are shifted by (16-3)-7 = 6 positions to the right so they are stored in to the rightmost part of this new short and the id will stay at the leftmost 3 bits:
010 0000000000101 'pushed off: 000001'
so now we have both 1111110 and 000001 'pushed' off of the same short, as the length of bits of this remainder gets longer and reaches 16, a new short should be created and added to the result vector.
One more example just to show it visually:
this time the indexes after the 'id' part are all 6
int[] indexLengths = {6, 6, 6, 6, 6, 6, 6, 6};
a vector of 3 shorts:
111 1000011111111, 011 0111111100000, 101 1000000000000,
results in:
111 0000000100001, 111 1111011 011111, 110 00001011000000, 000000
looking at the first resulting short:
(id) (6 bits that followed the index shifted to the right most 6 bits)
111 0000000100001
the remiander that had to be 'pushed off' is inserted in to the start of the next short and the process starts again.
I know this is alot to ask, but any tips would be great, java isn't being any help when working with bits and shorts, for example when extracting the id (using a mask and then shifting to the right 13 places) I get negative numbers sometimes!
Any suggestions on how to break this down into a managable problem to solve would be great too : )
Thanks!
Message was edited by:
digiology

this might help, heres a method doing the opposite, turning fixed legnth codes into variable length codes, the whole idea of this method is to splim down the array of shorts before sending it in a message. This works fine, however the problem above of doing it the other way around has caused me alot of grief after 3 attempts!
public Vector convertVectorToSlimmerVector(Vector v)
          System.out.println("initial:");
          for(int i=0;i<v.size();i++)
               System.out.print(toBinaryString(((Short)v.get(i)).shortValue())+", ");
          System.out.println();
          Vector result = new Vector();
          //assume vector starts at message part for now
          //seems to be fine for legnths
          int[] indexLengths = {6, 6, 6, 6, 6, 6, 6, 6}; //this will be passes as a parameter or stored in the incomming vector later!
          // above values cant be greater than 13!
          short mask1 = 0x1;
          short mask2 = 0x3;
          short mask3 = 0x7;    //000 0000000000111;
          short mask4 = 0xF;       //000 0000000001111;
          short mask5 = 0x1F;       //000 0000000011111;
          short mask6 = 0x3F;       //000 0000000111111;
          short mask7 = 0x7F;       //000 0000001111111;
          short mask8 = 0xFF;       //000 0000011111111;
          short mask9 = 0x1FF; //000 0000111111111;
          short mask10 = 0x3FF; //000 0001111111111;
          short mask11 = 0x7FF; //000 0011111111111;
          short mask12 = 0xFFF; //000 0111111111111;
          short mask13 = 0x1FFF;//000 1111111111111;
          short mask14 = 0x3FFF;//001 1111111111111;
          short mask15 = 0x7FFF;//011 1111111111111;
          //short mask16 = 0xFFFF;//111 1111111111111;
          long longMask1 = 0x8000;//100 0000000000000;
          long longMask2 = 0xC000;//110 0000000000000;
          long longMask3 = 0xE000;//111 0000000000000;
          long longMask4 = 0xF000;
          long longMask5 = 0xF800;
          long longMask6 = 0xFC00;
          long longMask7 = 0xFE00;
          long longMask8 = 0xFF00;
          long longMask9 = 0xFF80;
          long longMask10 = 0xFFC0;
          long longMask11 = 0xFFE0;
          long longMask12 = 0xFFF0;
          long longMask13 = 0xFFF8;
          long longMask14 = 0xFFFC;
          long longMask15 = 0xFFFE;
          //others omitted for now
          Vector redundantShortPositions = new Vector();
          //short lengthMask=0xE000;
          long lengthMask = (long)0xF000; //111 0000000000000;
          short[] masks = {mask1, mask2, mask3, mask4, mask5, mask6, mask7, mask8, mask9, mask10, mask11, mask12, mask13, mask14, mask15};
          long[] longMasks = {longMask1, longMask2, longMask3, longMask4, longMask5, longMask6, longMask7, longMask8, longMask9, longMask10, longMask11, longMask12, longMask13, longMask14, longMask15};
          short currentShort;
          Short currentShortObject;
          long currentWordLength;
          int indexLength;
          int currentBitLength;
          int numberOfCarriedBits = 0;
          int numberOfBitsToSpillOver = 0; //number of bits that cant be stored in this iteration and will spill over into the next
          int numberOfBitsLeftOver = 0; //number of redundant bits at the end of the current byte(/short?)
          short valueCarriedOver = 0;
          long currentLong;
          String currentProgress;
          Short lastShort = null;
          short l;
          System.out.println();
          for(int index=0; index<v.size(); index++)
               System.out.println("index:"+index);
               currentShort = ((Short)v.get(index)).shortValue();
               currentProgress = toBinaryString(currentShort);
               System.out.println("progress: "+currentProgress);
               currentShortObject = (Short)(v.get(index));
               currentLong = currentShortObject.longValue();
               currentWordLength = (long)(currentLong & lengthMask);
               currentWordLength = (currentWordLength>>13);
               //currentShort = (short)currentLong;
          //     short l2 = (short)currentWordLength;
               indexLength = indexLengths[(int)currentWordLength]; //make sure that the index length for word legnth 0 is stored above somewhere
               //System.out.print("isolated legnth: "+toBinaryString((short)currentWordLength)+", ");
               //l = (short)(currentShort & lengthMask);
               //currentWordLength = (short)(currentShort & lengthMask);
               //l = (short)currentWordLength;
               //currentWordLength >> 13;
          //System.out.println(toBinaryString((short)l));//currentWordLength));
               //that 1 is added to it
               if(currentWordLength != 0)
                    currentShort = (short)(currentShort & masks[indexLength-1]); //extract index
                    currentShort = (short)(currentShort << ((16-3)-indexLength));//shift index over (just 3 bits from the left most bit, next to where the length will go)
                                                                                          //number of bits from this short placed in previous short
                    currentBitLength = (3 + indexLength + numberOfCarriedBits)-numberOfBitsLeftOver;
                    currentWordLength = currentWordLength<<13;
                    currentShort = (short)(currentWordLength + currentShort);
                    currentProgress = toBinaryString(currentShort);
                    System.out.println("progress: "+currentProgress);
                    if(index!=0)
                         //number of free bits from last short is > 0
                         if(numberOfBitsLeftOver > 0)
                              System.out.println("last short: "+toBinaryString(lastShort));
                              System.out.println("current short: "+toBinaryString(currentShort));
                              //isolate left most bits from current short that can be stored in previous short
                              short tmp = (short)(currentShort & longMasks[numberOfBitsLeftOver-1]);
                              System.out.println("tmp after mask: "+toBinaryString(tmp));
                              //shift over to rightmost position
                              tmp = (short)(tmp >> (16-numberOfBitsLeftOver));
                              tmp = (short)(tmp & masks[numberOfBitsLeftOver-1]);
                              System.out.println("tmp: "+toBinaryString(tmp));
                              lastShort = new Short((short)(lastShort.shortValue() + tmp));
                              System.out.println("lastshort fter spillage: "+toBinaryString(lastShort));
//                              v.setElementAt(lastShort,(index-1));
//                              v.remove(index-1);
//                              v.add(index-1,lastShort);
                              result.setElementAt(lastShort,(index-1)); //could be buggy (check with dict legnths of 2!)
                              currentShort = (short)(currentShort << numberOfBitsLeftOver);
                    currentProgress = toBinaryString(currentShort);
                    System.out.println("progress after spilling to previous: "+currentProgress);
//                    if(currentBitLength <= 8)
//                         numberOfBitsLeftOver = 8 - currentBitLength;
//                    else
                    {// if currentBitLength > 8
                         numberOfBitsLeftOver = 16 - currentBitLength;
                         if(numberOfBitsLeftOver < 0)
                              numberOfBitsToSpillOver = Math.abs(numberOfBitsLeftOver);
                              numberOfBitsLeftOver = 0;
                         else
                              numberOfBitsToSpillOver = 0;
                         short pluggedInValue = (short)(valueCarriedOver << (16-numberOfCarriedBits)); //shift value to appropriate left most position
                         if(numberOfCarriedBits > 0)
//                              isolate part of currentShort that will be 'pushed off' to the right
                              short temp = (short)(currentShort & masks[numberOfCarriedBits-1]);
                              valueCarriedOver = temp;
                         else
                              valueCarriedOver = 0;
                         currentShort = (short)(currentShort >> numberOfCarriedBits);
                         currentShort = (short)(pluggedInValue + currentShort);
                         lastShort = new Short(currentShort);
                         numberOfCarriedBits = numberOfBitsToSpillOver;
                         currentProgress = toBinaryString(currentShort);
                         System.out.println("number of carried bits: "+numberOfCarriedBits);
                         System.out.println("num bits left over: "+numberOfBitsLeftOver);
                         System.out.println("progress: "+currentProgress);
                         //System.out.print(toBinaryString(currentShort)+", ");
               else
               {// currentWordLength = 0
                    System.out.println("word length is zero");
               if(numberOfBitsLeftOver >= 16)     //hopefully should be ok, remove condition if not and remove redundant shorts afterwards
                    //reset this value and dont add current shot
                    numberOfBitsLeftOver = numberOfBitsLeftOver - 16;
//                    System.out.println("BOOLEAN");
//                    System.out.println(toBinaryString((Short)result.get(index-1)));
                    //result.add(new Boolean(false)); //just to act as a flag
                    System.out.println("position of redundantness? "+index);
                    //store position of redundant short
                    redundantShortPositions.add(new Integer(index));
//               else
//                    result.add(new Short(currentShort));
               result.add(new Short(currentShort));
          //remove redundant shorts
          int offset = 0;
          for(int j=0;j<redundantShortPositions.size();j++)
               int p = ((Integer)(redundantShortPositions.get(j))).intValue();
               result.remove(p-offset);
               offset++;
          System.out.println("result:");
          for(int i=0;i<result.size();i++)
               System.out.print(toBinaryString(((Short)result.get(i)).shortValue())+", ");
          return result;
     }here my crappy attempt at solving the first mentioned problem (converting from variable length to fixed legnth):
public Vector convertToFatterVector(Vector v)
          System.out.println("initial:");
          for(int i=0;i<v.size();i++)
               System.out.print(toBinaryString(((Short)v.get(i)).shortValue())+", ");
          short mask1 = 0x1;
          short mask2 = 0x3;
          short mask3 = 0x7;    //000 0000000000111;
          short mask4 = 0xF;       //000 0000000001111;
          short mask5 = 0x1F;       //000 0000000011111;
          short mask6 = 0x3F;       //000 0000000111111;
          short mask7 = 0x7F;       //000 0000001111111;
          short mask8 = 0xFF;       //000 0000011111111;
          short mask9 = 0x1FF; //000 0000111111111;
          short mask10 = 0x3FF; //000 0001111111111;
          short mask11 = 0x7FF; //000 0011111111111;
          short mask12 = 0xFFF; //000 0111111111111;
          short mask13 = 0x1FFF;//000 1111111111111;
          short mask14 = 0x3FFF;//001 1111111111111;
          short mask15 = 0x7FFF;//011 1111111111111;
          //short mask16 = 0xFFFF;//111 1111111111111;
          long longMask1 = 0x8000;//100 0000000000000;
          long longMask2 = 0xC000;//110 0000000000000;
          long longMask3 = 0xE000;//111 0000000000000;
          long longMask4 = 0xF000;//111 1000000000000;
          long longMask5 = 0xF800;
          long longMask6 = 0xFC00;
          long longMask7 = 0xFE00;
          long longMask8 = 0xFF00;
          long longMask9 = 0xFF80;
          long longMask10 = 0xFFC0;
          long longMask11 = 0xFFE0;
          long longMask12 = 0xFFF0;
          long longMask13 = 0xFFF8;
          long longMask14 = 0xFFFC;
          long longMask15 = 0xFFFE;
          short[] masks = {mask1, mask2, mask3, mask4, mask5, mask6, mask7, mask8, mask9, mask10, mask11, mask12, mask13, mask14, mask15};
          long[] longMasks = {longMask1, longMask2, longMask3, longMask4, longMask5, longMask6, longMask7, longMask8, longMask9, longMask10, longMask11, longMask12, longMask13, longMask14, longMask15};
          Vector result = new Vector();
          int[] indexLengths = {6, 6, 6, 6, 6, 6, 6, 6};
          long lengthMask = (long)0xF000;
          //long tmp = 0xE000;
          //short lengthMask = (short)tmp;      //111 0000000000000;
          short indexMask = 0x1FFF;           //000 1111111111111;
          System.out.println();
          System.out.println("length mask: "+toBinaryString((short)lengthMask));
          System.out.println();
          short currentShort;
          long currentLong;
          String currentProgress;
          Short currentShortObject;
          long currentWordLength;
          int indexLength;
          //int numberOfBitsSpillingOver=0;
          short spillValue = 0;
          Short lastShort;
          int currentBitLength;
          int numBitsCarriedOver=0;
          short firstShort;
          short secondShort;
          long firstLong;
          long secondLong;
          short valueThatWasSpilledOver=0;
          short valueThatWillSpillOver=0;
          for(int index=0;index<v.size();index++)
               currentShort = ((Short)v.get(index)).shortValue();
               currentLong = ((Short)v.get(index)).longValue();
               if(index == 0)
                    currentWordLength = (short)(currentShort >> 13);
//                    currentWordLength = (long)(currentShort & lengthMask);
//                    System.out.println("currentShort: ");
//                    currentWordLength = (long)(currentWordLength>>13);
                    System.out.println("current word legnth: " + toBinaryString((short)currentWordLength));
                    indexLength = indexLengths[toAbsoluteIntValue((short)currentWordLength)];//(int)currentWordLength];
                    //numBitsCarriedOver = (int)(13-indexLength);//////
               //valueThatWillSpillOver = (short)(masks[numBitsCarriedOver-1]&currentShort);
               currentWordLength = (valueThatWasSpilledOver<<(16-numBitsCarriedOver)&lengthMask);
               currentWordLength = (short)(currentWordLength>>13);
                                                       //dont forget might need to be set somewhere!
               currentShort = (short)((currentShort>>numBitsCarriedOver)+(valueThatWasSpilledOver<<(16-numBitsCarriedOver)));
               System.out.println("progress after spilling from previous:"+toBinaryString(currentShort));
               //currentShort should now have the length and index contained in it but the index is shifted to the left
               indexLength = indexLengths[(int)currentWordLength];
               numBitsCarriedOver = (int)(13-indexLength);
               valueThatWillSpillOver = masks[13-indexLength];
               valueThatWasSpilledOver = valueThatWillSpillOver; //?
               //get index(shifted to the right) on its own
               short temp = (short)((currentShort & indexMask)>>(13-indexLength));
               System.out.println("index on its own shifted to the right: "+toBinaryString(temp));
               //get length on its own
               short temp2 = (short)(currentShort & lengthMask);
               System.out.println("length on its own: "+toBinaryString(temp2));
               currentShort = (short)(temp + temp2);
               System.out.println("progress after shifting index to the right: "+toBinaryString(currentShort));
               result.add(new Short(currentShort));
          System.out.println("result");
          for(int i=0;i<result.size();i++)
               System.out.print(toBinaryString(((Short)result.get(i)).shortValue())+", ");
          }

Imessage never deletes messages and shows them to anyone who wants to see them

here's the problem that in my opinion can cost millions of $$ in court for Apple:
iMesage never deletes conversations. If you delete a converstion from the list, it is still cached on the device. Problem is present in iOS6 & iOS7.
Do the following:
1) spotlight settings should have messages selected for search results
2) open Messages.app and delete a conversation that had iMessages there
3) open spotlight and search for something that the dialog contained
*not everything will be found though, I guess it doesn't cache everything or delete the oldest / doesn't cache the newest nessages fast*
4) you will be surprised when your deleted conversation shows up
5) for an even more unpleasant surprise, turn off and log out from imessage. Your conversations will still be displayed in spotlight.
Best words to look up on your significant other's iDevice: dear, kiss, love etc.
6) To make things even more interesting, spotlight will neither display the sender of the message (i.e. if it is a message or reply from your contact), nor the date. Plus it picks phrases out of context in such a way, that they will look more than interesting.
P.S. iMessage ruined my relationship with a girlfriend. Should I mention how angry I am?
P.P.S. the only way to stop iMessage from hijacking deleted conversations and terrorising you is to do a clean restore of the device. Set it up as new. Cached messages are backed up - if you restore from backup, they will still be there.
Some images to clarify this:

You said you text a lot - if your inbox and sent message folder is FULL, it could also cause delays. Try deleting messages, then restart the phone. It should work until the folders are full; then delete and restart, or just delete your messages every day.

Anyone who wants zCover action for their Nano.

http://cgi.ebay.ca/ws/eBayISAPI.dll?ViewItem&rd=1&item=5812282517&ssPageName=STR K:MEWN:IT
I just bought one from this vendor in preparation before my Nano arrives.
Got a shield for the screen, two shells, a lanyard.
Looks to be high quality stuff.

I ordered one (black) a few days ago, and am waiting for it to arrive. will link photos when i get it.

Hi I have a customer who wants to know if Win XP will be a supported platform for iAS 7.0, if not what will be iPlanet official line for people using iAS 7.0 on Xp.

All information about iAS 7.0 still requires a non-disclosure agreement. So, there isn't an "official line" yet. (iAS 7.0 hasn't even been formally announced yet.)
If you or your client can contact your local sales team and execute an NDA you should be able to find out the planned platform support.
David

I am wanting to know if my blackberry curve that I no longer use could be put on a phone card plan and if the number that she has on another phone can be transfered to the curve?

I am giving my old phone the curve to a friend who wants to know if the phone can be phone card used?

Good afternoon shrimpski. What a wonderful friend you are to be giving your friend your old Blackberry Curve. I need to find some friends like you to get me out of sticky situations. Are you wondering if they can use it on a prepaid account? Depending on the make and model of the Blackberry, they may be able to activate it on a Verizon Wireless prepaid account. For more information on our prepaid options please reach out to our prepaid team at 888-294-6804.
Verizon Wireless phones can only be activated on Verizon Wireless accounts. If they are looking to use the device with a different carrier, they would want to bring it to the carrier to see if it is a device that they can activate on their network.
NickB_VZW
Follow us on Twitter @VZWSupport.

I want to know that if i want to download facebook on my iphone 4 or any other apps then it ask me put my card details for payment. why is that. if they are free then why do i need to give my card details?please help me anyone.

I want to know that if i want to download facebook on my iphone 4 or any other apps then it ask me put my card details for payment. why is that. if they are free then why do i need to give my card details?please help me anyone.

Just select no credit card as outlined here:
http://support.apple.com/kb/ht2534

In iTunes the iPhone device icon will not show up whenever I plug in a USB into my PC but the iPhone icon will show up in 'This PC' so if anyone who knows a resolution to my problem with my iTunes or PC,it would really help me.I need at least Help or Tip

In iTunes the iPhone device icon will not show up whenever I plug in a USB into my PC but the iPhone icon will show up in 'This PC' so if anyone who knows a resolution to my problem with my iTunes or PC,it would really help me.I need at least Help or some Tips.I have already tried many things to iTunes and my PC like trying to restore my PC but that do anything.Also,would it be fine if i contacted (call) Apple Support? Please,I need help because what I think is wrong is my PC,iPhone,or USB might be messed up so if anyone could help me with this,it would be really helpful and for anyone to be nice enough to help me.

I think this article will help you.

I have WD 1TB and use Time Machine for the past 2 years. Now I have multiple folders in my external hard drive and want to know how to condense all folders into yearly folders instead. Anyone know how to do this?

Now I have multiple folders in my external hard drive and want to know how to condense all folders into yearly folders instead. Anyone know how to do this?

anthonycancel wrote:
I want the folders I already backed up to come together into one folder when that year is over. Is there a way to manually do that or automatic through TM?
I'm quite sure there is no "automatic" way to do this. I've never heard of anyone trying it either. I suppose if you wanted try it, you could simply create a new folder in the same partition TM is on, label it for that year, then gather all the days for that year and drag/drop them into the folder. I suspect (but do not know) you'd be risking the continuity of your backups, meaning TM would simply start over again, meaning that next back up would start a new series of backups, with the first one roughly equalling the entire capacity of your internal HD, instead of adding only the new data to the previous backup. Once again, I would recommend against it, unless you're fine with TM starting a new series of backups if it doesn't work out the way you want it to. Hope you'll post back with results so we can learn from it.

I deleted the playlists on my iPhone and when I now try to synchronize with my iTunes account to put the music back, nothing happens and I do not get the music back on my iPhone. Anyone who knows why that could be? Grateful for any suggestions!

I deleted the playlists on my iPhone and when I now try to synchronize with my iTunes account to put the music back, nothing happens and I do not get the music back on my iPhone. Anyone who knows why that could be? Grateful for any suggestions!

I know it sounds weird, and that is the reason I posted my question. Because my case is not like all the ones I've found online and it's confusing. I added a screen capture of my itunes with my old iphone (the one that houses my playlists) connected to it.
My playlists "ARE" in my iphone 4s. They are still there even though they do not show up when I plug in to itunes in my computer.
When connecting my phone to itunes on my macbook, the playlists do not appear anywhere in itunes. I have found my connected iphone icon, I have clicked on the arrow next to it and it does pull up the standard lists that come with the iphone/itunes: Music, Movies, TV shows, books. That's it! below that is "Genius" and below "Geniuns" is "PLAYLISTS" but the only playlist of mine that shows there is one that I created several years back titled "90's music" and that one I created it on my computer, not my phone. Under "90's music" there are also other standard playlists that itunes automatically adds.
Does anyone else have this issue or know how to get around this. I am starting to think that I am going to have to recreate these lists on my computer

HT1414 Can anyone help me? I just want to know if I just put my iPhone 4 which has been fixed can I start it as a new phone and still have my contacts and photos as it won't let me log in with my iCloud address

Can anyone help me? I just want to know if I just put my iPhone 4 which has been fixed can I start it as a new phone and still have my contacts and photos as it won't let me log in with my iCloud address

Try assigning Queen as the Album Artist on the compilations in iTunes on your computer.

To anyone who wants to know

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