Traditional classful IP addressing?

In classful addressing, class A networks would allow up to 16,777,214 hosts be attached to the network. In reality, how was this managed? This many hosts were attached to a single LAN? Was the traffic so light that this many hosts could be attached? Were there no routers used to break up collision domains? As I understand, any bridging employed would only compartmentalize broadcasts.
Any insight which can be shared would be appreciated as this seems to be an unreal number of hosts to have on a single segment.

Hi,
I think at that point of time since a lot of IP addresses were available, people were easily assigned class A IP addresss so for example a company is assigned 11.0.0.0 IP address then 11.0.0.1 till 11.255.255.255 IP belongs to him. I am sure noone would have connected so many IP addresses in a single LAN. The inside LAN will be a big structured network with lot of broadcast domains by using routers and layer 3 devices. It is just that for the outside world (internet) the full 11.0.0.0/8 range belongs to one compnay. Ofcourse inside that company the IP addresses were sumnetted.
Regards
Dinesh
http://Knowurtech.com
(Good technical articles. Submit your articles and get featured on our website. Send email to [email protected] To know the benefits http://www.knowurtech.com/be_an_expert.html)
Hi,
I think at that point of time since a lot of IP addresses were available, people were easily assigned class A IP addresss so for example a company is assigned 11.0.0.0 IP address then 11.0.0.1 till 11.255.255.255 IP belongs to him. I am sure noone would have connected so many IP addresses in a single LAN. The inside LAN will be a big structured network with lot of broadcast domains by using routers and layer 3 devices. It is just that for the outside world (internet) the full 11.0.0.0/8 range belongs to one compnay. Ofcourse inside that company the IP addresses were sumnetted.
Regards
Dinesh
http://Knowurtech.com
(Good technical articles. Submit your articles and get featured on our website. Send email to [email protected] To know the benefits http://www.knowurtech.com/be_an_expert.html)

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$lname = $HTTP_POST_VARS['textfield2'];
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$email = $HTTP_POST_VARS['textfield4'];
$address = $HTTP_POST_VARS['textfield5'];
$state = $HTTP_POST_VARS['textfield6'];
$zip = $HTTP_POST_VARS['textfield7'];
$find = $HTTP_POST_VARS['select'];
$goals = $HTTP_POST_VARS['select2'];
$practice = $HTTP_POST_VARS['select3'];
$learn = $HTTP_POST_VARS['select4'];
$handicap = $HTTP_POST_VARS['select5'];
$timeplaying = $HTTP_POST_VARS['select6'];
$lesson = $HTTP_POST_VARS['select7'];
$additional = $HTTP_POST_VARS['textfield8'];
mail('[email protected]','Owen Dawson PGA Contact Form Submission',"First Name: $fname\nLast Name: $lname\nPhone Number: $phone\nEmail: $email\nAddress: $address\nState: $state\nZip Code: $zip\nHow did you find me? $find\nWhat are your goals? $goals\nHow much can you practice? $practice\nWhat would you like to learn? $learn\nWhat is your handicap? $handicap\nHow long have you been playing golf? $timeplaying\nHave you ever taken a lesson? $lesson\nAdditional Information: $additional\n",'From: [email protected]');
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The only thing that really jumps out at me with your script is $HTTP_POST_VARS. That is a deprecated function as of PHP 4. something I don't remember the exact number. It is possible if your host upgraded the PHP installation that the function is now replaced by the simpler $_POST global variable ( http://php.net/manual/en/reserved.variables.php ).
Also the easiest way to test this type of thing is to print your email text to the screen and stop the PHP script there before the mail can execute. Then you can check out what variables exist and what don't before finishing your script. Also I hope you have left stuff out for security reasons, because right now you appear to have no way to validate that a form was submitted in the first place.

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Settings:
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... 10 more
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at java.lang.reflect.Constructor.newInstance(Constructor.java:513)
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at com.tangosol.util.ClassHelper.newInstance(ClassHelper.java:587)
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Cannot start daemon
First question:
1) without address provider section in the proxy server configuration xml, will it use any default address provider implementation?
2) what's wrong with the proxy server settings xml which causes above error?
Thanks
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Hi LuK,
Sounds like there is no load balancing is happening in my environment.
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*<socket-address>*
*<address>PROXY-B</address>*
*<port>9099</port>*
*</socket-address>*
*</remote-addresses>*
<connect-timeout>10s</connect-timeout>
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I will be having lot of web service queries which runs very fast. I would like to see both the proxies serves the web requests.
I am observing, One connection has been made to one proxy when it's starts up and keep hold on to it (no matter whether other proxy is free or not).
is it a bug? or am i doing some mistake?
Thanks
Prab

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128/25.xxx.xxx.xxx.in-addr.arpa. IN NS dns.domain.net.
212.xxx.xxx.xxx.in-addr.arpa. IN PTR mail.domain.net.
My ISP has setup their system to pull zone data from my DNS server. This is working fine for my domain names (zones) but not for the reverse ip.
Please help, and Thank you!

You need to match the zone name your ISP has delegated to you.
We have one customer with the same setup working (Tiger server) but we have to do it manually not through the GUI.
The named.conf and zone file should probably look something like:
zone "128-25.xxx.xxx.xxx.in-addr.arpa" {
type master;
file "db.128-25.xxx.xxx.xxx.in-addr.arpa.";
allow-transfer {any;};
allow-update {none;};
$TTL 10800
128-25.xxx.xxx.xxx.in-addr.arpa. IN SOA dns.domain.net. apurvis.domain.net. (
2008032100 ;Serial
86400 ;Refresh
3600 ;Retry
604800 ;Expire
345600 ;Negative caching TTL
128-25.xxx.xxx.xxx.in-addr.arpa. IN NS dns.domain.net.
128-25.xxx.xxx.xxx.in-addr.arpa. IN NS <ISP slave/secondary-dns name>.
???.128-25.xxx.xxx.xxx.in-addr.arpa. IN PTR dns.domain.net.
212.128-25.xxx.xxx.xxx.in-addr.arpa. IN PTR mail.domain.net.
I have used www.dnsreport.com / www.dnsstuff.com reverse lookup to see the DNS traversal ("backtrace"), but they now restrict usage a bit or you can pay to use their services.
Using that might reveal the correct name of the zone (if you don't get it working with the above name).
HTH

Ip addressing and subnets

I was wondering if anyone knew if I could use a subnet mask of 255.255.255.128 with a network number of 10.107.128.xxx I believe I cannot use this mask with a Class C address but since this is a class A address I though I might be able to. I want to have two subnets each with 126 addresses. These address will be split between two office each with a Cisco 3620 router.
Thanks,
Scott Graham

The topic of this forum is IP + Optical however there are a number of professionals online who may be able to assist you. We are always considering additional forums for such topics and I will make a note of your post.
If you don't get a suitable response to your post, you may wish to review our resources at the online Technical Assistance Center http://www.cisco.com/tac or speak with a TAC engineer. You can open a TAC case online at www.cisco.com/tac/caseopen
If anyone else in the forum has some advice, please reply to this thread.
Thank you for posting.

IP Address Calculator

I need to write a program that parses an ip address and subnet mask and prints out the associated network id and host id.
The program should accept the ip address and subnet mask as input parameters, e.g.,
ipcalc 192.168.1.129 255.255.255.240+
The output should display the class of the address, along with the network and host id, e.g.,
Class C Address+
Network ID: 192.168.1.128+
Host ID : 0.0.0.1+
Can someone please help me solving this question.
Thanks!

I can tell you, you don't need any of the networking APIs.
You can just parse the command line arguments and calculate a results.
We won't do your homework for you but if you show what you have tried, we can give you hints on how to fix a problem.

VM IP Address network size

Hello all,
I have a quick question on setting up VM's on the cisco UCS or any other virtual server type system.
Our server team claim that a dedicated class 'C' address range set up in DHCP is filling quickly and will soon be fully used up by an increasing number of virtual servers.
So our network team has suggested that we could just set up another routed VLAN to accommodate any further growth.
Our server team then claim that managing other VLANs is too hard and just want a huge supernet range instead.
I'm pretty sure that a large supernet is not a best practice for many reasons but can anyone back up this theory and maybe point out a document that reports this formally.
Thanks in advance.

Yes Reza, but they are saying that it is too hard to create multiple virtual switches to accommodate many subnets/VLANs as their server requirements grow. On the extreme side of the argument they are saying why not just give us 65,000 addresses and then we only need one virtual switch configured within their VM environment.
I am saying that that is not best practice and the limit should be a /24 subnet, and if they need more subnets then create more virtual switches per VLAN and so be it.
I'm not a VM guru so I'm just guessing that you must be able to manage multiple VLANs or subnets without having a single supernet which goes against IP addressing best practice ???

Implementing association classes in Java

Hi. I'm having trouble in implementing an association class.
I have two classes, Customer and Address.
A customer might have different billing address and shipping address.
I found from a book that In this kind of situations, Customer class and Address class should be linked with an association class "Type" that has the attribute "addresstype". My problem is that I dont know how to inplement this kind of association classes in Java. Could anyone please show me some example of implementing an association class.
thanks.

example of implementing an association class.It could look like this,
public class AddressAssociation {
   public enum Type = {BILLING, SHIPPING};
   public void put(Type t, Address a);
   public Address get(Type t);
}The idea is that the Customer class holds a reference to one AddressAssociation object. Basically the Customer class can be kept ignorant (but doesn't have to of course) of what types of addresses there are. In that case when a new type of address is added Customer wouldn't have to be modified, only AddressAssociation.
Note that AddressAssociation probably should be an interface. In the implementation of AddressAssociation to avoid switches in put and get a Map (sometimes called an associate array) could be used.

How to code a method that returns string for class object

I have a class named Address.
public class Addresss{
private String street;
private String city;            // instance variables
private String zipcode;}I have been asked to write a method that returns a string for Address object. I dont understand how to create address object.Can anyone pls help me understand.
do I have to write (for creating object)
Address addressObject = new Address(); ( coding method that returns a string for address object) ---> I really dont understand this part.

looks almost right. The problem is that your method name AddressBookEntry does not match the name of your class AddressBook and therefore is not a constructor.
Furthermore, you probably need to make a distinction between a single entry into the address book which consists of a single name and a single address, (which is just what you have done) and an address book itself which is probably a list of AddressBookEntries
So for your code I would change the class that you called "AddressBook" to "AddressBookEntry" and have a third class that represents the collection of AddressBookEntries.
Now to be honest, I don't know why you keep the name split apart from the street address portion of the address. I would be more inclined to keep the name as a field of the address itself, but it's your code, you carve it up the way you like.

I just typed out an email on my macbook, it stated cannot be sent due to invalid address, there were 33 of them, where exactly did my message go

I just typed out an email to my daughters class (34 addresses) when I hit send it stated the message could not be sent due to a bad address .. but I cannot find my message anywhere in my mail account .. is it completely gone? or sitting somewhere where I don't know to look?

thank you for your help .. actually about 10 minutes after I sent it a folder popped up with a little up arrow on it .. I think maybe an unsent folder .. it was in there .. I am not overly computer savvy and apparently not very patient.

Class C subnet challenge

Given a class C address of 192.168.25.0 / 24, I need to design a network address scheme for 4 subnetworks where the zero subnet is used and the number of hosts on subnet A is 2, Subnet B is 5, Subnet C is between 20 and 30 and subnet D is between 75-100. I'm stumped because if I use a /26 mask then I won't have enough host for subnet D. If I use a /25 mask then I don't have enough subnets. Clearly I am missing something in this simple problem and help will be most appreciated. VLSM is not being used or allowed.
Walt

Hi Walt,
Diving subnet equally will not ensure all subnet to be served as per your requirement. I think below is the only one as per
your requirement....or you can have one more supernet to cate this requirement
Subnet A: 192.168.25.0/30
Subnet B: 192.168.25.8/29
Subnet C: 192.168.25.32/27
Subnet D: 192.168.25.128/25
Regards
Mahesh

Traditional classful IP addressing?

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