Transmit file in HTTP POST

Hello,
Sorry I am french my english is not very good !
I have an JAVA applet and I would transmit a file of my applet to an ASP web page with HTTP POST. I try with HTTPClient but I don't success. If you have solution for transmit file in HTTP POST ?
Thanks
[My PortFolio|http://florent.lagoda.free.fr]

Crossposted and already answered: [http://forums.sun.com/thread.jspa?threadID=5347746].
In the future, do not crosspost without mentioning about the crosspost. It is considered very rude to crosspost at forums. Others may spend lot of time and effort in helping you and they may got very angry when they discovered that you already got help and answer at aonther topic which you didn't mention about at all.
Edited by: BalusC on 14-nov-2008 9:28 (wrong link)

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Retrieve data/files fro HTTP POST request in On-Demand process

Hello,
I would like to integrate https://github.com/blueimp/jQuery-File-Upload to my APEX 4.2 application inside XE11g. I would like to use this kind of jQuery component, multiple file upload, use Drag & Drop, image resize, size limit, filter extensions etc...
This jQuery component and also others javascript uploaders sends data files to some defined URL. Developer need to build some servlet, php script or something on server side that will read files from HTTP request and stores it somewhere.
Do you know how to do it in APEX? How can I read data from HTTP POST request in PL/SQL? Now I can only call my On-Demand application process from javascript, but I am not able to read any data from HTTP POST in it.
Can I do it in APEX, or using MOD_PLSQL?
I would like to implement this:
1) some javascript uploader will call some URL of my application and sends HTTP POST with data files
2) I will read data files from HTTP POST and store them into database
3) I will create some HTTP response for javascript uploader
Thank you for some tips

I know about that existing plugin " Item Plugin - Multiple File Upload"
But I doesn't work in IE and has only basic features. Licence for commercial use is also needed. I would like to use some existing jQuery plugin. There are many of these plugins with nice features. And only one problem is that I need to create some server side process/servlet/script.. that can recieve HTTP request, get files from it and stores them into DB.

Uploading big files via http post to XDB table

Hello,
I ve created a web form for to upload files as blobs to the database using XML DB, DBPS_EPG package and preconfigured DAD.
The issue is that small files (~10kb) are being uploaded ok, but file which is 100K during http post returns connection reset from the server side.
To my opinion there might be some max file size parameter for oracle server to accept during oracle listener tcp connection (as apach has maxrequestlimit).
Is there any workaround for to load large files to the XDB table via webform?
Here is a piece of code:
CREATE USER web IDENTIFIED BY web_upload;
ALTER USER web DEFAULT TABLESPACE XML_DATA;
ALTER USER web QUOTA UNLIMITED ON XML_DATA;
ALTER USER web TEMPORARY TABLESPACE TEMP;
GRANT CONNECT, ALTER SESSION TO web;
GRANT CREATE TABLE, CREATE PROCEDURE TO web;
ALTER SESSION SET CURRENT_SCHEMA = XDB;
BEGIN DBMS_EPG.CREATE_DAD('WEB', '/upload/*'); END;
BEGIN
    DBMS_EPG.SET_DAD_ATTRIBUTE('WEB', 'database-username', 'WEB');
    DBMS_EPG.SET_DAD_ATTRIBUTE('WEB', 'document-table-name', 'uploads');
    DBMS_EPG.SET_DAD_ATTRIBUTE('WEB', 'nls-language', '.al32utf8');
    DBMS_EPG.SET_DAD_ATTRIBUTE('WEB', 'default-page', 'upload');
    COMMIT;
END;
ALTER SESSION SET CURRENT_SCHEMA = SYS;
CREATE TABLE web.uploads (
    name VARCHAR2(256) NOT NULL
        CONSTRAINT pk_uploads PRIMARY KEY,
    mime_type VARCHAR2(128),
    doc_size NUMBER,
    dad_charset VARCHAR2(128),
    last_updated DATE,
    content_type VARCHAR2(128) DEFAULT 'BLOB',
    blob_content BLOB
CREATE OR REPLACE PROCEDURE web.upload
AS
url VARCHAR2(256) := 'http://demo.test.com:9090/upload/uploaded';
BEGIN
    HTP.P('<html>');
    HTP.P('<head>');
    HTP.P(' <title>Upload</title>');
    HTP.P('</head>');
    HTP.P('<body>');
    HTP.P(' <h1>Upload</h1>');
    HTP.P(' <form method="post"');
    HTP.P('      action="' || url || '"');
    HTP.P('      enctype="multipart/form-data">');
    HTP.P('    <p><input type="file" name="binaryfile" /></p>');
    HTP.P('    <p><input type="file" name="binaryfile" /></p>');
    HTP.P('    <p><button type="submit">Upload</button></p>');
    HTP.P(' </form>');
    HTP.P('</body>');
    HTP.P('</html>');
END;
CREATE OR REPLACE PROCEDURE web.uploaded (
    binaryfile OWA.VC_ARR
AS
BEGIN
    HTP.P('<html>');
    HTP.P('<head>');
    HTP.P(' <title>Uploaded</title>');
    HTP.P('</head>');
    HTP.P('<body>');
    HTP.P(' <h1>Uploaded</h1>');
    FOR i IN 1 .. binaryfile.COUNT LOOP
        IF binaryfile(i) IS NOT NULL THEN
            HTP.P(' <p>File: ' || binaryfile(i) || '</p>');
        END IF;
    END LOOP;
    HTP.P('</body>');
    HTP.P('</html>');
END;
/帖子经 anatoly编辑过

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Get file from HTTP POST (upload image)

Hello,
I would like to integrate http://www.plupload.com flash component to my APEX 4.1 website. I need it because I want to resize image and transform image before upload on client side, upload multiple files etc..
But I don't know how to read image binary data from POST method.
When I hit "Start upload" button on plupload component it makes some transformations and creates POST method like this:
------pluploadboundary1334433145869
Content-Disposition: form-data; name="name"
p16qp6jm3nhan1ca46me1ocr3tu1.jpg
------pluploadboundary1334433145869
Content-Disposition: form-data; name="chunks"
1
------pluploadboundary1334433145869
Content-Disposition: form-data; name="chunk" 0
------pluploadboundary1334433145869
Content-Disposition: form-data; name="file"; filename="centerd.jpg"
Content-Type: image/jpeg
ÿØÿà�JFIF��ÿÛ��
image content
now I would like to read content of this HTTP POST and read sended image and store it to DB.
Question is... how can I read file sended with HTTP POST in APEX pl/sql process or pl/sql procedure?
Thank you...
Edited by: cardel on Apr 14, 2012 11:17 PM

Hi,
here are my two cents ...
this will be a bit difficult. When you use the standard APEX File upload it is not PL/SQL handling the POST request. The request is handled by the webserver - depending on the variant you are using it is either mod_plsql, the C code of the Embedded Gateway or the APEX Listener. The webserver is also doint the insert into APEX' file repository. So I see two options:
It might be possible to configure your plugin (don't know about it) the behave the same as a standard browser upload. Then for APEX there would be no difference - mod_plsql should handle the files accordingly.
If you want to handle the POST request yourself, as said, you can't do this in PL/SQL. It would be possible to write a Java servlet doing this and deploy that servlet on the same container as the APEX Listener (when using Apache with mod_plsql you would need an additional Java server for that) ....
Hope this helps ...
Best regards
-Carsten

WebLogic Apache bridge problems on uploading large files via HTTP post

I have a problem uploading files larger than quarter a mega, the jsp
page does a POST
to a servlet which reads the input stream and writes to a file.
Configuration: Apache webserver 1.3.12 connected to the Weblogic 5.1
application server
via the bridge(mod_wl_ssl.so) from WebLogic Service pack 4.
The upload goes on for about 30 secs and throws the following error.
"Failure of WebLogic APACHE bridge:
IO error writing POST data to 100.12.1.2:7001; sys err#: [32] sys err
msg [Broken pipe]
Build date/time: Jul 10 2000 12:29:18 "
The same upload(in fact I uploaded a 8 MEG file) using the
Netscape(NSAPI) WebLogic
connector.
Any answers would be deeply appreciated.

I have a problem uploading files larger than quarter a mega, the jsp
page does a POST
to a servlet which reads the input stream and writes to a file.
Configuration: Apache webserver 1.3.12 connected to the Weblogic 5.1
application server
via the bridge(mod_wl_ssl.so) from WebLogic Service pack 4.
The upload goes on for about 30 secs and throws the following error.
"Failure of WebLogic APACHE bridge:
IO error writing POST data to 100.12.1.2:7001; sys err#: [32] sys err
msg [Broken pipe]
Build date/time: Jul 10 2000 12:29:18 "
The same upload(in fact I uploaded a 8 MEG file) using the
Netscape(NSAPI) WebLogic
connector.
Any answers would be deeply appreciated.

File upload using http-post in OSB

Hi All,
I am trying to upload a file using http-post method in OSB.
I have created a business service pointing to the service url, with http method post.
and calling this business service from a proxy service.
I am unable to send the form data to the business service.
Please let me know how to send trhe form data and the file information.
The error given by Business Service is-
the request doesn't contain a multipart/form-data or multipart/mixed stream, content type header is text/plain
Thanks in advance.
Seemant
Edited by: Seemant Srivastava on Oct 12, 2010 12:28 PM

Hi Anuj,
A sample HTML form code for. Post HTTP service-
<html>
<head> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8"> <title>CSV File</title>
</head>
<body>
<form method="post" enctype="multipart/form-data" action="http://xyz/UploadFile">
<table>
<tr>
<td> Feed id </td>
<td><input type="text" name="refid" value="" size="20"></td>
</tr>
<tr>
<td> Username (optional)</td>
<td><input type="text" name="username" value="" size="20"></td>
</tr>
<tr>
<td> Password (optional)</td>
<td><input type="password" name="password" value="" size="20"></td>
</tr>
<tr><td> Select CSV File </td>
<td> <input type="file" name="upload" value="" width="30"/></td>
</tr>
<tr>
<td><input type="submit" name="Ok" value="Go"> <input type="reset" name="reset" value="Reset"> </td>
</tr>
</table>
</form>
</body>
</html>
I need to pass all these information to OSB business service.

Http-post XML file to Localhost:1301 - No XI available

Hi guys,
I hava a problem finding a preferrably easy answer to a task: send a XML-file via http-post to localhost:13001. I am using the iXML library to create the XML (as it contains some stuff not available in the crm) and thats about it. The system will not have an XI available, but the application listening on 13001 will be expecting data, whenever it ist sent. As far as I know, the file should be sent everytime a user presses a certain button.
Never done this before, so even basics are fine.
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Try reading: https://metro.dev.java.net/discover/

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we also ran into issues while transforming using a target xsd. Listed below:
Use Case Context: In an ODI interface, Data from a database view is mapped to a target XSD schema. A package is then created, wherein, in the first step, this interface is executed. Then, in the second and final step, data transferred to the target XSD schema is saved as an XML file using OdiSqlUnload function.
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When the data from the target XSD schema is saved as an XML file using OdiSqlUnload function, the XML does not match the XSD, which was initially imported into ODI.
Regards
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This is a user to user forum. We are all end users like yourself. Know one here knows what Apple is going to do.

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Hello,
we are submitting a PDF form by calling submitForm function:
doc.submitForm
        cURL: "http://localhost/script",
        cSubmitAs: "XML"
The server returnes data of type "Content-type: application/pdf" and as a result this aplication/pdf data is displayed in a new window in Acrobat Reader.
The document in new window has name e.g. A9R3347.tmp, is it possible to force some concrete name ?
We tried to send from server the http header:
Content-Disposition: attachment; filename=\"custom_name.pdf\"
or
Content-Type: application/pdf;         filename=custom_name.pdf
but non of this works.
1/ is it possible to set some custom name of the document, which is returned from a server in response of HTTP Post submit ?
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See Oracle Metalink,
..Oracle Portal Technical Forum,
....Subject: PORTAL - uploading files (file attachments) with file names.
This message thread outlines javascript code that automatically captures the filename during an upload.

Http post from an application with file attachment

Hi ! I didn't know where else to post this message...
I'm trying to make a HTTP POST from an application and upload a file with it. I have no problems with the posting, just that I haven't got any ideas how to get the file uploaded as well. I've been reading loads of examples regarding the topic, and searching older posts the forum here, without any help.
Here's the method i'm using:
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              URL url = new URL ("TheURL");
               URLConnection urlConn = url.openConnection();
                          // We do input & output, without caching
               urlConn.setDoInput (true);
               urlConn.setDoOutput (true);
               urlConn.setUseCaches (false);
                          // multipart/form-data because we want to upload a file
                 urlConn.setRequestProperty ("Content-Type", "multipart/form-data");
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                   content += "other_key-value_pairs";
              // write the data to stream, and flush it.
                 printout.writeBytes (URLEncoder.encode(content));
               printout.flush ();
               printout.close ();
               // Get the response.
                 DataInputStream input = new DataInputStream (urlConn.getInputStream());
               FileOutputStream fos=new FileOutputStream("postto.txt");
               String str;
                 BufferedReader bufr = new BufferedReader(new InputStreamReader(input));
              // Write response to outputfile
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                     if (str.length() >0) {
                     fos.write(str.getBytes());
                     fos.write(new String("\n").getBytes());
               input.close ();Now, the response here I get from the url i'm posting to is "Failure, no data-file". I've tried many diff methods of writing the file to the stream, but always get the same result.
I need to file attached like it would be when using a HTML form's <input type="file">.
Please help ! This is getting really urgent !

String content = "upfile=" + System.getProperty("user.dir") + "\\file.ext&";
content += "other_key-value_pairs";
printout.writeBytes (URLEncoder.encode(content));
printout.flush ();
printout.close ();Actually, what this does is create a request like:
GET /path/to/file/script.language?upfile=/home/user/file.ext&other=params HTTP/1.1
Content-Type: multipart/form-data
-- And other HTTP params --
The file is not actually appended to the request.
I really don't know how Java handles the file upload, but you could do it by hand, like so:
public static void doFileUpload(String url, String filename, Hashtable params) throws IOException {
    // Construct the request
    String boundary = "----------------------mUlTiPaRtBoUnDaRy";
    String request_head = "POST " + url + " HTTP/1.0\r\n" +
                                     "Content-type: multipart/form-data; boundary=" + boundary + "\r\n";
    String request_body = boundary + "\r\n\r\nContent-disposition: form-data; name=\"upload\"" +
                                     "\r\n\r\n";
    BufferedReader in = new BufferedReader(new InputStreamReader(new FileInputStream(filename)));
    int b = -1;
    while((b = in.read()) != -1) {
         request_body += (char)b;
    in.close();
    Enumeration keys = params.keys();
    while(keys.hasMoreElements()) {
        String key = keys.nextElement();
        requst_body += "\r\n" + boundary + "\r\n\r\nContent-type: form-data; name=\"key\"\r\n" +
                                (String)params.get(key);
    request_body += "\r\n" + boundary + "--\r\n";
    int length = request_head.length() + request_body.length() + "Content-length: \r\n";
    String req_length = "Content-length: " + (length + new String("" + length).length()) + "\r\n";
    Socket socket = new Socket(url,80);
    PrintStream stream = socket.getOutputStream();
    stream.print(request_head + req_length + req_body);
    // And now an option to read the response, I will omit that...
}Note: I have not tested this code, just wrote it up out of memory. If it does not work, it will propably need some small fixes.
Tuomas Rinta

HTTP POST with Java? (Submit file)

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http://www.innovation.ch/java/java_comp_instr.html

HTTP POST Request with XML file in

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I have the target URL and the a XML File.
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If yes can anybody give me a hint?
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// send post request to PI server
function postToHost($host, $port, $path, $referer, $data_to_send) {
$fp = fsockopen($host, $port);
if($fp) {
     $res="";
       fputs($fp, "POST $path HTTP/1.1\r\n");
       fputs($fp, "Host: $host\r\n");
       fputs($fp, "Referer: $referer\r\n");
       fputs($fp, "Content-type: text/plain\r\n");
       fputs($fp, "Content-length: ". strlen($data_to_send) ."\r\n");
       fputs($fp, "Connection: close\r\n\r\n");
       fputs($fp, $data_to_send);
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Would be great if anybody could give me a hint how to solve such a HTTP Post request with XML body data.
Thanks in advance.
Chris
Edited by: Christian Kuehne on Feb 26, 2009 4:32 PM

hi friend could you please share your solution regarding this query if u got it already?

Error Unexpected end of file from server with HTTP POST

Hi everyone,
I'm coding a simple client to download some information from a local machine in my LAN.
I have to do this with an http post request.
When i try to parse the http response the program catch an exception, this one:
java.net.SocketException: Unexpected end of file from server
at sun.net.www.http.HttpClient.parseHTTPHeader(...)
the parameter is a JSON request, and of course the response is a JSON formatted.
i put the http request code:
import java.io.BufferedInputStream;
import java.io.BufferedReader;
import java.io.ByteArrayOutputStream;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.io.OutputStreamWriter;
import java.net.HttpURLConnection;
import java.net.URL;
public class HttpDownloaderThread extends Thread{
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        private String param;
     private HttpDownloadListener listener;
     private HttpURLConnection connection=null;
     private InputStream is;
        private OutputStreamWriter wr;
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                        connection.setRequestProperty("Content-Type", "application/jsonrequest");
                        connection.setDoOutput(true);
                        wr = new OutputStreamWriter(connection.getOutputStream());
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                        wr.flush();
                        int responseCode=0;
               System.out.println();
                        try{
                         responseCode= connection.getResponseCode();
                        }catch(Exception e){
                            e.printStackTrace();
               if (responseCode == HttpURLConnection.HTTP_OK){
                    is = connection.getInputStream();
                                 BufferedReader rd = new BufferedReader(new InputStreamReader(is));
                                String line;
                                while ((line = rd.readLine()) != null) {
                                    System.out.println(line);
                    closeHttpConnection();
                    listener.resourceDownloaded(url, null);
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                            closeHttpConnection();
                            listener.downloadFailed(url, new Exception("Http error: " + Integer.toString(responseCode)));
          }catch(Exception e){
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               listener.downloadFailed(url, e);
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          if (is != null){
               try{
                    is.close();
                                wr.close();
               }catch (Exception e){
               }finally{
                    is = null;
                                wr=null;
          if (connection != null){
               try{
                    connection.disconnect();
               }catch (Exception e){
               }finally{
                    connection = null;
}there's someone who know's why??
Thanks to everyone :)
Thomas.

jole_star wrote:
this problem also happen to me,.So since you provided actually no information about your problem you are going to get exactly the same response.
Please don't hijack old threads. Start your own and provide much much much more information.
I shall lock this thread.

How would I do a http post with a xml file

How would I do a http post with a xml file.
I have a url called https://localhost:8443/wss/WSS and the XML file is sent as part of the HTTP POST body.
How would I send this XML file when posting?

most people just add feedback to the comments they've asked about already, rather than ignoring all the feedback and making a new post with the exact same information:
http://forum.java.sun.com/thread.jspa?threadID=5247331&messageID=10020973#10020973
If you want to add in an XML file to a POST command, you'd add it just like any other file you'd attach to a post request, especially (if you're request is the same as your last post) if you're just doing a jsp page. I'd do it something like this:
<form method=POST ENCTYPE="multipart/form-data" action="https://rcpdm.mnb.gd-ais.com/Windchill/servlet/IE/tasks/DJK/fcsAddContentComplete.xml">
<H3> File Name </H3>
<input type=file name=filename>
<input type=submit value="Do it!">
</form>Then again, this solution has literally nothing to do with java, and you still need to make sure that your servlet knows what to actually do with that information you're sending it.

Post file over Http

Hi All,
I am working on EDI scenario in which EDI partner has given one HTTP site address with user name and password. I will have to put EDI file at that site using http/soap adaptors at receiver end.
One thing I know for sure that I can not use File channel at reveiver side as there is no FTP available. Now Can anybody please let me know how to generate file using http connection?
I have absolutely no idea how to use http and soap adaptors so if any links to the blogs will also be helpful.
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Hi Aamir,
Thanks for your reply.
I just want to generate a file at given location. I am confused what is the difference in data sent as a payload or as attachment?
As you said in case of attachement we need to use some modules(Looks bit difficult ) I would perhaps like to generate file by using Payload .
Can you suggest some blog for the same?
Thanks and Regards,
Atul

Transmit file in HTTP POST

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