Tree Node In Oracle Forms

Hell ow my dear Fiends
I am the beginner in oracle forms
I want to create a tree node below
For example
Purchase order
  Forms
          POM1010
  Reports
          Pom2010
  Queries
          POM3010
Human Resource Management
   Forms
          POM1010
  Reports
          Pom2010
  Queries
          POM3010

Hi,
You can see
https://forums.oracle.com/thread/512425
or
https://sites.google.com/site/craigsoraclestuff/oracle-forms---how-to-s/forms-how-to-create-a-hierachical-tree-form

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  • Tree view in Oracle forms

    Hello experts,
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    1
    MAN
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    Thank You
    regards
    aaditya.

    how to create hierarchical tree form
    https://sites.google.com/site/craigsoraclestuff/oracle-forms---how-to-s/forms-how-to-create-a-hierachical-tree-form

  • Tree Node - Open new FORM

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    Message was edited by:
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    Hi,
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  • Make an hierarchical Tree in oracle Forms 6i

    Hi everybody,
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    I create one non database block e.g. 'Bloc2' then
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    ID NUMBER(5),
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    ICON VARCHAR2(40 BYTE),
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    VALUE VARCHAR2(128 BYTE)
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    FROM MENU_tree
    CONNECT BY PRIOR ID = MASTER
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    htree ITEM;
    V_IGNORE number;
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    When i run the forms, It don't give me a structure of node.
    It give me only a icon with two arrows.
    Where is the problem ?
    Must I add code somewhere ?
    Help me for your ideas.
    Regards.
    Edited by: 794982 on 17 sept. 2010 04:55
    Edited by: 794982 on 17 sept. 2010 05:01
    Edited by: 794982 on 17 sept. 2010 05:04
    Edited by: 794982 on 17 sept. 2010 05:06
    Edited by: 794982 on 17 sept. 2010 05:13
    Edited by: 794982 on 17 sept. 2010 05:19
    Edited by: 794982 on 17 sept. 2010 05:23

    Ok Francois Thanks for your response.
    Just I pricise i work with oracle forms version 9.0.4.0.19 .
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    When I execute it just shows a line with two arrows but not a real tree.
    Then I do a block-non based and a elemnt with type hierarticall tree and a canevas.
    and i create a record_group. and in a palette property of the element i precise the canevas and the record_group
    I don't khnow where is the problem ?
    Any other suggestion ? please
    Regards.

  • Call forms and reports from a hierarchical tree node.

    Hello,
    I am new in pl/sql programming and I have some dificulties. I have created a hierarchical tree, in order to use it as a menu in an application that I am trying to develope. The problem is that I do not know how can I make the last nodes to be either a form or a report and when somebody double clicks on these nodes the form or the report will run. What is more, should I use the when-tree-node-selected trigger or the when-tree-node-activated?
    Thank you in advance,
    Vag

    Hi ,
    In Oracle Forms , a hierarchical tree is developed through the use of a sql statement and column which defines the order of leaves...
    Visit the on-line help of Forms10g to find out the details , and the triggers as well...
    Something else...post this question to Oracle Forms to get more detailed answer...
    Regards,
    Simon

  • How we know the selected node in a Tree object in a form?

    In a TREE object in forms, how can we know the current selected node by clicking a push button.
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    Hello
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  • How to run a form using tree node selection??

    hi...
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    I've done the same thing, and i think it works fine.
    Check this code (Sorry for the long post, but i cannot find how to attach files.
    PACKAGE menu_pk IS
    --Initialization of the menu.
    procedure Init;
    --Called from WHEN-TREE-NODE-EXPANDED
    procedure Expanded;
    --Called from WHEN-TREE-NODE-ACTIVATED
    procedure ExecuteCommand;
    END;
    PACKAGE BODY menu_pk IS
    MENU_NAME constant varchar2(30) := 'menu.menu';
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    decode(apm_type, 0, 'menu', 1, 'form', 2, 'report') || '.ico' apm_icon
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    where apm_parcode = pRoot
    order by apm_code asc;
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         loop
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    Ftree.PARENT_OFFSET, Ftree.LAST_CHILD,
    i.apm_type, i.apm_descr, i.apm_icon, i.apm_code);
         end loop;
    end;
    procedure FillNode(pNode in FTree.Node) is
         new_node ftree.node;
    begin
         for i in c_menu(FTree.get_tree_node_property(MENU_NAME, pNode, FTree.NODE_VALUE))
         loop
    new_node := Ftree.add_tree_node(MENU_NAME, pNode,
    Ftree.PARENT_OFFSET, Ftree.LAST_CHILD,
    i.apm_type, i.apm_descr, i.apm_icon, i.apm_code);
         end loop;
    end;
    procedure DeleteNodeChilds is
    node FTree.NODE;
    begin
         loop
    node := FTree.Find_Tree_Node(MENU_NAME, '',
         FTree.FIND_NEXT_CHILD, FTree.NODE_VALUE,
         name_in('system.trigger_node'), name_in('system.trigger_node'));
              exit when Ftree.ID_NULL(node);
              FTree.delete_tree_node(MENU_NAME, node);
         end loop;
    end;
    procedure Expanded is
    begin
         if (FTree.GET_TREE_NODE_PROPERTY(MENU_NAME, :system.trigger_node, FTree.Node_State) = FTree.EXPANDED_NODE) then
         menu_pk.FillNode(name_in('system.trigger_node'));
         else
              menu_pk.DeleteNodeChilds;
         end if;
    end;
    procedure ExecuteCommand is
    cursor c_command(pCode in varchar2) is
    select apm_form, apm_type
    from app_menu
    where apm_code = pCode;
    fCommand c_command%rowtype;
    fMenuCode varchar2(20);
    begin
         -- if it is as menu node then exit.
    if (not FTree.Get_Tree_Node_Property(MENU_NAME, :system.trigger_node, FTree.NODE_STATE) = FTree.LEAF_NODE) then
         return;
    end if;
    fMenuCode := FTree.Get_Tree_Node_Property(MENU_NAME, :system.trigger_node, FTree.NODE_VALUE);
         open c_command(fMenuCode);
         fetch c_command into fCommand;
         close c_command;
         if (fCommand.apm_type = 1) and (fCommand.apm_form is not null) then
              globals.Set_MenuChoice(fMenuCode);
              OPEN_FORM(fCommand.apm_form);--, ACTIVATE, SESSION);
         end if;
    end;
    END;
    The menu table definition follows.
    create table APP_MENU
    APM_CODE VARCHAR2(10) not null,
    APM_PARCODE VARCHAR2(10) not null,
    APM_DESCR VARCHAR2(40) not null,
    APM_TYPE NUMBER(1) not null,
    APM_FORM VARCHAR2(50)
    alter table APP_MENU
    add constraint APP_MENU_PRI primary key (APM_CODE);
    Hope this helps

  • Hierarchy tree in oracle forms problem

    Hello Experts,
                         I am new in oracle forms.I am using oracle forms 11g with weblogic server 10.3.5 at windows 7.I have two table as tbl_country and tbl_state.I have to make a hierarchy tree in oracle forms.My table structure as:
    tbl_country
    CREATE TABLE "SCOTT"."TBL_COUNTRY"
       (    "CNTRY_CODE" NUMBER NOT NULL ENABLE,
        "NAME" VARCHAR2(80 BYTE),
         CONSTRAINT "TBL_COUNTRY_PK" PRIMARY KEY ("CNTRY_CODE")  
    tbl_state:
    CREATE TABLE "SCOTT"."TBL_STATE"
       (    "SATE_CODE" NUMBER NOT NULL ENABLE,
        "COUNTRY_CODE" NUMBER NOT NULL ENABLE,
        "STATE_NM" VARCHAR2(80 BYTE),
         CONSTRAINT "TBL_STATE_PK" PRIMARY KEY ("SATE_CODE")
         CONSTRAINT "FK_CNTRY_STATE" FOREIGN KEY ("COUNTRY_CODE")
    Table Date as:
    insert into tbl_COUNTRY values(0,'country ');
    insert into tbl_COUNTRY values(91,'HHH');
    insert into tbl_COUNTRY values(72,'III');
    insert into tbl_COUNTRY values(83,'JJJ');
    insert into tbl_state values(1,'state',0);
    insert into tbl_state values(2,'BH',91);
    insert into tbl_state values(3,'CI',72);
    insert into tbl_state values(4,'DI',72);
    insert into tbl_state values(5,'EH',91);
    insert into tbl_state values(6,'FI',72);
    insert into tbl_state values(7,'GJ',83);
    insert into tbl_state values(8,'HJ',83);
    insert into tbl_state values(9,'IH',91);
    Desired Output in oracle forms tree:
    |__Country
             |____HHH
                       |____BH
                       |____EH
                       |____IH
             |____III
                      |__CI
                      |__DI
                      |__FI
             |____JJJ
                       |__GJ
                       |__HJ
    I Have tried but got no output
    select
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    from   (SELECT c.name,c.cntry_code from TBL_COUNTRY c union all select s.STATE_NM,s.COUNTRY_CODE from tbl_state s) esm
    connect by prior esm.CNTRY_CODE = esm.CNTRY_CODE
    start   with esm.code=0
    what is going wrong here.
    thank you
    regards
    aaditya

    If you have never worked with a Forms Tree control, I recommend you look at this tutorial: How To Create a Hierachical Tree form.
    Craig...

  • Call forms and reports through a hierarchical tree node.

    Hello,
    I am new in pl/sql programming and I have some dificulties. I have created a hierarchical tree, in order to use it as a menu in an application that I am trying to develope. The problem is that I do not know how can I make the last nodes to be either a form or a report and when somebody double clicks on these nodes the form or the report will run. What is more, should I use the when-tree-node-selected trigger or the when-tree-node-activated? I use forms 6i.
    Thank you in advance,
    Vag
    Message was edited by:
    user537672

    Thank you very much for your reply. I tried what you said and managed to create a when-tree-node-activated trigger that works fine. The only problem is that I do not know how to find the last 3 characters of every node in order to make the form understand if it is a form or a report. I mean that the name of each node maybe of different length so I do not know how exactly to use the substr().
    Thank you
    Vag

  • OPEN FORM WHEN-TREE-NODE-SELECTED

    hello all...
    i have a tree and i wanna when i click on the node another forms open due to form name
    i have table includes form_if,form_name " as in H.D.D"
    when i present all nodes and i click on the node the form opened and when i click on other node from the tree
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    path varchar2 (100);
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    node_value := ftree.get_tree_node_property('block33.sub_TREE',:SYSTEM.TRIGGER_NODE, FTREE.NODE_VALUE);
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    path :=(frm_name||'.fmx');
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    path:=null;
    frm_name:=null;
    EXCEPTION
    WHEN NO_DATA_FOUND THEN NULL;
    END;

    Hi,
    >
    when-tree-node-selected
    >
    Fires when a node is selected or deselected.
    So your code is getting executed for selection and deselection
    use SYSTEM.TRIGGER_NODE_SELECTED to check
    IF SYSTEM.TRIGGER_NODE_SELECTED THENRegards
    Yoonas

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