Turn byte array into file

hi,
I got a byte array from a file and want to turn it into a file, so i can access it thru the operating system.
byte[] lop = rs.getBytes("data");
can anyone give any help, or a good tutorial to do this.

Check out the API docs for the FileOutputStream class and pay special attention to its
write(byte[]) method.
kind regards,
Jos

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In followup to my previous reply, here is the sample code.
import java.security.spec.KeySpec;
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Hi,
i need to display a PDF file. The PDF is stored in a byte array. This works fine when i run my code (see below) from the .jpf via the debugger/browser, but when i use it as a portlet, in the portal, it does not work ?
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byte[] pdfDocument = docStore.getPDF();
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Mark,
Note that the portal sets the content type (e.g, text/html) and encoding
as the portal page starts rendering. In your case, the
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Mark Gilleece wrote:
Hi,
i need to display a PDF file. The PDF is stored in a byte array. This works fine when i run my code (see below) from the .jpf via the debugger/browser, but when i use it as a portlet, in the portal, it does not work ?
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FileOutputStream#write(byte[] array).

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- K

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Hi,
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rrrr007 wrote:
Hi,
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Hi,
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File file = new File(filename);
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MyDataSource ds = new MyDataSource(data);
ds.connect();
try
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catch (NoPlayerException e)
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import java.io.IOException;
import javax.media.Time;
import javax.media.protocol.PullBufferDataSource;
import javax.media.protocol.PullBufferStream;
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    protected PullBufferStream stream = null;
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return cs[i];
return null;
catch (Exception e)
// no such controlType or such control
return null;
public Time getDuration()
return duration;
public PullBufferStream[] getStreams()
if (streams == null)
streams = new MyPullBufferStream[1];
stream = streams[0] = new MyPullBufferStream(data);
return streams;
import java.io.ByteArrayInputStream;
import java.io.IOException;
import javax.media.Buffer;
import javax.media.Control;
import javax.media.Format;
import javax.media.format.AudioFormat;
import javax.media.protocol.ContentDescriptor;
import javax.media.protocol.PullBufferStream;
public class MyPullBufferStream implements PullBufferStream
private static final int BLOCK_SIZE = 500;
protected final ContentDescriptor cd = new ContentDescriptor(ContentDescriptor.RAW);
protected AudioFormat audioFormat = new AudioFormat(AudioFormat.GSM_MS, 8000.0, 8, 1,
Format.NOT_SPECIFIED, AudioFormat.SIGNED, 8, Format.NOT_SPECIFIED,
Format.byteArray);
private int seqNo = 0;
private final byte[] data;
private final ByteArrayInputStream bais;
protected Control[] controls = new Control[0];
public MyPullBufferStream(final byte[] data)
this.data = data;
bais = new ByteArrayInputStream(data);
public Format getFormat()
return audioFormat;
public void read(Buffer buffer) throws IOException
synchronized (this)
Object outdata = buffer.getData();
if (outdata == null || !(outdata.getClass() == Format.byteArray)
|| ((byte[]) outdata).length < BLOCK_SIZE)
outdata = new byte[BLOCK_SIZE];
buffer.setData(outdata);
byte[] data = (byte[])buffer.getData();
int bytes = bais.read(data);
buffer.setData(data);
buffer.setFormat(audioFormat);
buffer.setTimeStamp(System.currentTimeMillis());
buffer.setSequenceNumber(seqNo);
buffer.setLength(BLOCK_SIZE);
buffer.setFlags(0);
buffer.setHeader(null);
seqNo++;
public boolean willReadBlock()
return bais.available() > 0;
public boolean endOfStream()
return willReadBlock();
public ContentDescriptor getContentDescriptor()
return cd;
public long getContentLength()
return (long)data.length;
public Object getControl(String controlType)
try
Class cls = Class.forName(controlType);
Object cs[] = getControls();
for (int i = 0; i < cs.length; i++)
if (cls.isInstance(cs[i]))
return cs[i];
return null;
catch (Exception e)
// no such controlType or such control
return null;
public Object[] getControls()
return controls;

Here's some additional information. After making the following changes to MyPullBufferStream class, I can play a wav file with gsm-ms encoding with one issue: the wav file is played many times faster.
protected AudioFormat audioFormat = new AudioFormat(AudioFormat.GSM, 8000.0, 8, 1,
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// put the entire byte array into the buffer in one shot instead of
// giving a portion of it multiple times
public void read(Buffer buffer) throws IOException
        synchronized (this)
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            if (outdata == null || !(outdata.getClass() == Format.byteArray)
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thanks in advance..

hi friends,
i got the solution. i am using one external api of adobe acrobat, through which i am able to stream pdf document in form of byte array into acrobat viewer,without writing data in any file.
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import flash.events.Event;
import flash.net.FileFilter;
import flash.net.FileReference;
import flash.utils.ByteArray;
import mx.collections.ArrayCollection;
import mx.controls.Alert;
import mx.rpc.events.FaultEvent;
import mx.rpc.events.ResultEvent;
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import services.images.Images;
import services.images.ReturnMessage;
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        b64En.encodeBytes(fileByteArr);                                                  //<----------------------------------------------------------
        var str:String = b64En.flush();                                                        //<----------------------------------------------------------
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any help will be greatly appretiated!! thanks in advace!

yeah i did actually... except i think i changed a LOT of code since i last posted this article...
so i dont remember where this code is exactly... lol
i have the following code now...
hope this helps
i use a a lot of webservices... so there is some of that code included in there aswell...
* This file will do the file upload. It has been suggested to me multiple times, that using a queueing system for
* file upload is not a good idea. Instead I declared a counter and used the final function to fire the next item
* in the array. this also makes canceling a routine easier.
import flash.events.Event;
import flash.events.ProgressEvent;
import flash.net.FileReference;
import flash.net.FileReferenceList;
import flash.utils.ByteArray;
import mx.collections.ArrayCollection;
import mx.controls.*;
import mx.managers.*;
import mx.rpc.events.FaultEvent;
import mx.rpc.events.ResultEvent;
import mx.utils.Base64Decoder;
import mx.utils.Base64Encoder;
import services.images.Images;
import valueObjects.*;
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Reading in any file and converting to a byte array

Okay what I am trying to do is to write a program that will read in any file and convert it into a int array so that I can then manipulate the values of the int array and then re-write the file. Once I get the file into an int array I want to try and compress the data with my own algorithm as well as try to write my own encryption algorithm.
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You can read a whole file into a byte array like this:File f = new File("somefile");
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byte[] contents = new byte[size];
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How to Read Java Byte Array back into SAP xstring Table?

Hi Guys,
I have a situation whereby a user can upload a document in a WebDynpro Java Application. This needs to be saved. I am trying to see if I can make the location of this file that is being saved to be on our SAP AS. I have written a SAP RFC that is imported into the Java Application for use.
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Please advise,
Kind regards,
Christiaan

Loop it...
File file = new File("java.pdf");
FileInputStream fis = new FileInputStream(file);
byte[] buf = new byte[1024];
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        } catch (IOException ex) {

Unable to merge two byte arrays

Hi there,
I am trying to merge two byte arrays into one byte array
and write into a new word document using OutputStream object.
But in the new word document that is created only the contents
of the first byte array are being shown and not that of the second one.
I have pasted the code below.
Any pointers will be of great help.
Thanks and Regards,
Partha.
package com.cisco.asit.icn.common.servlets;
import java.io.ByteArrayInputStream;
import java.io.File;
import java.io.FileInputStream;
import java.io.FileOutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.OutputStream;
import org.apache.poi.hwpf.HWPFDocument;
import org.apache.poi.poifs.filesystem.POIFSFileSystem;
public class TestPOC {
     public static void main(String[] args) {
          try
               System.out.println("I am here...");
               System.out.println("I am in example 4...");
               byte[] byteAr1 = getBytesFromFile(new File("c:\\Testing_POC\\Not_blank.doc"));
               System.out.println(byteAr1.toString());
               System.out.println();
               byte[] byteAr2 = getBytesFromFile(new File("c:\\Testing_POC\\Quest.doc"));
               byte[] finalOne = concatenate(byteAr1, byteAr2);
               System.out.println("byte array 1..."+ byteAr1.length);
               System.out.println("byte array 2..."+ byteAr2.length);
               System.out.println("Final byte array ..."+ finalOne.length);
               InputStream is = new ByteArrayInputStream(finalOne);
               POIFSFileSystem fss = new POIFSFileSystem(is);
               OutputStream out1 = new FileOutputStream("c:\\Testing_POC\\Result.doc");
               fss.writeFilesystem(out1);
               System.out.println("Stored to file system...");
               try {
                    Runtime.getRuntime().exec("rundll32 SHELL32.DLL,ShellExec_RunDLL \"" + "c:\\Testing_POC\\Result.doc");
               catch (IOException e1){
                    e1.printStackTrace();
               System.out.println("I am fine till here...");
     out1.flush();
     out1.close();
     catch (Throwable t) {
     t.printStackTrace();
     byte[] res = new byte[l.length + r.length];
     System.arraycopy(l, 0, res, 0, l.length);
     System.arraycopy(r, 0, res, l.length ,r.length);
return res;
     public static byte[] getBytesFromFile(File file) throws IOException {
InputStream is = new FileInputStream(file);
// Get the size of the file
long length = file.length();
// You cannot create an array using a long type.
// It needs to be an int type.
// Before converting to an int type, check
// to ensure that file is not larger than Integer.MAX_VALUE.
if (length > Integer.MAX_VALUE) {
// File is too large
// Create the byte array to hold the data
byte[] bytes = new byte[(int)length];
// Read in the bytes
int offset = 0;
int numRead = 0;
while (offset < bytes.length
&& (numRead=is.read(bytes, offset, bytes.length-offset)) >= 0) {
offset += numRead;
// Close the input stream and return bytes
is.close();
return bytes;
}

parthInfy wrote:
Hi there,
I am trying to merge two byte arrays into one byte array
and write into a new word document using OutputStream object.
But in the new word document that is created only the contents
of the first byte array are being shown and not that of the second one.
Because the end of the first byte array contains a "document ending" tag and anything after that is just flotsam. And, even if you could remove that "document ending" tag, there is for the second a "document begin" tag. (Among many other tags and flags in both documents.) Word (ar just about any) documents are not simple text files to be concatented, truncated, twisted, inverted, or whatever else, at your pleasure. You actually, God forbid, have to kinow what you're doing, to manipulate them at this level. And, surprise, surprise, you don't.
Edit: Google "POI"

Turn byte array into file

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