Using regular expressions in Java SE v1.3.1

Hi,
I have made a package in which I use the regular expressions package in J2SE v1.4. Unfortunately it turned out that my users are only using v1.3. I wonder if it is somehow possible to import the regexp package in v1.3?
Kind regards
Jesper

Sorry No you cant use 1.4.1 RE in 1.3.1
3 ways of getting round this
1)
have 2 diff jar Files, one for 1.3.1 and one for 1.4.1
2)
use a seperate RE package
such as the Java RE package (before it was added in 1.4.1)
or apache's regexp (This is what I do) from
http://jakarta.apache.org/regexp/index.html
3)
tell your users to update to 1.4.1 !!

Similar Messages

Using regular expressions in java

Does anyone of you know a good source or a tutorial for using regular expressions in java.
I just want to look at some examples....
Thanks

thanks a lot... i have one more query
Boundary matchers
^      The beginning of a line
$      The end of a line
\b      A word boundary
\B      A non-word boundary
\A      The beginning of the input
\G      The end of the previous match
\Z      The end of the input but for the final terminator, if any
\z      The end of the input
if i want to use the $ for comparing with string(text) then how can i use it.
Eg if it is $120 i got a hit
but if its other than that if should not hit.

Can I use regular expressions in Java 1.3

Hi,
Dose Java 1.3 suport regular expressions?
How can I use it?
Thanks.
bevin ye

The 1.3 core API doesn't support regular expressions. Hint: There's an item "Since:" in the JavaDoc of most classes that indicates the version it was initially available. If you look it up in the JavaDoc of java.util.regex.Pattern you'll notice that it's value is 1.4.
But there are several third party libraries that implement regular expressions, 'though I've not used them extensivly, so I can't tell you which one's the most usefull.

How to fetch substring using regular expression

Hi,
I am new to using regular expression and would like to know some basic details of how to use them in Java.
I have a String example= "http://www.google.com/foobar.html#*q*=database&aq=f&aqi=g10&fp=c9fe100d9e542c1e" and would like to get the value of "q" parameter (in bold) using regular expression in java.
For the same example, when we tried using javascript:
match = example.match("/^http:\/\/(?:(?!mail\.)[^\.]+?\.)?google\.[^\?#]+(?:.*[\?#&](?:as_q|q)=([^&]+))?/i}");
document.write('
' + match);
We are getting the output as: http://www.google.com/foobar.html#q=database,*database* where the bold text is the value of "q" parameter.
In Java we are trying to get the value of the q parameter separately or atleast resembles the output given by JavaScript. Please help me resolving this issue.
Regards
Praveen

BalusC wrote:
Regex is a cumbersome solution for fixed patterns like URL's. String#substring() in combination with String#indexOf would most likely already suffice.I usually agree, although, in this case, finding the exact parameter might be difficult without a small regex, perhaps:
"\\wq=\\s*"in conjunction with Pattern/Matcher, used similarly to an indexOf() to find the start of the parameter value.
Winston

Regular expression in java -- specifically email

Does anyone know how I can do a regular expression with java that is going to retrieve an email address pattern.
For example, let's say i have a huge string
this is a sample test. perhaps someoen can tell me how to retrieve my [email protected] from this string. sincerely yours [email protected]
could someone explain to me how to retrieve these emai addresses most efficiently using java's regular expressions
thanks
stev

A citing (http://jregex.sourceforge.net/examples-email.html):
String someValidChars="[\\w.\\-]+";
String someAlphaNums="\\w+";
String dot="\\.";
Pattern email=new Pattern(someValidChars + "@" + someValidChars + dot + someAlphaNums);

How to define a regular expression using regular expressions

Hi,
I am looking for some regular expression pattern which will identify a regular expression.
Also, is it possible to know how does the compile method of Pattern class in java.util.regex package work when it is given a String containing a regex. ie. is there any mechanism to validate regular expression using regular expression pattern.
Regards,
Abhisek

I am looking for some regular expression pattern which will identify a regular
expression. Also, is it possible to know how does the compile method of
Pattern class in java.util.regex package work when it is given a String
containing a regex. ie. is there any mechanism to validate regular
expression using regular expression pattern.It is impossble to recognize an (in)valid regular expression string using a
regular expression. Google for 'pumping lemma' for a formal proof.
kind regards,
Jos

Using Regular Expressions to replace Quotes in Strings

I am writing a program that generates Java files and there are Strings that are used that contain Quotes. I want to use regular expressions to replace " with \" when it is written to the file. The code I was trying to use was:
String temp = "\"Hello\" i am a \"variable\"";
temp = temp.replaceAll("\"","\\\\\"");
however, this does not work and when i print out the code to the file the resulting code appears as:
String someVar = ""Hello" i am a "variable"";
and not as:
String someVar = "\"Hello\" i am a \"variable\"";
I am assumming my regular expression is wrong. If it is, could someone explain to me how to fix it so that it will work?
Thanks in advance.

Thanks, appearently I'm just doing something weird that I just need to look at a little bit harder.

Using regular expressions for validation in i18n

Can we use regular expressions for validation of inputs in a java application taking care of i18N aspects too. Zip code for different locales are different. Can we use regular expressions to validate zipcode inputs from different locales

hi,
For that shall i have to create individual patterns for matching the inputs from different locales or a single pattern will do in the case of validating phone nos. around the world, zip codes etc. In case different patterns are required, programmer should have a konwledge of difference in patters for different locales.
regards
sdas

Getting "Inner Html" using Regular Expressions. Learning RE in SDK1.4.

Hello group.
I am learning Regular Expressions in JAVA SDK 1.4 first. Not PERL or other language.
Using the utility at the following link I am trying to get all the text between the <TR> and </TR> tags.
http://jakarta.apache.org/oro/demo.html
This seems simple but the line returns, breaks etc.. make it more difficult. I have worked on this for hours.
There will be multiple table rows in my stream.
My goal is to first get the text between the <TR> Tags...
Then I was going to use groups to get data0, data1, data2, data3.
Does this sound like a good plan? Should I use multiple RE or one RE that does 4 group returns.
I was thinking the applet was causing my problem.
<TR>.*?</TR> does not work.
(<tr>\s*([^(</tr>)])+</tr>) does not work.
I can get data0 to work as well as data1,2,3.
Would it make more sense to split this multiple row table by </tr>?
One row of malformed html (actually multiple rows):
<TR>
<TD bgColor=#ffffff><A class=fav
href="http://nicesite.com/data0"
>nicesite</A><IMG
src="smile.gif"></TD>
<TD bgColor=#12ff22>data1</TD>
<TD bgColor=#12ff22>data2</TD>
<TD bgColor=#12ff22>data3</TD>
<TD align=middle bgColor=#ffffff><A
href="#"><IMG
src="smile.gif" border=0></A></TD>
<TD align=middle bgColor=#ffffff>data
4</TD>
<TD align=middle bgColor=#ffffff>data5</TD></TR>
s_____ I have seen some of your post and tryed to apply them. What do you think?
Regards,
NupeVic

http://jakarta.apache.org/oro/demo.htmlI prefer
http://jregex.sourceforge.net/demoapp.html
>
This seems simple but the line returns, breaks etc..
make it more difficult. Yes, they do indeed
There will be multiple table rows in my stream.
My goal is to first get the text between the <TR>
Tags...
Then I was going to use groups to get data0, data1,
data2, data3.
Does this sound like a good plan? Should I use
multiple RE or one RE that does 4 group returns.One of the main features of regexes that you must realize
is that they are mainly suited for non-recursive, linear data structures
(btw, that's why regexes in general are hardly suited for html).
So, if the number of TD items is fixed, you could
1. search using a single pattern for the whole row, something like
"<PatternForTR>"+
"<PatternForTD>(<PatternForData>)<PatternFor/TD>"+
"<PatternForTD>(<PatternForData>)<PatternFor/TD>"+
"<PatternFor/TR>"
so the group1 would contain data1 and so on
Otherwise, you should
2. find each row using
"<PatternForTR>(.*?)<PatternFor/TR>",
then search the contents of group1 using the
"<PatternForTD>(<PatternForData>)<PatternFor/TD>".
>
<TR>.*?</TR> does not work.The pattern itself is ok, but in order for it to work one should enable the DOTALL flag (the 's' flag in jregex demo), as the '.' doesn't accept line breaks by default.
(<tr>\s*([^(</tr>)])+</tr>) does not work.It seems that [^(</tr>)]+ actually is a nonsense in this context.
It describes a string that consists of any chars but '(', ')', '<', '>', 'r', 't', '/'.
What you actully meant (a string that doesn't contain "</tr>")
is just achieved by using non-greedy quantifier in <TR>.*?</TR>.
>
I can get data0 to work as well as data1,2,3.
Would it make more sense to split this multiple row
table by </tr>?Going the second way above, you could find rows using the
general pattern for TR:
<tr.*?>(.+?)</tr> and search their contents(i.e. the group#1) using the
general pattern for TD
<td.*?>(.+?)</td> Finally, this is the specific pattern for TD that doesn't include the leading
and trailing tags into group1:
<td[^>]*>(?:\s*</?[^>]*>)*\s*(.+?)(?:\s*</?[^>]*>)*\s*</td>It succeded in finding
nicesite
data1
data2
data3
data
4
data5in your sample.

Matching substrings between square brackets using regular expressions

Hello,
I am new at Java and have a problem with regular expressions. Let me describe the issue in 3 steps:
1.- I have an english sentence. Some words of the sentence stand between square brackets, for example "I [eat] and [sleep]"
2- I would like to match strings that are in square brackets using regular expressions (java.util.regex.*;) and here is the code I have written for the task
+Pattern findStringinSquareBrackets = Pattern.compile("\\[.*\\]");+
+ Matcher matcherOfWordInSquareBrackets = findStringinSquareBrackets.matcher("I [eat] and [sleep]");+
+//Iteration in the string+
+ while ( matcherOfWordInSquareBrackets.find() )+
+{+
+ System.out.println("Patter found! :"+ outputField.getText().substring(matcherOfWordInSquareBrackets.start(), matcherOfWordInSquareBrackets.end())+""); +
+ }+
3- the result I have after running the code described in 2 is the following: *Patter found!: [eat] and [sleep]*
That is to say that not only words between square brackets are found but also the substring "and". And this is not what I want.
What I would like to have as a result is:
*Patter found!: [eat]*
*Patter found!: [sleep]*
That is to say I want to match only the words between the square brackets and nothing else.
Does somebody know how to do this? Any help would be great.
Best regards,
Abou

You can find the words by looping through the sentence and then return the substring within the indexes.
int start=0;
int end=0;
for(int i=0; i<string.length(); i++)
 if(string.substring(i,i+1).equals("[");
start=i;
if(start!=0)
if(string.substring(i,i+1).equlas("]");
end=i;
return string.substring(start,end+1);
}something like that. This code will only find the firt word however. I do not know much about regex so I cannot help anymore.
Edited by: elasolova on Jun 16, 2009 6:45 AM
Edited by: elasolova on Jun 16, 2009 6:46 AM

Checking valid e-mail's using Regular expressions

Hey buddies ,
I desperately need some help here. I need to develop a generic method that wiull use regular expressions and patterns to validate an e-mail.
Does anyonw have any idea on how to do this. And if possible please share some code with me.
Thanks a lot

You can do regular expresions in java using java.util.regex.*:
import java.util.regex.*;
   Pattern p = Pattern.compile("\\S++\\s++");
   Matcher m = p.matcher(sInputLine);
   if(m.find()){
      sUser = m.group().trim();
   }For more info on regular expressions in java, check out the javadocs:
http://java.sun.com/j2se/1.4.2/docs/api/java/util/regex/Pattern.html

Finding URLs using regular expression.

I have an requirement where user will type some text containing URLs like "Please visit this site http://www.google.com/e/qHvQcWco`~!@#$%^&*()-7747. Thank you". This text has to be modified as below before saving it to the database.
"Please visit this site <a href='http://www.google.com/e/qHvQcWco`~!@#$%^&*()-7747'>http://www.google.com/e/qHvQcWco`~!@#$%^&*()-7747</a>. Thank you"
I am using regular expression (http|https)://.+?\\s which marks the end of the url with a white space character.This pattern doesn't work if the URL is located at the end of the string since there will be no space at the end.
For example if the string is "Please visit this site http://www.google.com/e/qHvQcWco`~!@#$%^&*()-7747" the regex will fail.
My acutal problem is to find the URL irrespective its position within the string.
Pattern urlPattern = Pattern.compile("(http|https)://.+?\\s", Pattern.CASE_INSENSITIVE);
Matcher matcher = urlPattern.matcher(plainText);
Map stringIndexMap = new HashMap();
//Searching the input string for urlPattern...
while(matcher.find()) {
String urlString = matcher.group();
//Storing the urls in a hashmap with their indices as keys....
stringIndexMap.put(new Integer(matcher.start()), urlString.trim());
Set keySet = stringIndexMap.keySet();
Iterator it = keySet.iterator();
//Iterating over the hashmap containing urls...
while(it.hasNext()) {
String urlString = (String) stringIndexMap.get(it.next());
* Replacing the url string in the input text with <a href="#" onclick="window.open('<urlString>')"
* using String index
clickableURLString.replace(clickableURLString.indexOf(urlString),
clickableURLString.indexOf(urlString) + urlString.length(),
"<a href=\"#\" onclick=\"window.open('" + urlString
+ "')\">" + urlString + "</a>");
return clickableURLString.toString();

The end of the input is '$' as a regex.
import java.util.regex.*;
public class Prasanna{
public static void main(String[] args){
 String text
= "Please visit this site http://www.google.com/e/qHvQcWco`~!@#$%^&*()-7747";
// String regex = "(http|https)://.+?(?:\\s|$)"; // this works
 String regex = "(http|https)://[^ ]+"; // this also works
 Pattern pat = Pattern.compile(regex, Pattern.CASE_INSENSITIVE);
 Matcher mat = pat.matcher(text);
 while (mat.find()){
 System.out.println(mat.group());
}

Searching for a substring using Regular Expression

I have a lengthy String similar to repetetion of the one below
String str="<option value='116813070'>Something1</option><option value='ABCDEF' selected>Something 2</option>"I need to search for the Sub string "<option value='ABCDEF' selected>" (need to get the starting index of sub string) and but the value ABCDEF can be anything numberic with varying length.
Is there any way i can do it using regular expressions(I have no other options than regular expression)?
thanks in advance.

If you go through the tutorial then you will find this on the second page:
import java.io.Console;
import java.util.regex.Pattern;
import java.util.regex.Matcher;
public class RegexTestHarness {
 public static void main(String[] args){
 Console console = System.console();
 if (console == null) {
 System.err.println("No console.");
 System.exit(1);
 while (true) {
 Pattern pattern =
 Pattern.compile(console.readLine("%nEnter your regex: "));
 Matcher matcher =
 pattern.matcher(console.readLine("Enter input string to search: "));
 boolean found = false;
 while (matcher.find()) {
 console.format("I found the text \"%s\" starting at " +
 "index %d and ending at index %d.%n",
 matcher.group(), matcher.start(), matcher.end());
 found = true;
 if(!found){
 console.format("No match found.%n");
}It's does everything you need and a bit more. Adapt it to your needs then write a regular expression. Then if you have problems by all means come back and post them up here, but first at least attempt to solve it yourself.

Procedure using regular expression

How to write a procedure using regular expression where i pass a string as input
The procedure should check whether it is a valid email address or not
Please help me

Hello,
perhaps you don't need to code it, because it's already there.
When you use the database to send your mails it or the appropriate package throws the exception
ORA-29279: Permanenter SMTP-Fehler: 501 5.5.4 Invalid Address
When you just need a procedure to check it you can write a wrapper for a java function.
import javax.mail.internet.*;
import oracle.sql.NUMBER;
public class mail_utility {
public static NUMBER validate_address(String rfc822Address) {
    int rc = 0;
    try {
      InternetAddress ia = new InternetAddress(rfc822Address);
      rc = 1;
    } catch (AddressException ae) {
      rc = 0;
    } catch (Exception e) {
      rc = -1;
    } finally {
      return new NUMBER(rc);
CREATE OR REPLACE FUNCTION VALIDATE_ADDRESS (p_address in varchar2)
return number
as language java name
'mail_utility.validate_address(java.lang.String) return oracle.sql.NUMBER';I think i've got it from the forum but i don't remember from whom.
Bernd

Help in query using regular expression

HI,
I need a help to get the below output using regular expression query. Please help me.
SELECT REGEXP_SUBSTR ('PWRPKG(P/W+P/L+CC)', '[^+]+', 1, lvl) val, lvl
FROM DUAL,(SELECT LEVEL lvl FROM DUAL
CONNECT BY LEVEL <=(SELECT MAX ( LENGTH ('PWRPKG(P/W+P/L+CC)') - LENGTH (REPLACE ('PWRPKG(P/W+P/L+CC)','+',NULL))+ 1) FROM DUAL));
I need the output as
correct result:
==============
val lvl
P/W 1
P/L 2
CC 3
But i tried the above it is not coming the above result. Please help me where i did a mistake.
Thanks in advance

Frank gave you a solution in your other thread. You could simplify it if you are on 11g:
SQL> select * from table_x
2 /
TXT
TECHPKG(INTELLI CC+FRT SONAR)
PWRPKG(P/W+P/L+CC)
select txt,
 regexp_substr(
 txt,
 '(.*\()*([^+)]+)',
 1,
 column_value,
 null,
 2
 ) element,
 column_value element_number
from table_x,
 table(
 cast(
 multiset(
 select level
 from dual
 connect by level <= regexp_count(txt,'\+') + 1
 as sys.OdciNumberList
order by rowid,
 column_value
TXT ELEMENT ELEMENT_NUMBER
TECHPKG(INTELLI CC+FRT SONAR) INTELLI CC 1
TECHPKG(INTELLI CC+FRT SONAR) FRT SONAR 2
PWRPKG(P/W+P/L+CC) P/W 1
PWRPKG(P/W+P/L+CC) P/L 2
PWRPKG(P/W+P/L+CC) CC 3
SQL> SY.

Using regular expressions in Java SE v1.3.1

Similar Messages

Maybe you are looking for