Web.xml & Servlet

          Hello,
          If i put my servelt class file as per directory provided by WLS.(i.e
          web-inf/... . ) Then do i need to add it into wex.xml file ?
          Thanks
          Jigar

Similar Messages

Web.xml servlet redirection question

Hi everyone;
As you know web.xml file allows you to enter something like this
     <servlet-mapping>
          <servlet-name>application1</servlet-name>
          <url-pattern>/application1</url-pattern>
     </servlet-mapping>
so you can find your application.
As you know it is case sensitive so if a user enters /Application1 it wouldn't be found. I was wondering if i could put a node in there that would redirect requests from Application1 to application.
Any ideas ?
Stev

oh i wasn't aware that i could put multiple nodes in there like this
<servlet-mapping>
<servlet-name>application1</servlet-name>
<url-pattern>/application1</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>application1</servlet-name>
<url-pattern>/Application1</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>application1</servlet-name>
<url-pattern>/APplication1</url-pattern>
</servlet-mapping>
is there a way to simply make this case insensitive and all requests get translated to the lowercase versioN?
Stev

Need HELP!! Where I have to place an web.xml(servlet) file on server

I'm using E-business suite for oracle HR version 11.
On localhost i have developed an servlet file with using web.xml. On web.xml i have customized the file that can load a class for my servlet.But when I deploy on the server i had a cnfused wher do i have to place web.xml and my servlet.
I have made an servlet file for my custom. Where do I have to place an xml(servlet) file on server?
Would you give me know forsolving my problem.Please give me know,I really appreciated if you want to give some solution.
Regards,
Dany Fauzi

Copy web.xml to WEB-INF directory of the web application.

Adding servlet entry in web.xml of j2ee engine

Hi ,
I want a servlet to be loaded on startup of the j2ee engine SAP WAS which is basically flex based (MessageBrokerServlet).
The init param for the servlet is not accessible or cannot be initialized in init method of the servlet using the servletconfig object.
This is when the servlet is used as a portal component of type servlet.
So as to load the servlet and the servlet being able to access the init param i would be changing the web.xml of the sap j2ee engine (NW CE 7.1). are there any other effects of the same or is it fine if i just add this param in the web.xml
    <servlet>
        <servlet-name>MessageBrokerServlet</servlet-name>
        <display-name>MessageBrokerServlet</display-name>
        <servlet-class>flex.messaging.MessageBrokerServlet</servlet-class>
        <init-param>
            <param-name>services.configuration.file</param-name>
            <param-value>/WEB-INF/flex/services-config.xml</param-value>
       </init-param>
        <load-on-startup>1</load-on-startup>
    </servlet>

Hi ,
Vivek in case my servlet is part of the Portal Application as PortalComponent how do i define init parameters that can be accessed in the servlet.
The config file would be accessed in the init method of the servlet how do i do that when the servlet is added as PortalComponent in PortalApplication. The servlet config file needs to accessed in t he init method.
The load on startup thing would be taken care of by setting parameter startup = true of application properties.
Regards
Srikumar V

Web.xml configuration for initial servlet load

Hi all,
I have heard of entering some tag into web.xml file (deployement descriptor) if we need some servlets to be loaded wheneve the app server starts or restarts. can some body help me regarding what to write in web.xml.
thanks in advance

I am having some problems with the same issue although specifying the load-on-startup param is not working for.
Here is snipet of the web.xml:
<servlet id="Servlet_1206024889339">
<servlet-name>ContentServer</servlet-name>
<servlet-class>COM.FutureTense.Servlet.SContentServer</servlet-class>
<init-param id="InitParam_1206024988781">
<param-name>inipath</param-name>
<param-value>/data/WebSphere/ContentServer</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
This however doesn't init the contentServer servlet. Is there anythign else i need to check? I am using websphere5-1.
I saw somewhere you might have to specify a loadonstartup=true? Where is this set?
I know the app is reading the right web.xml because i put in a bad value and saw the error being outputted in the startup log.
There are some servlets being initialised on startup but not the ones I want. These servlets don't seem to be in the web.xml.
[10/10/08 11:53:30:265 IST] 1e06de8 WebContainer A SRVE0169I: Loading Web Module: cs.war.
[10/10/08 11:53:33:330 IST] 1e06de8 WebGroup I SRVE0180I: [cs.war] [servlet] [Servlet.LOG]: JSP 1.2 Processor: init
[10/10/08 11:53:34:098 IST] 1e06de8 WebGroup I SRVE0180I: [cs.war] [servlet] [Servlet.LOG]: SimpleFileServlet: init
[10/10/08 11:53:34:117 IST] 1e06de8 WebGroup I SRVE0180I: [cs.war] [servlet] [Servlet.LOG]: DirectoryBrowsingServlet: init

Need help to set values from web.xml in a jsp class

Hey :-)
I`m trying to get value from my web.xml file into a jsp class. The problem is that the value always retur null. My web.xml file is replaced in the WEB-INF directory where should be. Here is my web.xml
<servlet>
<servlet-name>Html</servlet-name>
<servlet-class>Html</servlet-class>
<init-param>
<param-name>html_test</param-name>
<param-value>Value I want have in my jsp class
</param-value>
</init-param>
</servlet>
And her i my java class who don`t work:
import javax.servlet.jsp.*;
import javax.servlet.jsp.tagext.*;
import javax.servlet.ServletConfig;
public class Html extends BodyTagSupport
String title="";
String html_test;
ServletConfig config;
public void doInitBody() throws JspException
html_test = config.getInitParameter("html_test");
}//End of method doInitBody()
public int doStartTag() throws JspException
try
JspWriter out = pageContext.getOut();
out.print( "<HTML>\n" );
out.print( "<HEAD><TITLE>" + title + "</TITLE></HEAD>\n" );
out.print( "<BODY>\n" );
out.print( "<BR><H1>" + html_test + "</H1>" );
And here are my html_test variable return null.
I hope somone can help me, duke dollars will be given away for the solution answer.
paulsep

Nothing seems to work, have change the string and rewritten the web.xml file to:
<?xml version="1.0" encoding="ISO-8859-1"?>
<!DOCTYPE web-app
PUBLIC "-//Sun Microsystems, Inc.//DTD Web Application 2.3//EN"
"http://java.sun.com/dtd/web-app_2_3.dtd">
<web-app>
          <context-param>
               <param-name>html_test</param-name>
               <param-value>Value I want have in my jsp class</param-value>
          </context-param>
</web-app>

Do we need to put the following code in the web-xml for the project to run

Hi^^^,
actually I have created a project in Eclipse WTP and I am running it from remote server. Its giving me 404 error when I tried to run it.
I know 404 error is generally due to some error in deployment descriptor.
I am going through this tutorial for creating project in eclipse WTP
this says that I need to include the following code in web-xml. Please look at the quotes below
"Web modules in J2EE has a deployment descriptor where you configure the web application and its components. This deployment descriptors is called the web.xml. According to the J2EE specification, it must be located in the WEB-INF folder. web.xml must have definitions for the Servlet and the Servlet URI mapping. Enter the following lines into web.xml:"
"Listing 2. Deployment Descriptor web.xml"
<servlet>
<servlet-name>Snoop Servlet</servlet-name>
<servlet-class>org.eclipse.wtp.tutorial.SnoopServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>Snoop Servlet</servlet-name>
<url-pattern>/snoop/*</url-pattern>
</servlet-mapping>
My question is, it is necessary to include the above lines between <servlet> and </servlet-mapping> in web-xml
thanks and regards,
Prashant

pksingh79 wrote:
actually I have created a project in Eclipse WTP and I am running it from remote server. Its giving me 404 error when I tried to run it.
I know 404 error is generally due to some error in deployment descriptor. what's the url you've put.
<servlet>
<servlet-name>Snoop Servlet</servlet-name>
<servlet-class>org.eclipse.wtp.tutorial.SnoopServlet</servlet-class>
</servlet> Every Servlet has to have a <servlet></Servlet> tag in the web.xml
the <servlet-name>is for the naming the servlet and the <servlet-calss>is for class file of the servlet in your case the .class file is to be in the package of tutorial,if it's not then how the container will no where the calss file is
<servlet-mapping>
<servlet-name>Snoop Servlet</servlet-name>
<url-pattern>/snoop/*</url-pattern>
</servlet-mapping>You type something in your url likk http://localhost:8080/webappname (Tomcat server),so for url mapping instead of typing the entire class file name ,you just enough have to type what you've put in the <url-mapping> tag and it has to be inside of <servlet-mapping>
I think the problem is in <url-pattern> change it like /snoop<url-pattern>
My question is, it is necessary to include the above lines between <servlet> and ></servlet->mapping> in web.xmlSo now you think whether you need something inside <servlet>and </servlet-mapping>

Init parameter in web.xml throwing an error..?

OK.. this is probably going to sound strange, but here goes:
Here is my entry in the web.xml:
<servlet>
          <servlet-name>ServletTestRunner</servlet-name>
          <servlet-class>
               org.apache.cactus.server.runner.ServletTestRunner
          </servlet-class>
     </servlet>
     <servlet-mapping>
          <servlet-name>ServletTestRunner</servlet-name>
          <url-pattern>/ServletTestRunner</url-pattern>
     </servlet-mapping>Everything works fine - I pull up the servlet with the following URL (http://localhost:7001/CDCAppWeb/ServletTestRunner?suite=com.testcases.decision.service.SendCreditRequestBeanTest)
, and receive the results in XML format. However, if I change the web.xml to have the following:
     <servlet>
          <servlet-name>ServletTestRunner</servlet-name>
          <servlet-class>
               org.apache.cactus.server.runner.ServletTestRunner
          </servlet-class>
          <init-param>
               <param-name>xsl-stylesheet</param-name>
               <param-value>cactus-report.xsl</param-value>
          </init-param>
     </servlet>(notice the cactus-report.xsl init-param entry) - the servlet does not work. Actually, NONE of the other servlets in my application work when I put in this init-param for the ServletTestRunner. I have verified that the xsl is in the classpath (WEB-INF/classes).
What I am missing... any ideas?

I know what the problem is. If you call servlet with the default URL (http://host/app/servlet/package.Servlet) than Servlet DOES NOT read init parameters. I don't know why it was designed this way.
To make servlet read init parameters, you have to assign it a name and then call it with that name, like this:
<servlet>
<servlet-name>ServletName</servlet-name>
<servlet-class>package.ServletClass</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>ServletName</servlet-name>
<url-pattern>/app/path/ServletName</url-pattern>
</servlet-mapping>
You can then call servlet using path specified in url-pattern and read init parameters in the normal way.

Web.xml configured correctly(I think), but still getting '404...resource

not found error' from tomcat. Here is my web.xml:
<servlet>
<servlet-name>HelloServlet</servlet-name>
<servlet-class>HelloServlet</servlet-class>
</servlet>
<servlet>
<servlet-name>HelloServlet2</servlet-name>
<servlet-class>coreservlets.HelloServlet2</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>HelloServlet</servlet-name>
<url-pattern>/classes/HelloServlet</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>HelloServlet2</servlet-name>
<url-pattern>/classes/coreservlets.HelloServlet2</url-pattern>
</servlet-mapping>
</web-app>
when I went to the following urls after I had edited web.xml to the above,
http://localhost:8080/cucoweb/classes/coreservlets.HelloServlet2
http://localhost:8080/cucoweb/classes/HelloServlet
I go the expected results, ie, 'Hello(2)' and 'Hello'. Then I shutdown tomcat and restarted it.
And when i tried to access those 2 urls again, I got the above error.
(Actually I had the same web.xml before except that it didnt have the /classes in front in the
url-pattern. I was able to access it by the same url - without the /classes - and then the next day
when started tomcat and tried to access it, it didnt work, same error.)
In this example, cucoweb is the context root, correct ? Shouldn't the url-pattern be relative to the
context root ? Thats how I have it now, I think.
Would adding my webapp directory, ie cucoweb/classes, to my CLASSPATH help ?
I'm in ubuntu, when I do echo $CLASSPATH, I get :
.:/usr/lib/jvm/java-6-sun-1.6.0.00/lib:/usr/lib/jvm/java-6-sun-1.6.0.00/imq/lib/:/usr/lib/jvm/java-6-sun-1.6.0.00/jre/lib
I havent tried this yet because doing this is kind of tricky in ubuntu. (You have etc/environment and
bash.bashrc, for ex.) But if I try that and it works I will post about it. I suspect its something else,
though, because it worked once, before restarting tomcat, thats why I'm posting here first.
Any info, even educated guesses, would be greatly appreciated. Thanks in advance.

Thanks for the reply. Here is my web structure :
/usr/local/tomcat/apache-tomcat-6.0.14/webapps/cucoweb/WEB-INF/classes
From my understanding you are supposed to have your own webapp deployment directory
under webapps, ie, cucoweb, and not use webapps/ROOT. (I'm not sure what /ROOT is even for)
My web.xml is in WEB-INF. My /classes directory contains HelloServlet.class and a directory
called coreservlets which contains HelloServlet2.class.
I'm not sure what you mean by 'better you to delete under tomcat/work/catalina/localhost folder'.
Can you please clarify ?
FYI, my work/catalina/localhost contains the following :
cucoweb docs examples host-manager manager
Here cucoweb just contains a SESSIONS.ser file. Are you saying i should delete that ?

How to deploy web.xml in OAF to server?

Hello,
Currently i used oracle 9i jeveloper to develop OAF page for EBS 11.5.10
based on requirement, i need create a new JSP file and change default web.xml file in jeveloper. Who can help how to deploy new web.xml to server? Thank you very much!
Added following code to web.xml
---web.xml------------
<servlet>
<servlet-name>barbecue</servlet-name>
<servlet-class>net.sourceforge.barbecue.BarcodeServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>barbecue</servlet-name>
<url-pattern>/CreateBarCode</url-pattern>
</servlet-mapping>
-----------------------------------

Anyone know how to deploy web.xml in local jeveloper to server? thanks a lot!

Web service and servlets in the same project...web.xml?

Hello, I have a problem with my web service.
I have a server, which displays a web service. I programmed this service with JAXRPC.
I have a client, in another directory. I succeded in compiling, deploying and running the web service.
The problem is that after I tried to integrate this service in an existing project. This project contains servlets. In these servlets, I'm using sessions.
These servlets are on the same side as the server of the web service. Because of the implementation of my code, I'd like to use in the class that represents the server of the service, the same session as the one I'm using in the servlets.
But of course, it's not working by itself. I know there's something to do with the web.xml files.
The thing is that I created a web.xml file for the service, and another for the servlets.
I was thinking of joining both of them in one xml file, but everything crashes then...
Could someone tell me how to create a project with a web service and servlets, and mostly how to configure the xml file??
Thanks for any help
Philippe

Hello, I have a problem with my web service.
I have a server, which displays a web service. I programmed this service with JAXRPC.
I have a client, in another directory. I succeded in compiling, deploying and running the web service.
The problem is that after I tried to integrate this service in an existing project. This project contains servlets. In these servlets, I'm using sessions.
These servlets are on the same side as the server of the web service. Because of the implementation of my code, I'd like to use in the class that represents the server of the service, the same session as the one I'm using in the servlets.
But of course, it's not working by itself. I know there's something to do with the web.xml files.
The thing is that I created a web.xml file for the service, and another for the servlets.
I was thinking of joining both of them in one xml file, but everything crashes then...
Could someone tell me how to create a project with a web service and servlets, and mostly how to configure the xml file??
Thanks for any help
Philippe

How to create a simple web.xml for using servlets

Hello i wanna configure the web.xml that i can use sevlets and beans, but how can i do that?
This is de directorie i have installed my webapp
C:\Tomcat 4.1\webapps\testapp
C:\Tomcat 4.1\webapps\test\WEB-INF\classes (in this dir, I wanna put my beans and servlets, I got one servlet and the name is LogIn.class).
And i wanna request my servlets with the url http://localhost:8080/testapp/servlet/LogIn
How can i create a very basic web.xml with working beans, servlets and session? It is for testing-use only, so the security is not important for me at this moment.
Tnx

under your web-inf
in your web.xml file you must map
the servlets
under the <web-app> tag type
<servlet>
     <servlet-name>LogIn</servlet-name>
     <servlet-class>com.LogIn</servlet-class>
</servlet>
<servlet-mapping>
      <servlet-name>LogIn</servlet-name>
      <url-pattern>/LogIn</url-pattern>
</servlet-mapping>ps: start using some IDE such as NetBeans or Ecclipse
since they will take care of mapping all servlets and Beans
and generate all the necessary files for your web-app

Can i run a servlet without a web.xml file for servlet mapping?

Hello everyone.
The code i want to run compiles and everythink looks ok.
It produces the .class file.
I run Tomcat 4.1 and i build my Web site with Dreamweaver.
I have a form in a page and i want to send the data upon form completion to a database i already have build with MySql.
The database is up and running and the server is set-up ok.
I have changed the port in Tomcat to run on port 80.
The directory i have my site is
Tomcat41\webapps\ROOT\se
and the directory where i keep the servlet class is
Tomcat41\webapps\ROOT\se\WEB-INF\servlet
I have a web.xml file to map the servlet and placed it in
Tomcat41\webapps\ROOT\se\WEB-INF
In the Form action i write action:"/servlets/Classes/GroupRegistration"
and I RECEIVE AN 404 ERROR FROM APACHE.
Somethink is wrong .
The following is the code from the GroupRegistration.java file
and follws the web.xml file.
Please Help.
import java.sql.*;
import java.io.*;
import javax.servlet.*;
import javax.servlet.http.*;
public class GroupRegistration extends HttpServlet
Connection con;
public void doPost (HttpServletRequest req, HttpServletResponse res)
                         throws ServletException, java.io.IOException
     handleForm(req, res);
public void init() throws ServletException {
     try{
     /* Loading the driver for the database */
     Class.forName("com.mysql.jdbc.Driver");
     Connection Con = DriverManager.getConnection("jdbc:mysql://localhost/se?user=luser&password=");
     catch (ClassNotFoundException e) {
     throw new UnavailableException("Couldn't load JdbcOdbcDriver");
     catch (SQLException e) {
     throw new UnavailableException("Couldn't get db connection");
     private void handleForm(HttpServletRequest req, HttpServletResponse res)
     throws ServletException {
     //ServletOutputStream out = res.OutputStream();
     //res.setContentType("text/html");
     //Extract the form Data Here
     String group = req.getParameter("GroupNo");
     String Name1 = req.getParameter("Name1");
     String LoginID1 = req.getParameter("LoginID1");
     String Name2 = req.getParameter("Name2");
     String LoginID2 = req.getParameter("LoginID2");
     String Name3 = req.getParameter("Name3");
     String LoginID3 = req.getParameter("LoginID3");
     String Name4 = req.getParameter("Name4");
     String LoginID4 = req.getParameter("LoginID4");
     String URL = req.getParameter("URL");
     String Title2 = req.getParameter("Title2");
     String date = req.getParameter("date");
     String INSERT = "INSERT INTO registration (groupno, name1, loginid1, name2, loginid2, name3, loginid3, name4, loginid4, url, topic, date) VALUES (" + group + "," + Name1 + "," + LoginID2 + "," + Name2 + "," + LoginID2 + "," + Name3 + "," + LoginID3 + "," + Name4 + "," + LoginID4 + "," + URL + "," + Title2 + "," + date + ")";
     PreparedStatement pstmt = null;
     try{
     pstmt = con.prepareStatement(INSERT);
     pstmt.executeUpdate();
     catch (SQLException e) {
     throw new ServletException(e);
     finally {
     try {
     if (pstmt != null)pstmt.close();
     catch (SQLException ignored){
The web.xml file
<?xml version="1.0" encoding="ISO-8859-1"?>
<web-app xmlns="http://java.sun.com.xml/ns/j2ee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee
http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd" version="2.4">
<servlet>
<servlet-name>GroupRegistration</servlet-name>
<servlet-class>GroupRegistration</servlet-class>
</servlet>
<servlet-maping>
<servlet-name>GroupRegistration</servlet-name>
<url-pattern>/myGroupRegistration</url-patern>
</servlet-mapping>
</web-app>
I apreciate your time.
Thanks for any help.

and the directory where i keep the servlet class is
Tomcat41\webapps\ROOT\se\WEB-INF\servletOthers have pointed out that "servlet" should be "classes", but there is another mistake that hasn't been spotted. If you want your servlet to appear in the root context, you should use:
Tomcat41\webapps\ROOT\WEB-INF\classes
If you want your servlet to appear under the /se context, then you should use:
Tomcat41\webapps\se\WEB-INF\classes
and also, in the latter case, your form action should be /se/myGroupRegistration.

JDev 10.1.3 compile error in servlet 2.4 web.xml

I built a Servlet 2.4/JSP 2.0 application in JDev 10.1.3. When I try to make/compile/deploy it the compiler gives me errors like the following for every JSP file that has a JSTL 1.1 taglib:
Error(2,9): Element "web-app' used but not declared
Error(2,63): Attribute 'xmlns:xsi' used but not declared
Error(3,103): Attribute 'xsi:schemaLocation' used but not declared
Error(4,16): Attribute 'version' used but not declared
Error(4,56): Attribute 'xmlns' used but not declared
Error(4,57): Can not build schema 'http://java.sun.com/xml/ns/j2ee' located at 'http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd'
Error(5,15): Element 'description used but not declared
It is obviously havng problems with the web.xml file (which is in the servlet 2.4 format) and is probably not finding the web.xml DTD document. How do I fix it?
Installation is on Solaris 9 using J2SDK 1.4.2_04-b05
By the way, this system is on a disconnected network. How do I get JDeveloper updates for a system not connected to the Internet?

Allen,
A JSP with web.xml web-app element
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd" version="2.4" xmlns="http://java.sun.com/xml/ns/j2ee">
runs in JDeveloper 10.1.3
thanks,
Deepak

Weblogic.servlet.reloadCheckSecs in web.xml not working

Given the following web.xml file:
          <!DOCTYPE web-app PUBLIC "-//Sun Microsystems, Inc.//DTD Web Application
          1.2//EN" "http://java.sun.com/j2ee/dtds/web-app_2_2.dtd">
          <web-app>
          <context-param>
          <param-name>weblogic.servlet.reloadCheckSecs</param-name>
          <param-value>100</param-value>
          </context-param>
          <servlet>
          <servlet-name>CookieCounter</servlet-name>
          <servlet-class>servlets.CookieCounter</servlet-class>
          </servlet>
          <servlet-mapping>
          <servlet-name>CookieCounter</servlet-name>
          <url-pattern>monster</url-pattern>
          </servlet-mapping>
          <welcome-file-list>
          <welcome-file>hello.html</welcome-file>
          </welcome-file-list>
          <error-page>
          <error-code>404</error-code>
          <location>/error.jsp</location>
          </error-page>
          </web-app>
          It seems the weblogic.servlet.reloadCheckSecs property is not taking effect.
          The
          default value of -1 is always used. I did stop and restart weblogic.
          I also trid to set the servlet classpath in the web.xml file with
          weblogic.servlet.classpath
          property and it did not change the classpath for the servlet. It seems that
          other
          items are working such as adding new servletrs to the web application. Note
          that
          this is the cookie sample application that installes with the beta 2
          download.
          Thanks,
          Dan.


Hi All:
Thanks for all your help regarding the adfAuthentication success_url. Now I am able to configure to make this work. But now I am facing another issue i.e. I am getting 401 Not authorized message when the success_url is pointed to the jspx page.
Note: I am using custom login module similar to DBProcOraDataSourceLoginModule so my roles are stored in the custom Role class. So I am not sure how to pass this role info to the security in ADF in order to authorize the page to be viewed.
Could you please help and can you point me to any specific link.
Thanks & Regards
Sridhar Doki

Web.xml & Servlet

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