What's "!" in method declaration in class?

See the excerption below, what's the meaning of "!"?
protected section.
methods CALC
    importing
      !IV_PROC_TYPE type STRING optional
      !IV_PROC_NAME type STRING optional
      !IV_PROC_CLASS type STRING optional .
Thanks in advance

hi,
the exclamation mark is nothing more than a hint to the ABAP compiler. It is required when you want use keywords like export, exceptions and so on as formal / actual argument.
In the given scenario it is no must. But maybe the code is produced by some generator. For a generator not smart enough to no all rules, it is good advice to use exclamation marks for any parameter.
Regards,
anver
<i>
if hlped pls mark points</i>

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There are 2 main differences.
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What is the purpose of Static methods inside a class?

Hi,
What is the purpose of Static methods inside a class?
I want the answers apart from "A static method does not require instance of class(to access) and it can directly be accessed by the class name itself"
My question is what is the exact purpose of a static method ?
Unlike attributes, a separate copy of instance attributes will be created for each instance of a class where as only one copy of static attributes will be created for all instances.
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Hi Sharma,
Static methods is used to access statics attributes of a class. We use static attributes when we want to share the same attribute with all instances of a class, in this case if you chage this attribute through the instance A this change will change will be reflected in instance B, C........etc.
I think that your question is correct -> a separate copy of instance method will be created for each instance of a class and only one copy of static methods be create ?
"A static method does not require instance of class(to access) and it can directly be accessed by the class name itself"
Static Method: call method class=>method.
Instance Method: call method instance->method.
Take a look at this wiki pages.
[https://wiki.sdn.sap.com/wiki/x/o5k]
[https://wiki.sdn.sap.com/wiki/x/ZtM]
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Marcelo Ramos

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compiler performance is utterly unimportant anyway...
If the compiler takes too long, just get a faster build system :)

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Got the below code for the Bank class with a log in system, Want i need is a While loop for
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package bank;
import javax.swing.*;
import java.lang.*;
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this.Balance=this.Balance-val;
public static void account (String args[] ){
String Deposit = new String();
String Withdraw = new String() ;
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Maxideon wrote:
All of these are valid,
while(validUser == true) {
while(validUser) {
//I prefer this one
if(validUser == true) {
if(validUser) {
//I prefer this one
} What you have,
if(validUser = true) {
if(validUser = false) {
}is different. I have two equal signs, while you have one. What do you think one equal sign does?
P.S. All your variable names are screwed up. They should begin with a lower case letter.
Edit
Some other anomalies: you declared ValidUser as a Boolean and you imported java.lang. .... Why?
Edit
Another weird thing.
String Deposit = new String();
String Withdraw = new String();?I Am fairly new to java, I have things "working" to an extent, and i am aware of the naming conventions over the variable names,

Calling a non-static method from another Class

Hello forum experts:
Please excuse me for my poor Java vocabulary. I am a newbie and requesting for help. So please bear with me! I am listing below the program flow to enable the experts understand the problem and guide me towards a solution.
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way?
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Hello Forum:
Danny_From_Tower, Encephalatic: Thank you both for your responses.
Here is what I have done so far. I have a button called "btnAccept" created in the class MyMenu.
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To access a method frm a class derived frm a base class with the same name

Here' s an example:-
class TestA {
public void start() {
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public void start() {
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TestA.
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Thanks,
Heena

>
>
Secondly, when i say ((TestA).testB).start(); output is TestB. But when i define start() method as static output is TestA. I need clarity for the same.In the static case, all that the compiler is interested in is the class of the expression before the ".". Because you've put in an explicit cast the type of expression is assumed to be TestA the compiler doesn't know what kind of object will actually be referenced at runtime. In the static case which method is called is determined at compile time.
In the instance method case what determines the method called is determined the class of the actual, run time, value of the expression, and despite your cast, the actual value is still a reference to a TestB instance, so the TestB method is called. In the instance case which method called is determined at run time.

What's "!" in method declaration in class?

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